A'B'C' is a dilation image of ABC. Which is the correct description of the dilation?

Answer:

In 26 seconds to complete a transaction, 2 products are being purchased.

Step-by-step explanation:

1 item  = 9 seconds

Time taken in all to check out = 8 seconds

Time taken to shop = 26 seconds

Now as check out process takes 8 seconds, so the

Time left to ACTUALLY SHOP =  Total Time  - Time Used to check out

                                                  = 26 seconds = 8 seconds = 18 seconds

Shopping of 1 item = 8 seconds

Shopping of 2 items  = 2 x ( Time taken in 1 item) = 2 x  9 = 18 seconds

So, in 18 seconds, 2 clothing item can be selected.

Hence,in 26 seconds to complete a transaction, 2 products are being purchased.

Answer:

-12x-9+50-5=0

-12x+41-5=0

-12x+36=0

-12x=0-36

x= -36/-12

x = 3 Answer...

hope it helps

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

[tex]3(-4x - 3) + 50 - 5= 0[/tex]

⇒ Subtract 50- 5 from both sides:-

[tex]3\left(-4x-3\right)+50-5-\left(50-5\right)=0-\left(50-5\right)[/tex]

[tex]3\left(-4x-3\right)=-45[/tex]

⇒ Divide both sides by 3:-

[tex]\frac{3\left(-4x-3\right)}{3}=\frac{-45}{3}[/tex]

[tex]-4x-3=-15[/tex]

⇒ Add 3 to both sides:-

[tex]-4x-3+3=-15+3[/tex]

[tex]-4x=-12[/tex]

⇒ Divide both sides by -4:-

[tex]\frac{-4x}{-4}=\frac{-12}{-4}[/tex]

[tex]x=3[/tex]

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Answer:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

(a) The IQR for the males' data is 12, because Q3 is at 15 and Q1 is at 3.

(b) The difference between the median values of each data set is 4 because 10-6 = 4

(c) For the males' data, the median would be a better measure of center, since the data is skewed right. For the females' data, the mean would be a better measure of center, because the data is pretty balanced (except for the outlier).

(d) Maybe a superhero movie had their opening night one day of this month, which would explain the outlier.

Answer:

m BC = 100

Step-by-step explanation:

Since the angle is at the center, the arc has the same measurement as the angle

m BC = 100

In the diagram, ∠5 is adjacent to ∠EHD.

Angle

Angles are formed when two rays intersect at a point. An angle is also formed when to lines intersect each other, thereby the two lines share a common endpoint.

Adjacent angles are two angles that have a common side and a common vertex (corner point). They are placed side by side to each other.

In the diagram, ∠5 is adjacent to ∠EHD.

Find out more on Angle at: https://brainly.com/question/25770607

This triangle has base 16 therefore the sides must be 17cm and 17 cm

When we make a altitude it divides it into two right triangles and there is a property in which the altitude of the isoceles triangle divides the base in 2 equal halves

So the side of the right triangle will be x , 8 , 17

Using pythgoreus theorem

x²+8²=17²

x = √225

x = 15

So the altitude is 15 cm

Must click thanks and mark brainliest

The net cost after discounts will be $ 2,450.

Given that Economy Hardware Store ordered items retailing for $ 2,500, and they received a chain discount of 5/20/2, the following calculation must be performed to find the net cost, knowing that the net cost is equal to the initial cost minus the discounts made about it:

First, the discount percentage must be calculated.

5/20/2 = X

4/2 = X

2 = X

Then, this percentage must be subtracted from the initial value.

2500 x (1-0.02) = X

2500 x 0.98 = X

2450 = X

Therefore, the net cost after discounts will be $ 2,450.

Learn more in https://brainly.com/question/17003148.

Answer:

7

Step-by-step explanation:

[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]

Answer: First Choice. 3 ( x - 5 )

Step-by-step explanation:

Concept:

When we are doing factoring, we should try to find any Greatest Common Factor (GCF) of all constants in the given expression.

The Greatest Common factor is the largest value of the values you have, that multiplied by the whole number is able to "step onto both".

Solve:

Factors of 3: 1, 3

Factors of 15: 1, 3, 5, 15

As we can see from the list above, 3 appears in both lists of factors and is the greatest for 3. Therefore, [3] is the GCF of 3 and 15

Divide 3 for both numbers to find the remaining.

