A motorboat travels 104 kilometers in 4 hours going upstream. It travels 200 kilometers going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?

Answer:

Male-19&Female-13

Step-by-step explanation:

See the image for solution

Hope it helps

Have a great day

Answer:

7yz

Step-by-step explanation:

You can take 7yz common from all the terms in the given expression

Answered by GAUTHMATH

Answer:

$54

Step-by-step explanation:

10% of $60 is $6

$60-$6=$54

Answer:

x=–2

Step-by-step explanation:

x-8=-10

x=-10-8

x=–2

Answer:

-8= -10

, = -10+8

, = -2

Answer:

The 95% confidence interval for the population mean is ($6510, $7138).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 7 - 1 = 6

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.4469.

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.4469\frac{340}{\sqrt{7}} = 314[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 6824 - 314 = $6510.

The upper end of the interval is the sample mean added to M. So it is 6824 + 314 = $7138.

The 95% confidence interval for the population mean is ($6510, $7138).

Answer:

18 divided by nine is two. so for every one table spoon of oil there's two table spoons of vinegar. Please give brainliest

Answer:

2

Step-by-step explanation:

Make a ratio:

Oil : Vinegar

9 : 18

1 : 2

For each tablespoon of oil, 2 tablespoons of vinegar is needed.

Hope this helped.

Answer: A: 22, 33, 45.5, 56, 59

Step-by-step explanation:

The minimum is the lowest number in the data, in this case, it was 22.

Q1 is the median of the lower quartile range, anything below the median of the overall data.

Median, the middle number in the overall data. You first need to put them from lowest to highest (numerical order). After that, I find it a lot easier to cross one from each side until I'm either left with one or two. If I'm left with one, then that is my median for the overall data set. If I'm left with two, then I simply need to add both the numbers together and divide it by 2. Typically if it is a whole number, and the numbers are 1 number value away from each other, it is usually just 0.5 more of the lower value of the two. (For example, the two numbers I come down to is 10 and 11. The median would be 10.5).

Q3 is the exact same principle as Q1 just on the upper quartile range. Just repeat what you did in Q1 but for the numbers above the overall median of the data set.

Maximum is the highest number in the data set, in this case, it was 69.

Hope this helps!

Answer:

i thank the ans id 450

Step-by-step explanation:

Answer:

the union of l and m is minus 1,1,2,4,5,7,8.....and the intersection of l and m is 1.......

Answer:

B 180

Step-by-step explanation:

The period is the interval it takes to repeat

The bottom of the first curve to where it repeats is 180

Answer:

?

Step-by-step explanation:

Mark as braianlist

15 multiple by 5 equal 75 -390 equal 315 -15equal 200

Answer:

Step-by-step explanation:

Let f = ln(x + √(x ² + y ²)) ln(sin(y/x)).

Then the total differential is

[tex]\mathrm df = \dfrac{\mathrm d\left(x+\sqrt{x^2+y^2}\right)}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\mathrm d\left(\sin\left(\frac yx\right)\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{\mathrm d(x^2+y^2)}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\cos\left(\frac yx\right)\,\mathrm d\left(\frac yx\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{2x\,\mathrm dx+2y\,\mathrm dy}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}}\right)\dfrac{\cos\left(\frac yx\right)\frac{x\,\mathrm dy-y\,\mathrm dx}{x^2}}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\left(2x+\sqrt{x^2+y^2}\right)\,\mathrm dx +2y\,\mathrm dy}{x\sqrt{x^2+y^2}+x^2+y^2\right)\ln\left(\sin\left(\dfrac yx\right)\right) \\\\ \indent + \dfrac1{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}}\right)(x\,\mathrm dy-y\,\mathrm dx)[/tex]

[tex]\mathrm df = \left(\left(\dfrac{2x+\sqrt{x^2+y^2}}{x\sqrt{x^2+y^2}+x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) - \dfrac y{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dx \\\\ \indent + \left(\dfrac{2y}{x\sqrt{x^2+y^2}+x^2+y^2}\ln\left(\sin\left(\dfrac yx\right)\right)+\dfrac1x\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dy[/tex]

============================================================

Explanation:

For any cyclic quadrilateral (aka inscribed quadrilateral), the opposite angles are always supplementary.

One pair of such angles is A and C

A+C = 180

x+y = 180 is one equation to form

The other pair of supplementary angles is B and D

B+D = 180

y-45+2x+15 = 180

2x+y-30 = 180

2x+y = 180+30

2x+y = 210 is the other equation to form

--------------

So the system of equations we have is

[tex]\begin{cases}x+y = 180\\2x+y = 210\end{cases}[/tex]

Both equations involve 'y', with the same coefficient, so we can subtract straight down to eliminate this variable.

We end up with -x = -30 which solves to x = 30

--------------

Once we know x, we can determine y by plugging it into any equation involving x,y and solving for y

Let's say we picked on the first equation

x+y = 180

30+y = 180

y = 180-30

y = 150

Or we could pick on the second equation

2x+y = 210

2(30) + y = 210

60+y = 210

y = 210-60

y = 150

Only one equation is needed. However, doing both like this shows that we get the same y value, and it helps confirm the answers.

