A student drops their notes and their papers scatter. The fact that the papers scatter and do not remain neatly stacked is an illustration of :

Answers

Answer 1

Answer:

-- increase in entropy

-- second law of thermodynamics

Step-by-step explanation:

The 1st law of thermodynamic states that there is conservation of energy, i.e. we cannot create energy and we cannot destroy energy also in an isolated system.

The given example is not a representative of the 1st law.

The [tex]\text{2nd law of thermodynamics}[/tex] states that there is a natural tendency of an isolated system to [tex]\text{degenerate}[/tex] into a more [tex]\text{disordered state.}[/tex] Before dropping the notes and papers were in an isolated ordered system.

After dropping the papers scattered and did not remain in a stack position. It moves into a more disordered state.

Begore dropping down the notes and papers, they were in a stable position, i.e. no kinetic energy is there. No randomness when the notes and the papers were dropped. There is an increase in kinetic energy. There is randomness among the molecules by bombardment. So there is an increase in entropy.

Thus, above illustrations represents :

an increase in entropythe second law of thermodynamics

Related Questions

A 90 % confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a random survey of 45 CEOs. the interval was ($133, 306, $150, 733). To make useful inferences from the data, it is desired to reduce the width of the confidence interval. Which of the following will result in a reduced interval width?
A) Increase the sample size and increase the confidence level.
B) Decrease the sample size and increase the confidence level.
C) Decrease the sample size and decrease the confidence level.
D) Increase the sample size and decrease the confidence level.

Answers

Answer: D) Increase the sample size and decrease the confidence level.

Step-by-step explanation:

A reduced interval width means that the data is more accurate. This can only be achieved if the sample size is increased because a larger sample size is able to capture more of the characteristics of the variables being tested.

A smaller confidence interval will also lead to a reduced interval width because it means that the chances of the prediction being correct have increased.

Last year there were 221 students and 12 teachers at Hilliard School. This year there are 272 students. The principal wants to keep the same student to teacher ratio as last year. Which proportion can the principal use to find x, the number of teacher needed this year?

Answers

Answer:

3264:221

Step-by-step explanation:

If by last year there were 221 students and 12 teachers at Hilliard School, then;

221students = 12teachers

To find the equivalent ratio for 272students, we can say;

272students = x teachers

Divide both expressions

221/272 = 12/x

Cross multiply

221 * x = 272 * 12

221x = 3264

x = 3264/221

x = 3264:221

This gives the required proportion

The vertices of a triangle are P(-6,1), Q(-2,-5) and R(8,1).

Find the equation of the perpendicular bisector of the side QR

Answers

Answer:

Step-by-step explanation:

Find the slope of QR. From that we can find the the slope of the line perpendicular to QR.

Q(-2, -5)   & R(8,1)

[tex]Slope \ = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{1-[-5]}{8-[-2]}\\\\=\frac{1+5}{8+2}\\\\=\frac{6}{10}\\\\=\frac{-3}{5}[/tex]

So, the slope of the line perpendicular to QR =  -1/m - 1÷ [tex]\frac{-5}{3} = -1*\frac{-3}{5}=\frac{3}{5}[/tex]

Bisector of QR divides the line QR to two half. We have find the midpoint of QR.

Midpoint = [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]

               [tex]=(\frac{-2+8}{2},\frac{-5+1}{2})\\\\=(\frac{6}{2},\frac{-4}{2})\\\\=(3,-2)[/tex]

slope = 3/5  and the required line passes through (3 , -2)

y - y1 = m(x-x1)

[tex]y - [-2] = \frac{3}{5}(x - 3)\\\\y + 2 = \frac{3}{5}x-\frac{3}{5}*3\\\\y=\frac{3}{5}x-\frac{9}{5}-2\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{2*5}{1*5}\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{10}{5}\\\\y=\frac{3}{5}x-\frac{19}{5}[/tex]

pls help me i’m so stuck

Answers

Answer:

Step-by-step explanation:

