A gas has density 2.41 g/liter at 25°C and 770 mm Hg. Calculate it's molecular mass (R = 0.0821 L atm.mol-1K-1.

ASAP!!!!!!!!! ​

Answers

Answer 1

Answer:

Molecular mass, M = 58.20 g/mol.

Explanation:

Given the following data;

Density = 2.41 g/literTemperature = 25°CPressure = 770 mmHgGas constant, R = 0.0821 L atm.mol-1K-1

Conversion:

760 mmHg = 1 atm

770 mmHg = 770/760 = 1.0131 atm

Temperature = 25°C = 273 + 25 = 298 K

To find the molecular mass, we would use the ideal gas law equation (density version);

PM = dRT

Where;

P is the pressure.M is the molecular mass.d is the density of a substance.R is the ideal gas constant.T is the temperature.

Making M the subject of formula, we have;

[tex] M = \frac {dRT}{P} [/tex]

Substituting into the formula, we have;

[tex] M = \frac {2.41 * 0.0821 * 298}{1.0131} [/tex]

[tex] M = \frac {58.9626}{1.0131} [/tex]

Molecular mass, M = 58.20 g/mol.


Related Questions

necesito que me ayuden a resolver lo de las imágenes por favor ... es urgente

Answers

wha-hat? I don't understand?




Which general equation shows a double-displacement reaction?


O A. AB + CD + AC + BD
O B. AB → A+B
O C. AB + CD → AD + CB
O D. A+B → AB

Answers

Answer:

O A. AB + CD + AC + BD

explanation:

Explanation:

A.ab+cd+ac+bd is your answer

I need answers to question 1,2,3

Answers

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

How could the experiment be changed to allow for a result to be shown for the insoluble food
colouring?

Answers

Answer:

no lo se yo hablo en español no en ingles

How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?

Answers

Hi there!

[tex]\large\boxed{3.203 * 10^{22} atoms}[/tex]

We can use the following conversions to solve:

Total mass --> amount of mols --> amount of atoms (Avogadro's number)

Begin by calculating the amount of boron trifluoride in 3.61 grams:

3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

Use avogadro's number to convert:

0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms

True or false, Henry Moseley discovered through X-Ray crystallography the number of neutrons that were present
in the nucleus of atoms of every element.

Answers

Answer:

Im pretty sure its true

Explanation:

Answer:

answer is true .

Explanation:

this may help you

Methane is the main component of natural gas. Using the given reaction enthalpy, calculate the heat energy produced by the combustion of one kilogram of methane.

Answers

Answer: The heat energy produced is 53831.25KJ

Explanation:

METHANE is the main component of natural gas. It can undergo combustion reaction in air with a bright blue flame to produce carbondioxide and water. The heat of reaction (enthalpy) is negative because heat is absorbed during the chemical reaction. To calculate the heat energy produced by the combustion of one kilogram (1 kg) of methane the following steps are taken:

Molecular mass of methane =16 gm/mol.

So moles of 1 kg methane =

Given mass of methane ÷ molecular weight of methane

But the given mass = 1kg = 1000g

Therefore,

moles of 1000g methane = 1000÷16

= 62.5 moles

Hence, energy evolved = (moles of methane) × (heat of combustion)

Therefore,

heat energy produced= 62.5 × (-861.3kj)

= -53831.25kj

The heat energy produced by the combustion of one kilogram of methane is –53831.25 KJ

We'll begin by calculating the number of mole in 1 Kg of CH₄

Mass of CH₄ = 1 kg = 1000 g

Molar mass of CH₄ = 12 + (4×1) = 16 g/mol

Mole of CH₄ =?

Mole = mass /molar mass

Mole of CH₄ = 1000 / 16

Mole = 62.5 moles

Finally, we shall determine the heat energy produced from the reaction.

CH₄ + 2O₂ —> CO₂ + 2H₂O ΔH = –861.3 KJ

From the balanced equation above,

1 mole of CH₄ reacted to produce –861.3 KJ.

