Answer:
a) 0 seconds.
b) The stunt diver is in the air for 2.81 seconds.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
Height of the diver after t seconds:
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
a) How long is the stunt diver above 15 m?
Quadratic equation with [tex]a < 0[/tex], so the parabola is concave down, and it will be above 15m between the two roots that we found for [tex]h(t) = 15[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]15 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t - 10 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = -10[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(-10) = -52[/tex]
Negative [tex]\Delta[/tex], which means that the stunt diver is never above 15m, so 0 seconds.
b) How long is the stunt diver in the air?
We have to find how long it takes for the diver to hit the ground, that is, t for which [tex]h(t) = 0[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]0 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t + 5 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = 5[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(5) = 242[/tex]
[tex]x_{1} = \frac{-12 + \sqrt{242}}{2*(-4.9)} = -0.36[/tex]
[tex]x_{2} = \frac{-12 - \sqrt{242}}{2*(4.9)} = 2.81[/tex]
Time is a positive measure, so we take 2.81.
The stunt diver is in the air for 2.81 seconds.
Jodi has two bank accounts. Her parents started Account A for her. It currently has $100 in it, and Jodi deposits $20 into it each month. Jodi's grandparents started Account B for her. It currently has $300 in it, and her grandparents deposit $40 into it each month.
Answer:
(f+g)(x) = 60x + 400
Step-by-step explanation:
Given :
Amount in account A:
f(x) = 20x + 100
Amount in account B :
g(x) = 40x + 300
Total amount in Account A and B:
f(x) + g(x) = (20x + 100) + (40x + 300)
(f+g)(x) = (20x + 40x) + (100 + 300)
(f+g)(x) = 60x + 400
Identify the least common multiple of:
(x + 1), (x - 1), & (x^2 - 1)
Given:
The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex].
To find:
The least common multiple of given expressions.
Solution:
The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex]. The factor forms of these expressions are:
[tex](x+1)=1\times (x+1)[/tex]
[tex](x-1)=1\times (x-1)[/tex]
[tex](x^2-1)=(x-1)(x+1)[/tex] [tex][\because a^2-b^2=(a-b)(a+b)][/tex]
The least common multiple is the product of all distinct factors with its highest degree. So,
[tex]L.C.M.=1\times (x+1)\times (x-1)[/tex]
[tex]L.C.M.=(x+1)(x-1)[/tex]
[tex]L.C.M.=x^2-1^2[/tex] [tex][\because a^2-b^2=(a-b)(a+b)][/tex]
[tex]L.C.M.=x^2-1[/tex]
Therefore, the least common multiple of given expressions is [tex]x^2-1[/tex].
If (a,3) is the point lying on the graph of the equation 5x + 2y = -4, Then find a.
Answer:
I've attached the Answer
Answer:
a = - 2
Step-by-step explanation:
Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.
Find a :
Equation : 5x + 2y = - 4
5 ( a ) + 2 ( 3) = - 4
5a + 6 = - 4
5a + 6 - 6 = - 4 - 6 [ subtracting both sides by 6 ]
5a + 0 = - 10
5a = - 10
a = - 2 [ dividing both sides by 5]
[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4
5(-2) + 2( 3 ) = - 4
- 10 + 6 = - 4
- 4 = - 4 ]
)) A farmer placed an order for 16 2/3 tons of fertilizer. He calculates that the corn fields
will require 8 5/6 tons of it. How much fertilizer will the farmer have left for his other crops?
Answer:
7 5/6
Step-by-step explanation:
16 2/3 - 8 5/6
16 4/6- 8 5/6
7 5/6
NEED HELLPPPPP !!!!
Answer:
x = 14
Step-by-step explanation:
Triagle GIA and Triangle GNT are congruent.
Joseph and Mark have $230. Joseph and Kevin have $130. Mark had 3 times as much money as Kelvin. How much money does Kelvin have?
