Yes, she will be able to retrieve the item
An echo is the repetition of sound formed due to the reflection of the sound wave.
From the question, we are given the following;
Speed of sound through water v = 530m/s
The time it takes the echo to reach the sonar detector t = 6.2s
First, we need to know how far the echo can travel using the formula;
2x = vt
x is the distance from the source of the sound to the reflector
v is the speed of sound
t is the time
Substituting the given values into the formula:
[tex]x=\frac{vt}{2}\\x=\frac{530*6.2}{2} \\x=530*3.1\\x= 1643m[/tex]
Since the research historian knows that her equipment is only good enough to recover items that are at a depth of 5 000 m or less and 1643m is less than 5000m, hence she will be able to retrieve the item.
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The research historian can retrieve the item.
Sound is a form of mechanical waves, which is a kind of waves that needs a medium to propagate itself and whose kinematic is representative of motion at constant speed. The maximum echo time ([tex]t_{e}[/tex]), in seconds, is the distance travelled by waves ([tex]s[/tex]), in meters, divided by velocity of sound through the medium ([tex]v_{s}[/tex]), in meters per second:
[tex]t_{e} = \frac{s}{v_{s}}[/tex] (1)
Please notice that distance travelled by sound is twice the depth of the sunken object.
If we know that [tex]s = 10000\,m[/tex] and [tex]v_{s} = 1530\,\frac{m}{s}[/tex], then the maximum echo time is:
[tex]t_{e} = \frac{10000\,m}{1530\,\frac{m}{s} }[/tex]
[tex]t_{e} = 6.535\,s[/tex]
Any sunken object whose echo time is less than 6.535 seconds can be retrieved. As the echo time related to the item was 6.2 seconds, the research historian can be able to retrieve the object.
A water heater marked 4 kW takes 4 minutes to heat 1 kg of water from 20 °C to 50 °C. The cost of electrical energy per kWh
is $0.120. What will be the total cost of energy consumption?
The total cost of the energy consumption for the given time period is $0.0364
The given parameters include;
power rating of the heater, P = 4 kW = 4000 Wtime taken to completely boil the water,[tex]t = 4 \min = 4 \min \times \frac{1 \ h}{60 \ \min} = 0.067 \ h[/tex]mass of the water, m = 1 kginitial temperature of the water, t₁ = 20 ⁰Cfinal temperature of the water, t₂ = 50 ⁰Cspecific heat capacity of water, c = 4200 J/kg⁰Ccost of electrical energy = $0.12The total energy consumed in the process of heating the water;
Total electrical Energy = Energy of the heater (kWh) + Energy of the heated water (kWh)
Energy of the heater (kWh) = power x time
= 4 kW x 0.067 h
= 0.268 kWh
Energy of the heated water (J) = mcΔt
where;
Δt is the change in temperature = t₂ - t₁
= 50 ⁰C - 20 ⁰C = 30⁰C
Energy of the heated water (J) = 1 x 4200 x 30
= 126,000 J
Electrical power of the heated water (Watts) = [tex]\frac{126,000 \ J}{4 \ \min} \times \frac{1 \min}{60 \ s} = 525 \ W[/tex]
Energy of the heated water (kWh) = [tex]\frac{525}{1000} \times 4\min\times \frac{1 \ hr}{60 \min} = 0.035 \ kWh[/tex]
Total electrical Energy = 0.268 kWh + 0.035 kWh
= 0.303 kWh
The total cost of the energy consumed is calculated as;
[tex]Total \ cost = \frac{\$ \ 0.12}{kWh} \times 0.303 \ kWh = \$ \ 0.0364[/tex]
Therefore, the total cost of the energy consumption is $0.0364
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How is the potential difference same in capacitors arranged in parallel combination?
Answer:
Potential difference across capacitors in parallelTwo or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.
calculate the potential energy stored in a meta ball of mass of 80 kg kept at a height of 15m from the earth surface . What will be the potential energy when the metal ball is kept on the earth surface Take (g- 9.8 m/s]
Answer:
11760 J
Explanation:
cuz potential engery is PE = MHG
SO 80×15×9.8= 11760 J
Answer:
11769j
Explanation:
here,
mass(m)=80 kg
height(h)=15m
acceleration due to gravity(g)=9.8m/s^2
now,
potential energy = m×g×h
= 80×9.8×15
= 11760j
A variable is a letter that stands in for a number and unit... True or False?