If a point (x, y) is reflected across y = -x, coordinates of the image point will be,

(x, y)→ (-y, -x)

Following this rule,

Vertices of the triangle will be,

(3, 1) → (-1, -3)

(3, -2) → (2, -3)

(6, -3) → (3, -6)

Therefore, image of the given triangle A will be,

(-1, -3), (2, -3) and (3, -6)

Let ℤ be the set of all integers and let, (20) 0 = { ∈ ℤ| = 4, for some integer }, 1 = { ∈ ℤ| = 4 + 1, for some integer }, 2 = { ∈ ℤ| = 4 + 2, for some integer }, 3 = { ∈ ℤ| = 4 + 3, for some integer }. Is {0, 1, 2, 3 } a partition of ℤ? Explain your answer.

Answers

Answer:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z

Step-by-step explanation:

Given

[tex]$$A _ { 0 } = \{n \in \mathbf { Z } | n = 4 k$$,[/tex] for some integer k[tex]\}[/tex]

[tex]$$A _ { 1 } = \{ n \in \mathbf { Z } | n = 4 k + 1$$,[/tex] for some integer k},

[tex]$$A _ { 2 } = { n \in \mathbf { Z } | n = 4 k + 2$$,[/tex] for some integer k},

and

[tex]$$A _ { 3 } = { n \in \mathbf { Z } | n = 4 k + 3$$,[/tex]for some integer k}.

Required

Is [tex]\{0, 1, 2, 3\}[/tex] a partition of Z

Let

[tex]k = 0[/tex]

So:

[tex]$$A _ { 0 } = 4 k[/tex]

[tex]$$A _ { 0 } = 4 k \to $$A _ { 0 } = 4 * 0 = 0[/tex]

[tex]$$A _ { 1 } = 4 k + 1$$,[/tex]

[tex]A _ { 1 } = 4 *0 + 1$$ \to A_1 = 1[/tex]

[tex]A _ { 2 } = 4 k + 2[/tex]

[tex]A _ { 2} = 4 *0 + 2$$ \to A_2 = 2[/tex]

[tex]A _ { 3 } = 4 k + 3[/tex]

[tex]A _ { 3 } = 4 *0 + 3$$ \to A_3 = 3[/tex]

So, we have:

[tex]\{A_0,A_1,A_2,A_3\} = \{0,1,2,3\}[/tex]

Hence:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z

What function is graphed below?

Answers

Answer:

[tex]y\ =\ \ \tan\theta\ +2[/tex]

Step-by-step explanation:

The length of a rectangle is twice its width the perimiter is 60 ft find its area

Answers

Hello,

let's assume a=the length and b the width.

[tex]\left\{\begin{array}{ccc}a&=&2*b\\2(a+b)&=&60\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\a+b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\3b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b&=&10\\a&=&20\\\end{array}\right.\\\\\\Area=10*20=200\ (ft^2)\\[/tex]

what percent of 98 million is 7740

Answers

Answer:

Step-by-step explanation:

x : 100 = 7740 : 98 000 000

x = (7740 * 100)/98 000 000

x = 0.007898 %

A percentage is a hundredth of a number      Then                                                    [tex]\displaystyle\bf \frac{7740}{98\cdot10^6} \cdot100=\frac{387}{49000} \approx 0,00789\%[/tex]                                                      

People at the state fair were surveyed about which type of lemonade they preferred. The results are shown below. Pink lemonade: 156 males, 72 females Yellow lemonade: 104 males, 48 females The events "prefers pink lemonade" and "female" are independent because P(pink lemonade | female) = P(pink lemonade) = 0.6. P(female | pink lemonade ) = P(pink lemonade) = 0.3. P(pink lemonade | female) = 0.3 and P(pink lemonade) = 0.6. P(female | pink lemonade ) = 0.3 and P(pink lemonade) = 0.6.