Therefore,

62.5 moles of CH₄ will react to produce = 62.5 × –861.3 = –53831.25 KJ

Thus, –53831.25 KJ of heat energy is produced.

Complete Question is located in the attached photo

Learn more: https://brainly.com/question/13671340

Which redox reaction would most likely occur if silver and zinc metal were added to a solution that contained silver and zinc ions?

Answers

Answer:

D. Zn²⁺ + 2Ag → Zn + 2Ag⁺

Explanation:

On the reduction potential chart, we have that silver ion Ag⁺ is a stronger oxidizing agent than, zinc, Zn, which is a reducing reducing agent the compared to silver

Therefore, the redox reaction that will occur is that the zinc, Zn, will be oxidized to Zn²⁺ ion, while the silver, Ag²⁺ ion will be reduced to silver deposits Ag, therefore, the zinc will displace the silver in the solution containing silver and zinc ions because zinc is higher than silver in the reactivity series

The reduction potential Zn → Zn²⁺ + 2e⁻ = +0.76

The reduction potential for Ag⁺ + e⁻ → Ag = +0.8

Therefore, given that redox reactions are reversible, we get the following likely redux reaction;

Zn(s) + 2Ag⁺(aq) ⇄ 2Ag(s) + Zn²⁺(aq)

Therefore, from the given options;

Zn²⁺(aq) + 2Ag(s) → Zn(s) + 2Ag⁺(aq) is the reaction most likely to occur.

Help me please I really need this tomorrow

Answers

9.D

10.A

11.C

12.B

13.D

14.C

15.A

16.A

18.C

14. Which of the following alkanols on oxidation is most likely to yield the
compound below?
CHICHICOOON
.CO
(A) Butanol (B) Propan-2-ol(2-methylbutan-1-ol (D) 2-methylpropan-1-
ol (E) 2-methylpropan-2-ol.

Answers

Answer:

A

Explanation:

I think that is the ans but am not sure

Answer:

2-methylpropan-1-ol.

Explanation:

[tex]{ \tt{CH _{3}CH(CH _{3})CH _{2}OH}}[/tex]

please provide is matter about us pure all NCERT questions and answers

Answers

Answer:

I hope that's what u were lookong for :))

Explanation:

True or false The atomic number of an element is always more than the mass number of that element.

Answers

The sentence is true

Which phrase best describes a Hawaiian eruption?
A. Slow-moving lava flows and explosions of pumice
B. Ash shooting high into the atmosphere
C. Fast-moving lava flows and explosions of cinder
D. Lava fountains and fissure eruptions

Answers

Answer:

C.faste-moving lava flows and explosion of cinder

A chemical bond formed when two atoms share two pairs of electrons is a ________ bond; it is best described as ________.

Answers

Answer:

A chemical bond formed when two atoms share two pairs of electrons is a double bond; it is best described as a covalent bond.

Explanation:

A chemical bond in which two pairs of electrons are shared has to be defined as covalent since ionic bonds don't involve electron sharing. They consist only of electrostatic attraction between ions.

A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2KClO3 Right arrow. 2KCI 3O2 What is the percent yield of oxygen in this chemical reaction

Answers

Answer:

Percentage yield of O₂ = 73.4%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2KClO₃ —> 2KCl + 3O₂

Next, we shall determine the mass of KClO₃ that decomposed and the mass of O₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of KClO₃ = 39 + 35.5 + (3×16)

= 39 + 35.5 + 48

= 122.5 g/mol

Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 3 × 32 = 96 g

SUMMARY:

From the balanced equation above,

245 g of KClO₃ decomposed to produce 96 g of O₂.

Next, we shall determine the theoretical yield of O₂. This can be obtained as follow:

From the balanced equation above,

245 g of KClO₃ decomposed to produce 96 g of O₂.

Therefore, 400 g 245 g of KClO₃ will decompose to produce

= (400 × 96)/245 = 156.7 g of O₂.

Thus, the theoretical yield of O₂ is 156.7 g

Finally, we shall determine the percentage yield of O₂. This can be obtained as follow:

Actual yield of O₂ = 115.0 g

Theoretical yield of O₂ = 156.7 g

Percentage yield of O₂ =?