Answer:
Step-by-step explanation:
Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is
J + M = 230. The second equation is
J + K = 130. The third equation is
M = 3K. Sub that 3K into the first equation and get
J + 3K = 230. Now take th second equation and solve it for J:
J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:
130 - K + 3K = 230 and
2K = 100 so
K = 50
Kevin has $50
Suppose the hypotenuse of a right triangle is 13 cm and one of the legs is 10 cm. Use the Pythagorean Theorem to find the measure of the triangle’s other leg.
Answer:
3
Step-by-step explanation:
Pythagorean rule
[tex]hyp = opp + adj \\ therefore. \\ opp = hyp - adj \\ and \\ adj = hyp - opp[/tex]
opp=13-10
opp=3
if a triangle has one angle that measure 81 degrees and another that measures 47 degrees, what is the measure of the third angle?
Answer: 52
Step-by-step explanation:
81 + 47 is 128.
180 - 128 =52 degrees.
:)
Which equation represents a quadratic function with a leading coefficient of 2 and a constant term of –3?
Answer:
[tex]2x^{2} +bx-3=0[/tex]
Step-by-step explanation:
General form. A quadratic function [tex]f(x)[/tex] is of the form [tex](ax^2+bx+c)[/tex] where [tex]a,b,c[/tex] ∈ R or C and [tex]a[/tex] ≠ [tex]0[/tex].
We obtain an equation when [tex]f(x)=0[/tex]
⇒ [tex]ax^{2} +bx+c=0[/tex] is an quadratic equation.
Solution.
Given, [tex]a=2,c=-3[/tex], but b is not given
Thus the quadratic function with leading coefficient [tex]a=2[/tex] and constant term [tex]c=-3[/tex] is given by
[tex]f(x)=2x^{2} +bx-3[/tex]
∴ the required quadratic equation is
[tex]2x^{2} +bx-3=0[/tex]
how u work it
and answer
Answer:
B
Step-by-step explanation:
So if B is the midpoint of AC, AB must be 1/2 of AC.
If D is the midpoint of AB, it must be 1/2 of 1/2 of AC, which is 1/4 of AC.
So AC= 4 DB
What’s the equation of the blue line?
Answer:
Step-by-step explanation:
The equation of blue line A is x = 1.
That of blue line B is y = 4.
A bungee jumper leaps off a cliff 122 meters from the ground. Her cord, when fully stretched, is 72 meters long, and it takes 6 seconds after the jump for it to extend fully. The distance between e jumper and the ground as a function of time can be modeled as a quadratic function. Which equation represents her distance from the ground as a function of time?
Answer:
Answer is B.
Step-by-step explanation:
You can solve this by recognizing the vertex and the y-intercept of the quadratic equation based on the information provided.
The vertex occurs 6 seconds into the jump, when the cord is fully stretched to 72m, before it starts to contract again. This is when the jumper is closest to the ground, 122-72 = 50m above the ground. Notice the jumper never reaches the ground because the cord is only 72m long - it can't make it the full 122m - so there will not be an x-intercept (or t-intercept in this case). Anyway - the vertex is (6,50) using this information.
The y-intercept is the point at which t=0, the beginning of the jump. At the beginning of the jump, the jump is still on top of the cliff, 122m up. So the coordinates of the y-intercept are (0,122).
Now plug these values into the vertex form of the quadratic formula and solve for a:
[tex]f(t) = a(t-h)^2+k\\122=a(0-6)^2+50\\72 = 36a\\a=2[/tex]
This means our general equation (in vertex form) for this scenario is:
[tex]f(t)=2(t-6)^2+50[/tex]
Our answer options are in standard form, so just expand the vertex form of the equation to finish:
[tex]f(t)=2(t-6)^2+50\\f(t)=2(t^2-12t+36)+50\\f(t)=2t^2-24t+72+50\\f(t)=2t^2-24t+122[/tex]
Which of these is the lowest unit price for apples? $8.00 per 10-pound bag $21.40 per 3-pound bag $4.10 per 5-pound bag $.79 per pound Click on the correct answer.
