Answer:
625/100,000,000 or 6.25 out of one million
Step-by-step explanation:
(0.005)^4 = .000000000625 = 625/100,000,000
The probability that all four computers fail on one day is =6.3*[tex]10^{-10}[/tex].
What is probability?It is a branch of mathematics that deals with the occurrence of a random event.
The probability that a computer fails on any single day is 0.005.
Let X denotes no. of computers fail on day
So, n = 4 , p = 0.05, q= 1-0.05=0.995
P (X = x) = [tex]^{n} C_x \;p^{x} \;q^{n-x}[/tex]
P (X = 4)
= [tex]^{4} C_4 \;(0.005)^{4} \;(0.995)^{4-4}[/tex]
=1* 0.00000000063*1
=0.00000000063
=6.3*[tex]10^{-10}[/tex]
Hence, the probability that all four computers fail on one day is
=6.3*[tex]10^{-10}[/tex].
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Grandma baked 96 cookies and gave them to her grandchildren. One of the grandchildren, Cindy, received
c fewer cookies than she would have received had all of the cookies been evenly divided among the 8
grandchildren.
ining
How many cookies did Cindy receive?
Write your answer as an expression.
Answer:
12-c
Step-by-step explanation:
This is quite simple
We know grandma has made 96 cookies and IF all children 8 receive equal cookies
They would have 12 cookies each
Cindy got c less cookies
so we can say
12-c is what Cindy got
I guess grandma got hungry
Answer:
Step-by-step explanation:
98 = 8 = 12
cindy cookies = 12-c
PLEASE WILL NAME BRAINLIST
The table shows the length y (in inches) of a person’s hair after x months.
months x: 0 3 6
hair Length y:11.0 12.5 14.0
a. Write and graph a linear function that relates y to x .
y=
b. Interpret the slope and the y-intercept
The slope indicates that the hair length increases by what
inch per month. The y-intercept indicates that the initial hair length is what
inches.
betty closes the nozzle and fills it completely with a liquid. She then opens the nozzle. If the liquid drips at the rate of 14 cubic inches per minute, how long will it take for all the liquid in the nozzle to pass through(Use Pi = 3.14
Answer:
4.71 minutes
Step-by-step explanation:
Incomplete question [See comment for complete question]
Given
Shape: Cone
[tex]r = 3[/tex] -- radius
[tex]h = 7[/tex] --- height
[tex]Rate = 14in^3/min[/tex]
Required
Time to pass out all liquid
First, calculate the volume of the cone.
This is calculated as:
[tex]V = \frac{1}{3} \pi r^2h[/tex]
This gives:
[tex]V = \frac{1}{3} * 3.14 * 3^2 * 7[/tex]
[tex]V = \frac{1}{3} * 197.82[/tex]
[tex]V = 65.94in^3[/tex]
To calculate the time, we make use of the following rate formula.
[tex]Rate = \frac{Volume}{Time}[/tex]
Make Time the subject
[tex]Time= \frac{Volume}{Rate }[/tex]
This gives:
[tex]Time= \frac{65.94in^3}{14in^3/min}[/tex]
[tex]Time= \frac{65.94in^3}{14in^3}min[/tex]
Cancel out the units
[tex]Time= \frac{65.94}{14} min[/tex]
[tex]Time= 4.71 min\\[/tex]
Answer:
The time it will take for all the liquid to pass through is 4.71 minutes.
-Don't worry it's been already verified by myself .
The Spanish club wants to raise $325.00 to attend a special program at
the Museum. The club decides to sell tacos at basketball games. The
tacos will sell for $1.50 for a small and $2.50 for a large. Write an
equation to relate the number of small and large tacos you must sell
to raise $325.00.
In a display at a museum, two planets have volumes of 8 cubic inches and 27 cubic
inches. What is the ratio of their diameters?
2:3
413.5
2:9
4:13.5
Answer:
2:3
Step-by-step explanation:
V = 4/3*pi*r^3
Diameter = 2r
The ratio of diameters of the two planets has volumes of 8 cubic inches and 27 cubic will be 2/3.
What is Ratio?A ratio is defined as a relationship between two quantities, it is expressed as one divided by the other such that they should not be divisible.
The upper number is called as the numerator and the lower is called the denominator.
For example, 3/4 where 3 will be numerator and 4 will be denominator.
Given that the In a display at a museum, two planets have volumes of 8 cubic inches and 27 cubic.