Percentage yield = Actual yield /Theoretical × 100

Percentage yield = 115/156.7 × 100

Percentage yield = 11500/156.7

Percentage yield of O₂ = 73.4%

what is the application of chemistry​

Answers

Answer:

Chemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.

 Help ASAP only right answers only no spam don’t answer if you don’t know

















Answers

i know the answer is a theory

I believe it’s A.theory Im so sorry if it ain’t correct but I really think it is

Someone plz help me here are the photos, I need the last one

Answers

Answer:

(6 mol)·(-393.5 kJ/mol) + (6 mol)·(-285.83 kJ/mol) - (1 mol)·(-1,273.02 kJ/mol) + (6 mol)·(0 kJ/mol)

Explanation:

Question; From the given options, the chemical reaction in the question is presented as follows;

C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l), given that we have;

[tex]\Delta \text H _f^{\circ}[/tex] for C₆H₁₂O₆ = -1,273.02 kJ/mol

[tex]\Delta \text H _f^{\circ}[/tex] for O₂(g) = 0 kJ/mol

[tex]\Delta \text H _f^{\circ}[/tex] for CO₂(g) = -393.5 kJ/mol

[tex]\Delta \text H _f^{\circ}[/tex] for H₂O(l) = -285.83 kJ/mol

The heat or enthalpy of a reaction,  is given as follows;

[tex]\Delta\text H_{rxn}^{\circ} = \sum \text n \cdot \Delta \text H _f^{\circ}(\text {products}) - \sum \text m \cdot \Delta \text H _f^{\circ}(\text {reactants} \text)[/tex]

Therefore, the equation which should be used to calculate [tex]\Delta\text H_{rxn}^{\circ}[/tex], is given as follows;

[tex]\sum \text n \cdot \Delta \text H _f^{\circ}(\text {products})[/tex] = (6 mol)·(-393.5 kJ/mol) + (6 mol)·(-285.83 kJ/mol)

[tex]\sum \text m \cdot \Delta \text H _f^{\circ}(\text {reactants} \text)[/tex] = (1 mol)·(-1,273.02 kJ/mol) + (6 mol)·(0 kJ/mol)

Therefore;

[tex]\Delta\text H_{rxn}^{\circ}[/tex] = (6 mol)·(-393.5 kJ/mol) + (6 mol)·(-285.83 kJ/mol) - (1 mol)·(-1,273.02 kJ/mol) + (6 mol)·(0 kJ/mol)

A new element R shows chemical properties similar to the element sodium. What is the correct formula of a compound formed with R and sulfur?
R₂S
RS₂
RS
R₂S₂​

Answers

Answer:

R2S this is because sodium has one 1 valence and sulfur has valence of 2 so when they combine theyinterchange their valence

(d) (i) How can the water molecules from the iceberg end up as water in the lake?

Answers

Explanation:

If the iceberg is near the lake and the water molecules melt, then the molecules will slide down. The iceberg could be melting for many reasons - it can be purposely destroyed, the sun could be melting it, or it might naturally fall in. So, this is the answer to your question. Hope it helps!

A piece of solid tin is submerged in silver nitrate solution. A reaction occurs producing tin (iv) nitrate solution and solid silver. Write the word equation, write the skeletal equation and balanced chemical equation for the reaction.

Answers

Answer: For the given reaction-

The word equation is Tin + silver nitrate = tin (IV) nitrate + silverThe skeletal equation is [tex]Sn + AgNO_{3} \rightarrow N_{4}O_{12}Sn + Ag[/tex]The balanced chemical equation is  [tex]Sn(s) + 4AgNO_{3}(aq) \rightarrow N_{4}O_{12}Sn(aq) + 4Ag(s)[/tex]

Explanation:

When names of chemicals or species involved in a chemical reaction are represented in the form of an equation then it is known as a word equation.

For example, Tin + silver nitrate = tin (IV) nitrate + silver

The 'equal to' symbol denotes a forward arrow.

A skeletal equation contains only the chemical formula of species involved in a chemical reaction.