Answer:
.79 cents a pound is the lowest unit price for apples
Step-by-step explanation:
A car covered 450km in 5 hours. find the speed in meters per second
Step-by-step explanation:
Hey there!
Given;
Distance (d) = 450 km = 450*1000 = 450000 m
Time(t) = 5 hours = 5*60*60 = 18000s
Now;
Speed (s) = Distance (d) /Time(t)
Or, s = 450000/18000
Or, s = 25m/s.
Therefore, the speed is 25m/s.
Hope it helps!
Answer:
The car has a velocity of 25 m/s.
Step-by-step explanation:
There are two ways to solve this problem.
First way :
450km = 450.000m
5h = 5x 3.600s =18.000s
v = s/t = 450.000 / 18.000 = 25m/s
Second way :
Velocity = speed/time = 450 / 5 = 90 km/h
90/3.6 = 25 m/s
Either way, the car has a velocity of 25 m/s.
Put these numbers in order from least to greatest.
1/8,1/2,0.13, and 7/8
Answer: 1/8, 0.13, 1/2, 7/8
Step-by-step explanation: Mental Math
Step-by-step explanation:
0.13,1/2,1/8,and 7/8
hope it is helpful to you
HELP!!!!
Best answer gets brainliest.
Answer:
t-6=7 .................
Answer:
t - 6 = 7
Step-by-step explanation:
Find the value of x in the isosceles triangle shown below.
The two triangles are similar. What is the value of x? Enter your answer in the box. x = Two right triangles, one smaller than the other, back to back, so that their right angles form a straight angle. The two acute angles along the straight angle are congruent to each other. The overlapping part of the legs is labeled 12. The part of the overlapping side that extends above the smaller triangle is labeled 3. The leg of the smaller triangle that is a ray of the straight angle is labeled 3 x plus 1. The leg of the larger angle that is a ray of the straight angle is labeled 4 x.
Answer:
The two triangles are similar.
What is the value of x?
Enter your answer in the box.
x=
The value of x is 7 units.
What is Similarity of Triangles?Two triangles are said to be comparable if their two sides are in the same ratio as the two sides of another triangle and their two sides' angles inscribed in both triangles are equal.
Given :
AD = 6 units , BD = 8 units, m∠ABC = m∠DBE = 90° and
∠DEB ≅ ∠ACB
Now, AB = AD + BD
= 8 + 6 = 14 units
Now, In ΔABC and ΔDBE,
∠DBE = ∠ABC ( Each of 90° )
∠DEB = ∠ACB ( given )
So, By using AA postulate of similarity of triangles , ΔABC ~ ΔDBE
Now, proportion of the corresponding sides will be equal.
AD/ DB= BC/ BE
14/8 = 3x/ 2x-2
4x= 28
x= 7
Hence, the value of x is 7 units.
Learn more about similarity of Triangle here:
https://brainly.com/question/11923416
#SPJ6
Let $z$ and $w$ be complex numbers satisfying $|z| = 5, |w| = 2,$ and $z\overline{w} = 6+8i.$ Then enter in the numbers \[|z+w|^2, |zw|^2, |z-w|^2, \left| \dfrac{z}{w} \right|^2 \]below, in the order listed above. If any of these cannot be uniquely determined from the information given, enter in a question mark. Don't even know where to start.
I got 49 for the first one, 100 for the second one, 9 for the 3rd one, and 6.25 for the 4th one. But it was wrong, so I don't know how to do this question.
Answer:
1st entry: 41
3rd entry: 17
Step-by-step explanation:
The 1st and 3rd entry are incorrect.
We will use the following for the 1st and 3rd:
[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]
[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]
where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.
Let's do part 1 now)
25+4+2(6)
29+12
41
Let's do part 3 now)
25+4-2(6)
29-12
17
The ages of five children in a family are 6, 1, 3, 10, and 17. Which statement is true for this group of data?
mode>mean
median>mean
median=mode
mean>median
Answer:D - mean>median
Step-by-step explanation:
There are no repeating variables to have a mode so median and mean are the only options. The mean of this data set is 7.4 and the median is 6. Therefore mean greater than median
Given that X = - 2 and y = 4 , Evaluate the expression. 5y – 4x
Answer: 28
Step-by-step explanation: 5(4)-4(-2) which is 20+8 and that is 28.
