An equilateral triangle has a side length of 1.4x + 2 inches. A regular hexagon has a side length of 0.5x + 2 inches. The perimeters are equal. What is the side length of the triangle? What is the side length of the hexagon? Show your work.

Answer:

62.5% decrease

Step-by-step explanation:

Answer:

4(2-2c)

Step-by-step explanation:

because you switch it around

Answer:

-1

Step-by-step explanation:

times 4 by 2c and 4 by -2

8c and -8 then you divide by each other and get -1

Answer:

$51.75

Step-by-step explanation:

The meal cost $45. $45 is 100% of the cost. She wants to leave a 15% tip, so add 15% to 100%.

15% + 100% = 115%

She will pay 115% of $45.

115% of $45 = 1.15 * $45 = $51.75

(A): 825

(B): 42,900

Answer:

I'm pretty sure it's 1,1.

Step-by-step explanation:

Answer:

(1,1)

Step-by-step explanation:

sub to pewdiepie

Answer:

:)))

Step-by-step explanation:

31/50 - .062 - 62%

17/60 - .17 - 17%

2/5 - 0.4 - 20%

6/5 - 1.2 - 120%

11/25 - .44 - 44%

13/2 - 6.5 - 650%

Answer:

five trucks per hour

Step-by-step explanation:

Answer:

P(-2,4)

Q(2,5)

R(-1,8)

Step-by-step explanation:

The rule for reflecting points across the x-axis is to keep the x-value the same but "negate" the y-value. So, the points above are your answers.

Answer:

the second one, the one that is already highlighted is correct.

Step-by-step explanation:

she divided it up among them so 20 over x shows division

Answer:

Slope sides are;

5.07 m and 6.39 m

Step-by-step explanation:

I've attached a drawn diagram showing a triangle representing the roof slopes and I have attached it.

From the image attached, the missing angle is θ.

From sum of angles in a triangle,

θ = 180 - (44 + 34)

θ = 102°

Now, a & b represent the slopes of the roof.

Thus, using law of sines which is that;

a/sin A = b/sin B = c/sin C, we can solve as follows;

a/sin 34 = 9/sin 102

a = (9 × sin 34)/sin 102

a = (9 × 0.5512)/0.9781

a = 5.07 m

b/sin 44 = 9/sin 102

b = (9 × sin 44)/sin 102

b = (9 × 0.6947)/0.9781

b = 6.39 m

Answer:

Systematic Sampling

Step-by-step explanation:

Systematic sampling is one of the types of probability sampling method. It is an advanced form of simple random sampling. In this form, from the population of members, sample members are selected randomly. In this random selection, a starting point is fixed. The sample is created when the members are selected from the fixed intervals.  

In the given excerpt, systematic sampling method has been used. Here, the sample has been created by selecting every third listed phone member. The interval has been created between in the sample size.

answer is A

x^3 + 2x^2y + x^2 + y^2 + xy^2

Answer:

answer would be C.

Step-by-step explanation:

mUsing the distributive property.

Answer:

86

Step-by-step explanation:

180-94

Answer:

The domain of the vector function is :  ( -6, -2) ∪ ( -2, 6)

Step-by-step explanation:

The given vector function  can be correctly expressed as:

[tex]r(t) = \dfrac{t-2}{t+2}i + sin \ tj + In(36-t^2) k[/tex]

The domain of the given function can be determined by finding the domain of each respective component.

To start with [tex]\dfrac{t-2}{t+2}[/tex]

Not defined, t = -2

Thus, the domain of the first component of the vector = [tex]( - \infty , -2) \cup ( 2, \infty )[/tex]

The 2nd component = sin t

No restriction on t

The 3rd component of the function is ㏑(36 - t²)

Let recall that natural is defined for +ve numbers,

i.e.

36 - t² > 0

(6 + t) (6 - t) > 0

Thus, it satisfies the inequality  -6 < t < 6

The third domain = (-6,6)

Overall;

The domain of the vector function is :  ( -6, -2) ∪ ( -2, 6)

Domain of a function is the set all possible inputs for that function.The domain of the given vector function is,

[tex](-6, -2) \cap (-2,6)[/tex]

Domain of a function is the set all possible inputs for that function.

Given information-

The vector function given in the problem is,

[tex]r(t)=\dfrac{t-1}{t+2} \hat i++sin(t)\hat j+ln(49-t^2)\hat k[/tex]

To find the domain of the above vector function, we need to find the domain of each function of vector quantity.