Now volume of planets(sphere) = πD³/6 where D is diameter of sphere
So volume of first planet / volume of second planet ∝ (dia or first)³/(dia of second)³
⇒ V₁/V₂ ∝ (D₁/D₂)³
Given that V₁/V₂ = 8/27
So 8/27 = (D₁/D₂)³
D₁/D₂ = 2/3
Hence, the ratio of diameters of two planets will be 2/3.
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Find the 5th term of the arithmetic sequence -5x – 5, -12x – 8,
- 19x – 11, ...
Answer:
5th term of AP = -33x - 17
Step-by-step explanation:
Given:
Arithmetic sequences;
[-5x - 5], [-12x - 8], [ - 19x - 11] , ...
Find:
5th term of AP
Computation:
First term a = [-5x - 5]
Common difference d = a2 - a1
Common difference d = [-12x - 8] - [-5x - 5]
Common difference d = -12x - 8 + 5x + 5
Common difference d = -7x -3
5th term of AP = a + [n-1]d
5th term of AP = [-5x - 5] + [5-1][-7x -3]
5th term of AP = [-5x - 5] + [4][-7x -3]
5th term of AP = [-5x - 5] -28x -12
5th term of AP = -5x - 5 -28x -12
5th term of AP = -33x - 17
Find (g times f) (3)
f(x)=3x-2
g(x)=x^2
Check the pic
please explain
Answer:
Option C
Step-by-step explanation:
From the picture attached,
In ΔABC,
m∠BAC + y° = 180° [Linear pair of angles are supplementary]
m∠BAC = 180° - y°
m∠ABC = x° [Vertically opposite angles]
m∠ACB = z° [Vertically opposite angles]
By triangle sum theorem,
m∠BAC + m∠ABC + m∠ACB = 180°
(180 - y)° + x° + z° = 180°
x - y + z = 180 - 180
x - y + z = 0
Option C will be the answer.
Will give brainliest
Answer: Because the question uses the word “distinct” meaning obvious, and clear, I would select AB, AC, CB. (If it’s asking for all the possible line segments, I would select AB, AC, CB, BA, CA, BC).
Help me please!
Consider the function f(x) = V2x – 4. Iff-'(x) is the inverse function of f(x), find
f-16)
Answer:
[tex]f^{-1}(6) = 50[/tex]
Step-by-step explanation:
Given
[tex]f(x) = \sqrt{2x} - 4[/tex]
Required
Find [tex]f^{-1}(6)[/tex]
First, we calculate the inverse function
[tex]f(x) = \sqrt{2x} - 4[/tex]
Express f(x) as y
[tex]y = \sqrt{2x} - 4[/tex]
Swap the positions of x and y
[tex]x = \sqrt{2y} - 4[/tex]
Solve for y: Add 4 to both sides
[tex]4 + x = \sqrt{2y} - 4+4[/tex]
[tex]4 + x = \sqrt{2y}[/tex]
Square both sides
[tex](4 + x)^2 = 2y[/tex]
Divide both sides by 2
[tex]y = \frac{(4 + x)^2}{2}[/tex]
Express y as an inverse function
[tex]f^{-1}(x) = \frac{(4 + x)^2}{2}[/tex]
Next, solve for: [tex]f^{-1}(6)[/tex]
Substitute 6 for x
[tex]f^{-1}(6) = \frac{(4 + 6)^2}{2}[/tex]
[tex]f^{-1}(6) = \frac{(10)^2}{2}[/tex]
[tex]f^{-1}(6) = \frac{100}{2}[/tex]
[tex]f^{-1}(6) = 50[/tex]
Need help on this subject ????
9514 1404 393
Answer:
(c) 2
Step-by-step explanation:
The product of the lengths to the near and far circle intercepts is the same for both secants.
3×(3+5) = 4×(4+x)
24 = 16 +4x . . . simplify
6 = 4 +x . . . . . . divide by 4
2 = x . . . . . . . . .subtract 4
Dan bought 20 bunches of seedless green grapes for $48. How many bunches can Kali buy if she has $12?
5
29
4
6
Answer:
48/20=2.4
12/2.4=5
Step-by-step explanation:
Kai can buy 5 bunches of grapes if she has $12.
Answer:
It's 29.
Step-by-step explanation:
48/20=2.4
12x2.4=28.8
Round up to 29.
Choose the equation where b=6 is a solution. 11- b = 6 b + 4 = 9 8b = 48 63 b = 9
Answer:
8b = 48
Step-by-step explanation:
this is because you would substitute the b for the 6 and then multiply straight across giving you a total of 48.