The sky is blue because: Select one: a. the index of refraction for air is slightly larger for blue than for red b. atomic hydrogen is blue c. air molecules tend to polarize light along a horizontal axis d. oxygen and nitrogen molecules are small compared to the wavelengths of visible light e. oxygen molecules have a lower energy ground state than nitrogen molecules
Answer:
a. the index of refraction for air is slightly larger for blue than for red
6.
For a given prism the angle of incidence is changed from 0° and 90', the angle of deviation [ ]
b) decreases
c) first decreases and then increases
d) first increases and then decreases
a) increases
Answer:
increase
Explanation:
please mark as brainlyest
Answer
A.Increses
Explanation:
A car has a mass of 2000 kg. While it is traveling along a perfectly flat road, it goes around an unbanked turn that has a radius of 40.0 m. The coefficient of static friction between the car tires and the road is 0.500. The car travels successfully around the turn at a constant speed of 10.0 m/s. Calculate the magnitude of the car's acceleration as it goes around the turn. _______ m/s^2
Answer:
2.5 m/s²
Explanation:
The given parameters are;
The mass of the car, m = 2,000 kg
The radius of the car, r = 40.0 m
The coefficient of friction between the car tires and the road, μ = 0.500
The constant speed with which the car moves, v = 10.0 m/s
The normal reaction of the road on the car, N = The weight of the car;
∴ N = m × g
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
N ≈ 2,000 kg × 9.81 m/s² = 19,620 N
The frictional force, [tex]F_f[/tex] = μ × N
The centripetal force, [tex]F_c[/tex] = m·v²/r
The car moves without slipping when [tex]F_f[/tex] = [tex]F_c[/tex]
Therefore, [tex]F_f[/tex] = 0.500 × 19,620 N = 2,000 kg × [tex]v_{max}[/tex]²/40.0 m
∴ [tex]v_{max}[/tex] = √(0.500 × 19,620 N × 40.0 m/2,000 kg) ≈ 14.007 m/s
Therefore, the velocity with which the car moves, v < [tex]v_{max}[/tex]
The cars centripetal acceleration, [tex]a_c[/tex] = v²/r
∴ [tex]a_c[/tex] = (10.0 m/s)²/40.0 m = 2.5 m/s²
The cars centripetal acceleration as it goes round the turn, [tex]a_c[/tex] = 2.5 m/s².
Trong thí nghiệm về sự khúc xạ ánh sáng, một học sinh ghi lại trên tấm bìa ba đường truyền của ánh sáng như hình bên nhưng quên không ghi chiều truyền.
Tia khúc xạ là
Answer:
I R 2
Explanat
give one example where friction is a hindrance.
Answer:
an example of when friction is a hindrance, is if someone with shorts is sliding down a slide. their skin rubbing on the slide will cause friction and will slow them down. another example is if you're dragging a large wooden box across the floor. the wood and the floor interacting cause friction and will make it more difficult to push the box.
Explanation:
hope this helps :D
Hideki had normal vision for most of his life, but now that he is in his 60s, he has started to have difficulty focusing on near objects. He went to an optometrist, who explained that his vision problem was the result of the lenses in his eyes losing elasticity due to aging. Which condition does Hideki have
Answer:
He is suffering from hypermetropia.
Explanation:
There are some defects of vision.
Longsightedness of hypermetropia : It is the defect of vision in which the person is not able to see the nearby objects clearly but can see the far off objects clearly. This is due to the elongation of size of eye ball. It is cured by using convex lens of suitable focal length.
Nearsightedness or Myopia : It is the defect of vision in which a person is not able to see the far off objects clearly but can see the nearby objects clearly. It is due to the contraction in the size of eye ball. It is cured by using concave lens of suitable focal length.
So, Hideki is suffering from hypermetropia. So, he should use the convex lens of suitable focal length.
Invisible damage to the body resulting from repeating a movement often is a
show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
Calculate the upthrust on a object immersed in water if the object displace water of mass 2 kg.(g=9.8m/s²)
Thrust is force
Mass=2kgAcceleration due to gravity=g=9.8m/s^2Using Newtons Second law
[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow Thrust=2(9.8)[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow Thrust=19.6N[/tex]
We have that the the upthrust on a object immersed in water is
[tex]U=19.6N[/tex]
From the Question we are told that
mass= 2kg
Gravity g=9.8m/s^2
Generally the equation for the upthrust is mathematically given as
[tex]U=mg[/tex]
Therefore
[tex]U=2*9.8[/tex]
[tex]U=19.6N[/tex]
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The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4Pa.
While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?
