Answer:
c
Explanation:
wavelength = speed of light/ frequency
= (3x 10^8 m/s)/(5.0 x 10^14 Hz)
= 6.0 x 10^-7 m
What my fav food for 20 points if you know it!?
Answer:
pizza
Explanation:
Answer:
sea food???
Explanation:
A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it? 0.33 A 3 A 480 A 43,200 A
Answer:
I=R×V
360×120 V
=43,200 A
Answer:
A.)0.33 A
Explanation:
i just took the quiz 2021
What are 5 examples of steong forces and what are 5 examples of weak forces. Thx!
Answer: The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei.
Explanation:
Half Time At 3:00 the hour hand and the minute hand of a clock point in directions that are 90.0
apart. What is the first time after 3:00 that the angle between the two hands has decreased by half to 45.0?
The first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
Angular velocity of the hour hand
The angular velocity of the hour hand for 12 hours time is calculated as follows;
[tex]\omega_h = \frac{2\pi}{12(3600 \ s)}[/tex]
Angular velocity of the minute handThe angular velocity of the minute hand for 12 hours time is calculated as follows;
[tex]\omega _m = \frac{2\pi}{3600}[/tex]
Difference in the angular velocity[tex]\Delta \omega = \frac{2\pi }{3600} - \frac{2\pi }{12(3600)} = \frac{11(2\pi)}{12(3600)} = \frac{22\pi}{12 (3600)}[/tex]
First angle between the two hands in radians[tex]45^0 = \frac{45}{180} \pi= \frac{\pi}{4}[/tex]
Time after 3:00The time after 3:00 is calculated as follows;
[tex]t =( \frac{\pi}{4}) /\frac{22\pi}{12(3600)} \\\\t = \frac{\pi }{4} \times \frac{12(3600)}{22\pi} \\\\t = 490.91 \ s\\\\t = 8 \min, \ 10.91 \ s[/tex]
[tex]t \approx 8\min, 11 \ s[/tex]
Thus, the first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
Learn more time in angular difference here: https://brainly.com/question/7815
PHYSICS HELP
PLEASE HELP ITS ABOUT ATWOOD MACHINES
Answer:
7.23407 [tex]\frac{m}{s^2}[/tex]
Explanation:
(I will not include units in calculations)
I'm assuming FBD's are already drawn, so I will work from there.
Let the 2.2kg block equal [tex]m_2[/tex], and the 20kg block equal [tex]m_1[/tex].
Summation equation for [tex]m_2[/tex]: [tex]\sum F_x=F_t_2-(F_f+F_g_x)=m_2a[/tex], [tex]\sum F_y=F_n-F_g_y=0[/tex]
Summation equation for [tex]m_1[/tex]: [tex]\sum F_y=F_g-F_t_1=m_1a[/tex]
Torque Summation Equation: [tex]\sum\tau=F_t_1*r-F_t_2*r=I\alpha[/tex]
Do some plugging in with the values given: [tex]\sum\tau=F_t_1*r-F_t_2*r=.5Mr^2\alpha[/tex]
Replace [tex]\alpha[/tex] with [tex]\frac{a}{r}[/tex], and cancel out the r's.
[tex]\sum\tau=F_t_1-F_t_2=.5Ma[/tex]
This step is important: Rearrange the force summation equation to solve for each tension force.
[tex]F_t_2=m_2a+F_f+F_g_x\\F_t_1=m_1g=m_1a[/tex]
Perform Substitution: [tex]\sum\tau=m_1g-m_1a-(m_2a+F_f+F_g_x)=.5Ma[/tex]
Now, we need to find the friction force and the horizontal component of the force of gravity.
Note that [tex]F_f=[/tex]μ[tex]F_n[/tex]
And based on our earlier summation equation: [tex]F_n=F_g_y[/tex]
First, break [tex]F_g[/tex] into x and y components. [tex]F_g_y=F_g\cos(\theta)[/tex], [tex]F_g_x=F_g\sin(\theta)[/tex]
Perform substitution with this and the fact that [tex]F_g=mg[/tex].
[tex]\sum\tau=m_1g-m_1a-(m_2a+\mu*m_2g\cos(\theta)+m_2g\sin(\theta))=.5Ma[/tex]
Solving for a, plugging in numbers yields an answer of 7.23407 [tex]\frac{m}{s^2}[/tex]
Answer:
7.23407
Explanation:
easy
A student wearing in-line skates pushes against a brick wall. why does the student move away from the wall ?
1. Because the forces acting on the student are balanced
2. Because the forces acting on the student are creating a net force
3. Because gravity is less than the student's push on the wall
4. Because the friction between the skates and the pavement is greater than the student's push on the wall
Answer:
Because the forces acting on the student are creating a net force.