Answer: 15

Step-by-step explanation:

Answer:

7/3 is the answer

Step-by-step explanation:

Answer:

3 times 10 ^ 9

Step-by-step explanation:

3 × 10 ^ 9 = 3000000000

Answer:

2 is the factor of every even number hope this help you

Answer:

290.44

Step-by-step explanation:

The whole figure area can be calculated by assuming that the whole floor is a complete square of 18.2 x 18.2 and subtracting the area of the rectangular cutout which is 10.2 x 4

Area of the the flooring=18.2 x 18.2 - (10.2*4)=290.44

1099.56m² is the surface area of a cylinder that has a radius of 7 m and a height of 18 m.

Answer:

67

Step-by-step explanation:

DM=JM-JD=84-17=67

Answer:

Step-by-step explanation:

Answer:

Hello,

in order to simplify, i have taken the inverses functions

Step-by-step explanation:

[tex]\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\[/tex]

Answer:

hello thereeeee

ans is 23.5

Step-by-step explanation:

so lets start

first of all remove decimal of divisor 1.1/25.85 multiplying by 10

11/258.5

now first multiply by 2

now we get 22 and subtract with 25 => 25-22 = 3

so left is

38

now 11*3 = 33

so now by 3

38-33= 5

bringing another 5 down

we get 55

now quotient is 23. something ( as we bought .5 down)

and now 11*5 = 55

so

23.5 is answer

Answer:

Dependent event

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Step-by-step explanation:

Given

[tex]Total = 49[/tex]

[tex]Red = 5[/tex]

Solving (a): Are the events dependent?

Yes, they are.

When the first red candy is selected and eaten, the total number of candies reduced to 48 and the number of red candies also reduced to 4.

So, the probability of selecting a 2nd candy is dependent on the first candy selected.

Solving (b): P(Red = 2)

This is calculated as:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

The first selection has the following probability:

[tex]P(Red) = \frac{Red}{Total}[/tex]

[tex]P(Red) = \frac{5}{49}[/tex]

The second selection has the following probability:

[tex]P(Red|Red) = \frac{Red - 1}{Total - 1}[/tex]

[tex]P(Red|Red) = \frac{5 - 1}{49 - 1}[/tex]

[tex]P(Red|Red) = \frac{4}{48}[/tex]

So, we have:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

[tex]P(Red = 2) = \frac{5}{49} * \frac{4}{48}[/tex]

Reduce fraction

[tex]P(Red = 2) = \frac{5}{49} * \frac{1}{12}[/tex]

Multiply

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Answer:

Individual is represented by a single point

Step-by-step explanation:

Answer:

Step-by-step explanation:

there are function that "invert" each other..

subtraction inverts addition...

3+2 = 5 ... 5-2 = 3

division inverts multiplication

5*2 = 10 ... 10/2 = 5

Using that concept, "factoring" is basically the inverse of multiplication

3x^2 + 9x can be factored to 3x(x+3)

if you multiply that out it reverts back to the original equation

so  x^2 + 5x + 6 factors to (x+3)(x+2)

if you multiply that out (foil it)

you get x^2 + 5x + 6

Answer:

y = 54/25 when x = 4.

Step-by-step explanation:

y is given by the equation:

[tex]\displaystyle y = p\times q^{x-1}[/tex]

Where p and q are numbers.

We are also given that when x = 1, y = 10 and when x = 6, y = 0.7776.

And we want to determine the value of y when x = 4.

Since y = 10 when x = 1:

[tex]\displaystyle (10) = p\times q^{(1)-1}[/tex]

Simplify:

[tex]10 = p \times q^0[/tex]

Any number (except for zero) to the zeroth power is one. Hence:

[tex]p=10[/tex]

Thus, our equation is now:

[tex]y = 10\times q^{x-1}[/tex]

When x = 6, y = 0.7776. Thus:

[tex](0.7776) = 10\times q^{(6)-1}[/tex]

Simplify and divide both sides by ten:

[tex]\displaystyle 0.07776 = q^5[/tex]

Take the fifth root of both sides:

[tex]\displaystyle q = \sqrt[5]{0.07776}[/tex]

Use a calculator. Hence:

[tex]\displaystyle q = \frac{3}{5} = 0.6[/tex]

Our completed equation is:

[tex]\displaystyle y = 10\times \left(\frac{3}{5}\right)^{x-1}[/tex]

Then when x = 4, y equals:

[tex]\displaystyle \begin{aligned} y &= 10\times \left(\frac{3}{5}\right)^{(4)-1} \\ \\ &= 10\times \left(\frac{3}{5}\right)^3 \\ \\ &= 10\times \left(\frac{27}{125}\right) \\ \\ &= \frac{54}{25}\end{aligned}[/tex]

Answer:

the answer to the question is a:-3