For example, [tex]Sn + AgNO_{3} \rightarrow N_{4}O_{12}Sn + Ag[/tex]

A chemical equation which contains same number of atoms on both reactant and product side along with states of species is called a balanced chemical equation.

 [tex]Sn(s) + 4AgNO_{3}(aq) \rightarrow N_{4}O_{12}Sn(aq) + 4Ag(s)[/tex]

Which of the following make up an atom of gold? Select all that apply.

a
photons
b
electrons
c
neutrinos
d
protons
e
neutrons

Answers

Answer:

b, d, e

Explanation:

An atom is made up of electrons, protons and neutrons. Gold is an atom thus has the above particles.

Blood tests can be used to check a person's blood glucose and hormone levels. The tabular column given below shows the result of two blood tests carried out on three people to check their blood glucose levels. Person 1 is healthy

Answers

Answer:

In after fasting test, Person 2 has slightly higher blood glucose level than person 1.

In after drinking glucose test, Person 3 has much high glucose level than person 1.

Explanation:

Blood sugar test determines the level of glucose present in body. The test can be taken after intake of food / glucose or after fasting for 12 hours. Results of both tests are compared to identify level of glucose present in human body. In after fasting test person has higher glucose and in another test person 3 has higher glucose level.

What are the effects of acid precipitation in city centers

Answers

Answer:

Answer to the following question is as follows.

Explanation:

Acid rain causes harm to houses and buildings by dissolving stone or corroding metal exposed to the elements. Acid rain can degrade calcium carbonate or calcium-based chemicals found in some of these products.

The acidic particles damage metal and accelerate the deterioration of paint and stone. They also make buildings and other structures, like as monuments, filthy.

Trends in the periodic table indicate that the element with the greatest ionization energy is in which of the following periods and groups?

a
Period 2, Group 1
b
Period 7, Group 2
c
Period 6, Group 17
d
Period 1, Group 18

Answers

Answer:

D Period 1, Group 18

Explanation:

it's helium

it's top right corner of the periodic table

how many distinct monochlorinated products can result when methylcyclohexane is subjected to free radical chlorination under UV light

Answers

Answer:

How many distinct monochlorinated products can result when methylcyclohexane is subjected to free radical chlorination under UV light.

Explanation:

Consider 1-methylcyclohexane:

Its structure is shown below:

It has primary [tex]1^o[/tex], secondary [tex]2^o[/tex]and tertiary [tex]3^o[/tex] carbons as shown in the image.

So, the following mono chlorinated product will be formed.

If a reaction occurs, what will be the products of the unbalanced reaction below?

Cu(s) + Ni(NO3)2(aq)

The Activity Series of Elements
A.
CuNi(NO3)4(s)
B.
Ni(s) + Cu(NO3)2(aq)
C.
No reaction will occur.
D.
CuNi(s) + NO2(g)

Answers

Cu(s) + Ni(NO3)2(aq) ⇒Ni(s) + Cu(NO3)2(aq)

The answer is option B.

What is electrochemical series?

Electrochemical or hobby series when the electrodes (metals and non-metals) in touch with their ions are organized on the idea of the values of their preferred discount potentials or standard oxidation potentials, the resulting series is called the electrochemical.

The electrochemical series is built up by means of arranging various redox equilibria so as of their fashionable electrode potentials (redox potentials). The maximum poor E° values are placed at the pinnacle of the electrochemical series, and the maximum wonderful at the lowest.

Learn more about chemical equation  here:-https://brainly.com/question/11231920

#SPJ2

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?

CSF + XeF6 → CsXeF7

Answers

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:

Molar mass of CsXeF₇ = 397.193 g/mol73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:

Molar mass of CsF = 151.9 g/mol0.184 mol * 151.9 g/mol = 27.9 g

During a process called photoact, ________ give up an electron as a part of the light-dependent reactions.

Answers

Answer:

Chloroplasts?

Explanation:

please let me know if this is correct?

Answers

Answer: Yes! you're all good. Alkali metals in group 1 are the most metallic :)

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