Answers

Answer:

[tex]P(pink) = P(pink |\ female) = 0.6[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {Male} & {Female} & {Pink} & {156} & {72} \ \\ {Yellow} & {104} & {48} \ \end{array}[/tex]

Required

Why [tex]prefers\ pink\ lemonade[/tex] and [tex]female[/tex] are independent

First, calculate [tex]P(pink |\ female)[/tex]

This is calculated as:

[tex]P(pink |\ female) = \frac{n(pink\ \&\ female)}{n(female)}[/tex]

[tex]P(pink |\ female) = \frac{72}{48+72}[/tex]

[tex]P(pink |\ female) = \frac{72}{120}[/tex]

[tex]P(pink |\ female) = 0.6[/tex]

Next, calculate [tex]P(pink)[/tex]

[tex]P(pink) = \frac{n(pink)}{n(Total)}[/tex]

[tex]P(pink) = \frac{156 + 72}{156 + 72 + 104 + 48}[/tex]

[tex]P(pink) = \frac{228}{380}[/tex]

[tex]P(pink) = 0.6[/tex]

So, we have:

[tex]P(pink) = P(pink |\ female) = 0.6[/tex]

Hence, they are independent

Answer:

P(pink lemonade | female) = P(pink lemonade) = 0.6.

Step-by-step explanation:

A

1/5 + 3/4 + 1/2
please helpppo asap

Answers

Answer:

29/20 or 1 9/20 or 1.45

Answer:

[tex]\frac{1}{5}+\frac{3}{4}+\frac{1}{2}[/tex]

lease common multiplier of 5,4,2 is 20

[tex]\frac{4}{20}+\frac{15}{20}+\frac{10}{20}[/tex]

[tex]Add\: 4+15+10= 29[/tex]

[tex]1/5+3/4+1/2=29/20[/tex]

[tex]Answer :\frac{29}{20}[/tex]

--------------------------

hope it helps

have a great day!!

I need someone to please explain how to turn this into a simplified fraction. (NOTE: please explain!!) __ 3.541 The repeating sign is only above the 41, not the five

Answers

the way to do these recurring decimals is by firstly separating the repeating part or recurring part and then multiply it by some power of 10 so we move it to the left, lemme show

[tex]3.5\overline{41}\implies \cfrac{35.\overline{41}}{10}\qquad \stackrel{\textit{say that the repe}\textit{ating part is }~\hfill }{x = \overline{0.41}\qquad \qquad \textit{so that }35.\overline{41}=35+\overline{0.41}=35+x}[/tex]

now, let's multiply that repeating part by some power of 10 that moves the 41 to the left, well, we have two repeating decimals, 4 and 1, so let's use two zeros, namely 100 or 10², thus

[tex]100\cdot x = 41.\overline{41}\implies 100x - 41+\overline{0.41}\implies 100x = 41+x\implies 99x=41 \\\\\\ \boxed{x =\cfrac{41}{99}}\qquad \qquad \textit{so then we can say that}~~\cfrac{35.\overline{41}}{10}\implies \cfrac{35+\frac{41}{99}}{10} \\\\\\ \cfrac{~~\frac{3506}{99}~~}{10}\implies \cfrac{~~\frac{3506}{99}~~}{\frac{10}{1}}\implies \cfrac{3506}{99}\cdot \cfrac{1}{10}\implies \cfrac{3506}{990}\implies \blacktriangleright \stackrel{\textit{which simplifies to}}{\cfrac{1753}{495}} \blacktriangleleft[/tex]

What is the equation of the following line?

Answers

Answer:

The equation of the line is y=7x

Helpppp ,I will mark you brainlist

Answers

Answer:

Okay

Step-by-step explanation:

So the answer would be the one under 3 or C . 10 rebounds 20 points 40 points

Which shape has the greatest number of lines of symmetry?

A. rhombus
B. square
C. rectangle
D. parallelogram

Answers

I believe it’s B. Square
I believe It’s square:) too

Can someone please help?