Which formula gives the coordinates of the midpoint of the segment connecting points (u, v) and (s, 6,t),
Answer:
[tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option)
Step-by-step explanation:
The midpoint of a segment connecting two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] can be described by the following formula: [tex]\frac{x_1 + x_2}{2} = x_{mid}[/tex] and [tex]\frac{y_1 + y_2}{2} = y_{mid}[/tex]. As you can see, the formula essentially takes the average of the x- and y-coordinates to find the point in the middle.
With points (u, v) and (s, t), the midpoint becomes [tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option).
Find angle C!!!!! See the image below! I need this answer fast
Answer:
55
Angle C is a inscribed angle of the of Arc Ba.
CA is the diameter so that means Arc BA equal 110 becuase
110+70=180.
Angle C is half of Arc BA so Angle C is
[tex]55[/tex]
Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.
Answer:
a= 16
b= 2
Step-by-step explanation:
edge 2021
Answer:
a=16 and b=2
Step-by-step explanation:
next one is B.
Solve for b in the literal equation y = 12x + 12b.
b=
Answer:
[tex]b = \frac{y-12x}{12}[/tex]
Step-by-step explanation:
subtract 12x from both sides, then divide by twelve.
Ryder used front end estimation to estimate the product of -24.98 - 1.29 what is the zestimate
Answer:
20
Step-by-step explanation:
The numbers whose product are to be obtained :
(–24.98)(–1.29)
To use front end approximation, numbers are rounded to the greatest place value :
For :
(-24.98) is rounded to - 20 (4 is rounded here to 0)
(-1.29) is rounder to - 1 (2 is rounded to 0)
Then, the product of the two numbers will be :
-20 * - 1 = 20
In Which Quadrant is this true
Given:
[tex]\sin \theta <0[/tex]
[tex]\tan \theta <0[/tex]
To find:
The quadrant in which [tex]\theta[/tex] lie.
Solution:
Quadrant concept:
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.
In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.
In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.
We have,
[tex]\sin \theta <0[/tex]
[tex]\tan \theta <0[/tex]
Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.
Therefore, the correct option is D.
Quadrilateral GHIJ is similar to quadrilateral KLMN. Find the measure of
side LM. Round your answer to the nearest tenth if necessary.
Answer:
LM = 24.3
Step-by-step explanation:
In terms of similar shapes, we know that the ratio of the value of one side to its corresponding side value is equal to another. In other words, we know that LK and HG are corresponding sides by looking at the quadrilaterals. The ratio of LK to HG is equal to the ratio of another pair of corresponding sides, such as LM and IH.
Therefore, the ratio of LK and HG (LK/HG) is equal to the ratio of LM and IH (LM/IH) . Make sure to keep the same quadrilateral's sides on top/bottom. In this example, LM and LK are on the same quadrilateral, and are therefore both on top. Similarly, IH and HG are of the same quadrilateral and are both on bottom. We can write this as
LK / HG = LM / IH
34/7 = LM / 5
Multiply both sides by 5
34*5/7 = LM
LM ≈ 24.2857
Rounding to the nearest tenth, LM = 24.3
Answer:
24.3
Step-by-step explanation:
A side of the triangle below has been extended to form an exterior angle of 129°. Find the value of x.
129° + x = 180°. [Linear pair]
=> x = 180° - 129°
=> x = 51°
In the given figure alongside,prove that
Triangle ABC is simalar to Triangle SRT
Find the length of AC
Answer:
let's use Pythagoras theorem,
h²=b²+l²
so,
ad²=ac²+dc²
6²=ac²+3²
36-9=ac²=27
√27 can be written as 3√3,
hence ac= 3√3