Answer:
0 deg C = 4.81E4 pressure at 0 deg
100 deg C = 6.48E4 pressure at steam point
100 deg C - 50 deg C = (6.48 - 4.81) * 10^4 = 1.67E4 Pa
50 deg C = 50 / 100 * 1.67E4 + 4.81E4 = 5.65E4 Pa Just the halfway point between the two given pressures
A ball of mass 1.0 kg is rolling due west at 30 m/s. A second ball of mass 2.0 kg moving due north at 6.0 m/s collides with the first ball and they stick together. What is the magnitude of the momentum of the two-ball system immediately after collision
Answer:
the magnitude of the momentum of the two-ball system immediately after collision is 32.31 kg.m/s
Explanation:
Given;
mass of the first ball, m₁ = 1.0 kg
mass of the second ball, m₂ = 2.0 kg
initial velocity of the first ball, v₁ = 30 m/s due west
initial velocity of the second ball, v₂ = 6 m/s due north
From the principle of conservation of linear momentum;
the total momentum before collision = total momentum after collision
The westward momentum of the first ball, = m₁v₁ = 1 x 30 = 30 kg.m/s
The northward momentum of the second ball = m₂v₂ = 2 x 6 = 12 kg.m/s
The resultant momentum of the two balls;
R² = 30² + 12²
R² = 1044
R = √1044
R = 32.31 kg.m/s
Therefore, the magnitude of the momentum of the two-ball system immediately after collision is 32.31 kg.m/s
Resistivity of metallic wire
depends on *
It's length
It's shape
It's thickness
Nature of material
Answer:
nature of the material
hope this help you
pls,help ASAP .the question is in attachment
Answer:c
Explanation:
importance of estimation in our lives
solve two questions under inclined plane using Newton 2nd law
Explanation:
If the mass of the inclined plane is large enough, could N ever be equal to mgcosθ. Reasons?
So far I've come up with: mgcosθ−N=ma meaning if N were to equal mgcosθ, ma=0. Since the surfaces are frictionless and since N is acting on the inclined plane too(it'll have a horizontal component), this isn't possible. Am I right? Where am I going wrong?
resistances is inversely proprtional to___of the conductor
Answer:
resistances is inversely proportional to the area of cross section of the conductor
Explanation:
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area.
hope this helps you
have a nice day:)
mot o to ro ben luc 6h voi van toc toc 40 km/h
Answer:
? có thể cụ thể hơn ko
Explanation:
In----- theory, the actual wishes that are threatening to the dreamers conscious awareness are disguised
Answer:
Unconscious wish fulfillment
Explanation:
Unconscious wish fulfillment
(In the unconscious wish fulfillment theory, the actual wishes of the dreamer that are threatening to the dreamer's conscious awareness are disguised.)
help me please i will mark as brainliest
Answer:
you would be paying $1845.26
what is the definition of unit?definition of unit?
Answer:
The Reference standard with which we carry out the measurement of any physical quantity of the same kind is know as unit .
I HOPE I HELP YOU.
Answer:
The standard quantity which is used for the comparison with an unknown quantity is called unit.
Unit is a known or standard quantity in terms of which other physical quantities are measured.
for examples;kilogram,metre,second,etc.
Explanation:
hope it helps you
can someone please help me with a and b? what do they mean by amplitude?
Explanation:
first answer is that the to and fro movement of a pendulum is known as amplitude
Which of the following best describes reverberation?
A.The wave fronts become mixed and broken up due to contact with a rough or
irregular surface.
B. A change in the sound wave velocity causes the wave to bend in a different
direction.
C. A fraction of the sound waves are absorbed by an object and converted to heat
energy.
D. A single sound undergoes several reflections due to multiple reflecting surfaces.
Reverberation, in psychoacoustics and acoustics, is a persistence of sound after the sound is produced
Explanation:
I think it is right hope its helps
Answer:
D. A single sound undergoes several reflections due to multiple reflecting surfaces.
Explanation:
Sometimes, the source of a sound is surrounded by multiple reflecting surfaces. The waves traveling from the source strike these different surfaces, causing multiple reflections. For example, a single clap of thunder reflects on several clouds and the earth's surface, causing you to hear a rolling rumble instead of a single sound.
how do u calculate the kinetic energy of a ball of mass 0.25kg being kicked vertically upwards with a speed of 5m/s
Answer:
3.125J
Explanation:
K.E.= 1/2(mass)(velocity)^2
K.E.=1/2(0.25)(5)^2=3.125
is noise energy a kind of energy or not
........................
Answer:
14°F = 263.15 K
31°F = 272.594 K
71°F = 294.817 K
35°F = 274.817 K
Explanation:
Use the formula 273.15 + ((°F–32)•5)/9
One possible unit of speed is
Answer:
option d
Explanation:
Meter per second