Answers

Answer:

f(x) = (x + 4)^2 - 5

Step-by-step explanation:

Parent function: f(x) = x^2

To show this in a way that may look more familiar, f(x) = 1(x - 0)^2 + 0

Vertex form: f(x) = a(x - h)^2 + k

We know a = 1, because the slope is the same as the parent function.

Vertex: (h,k)

We can see that the vertex of the graph is (-4, -5)

So h = -4 and k = -5

Now all we need to do is plug the variables into our equation.

f(x) = a(x - h)^2 + k

f(x) = 1(x + 4)^2 - 5

f(x) = (x + 4)^2 - 5

Represent pictorially:

3x2/6 = 6/6 or = 1​

Answers

Answer:

yes is correct 6/6 = 1 / 3*2=6 =1

Answer:

nonsense. what's the difference between 6/6 or 1 .

Determine the area of the triangle.
96.0 square units
16.9 square units
192.0 square units
97.5 square units

Answers

Answer:

A. 96.0 square units

Step-by-step explanation:

The formula for the area of a triangle when we know the side length of two sides and the measure of an included angle of a triangle is given as:

A = ½*a*b*Sin C

Where,

a = 13

b = 15

C = 80°

Plug in the values into the formula

A = ½*13*15*Sin 80

A = 96.0187559

A = 96.0 square units (nearest tenth)

Answer:A

Step-by-step explanation: I took the test

Use the quadratic formula to find both solutions to the quadratic equation
given below.
3x2 - x + 4 = 0

Answers

Answer:

[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex]   or   [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]

Step-by-step explanation:

[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

We have a = 3; b = -1; c = 4.

[tex] x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4(3)(4)}}{2(3)} [/tex]

[tex]x = \dfrac{1 \pm \sqrt{1 - 48}}{6}[/tex]

[tex]x = \dfrac{1 \pm \sqrt{-47}}{6}[/tex]

[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex]   or   [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]

(NEED THIS ASAP)

Tests show that the hydrogen ion concentration of a sample of apple juice is 0.0003 and that of ammonia is 1.3 x 10-9. Find the approximate pH of each liquid using the formula pH = -log (H+), where (H+) is the hydrogen ion concentration The pH value of the apple juice is___ The pH value of ammonia is____

1.pH of apple juice
A. 8.11
B. 1.75
C. 3.5
D. 2.1

2. pH of ammonia
A. 1.1
B. 7.0
C. 5.4
D. 8.9​

Answers

Answer: I believe but not 100% sure

1) C

2) B

Step-by-step explanation:

The pH value of the apple juice is 3.5, option C) is the correct answer.

The pH value of the ammonia is 8.9, option D) is the correct answer.

What is pH of solution?

The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration  [H+] of the given solution.

From the formular;

pH = -log[ H⁺ ]

Given the data in the question.

For the Apple juice;

hydrogen ion concentration H⁺ = 0.0003 pH of the apple juice pH = ?

pH = -log[ H⁺ ]

pH = -log[ 0.0003 ]

pH = 3.5

The pH value of the apple juice is 3.5

Option C) is the correct answer.

For the ammonia;

hydrogen ion concentration H⁺ = 1.3 × 10⁻⁹pH of the ammonia pH = ?

pH = -log[ H⁺ ]

pH = -log[ 1.3 × 10⁻⁹]

pH = 8.9

The pH value of the ammonia is 8.9

Option D) is the correct answer.

Learn more about pH & pOH here: brainly.com/question/17144456

#SPJ2

Find the measure of the indicated angle

Answers

Answer:

Step-by-step explanation:

Because of the Isosceles Triangle Theorem, the angles across from the congruent sides will be congruent. That means that the angle x also measures 42 degrees.

WILL MARK BRAINLIEST

Please help solve problems with common tangents.