Lets find the domain of [tex]\hat i[/tex] first which is given by,

[tex]\dfrac{t-2}{t+2}[/tex]

This function is defined at all values except, t equals to -2 as the function is not defined at,

[tex]t=-2[/tex]

Hence the domain of component [tex]\hat i[/tex] is,

[tex](-\infty, -2) \cap (\infty,2)\\[/tex]

Lets find the domain of [tex]\hat j[/tex] first which is given by,

[tex]\sin(t)[/tex]

Two trigonometry function sine and cosine defined for all real number.

This function is defined at all real numbers. Hence the domain of component [tex]\hat j[/tex] is

Lets find the domain of [tex]\hat k[/tex] first which is given by,

[tex]\ln(36-t^2)[/tex]

Set the above argument greater than zero to find where the expression is defined.Thus,

[tex](36-t^2)>0\\(6+t)(6-t)>0[/tex]

Therefore,

The domain of it should be [tex](-6,6)[/tex]

Hence the domain of the given vector function is,

[tex](-6, -2) \cap (-2,6)[/tex]

Learn more about the domain here;

https://brainly.com/question/10197594

Answer:

y= 4/3x -1/3

Step-by-step explanation:

Find slope: y2-y1/x2-x1 = 5-(-3)/4-(-2) = 8/6 = 4/3

Use point slope to find the equation:

y - y1 = m ( x - x1 )

y - (-3) = 4/3 ( x - (-2))

y = 4/3x + 8/3 + (-3)

y = 4/3x + 8/3 - 9/3

y= 4/3x -1/3

Answer:

whats the problem

Step-by-step explanation:

Answer:

yup

Step-by-step explanation:

Answer: x=4

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

[tex]\frac{2}{3} (x-7)=-2\\[/tex]

[tex]\frac{2}{3} x+\frac{-14}{3} =-2[/tex]

[tex]\frac{2}{3}x=\frac{3}{8}[/tex]

[tex]x=4[/tex]

Answer:

true i think

Step-by-step explanation:

Answer:

14.

[tex]x = 11[/tex]  [tex]m<B = 108[/tex]   [tex]m<C= 36[/tex]   [tex]m<D = 36[/tex]

15.

[tex]x = 4[/tex]     [tex]WX = 25[/tex]     [tex]XY = 17[/tex]     [tex]WY = 25[/tex]

Step-by-step explanation:

Solving (14):

[tex]BC = BD[/tex]

[tex]m<B = 13x - 35[/tex]

[tex]m<C = 5x - 19[/tex]

[tex]m<D = 2x + 14[/tex]

First, we solve for x.

Since sides [tex]BC = BD[/tex], then

[tex]m<C = m<D[/tex]

This is so because the theorem of ASA (Angle-Side-Angle)

So, we have:

[tex]5x - 19 = 2x + 14[/tex]

Collect Like Terms

[tex]5x - 2x = 19 + 14[/tex]

[tex]3x = 33[/tex]

Divide both sides by 3

[tex]x = 11[/tex]

Solving for m<B, m<C and m<D.

We simply substitute 11 for x in their respective expressions.

[tex]m<B = 13x - 35[/tex]

[tex]m<B = 13*11 - 35[/tex]

[tex]m<B = 143 - 35[/tex]

[tex]m<B = 108[/tex]

[tex]m<C = 5x - 19[/tex]

[tex]m<C= 5*11 - 19[/tex]

[tex]m<C= 55 - 19[/tex]

[tex]m<C= 36[/tex]

[tex]m<D = 2x + 14[/tex]

[tex]m<D = 2*11 + 14[/tex]

[tex]m<D = 22 + 14[/tex]

[tex]m<D = 36[/tex]

Solving (15):

[tex]<X = <Y[/tex]

[tex]WX = 9x - 11[/tex]

[tex]XY = 4x + 1[/tex]

[tex]WY = 7x - 3[/tex]

First, we solve for x.

Since [tex]<X = <Y[/tex], then

[tex]WX = WY[/tex]

This is so because the theorem of SAS (Side-Angle-Side)

So, we have:

[tex]9x - 11 = 7x - 3[/tex]

Collect Like Terms

[tex]9x - 7x = 11-3[/tex]

[tex]2x = 8[/tex]

Divide both sides by 2

[tex]x = 4[/tex]

Solving for WX, WY and XY

We simply substitute 4 for x in their respective expressions.