Explanation:
I took the test and that was the answer
Answer:
Because the forces acting on the student are creating a net force
Explanation:
Which of the following is NOT a natural
source of pollution?
A. erupting volcanoes
B. dust storms
C. construction
D. forest fires
Answer:
hi
Explanation:
answer is C
have a nice day
what happens during subduction
Answer:
Subduction , Latin for "carried under," is a term used for a specific type of plate interaction. It happens when one lithospheric plate meets another—that is, in convergent zones —and the denser plate sinks down into the mantle.
Two identical speakers are set some distance apart in a large open field. Both are producing sound, in unison, with a wavelength of 4 m. An observer wandering around the field notices that the sound is surprisingly loud at certain locations and unusually quiet at others. The observer concludes that this is the effect of interference between the two sources of sound waves. For each location, indicate which sort of interference would occur at that point.
Answer:
Constructive interference occurs at the surprisingly loud locations and destructive interference occurs at the unusually quiet locations.
Explanation:
This is because, constructive interference tends to combine the effects of the wave when they are in phase (that is, moving in the same direction), which thus amplifies the effect and produces surprisingly loud sounds at those locations, while destructive interference occurs when the waves are out of phase with each other(that is, move in opposite directions) and thus, their effects tend to cancel out thus producing locations of unusually quiet sounds.
Which is true regarding a child standing up for their own rights?
Answer:
hey mate......looks like the question is incomplete
a shiny object reflects light. will a shiny object make a shadow when light shine on it? explain your answer
Answer:
yes I think it is possible
sample of pure boron contains only isotope X and isotope Y.
A nucleus of X has more mass than a nucleus of Y.
[o[4].[4] The sample is ionised, producing ions each with a charge of +1.6 x 10°C.
The specific charge of an ion of X is 8.7 x 10°C kg".
Calculate the mass of an ton of X.
[1 mark]
h
mass of ion = kg
[4].[2] Determine the number of nucleons in a nucleus of X.
mass of a nucleon = 1.7 x 1077 kg
[2 marks]
h
number of nucleons =
[o[4].[3] Compare the nuclear compositions of X and Y.
[2 marks]
[o[4].[4] lons of Y have the same charge as ions of X.
State and explain how the specific charge of an ion of X compares with that of an
ion of Y.
[2 marks]
Answer:
[tex]1.84[/tex]×[tex]10^{-26}[/tex]
Explanation:
specific charge = [tex]\frac{charge}{mass}[/tex] so by rearranging for mass we get
mass= [tex]\frac{charge}{sepcifc charge}[/tex]
[tex]\frac{1.6×10^{-26} }{1.7×10^{-27} }[/tex] = answer in kg
a disk of radius 10 cm speeds up from rest. it turns 60 radians reaching an angular velocity of 15 rad/s. what was the angular acceleration?
b. how long did it take the disk to reach this velocity?
Answer:
a) α = 1.875 [tex]\frac{rad}{s^{2} }[/tex]
b) t = 8 s
Explanation:
Given:
ω1 = 0 [tex]\frac{rad}{s}[/tex]
ω2 = 15 [tex]\frac{rad}{s}[/tex]
theta (angular displacement) = 60 rad
*side note: you can replace regular, linear variables in kinematic equations with angular variables (must entirely replace equations with angular variables)*
a) α = ?
(ω2)^2 = (ω1)^2 + 2α(theta)
[tex]15^{2}[/tex] = [tex]0^{2}[/tex] + 2(α)(60)
225 = 120α
α = 1.875 [tex]\frac{rad}{s^{2} }[/tex]
b)
α = (ω2-ω1)/t
t = (ω2-ω1)/α = (15-0)/1.875 = 8
t = 8 s
PLEASE HELP! I'LL GIVE BRAINLEST
Answer:
Weight = 8.162 Newton.
Explanation:
Given the following data;
Mass = 2.2 kg
Acceleration due to gravity = 3.71 N/kg
To find the weight of the textbook;
Weight = mass * acceleration due to gravity
Weight = 2.2 * 3.71
Weight = 8.162 N
Therefore, the weight of the science textbook in mars is 8.162 Newton.
Three 5 Ohm resistors are connected in series to a 10 Volt power supply. What is the current through each resistor?
Answer74.3
:
Explanation:
a wave travels one complete cycle in20sec and has wavelength of 1000mm.what is the speed
Answer:
20000
Explanation:
Speed = Wavelength x Wave Frequency. In this equation, wavelength is measured in meters and frequency is measured in hertz (Hz), or number of waves per second. Therefore, wave speed is given in meters per second, which is the SI unit for speed.
What do you mean by physics?