Answers

Answer:

not sure, sorry : p

Step-by-step explanation:

An item was marked down 64% from its original price,x . The amount discounted was $30. Which equation can be used to find the original price

Answers

Answer:

OP = discount amount × 100 / discount %

Step-by-step explanation:

if I understand this correctly, the actual sale price was 36% (100-64) of the originally marked price.

original price (OP) = 100%

64% of OP = 30

1% of OP = 30/64

OP (100%) = 100 × 30/64

this could be simplified to 100 × 15/32, but this hinders is finding the global formula :

OP = discount amount × 100 / discount %

What is (f.g)(x)?

f(x)=x^3 - 4x + 2
g(x)=x^2 + 2

Answers

Answer:

f(g(x)) =

[tex] {x}^{6} + 6 {x}^{4} + 8x^{2} + 2[/tex]

Step-by-step explanation:

put g(x) instead of any x in f(x)

[tex] {(x ^{2} + 2) }^{3} - 4( {x}^{2} + 2) + 2[/tex]

A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters.

Answers

Answer:

[tex]Height = 12cm[/tex]

Step-by-step explanation:

Given

[tex]Volume = 1200cm^3[/tex]

The dimension of the base is:

[tex]Base =10cm[/tex]

[tex]Sides = 13cm[/tex]

See comment for complete question

Required

The height of the base

To do this, we make use of Pythagoras theorem where:

[tex]Sides^2 = (Base/2)^2 + Height^2[/tex]

So, we have:

[tex]13^2 = (10/2)^2 + Height^2[/tex]

[tex]13^2 = 5^2 + Height^2[/tex]

[tex]169 = 25 + Height^2[/tex]

Collect like terms

[tex]Height^2 = 169 - 25[/tex]

[tex]Height^2 = 144[/tex]

Take square roots of both sides

[tex]Height = 12cm[/tex]

can anyone help with integers?

Fill in the blanks.

6) 83 + 17 = 17 +

7) |46| – |50| =

8) 42 – 2 + (18 – 10) =

9) 18 – (3 – 1) =

10) 8 - 0 =

Answers

Answer:

a) 83,b) -4,c) 48,d) 16,e) 8

Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x2 + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.

Answers

Answer:

There is no actual question here, this is just a statement.

re-read the question .... i assume it says "what is the highest that she will get during a dive?"

highest point is at t = 33/32  

– 16(33/32)^2 + 33(33/32) + 4 =

62.015625

Step-by-step explanation:

Lindsey will be 30 feet in the air at approximately 1.09 seconds and 2.48 seconds.

To find the time at which Lindsey will be 30 feet in the air, we need to solve the quadratic equation y = -16x² + 33x + 45 for x when y = 30.

Setting y equal to 30, we have:

30 = -16x² + 33x + 45

Rearranging the equation, we have:

16x² - 33x - 15 = 0

To solve this quadratic equation, we can factor or use the quadratic formula. In this case, factoring might be more challenging, so we'll use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values from our equation, we have:

x = (-(-33) ± √((-33)² - 4(16)(-15))) / (2(16))

Simplifying, we get:

x = (33 ± √(1089 + 960)) / 32

x = (33 ± √(2049)) / 32

Calculating the square root of 2049, we have:

x = (33 ± √(2049)) / 32

x ≈ 1.09 or x ≈ 2.48

To learn more about quadratic equation click on,

https://brainly.com/question/27958207

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Complete question is:

Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x² + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.

At what time will Lindsey be 30 feet in air?

Can Someone Help Me With This ?​

Answers

Answer:

its to pixelated

Step-by-step explanation:

It’s too blurry so yeah

Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter your answer using interval notation. Round your answer to four decimal places.)

Answers

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

[tex]R_{3}[/tex] = (x) = (e^z /4!)x^4

Since the aim is [tex]R_{3}[/tex](x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 - 11 x = - 118
what is the answer?

Answers

Answer:

x = 11

Step-by-step explanation:

I assume you want x, so I simply rearranged the terms, subtracted, and simplified.

X=11 should be the answer

Which of the following is the constant ratio of the relation shown in the table?

Answers

There is no constant ratio

Answer:

hello!

where are you from ?

Step-by-step explanation:

option 4 is correct ...there is no constant ratio.

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