[tex]WX = 9x - 11[/tex]

[tex]WX = 9 * 4 - 11[/tex]

[tex]WX = 36 - 11[/tex]

[tex]WX = 25[/tex]

[tex]XY = 4x + 1[/tex]

[tex]XY = 4 * 4 + 1[/tex]

[tex]XY = 16 + 1[/tex]

[tex]XY = 17[/tex]

[tex]WY = 7x - 3[/tex]

[tex]WY = 7 * 4 - 3[/tex]

[tex]WY = 28 - 3[/tex]

[tex]WY = 25[/tex]

Answer: 5on x axis 2 on the y axis

Answer:

The answer would be (5,2)

:D Have a Great Day :D

Answer:

148 i thk i did 16x-12

Step-by-step explanation:

Answer:

(-2,10)

(-1,7)

(0,4)

(1,1)

(2,-2)

(3,-5)

Step-by-step explanation:

Answer:

your anwer is x=-1/3y+4/3

Step-by-step explanation:

Answer:

you will need 3 quarters and 5 nickel  

Step-by-step explanation:

3 quarters is 75     and 5 nickels is 25 =1.00

Answer:

60/5=12  25/5=5   7 more miles a day

Step-by-step explanation:

plzz mark brainiest

Answer:

-0.96p - 1.82

Step-by-step explanation:

Answer:

Carly is wrong. The correct answer is 4:3

Step-by-step explanation:

40/10=4

30/10=3

Answer:

Carlie is wrong

Step-by-step explanation:

The correct answer is 4:3

Answer:

Please check the explanation below.

Step-by-step explanation:

In other words, in order for relation to be a function, we must make sure there must be no repetition of 'x' coordinate values, as it would violate the fundamental definition of a function.

A) (2, 5), (5, 7), (7, 9)

Here, the x-coordinates are: 2, 5, and 7

At x = 2, y = 5

At x = 5, y = 7

At x = 7, y = 9

Thus, the coordinate pairs (2, 5), (5, 7), (7, 9) represent the function.

B) (2, 3), (1, 4), (2, 8),(0, 1)

Here, the x-coordinates are: 2, 1, 2 and 0

At x = 2, y = 3

At x = 1, y = 4

At x = 2, y = 8

At x = 0, y = 1

Please observe that the x-coordinate values i.e. x=2 are repeated.

Thus, the coordinate pairs (2, 3), (1, 4), (2, 8),(0, 1) does not represent the function.

C) (4, 8), (5, 8), (6, 8)

Here, the x-coordinates are: 4,5 and 6

At x = 4, y = 8

At x = 5, y = 8

At x = 6, y = 8

Thus, the coordinate pairs (4, 8), (5, 8), (6, 8) represent the function.

D) (-1, 4), (0, -1), (8, 3)

Here, the x-coordinates are: -1, 0, and 8

At x = -1, y = 4

At x = 0, y = -1

At x = 8, y = 3

Thus, the coordinate pairs (-1, 4), (0, -1), (8, 3) represent the function.

E) (1, 8), (8, 1), (1, 3)

Here, the x-coordinates are: 1, 8, and 1

At x = 1, y = 8

At x = 8, y = 1

At x = 1, y = 3

Please observe that the x-coordinate values i.e. x=1 are repeated.

Thus, the coordinate pairs (1, 8), (8, 1), (1, 3) does not represent the function.

F) (9, 0), (9, 1), (9, 2), (9, 3)

Here, the x-coordinates are: 9, 9,9 and 9

At x = 9, y = 0

At x = 9, y = 1

At x = 9, y = 2

At x = 9, y = 3

Please observe that the x-coordinate values i.e. x=9are repeated.

Thus, the coordinate pairs (9, 0), (9, 1), (9, 2), (9, 3) does not represent the function.

We want the maximun or minimum of [tex]g(x)=-4x^2+4x-2[/tex]

Firstly, notice that we have a leading coefficient of -4, wich means our parabola is concave down. Thus, our function will have a maximum.

To find what is the maximum, let's firstly find on wich value of x it happens. We'll start by taking the first derivative of the function:

[tex]g'(x)=-8x+4[/tex]

To find the extremes of the function, we just need to find where the derivative equals zero. Setting g'(x)=0 we have

[tex]0 = -8x+4\\8x=4\\x=\frac{1}{2}[/tex]

So we found that the x coordinate of the maximum is x=1/2. To find the y coordinate we just need to substitute the value of x into the original function.

[tex]g(1/2)=-4(1/2)^2+4(1/2)-2\\g(1/2)=-1+2-2\\g(1/2) = -1[/tex]

Therefore, the maximum point [tex]M[/tex] of the function is

[tex]\boxed{M=(0.5,-1)}[/tex]

 Glad to help! Wish you great studies.

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