Answer:
Explanation:
Physics is the branch of science that studies the natural world and its rules and orders. It is one of the oldest sciences as ancient people study the stars and astronomy is considered part of Physics.
Describe the formation of the land, the atmosphere, and the oceans of earth
PLEASE HELP and actually help plz
The position of masses 4kg, 6kg, 7kg, 10kg ,and 3kg are (0,1), (4,2), (3,5), (5,6), and (-2,4) respectively. Where must you place a mass of 13kg if you want the center of mass to be at (-1,-3)?
Answer:
iEvaluate for \(x=2.\)Evaluate for \(x=2.\)Evaluate for \(x=2.\)Evaluate for \(x=2.\)Evaluate for \(x=2.\)Evaluate for \(x=2.\)Evaluate for \(x=2.\)
Explanation:
This force will cause the path of the particle to curve. Therefore, at a later time, the direction of the force will ____________. This force will cause the path of the particle to curve. Therefore, at a later time, the direction of the force will ____________. have a component along the direction of motion remain perpendicular to the direction of motion have a component against the direction of motion first have a component along the direction of motion; then against it; then along it; etc.
Answer:
have a component along the direction of motion that remains perpendicular to the direction of motion
Explanation:
In this exercise you are asked to enter which sentence is correct, let's start by writing Newton's second law.
circular movement
F = m a
a = v² / r
F = m v²/R
where the force is perpendicular to the velocity, all the force is used to change the direction of the velocity
in linear motion
F = m a
where the force is parallel to the acceleration of the body, the total force is used to change the modulus of the velocity
the correct answer is: have a component along the direction of motion that remains perpendicular to the direction of motion
Scroll over the answer choices to see the images. Choose all of the true statements concerning the corresponding image
The picture depicts an electric motor which turns electrical energy into mechanical energy.
The picture depicts a generator which turns electrical energy into mechanical energy
A series circuit is a good example of an electromagnet
F more wite is wound around this iron mail, the strength of the electromagnetic is increased
This image devices that the direction of the magnetic field does not depend on the direction of the current
Flow of electron |
Answer:
Explanation:
I jus did it on usatestprep
A 0.545-kg ball is hung vertically from a spring. The spring stretches by 3.56 cm from its natural length when the ball is hanging at equilibrium. A child comes along and pulls the ball down an additional 5cm, then lets go. How long (in seconds) will it take the ball to swing up and down exactly 4 times, making 4 complete oscillations before again hitting its lowest position
Answer:
t = 9.52 s
Explanation:
This is an oscillatory motion exercise, in which the angular velocity is
w = [tex]\sqrt{ \frac{k}{m} }[/tex]
Let's use hooke's law to find the spring constant, let's write the equilibrium equation
F_e - W = 0
F_e = W
k x = m g
k = [tex]\frac{m g}{x}[/tex]
k = 0.545 9.8 /0.0356
k = 150 N / m
now the angular velocity is related to the period
W = 2π / T
we substitute
4π² T² = k /m
T = 4pi² [tex]\sqrt{ \frac{m}{k} }[/tex]
we substitute
T = 4 pi² [tex]\sqrt{ \frac{0.545}{150} }[/tex]
T = 2.38 s
therefore for the spring to oscillate 4 complete periods the time is
t = 4 T
t = 4 2.38
t = 9.52 s
A 2.50 MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 78 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Part A Calculate the speed of the fetal heart wall at the instant this measurement is made.
Answer:
the speed of the fetal heart wall at the instant is 0.0325 m/s
Explanation:
Given the data in the question;
f₀ = 2.50 MHz = 1.80 × 10⁶ Hz
f[tex]_B[/tex] = 78 beat per sec ( Hz )
V = 1500 m/s
the speed of the fetal heart wall at the instant this measurement is made = ?
now, if v is the magnitude of hart wall speed, V is speed of sound and f[tex]_h[/tex] the frequency the heart receives( and reflects), f₀ is original frequency and f, is reflected back;
so
heart is moving observer and device is stationary source
f[tex]_h[/tex] = ((V + v)/v )f₀
Heart is moving source and device is stationary observer
f' = (V/(V-v ))f[tex]_h[/tex]
Beats
f[tex]_B[/tex] = f₀ - f' = f₀ - f₀( V+v / V-v ) = f₀( 2v / V-v )
so we solve for v
v = V( f[tex]_B[/tex] / ( 2f₀ + f[tex]_B[/tex] )
so we substitute
v = 1500 ( 78 / ( (2×1.80 × 10⁶) + 78 )
v = 1500 ( 78 / ( 3,600,000 + 78 )
v = 1500 ( 78 / 3,600,078 )
v = 1500 ( 2.1666 × 10⁻⁵ )
v = 0.0325 m/s
Therefore, the speed of the fetal heart wall at the instant is 0.0325 m/s
A train has a mass of 100000 kilograms.if its kinetic energy is 3mj what velocity is it travelling at
Answer:
V = 7.75 meters per seconds.