Answer:
8b = 48
Step-by-step explanation:
8 x 6 = 48
Sade used the two blocks pictured to build a tower. What is the TOTAL VOLUME of the two blocks for this entire tower? *
Answer: V=120
have an amazing day <3
Answer:what is the answer i dont understand
plz help
Fiona has $998 in her savings account. If the bank pays 2.5% simple interest on savings, how much does she earn in one year?
A.
$24.95
B.
$399.20
C.
$2,495
D.
$294.86
The traffic flow rate (cars per hour) across an intersection is
r
(
t
)
=
300
+
600
t
−
90
t
2
, where
t
is in hours, and
t
=0 is 6am. How many cars pass through the intersection between 6 am and 9 am?
Answer:
990 cars
Step-by-step explanation:
Find how many cars pass through at 6am, t=0:
r(0)= 300+600(0)-90(0²) = 300
Find how many cars pass through at 9am, t=3:
r(3)= 300+600(3)-900(3²)=300+1800-810=1290
Find the difference (how many cars pass between 6am and 9am): 1290-300=990
Perform the indicated operations and reduce to lowest terms. Assume that no denominator has a value of zero.
Answer:
[tex]\frac{x}{9}[/tex]
Step-by-step explanation:
Given
[tex]\frac{x^2 - 9}{9x + 27} \div \frac{x - 3}{x}[/tex]
Required
Solve
[tex]\frac{x^2 - 9}{9x + 27} \div \frac{x - 3}{x}[/tex]
Change the division to multiplication
[tex]\frac{x^2 - 9}{9x + 27} * \frac{x}{x - 3}[/tex]
Apply difference of 2 squares
[tex]\frac{(x - 3)(x+3)}{9x + 27} * \frac{x}{x - 3}[/tex]
Cancel out x - 3
[tex]\frac{x+3}{9x + 27} * \frac{x}{1}[/tex]
Factorize 9x + 27
[tex]\frac{x+3}{9(x + 3)} * \frac{x}{1}[/tex]
Cancel out x + 3
[tex]\frac{1}{9} * \frac{x}{1}[/tex]
Finally, this gives:
[tex]\frac{x}{9}[/tex]
Please answer this and I will give brainliest
Answer:
D is the right answer [(2f+2) / 2(s^3) ]
Find the third side in simplest radical form:
28
45
Answer:
20:23?
Step-by-step explanation:
A rectangular swimming pool is 15 meters long, 11- meters wide, and 4-meters deep. What is its 2 2. volume? The volume is cubic meters.
Answer:
the volume of the rectangular swimming pool is 660 meters cubic
Step-by-step explanation:
you multiply 15x11x4
Tinisha is planning a birthday party. She can buy:
10 balloons, 8 cupcakes, and 8 hats for $50
5 balloons, 9 cupcakes, and 7 hats for $46, or
12 balloons, 7 cupcakes, and 9 hats for $51
Using b for the number of balloons, c for the number of cupcakes, and h for
the number of hats, write a system of equations to represent this situation.
Answer:
b+c+h=50
Step-by-step explanation:
Its the first one because you need to have the same amount of hats as cupcakes cause the hat really stands for people.
Question 8
Which property justifies the fact that 5(x - 2) is equivalent to 5x - 10?
commutative
associative
O distributive
A number cube has faces 1 through 6. How many of the number on the cube are composite?
A. 1
B. 2
C. 3
D. 4
Answer:
B) 2 numbers
Step-by-step explanation:
composite #'s: 4, 6
prime #'s: 2, 3, 5
neither composite nor prime: 1
2 x - 3 / 5 = - 1 / 10
Answer:
1/4
Step-by-step explanation:
2x=-1/10 + 3/5
2x=1/2
x=1/4
Estimate 719 – 274. Round each number first.
20 POINTS!!!!!!!The monthly salary of an employee with 33 hours of training can be written as
D-Salary(33) or S(33)
D is correct hope this helps
saniyah collected a total of 9 seashells she gave 1/3 to her sis how many seashells did Saniyah have left?
Answer: The answer is 3.
Step-by-step explanation: You would multiply 9x1/3 which would give you 3. If you want to understand even better here's how to do so: Put 3(the answer that you got from multiplying 9x1/3) into the fraction 1/3 as 1. In other words, it would look something like this 3/3. Then, just multiply the two numbers 3x3 and that equals 9, the number you started with.