Check whether or not the remaining can be divisible

Put the factored out 3 and remaining together

Hope this helps!! :)

Please let me know if you have any questions

Answer:

all real numbers greater than or equal to 11

Answer:

-5/13

Step-by-step explanation:

sin theta = opp / hyp

sin theta = -12 /13

we can find the adj side by using the pythagorean theorem

adj^2 + opp ^2 = hyp^2

adj^2 +(-12)^2 = 13^2

adj^2 +144 =169

adj^2 = 169-144

adj^2 = 25

Taking the square root of each side

adj = ±5

We know that it has to be negative since it is in the third quad

adj = -5

cos theta = adj / hyp

cos theta = -5/13

Answer:

B) -5/13

Step-by-step explanation:

i hope it will help

plzz mark as brainliest if you want

Answer:

3744.64

Step-by-step explanation:

To know the answer to this question you need to know the formulas to find the volume of the cylinder and the rectangular prism. The volume of a cylinder is pi*r^2*h while the volume of the rectangular prism is l*w*h. The cylinder is 1808.64 cubic in while the rectangular prism is 1936 cubic. Together, they are 3744.64 cubic in.

Answer:

cylinder= A=πr²h

=3.14×4²×9

=452.16

rectangle=A=l×w×h

=19×11×11

=2299

total area=452.16+2299

=2751.16

Step-by-step explanation:

Answer:

30.80

Step-by-step explanation:

We can use a ratio to solve

4 tickets              7 tickets

-------------------  = ----------------

17.60 dollars           x dollars

Using cross products

4x = 17.60 * 7

4x =123.2

Divide each side by 4

4x/4 = 123.2/4

x=30.8

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ [tex]r^{6}[/tex] = 256 → (1)

a₁ [tex]r^{9}[/tex] = 2048 → (2)

Divide (2) by (1)

[tex]\frac{a_{1}r^{9} }{a_{1}r^{6} }[/tex] = [tex]\frac{2048}{256}[/tex]

r³ = 8 ( take the cube root of both sides )

r = [tex]\sqrt[3]{8}[/tex] = 2

Substitute r = 2 into (1)

a₁ × [tex]2^{6}[/tex] = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

Answer:

-14, 9 and - 54/7

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Add 10l to 12l to13l to11l to 14l=60l the divide 60l by the number of houses which will be 12 and there is your correct answer

they don't share any points

that's one thing, but I don't know what your options are of course.

see screenshot for illustration of the inequalities

since in a cube length, width and height are equal,

h = 6

w = 6

l = 6

and volume is 6³ = 216cm³

hope it helps :)

Answer:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

Step-by-step explanation:

Given

[tex]\angle 1[/tex] and [tex]\angle 2[/tex]

Required

The relationship between them [tex]\angle 1[/tex] and [tex]\angle 2[/tex]

From the question, we understand that [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are supplementary

Supplementary angles add up to 180.

So, the relationship between [tex]\angle 1[/tex] and [tex]\angle 2[/tex] is:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

In this question, a piece-wise function is asked to be graphed.

Piece-wise function:

A piece-wise function is a function that has different definitions, depending on the input.

In this question, the function has three different definitions:

For x between -1(inclusive) and 0, y takes a constant value of -1.

For x between 0(inclusive) and 1, y takes a constant value of -2.

For x between 1(inclusive) and 2, y takes a constant value of -3.

Additionally:

At the inclusive points, the interval is circled, and thus, the graphic is given at the end of this answer.

For another example of the graphic of a piece-wise function, you can check https://brainly.com/question/16855064

Answer:

Step-by-step explanation:

1. (1, 3); (2, 3)

2. (0, 0) (1, 0)

3. (-1, 1) (0,0)

Answer:

-26 sqrt(3)

Step-by-step explanation:

-12 sqrt(12) - 2 sqrt(3)

Rewriting

-12 sqrt(4*3) - 2 sqrt(3)

We know sqrt(ab) = sqrt(a)sqrt(b)

-12 sqrt(4)sqrt(3) - 2 sqrt(3)

-12 (2) sqrt(3) - 2 sqrt(3)

-24 sqrt(3) - 2 sqrt(3)

-26 sqrt(3)

[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]

[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]

[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]

[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]

[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]

- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.

Answer:

79.605

Step-by-step explanation:

sin 31° = 41/x

x = 41/sin 31°

x = 79.605

Answer:

30 =x

Step-by-step explanation:

The angles are correcting angle and corresponding angles are equal when the lines are parallel

55 = x+25

Subtract 25 from each side

55-25 = x+25

30 =x

Answer:

Step-by-step explanation:

(√63 + 144)/5 = (3√7 + 144)/5 = 0.6√7 + 28.8

Answer:

5.55%

Step-by-step explanation:

Hope this helped you

If this helped you, plz mark me as brainiliest

Sorry for bad handwriting.

Thank you

Part 1

[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]

Answer:  -4/11

====================================================

Part 2

Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.

[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]

This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.

Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]