Explanation:
Given the following data;
Mass = 100000 Kilograms
Kinetic energy = 3 Megajoules = 3 * 10⁶ Joules
To find the velocity of the train;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the formula, we have;
[tex] 3000000 = \frac{1}{2}*100000*V^{2}[/tex]
Cross-multiplying, we have;
[tex] 6000000 = 100000V^{2}[/tex]
[tex] V^{2} = \frac{6000000}{100000} [/tex]
[tex] V^{2} = 60 [/tex]
Taking the square root of both sides, we have;
[tex] V = \sqrt {60} [/tex]
V = 7.75 m/s
What is a gravitational force?
Answer:
It is the force that pulls down an object on the air
Answer: a downward pull on any object
Explanation:
Brian Lara is a cricketer playing in the field on the second day of a cricket test-match. He exerts a forward force on the 0.145kg cricket ball, as he catches it, to bring it to rest from a speed of 38.2m/s. During the process, his hand recoils a distance of 0.135m. Determine the acceleration of the ball and the force which is applied to it by Brian Lara.
Answer:
a = -3984.6 m/s²
F = 577.76 N
Explanation:
The acceleration of the ball can be calculated by using the third equation of motion:
[tex]2as = v_f^2 - v_i^2\\[/tex]
where,
a = acceleration of ball = ?
s = distance covered = recoil distance = 0.135 m
vf = final speed = 0 m/s
vi = initial speed = 38.2 m/s
Therefore,
[tex]2(0.135\ m)a = (0\ m/s)^2-(38.2\ m/s)^2\\[/tex]
a = -3984.6 m/s²
here negative sign shows deceleration.
Now, for the force applied by Brian Lara will be equal in magnitude but opposite in direction of the force required to stop the ball:
[tex]F = -ma\\F = -(0.145\ kg)(-3984.6\ m/s^2)\\[/tex]
F = 577.76 N
a bag of sugar has a mass of 2.26 kg. what is its weight
Answer:
2260
gimme brainliest rn
Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate View Available Hint(s) Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate four times as fast. at the same rate. one-fourth as fast. twice as fast. one-half as fast.
Answer:
w = w₀ / 2 the angular velocity is half the initial value.
Explanation:
We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved
initial instant.
L₀ = I₀ w₀
final moment
L_f = I w
the moment is preserved
L₀ = L_f
I₀ w₀ = I w
the moment of inertia of a disk is
I = ½ m R²
we substitute
½ m R² w₀ = ½ (2m) R² w
w = w₀ / 2
for the case of a disk with twice the mass, the angular velocity is half the initial value.
Coherent light with wavelength of 580 nm passes through two very narrow slits, and the interference pattern is observed on a screen a distance of 3.00 m from the slits. The first-order bright fringe is at 4.81 mm from the center of the central bright fringe. For what wavelength of light will the first-order dark fringe be observed at this same point on the screen?
Answer:
the required wavelength is 1.15815 μm
Explanation:
Given the data in the question;
The position of bright fringes [tex]y_m[/tex] on screen in double slit experiment is expressed as follows;
[tex]y_m[/tex] = mλD / d
solving for d, we substitute 1 for m
y₁ = (1)λD / d
d = λD / y₁
given that λ = 580 nm = 5.8 × 10⁻⁷ m, D = 3.00 m and y₁= y₀ = 4.81 mm = 0.00481 m
so we substitute
d = λD / y₁
d = ( 5.8 × 10⁻⁷ m × 3.00 m ) / 0.00481 m
d = 0.00000174 m² / 0.00481 m
d = 3.6117 × 10⁻⁴ m
Now, position of dark fringe [tex]y_m[/tex] on screen in double slit experiment is expressed as;
[tex]y_m[/tex] = ( m + 1/2 )λD / d
we substitute 0 for m
y₀ = ( 0 + 1/2 )λD / d
y₀ = λD / 2d
2y₀d = λD
λ = 2y₀d / D
we substitute
λ = ( 2(0.00481 m) ( 3.6117 × 10⁻⁴ m) ) / 3.0 m
λ = 1.15815 × 10⁻⁶ m
λ = 1.15815 μm
Therefore, the required wavelength is 1.15815 μm
what must be the mass of a rock if a boy applies a 64N force and causes it to accelerate at 4.51m/s2
first of all the formula of force is F=ma,so we are searching for m,so we can divide a on both sides F/a=m, after this substitute the values given above 64N/4.51=14.2°Kg