Hope that this helped!!:)
Considering the provided information in the given question, we have :
Total seashells Saniyah have = 9Number of seashells Saniyah gave to her sister = [tex]\sf \dfrac{1}{3} [/tex] of total.We need to find how many seashells did Saniyah have left.
⇒ Number of seashells Saniyah have left = Total seashells – Number of seashells she gave to her sister
⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup \dfrac{1}{3} \times 9 \Bigg \rgroup } [/tex]
⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup 1 \times 3 \Bigg \rgroup } [/tex]
⇒ Left seashells = 9 – 3
⇒ Left seashells = 6
Therefore, Saniyah have left [tex] \bf {6 \: seashells } [/tex].
Please assist me with this two column proof. Part 1A
Answer:
Answer is in the step by step explanation
Step-by-step explanation:
Since we are given parallel lines, we know <BCA is congruent to <DAC because of alternate interior angles
Then AC is congruent to AC, that's reflexive prop
Now we have SAS, so Tri. ABC cong to tri. CDA,
Then you're done
Answer:
Step-by-step explanation:
BC = AD Given
<BCA = <CAD Alternate interior angles of parallel lines cut by a transversal.
AC = AC That's the reflexive property. A line is equal to itself
Triangle BCA = Triangle CAD SAS
Notice that the angle is included inside the two lines that define it (the angle). That's a very important consideration when using SAS. SAA doesn't always work. You can draw exceptions. SAS has no exceptions. It always works.
A recent survey reported that small businesses spend 24 hours a week marketing their business. A local chamber of commerce claims that small businesses in their area are not growing because these businesses are spending less than 24 hours a week on marketing. The chamber conducts a survey of 93 small businesses within their state and finds that the average amount of time spent on marketing is 23.0 hours a week. Assuming that the population standard deviation is 5.5 hours, is there sufficient evidence to support the chamber of commerce’s claim at the 0.02 level of significance?
Step 1 of 3 :
State the null and alternative hypotheses for the test. Fill in the blank below.
H0: μ=24
Ha: μ ____ 24
Step 2 of 3:
What is the test statistic?
Step 3 of 3:
Do we reject the null hypothesis? Is there sufficient or insufficient evidence?
Answer:
Ha: μ < 24
The test statistic is z = -1.75.
The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.
Step-by-step explanation:
A recent survey reported that small businesses spend 24 hours a week marketing their business.
This means that the null hypothesis is:
[tex]H_0: \mu = 24[/tex]
A local chamber of commerce claims that small businesses in their area are not growing because these businesses are spending less than 24 hours a week on marketing.
This means that the alternate hypothesis is:
[tex]H_a: \mu < 24[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
24 is tested at the null hypothesis:
This means that [tex]\mu = 24[/tex]
The chamber conducts a survey of 93 small businesses within their state and finds that the average amount of time spent on marketing is 23.0 hours a week.
This means that [tex]n = 93, X = 23[/tex]
The population standard deviation is 5.5 hours
This means that [tex]\sigma = 5.5[/tex]
Value of the test-statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{23 - 24}{\frac{5.5}{\sqrt{93}}}[/tex]
[tex]z = -1.75[/tex]
The test statistic is z = -1.75.
Do we reject the null hypothesis? Is there sufficient or insufficient evidence?
The pvalue of the test is the probability of finding a sample mean below 23, which is the pvalue of z = -1.75.
Looking at the z table, z = -1.75 has a pvalue of 0.0401
The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.
he first date went well. You are still dating the same person and still looking for a great person to spend your life with. You are cautiously moving forward with the relationship and know that if they are a great match, their likelihood of being kind to animals is 0.9 whereas their likelihood of being kind to animals if they are not a great match is 0.7. You see that your prospective spouse is kind to animals. What is the probability that they are a great match now?
Answer:
0.125 = 12.5% probability that they are a great match now.
Step-by-step explanation:
To solve this question, we need the probability of a person being a great match, which i will use 0.1.
This question is solved using conditional probability.
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Is kind to animals.
Event B: Is a great match.
Probability of being kind to animals:
0.9 of 0.1(Is a great match).
0.7 of 1 - 0.1 = 0.9(is not a great match). So
[tex]P(A) = 0.9*0.1 + 0.7*0.9 = 0.72[/tex]
Probability of being kind to animals and a great match:
0.9 of 0.1. So
[tex]P(A \cap B) = 0.9*0.1 = 0.09[/tex]
What is the probability that they are a great match now?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09}{0.72} = 0.125[/tex]
0.125 = 12.5% probability that they are a great match now.