Answer:
62.5m
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Initial velocity = 35m/s
At the maximum height final velocity is 0m/s
Unknown:
Height of the rise of the ball = ?
Solution:
To solve this problem, we apply the right motion equation which is shown below;
v² = u² - 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
Now insert the parameters and solve;
0² = 35² - 2(9.8)(h)
-1225 = -19.6h
h = 62.5m
Which organisms release carbon dioxide as waste?
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour.
Answer:
first one 31
second one 23
Explanation:
on edge ;))
A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)
Explanation:
It is given that,
A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)
i. Total distance = total path covered
= 14 km + 43 km
= 57 km
ii. Let east is positive and west is negative.
Displacement = final position-initial position
= 43-14
= 29 km
iii. If time taken in the entire trip = 3.2 hours
Average speed = distance/time
[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]
1 km/h = 0.2777 m/s
17.81 km/h = 4.94 m/s
iv. If time taken in the entire trip = 2.5 hours
Average velocity = displacement/time
[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]
1 km/h = 0.621 mph
11.6 km/h = 7.2 mph
Henc, this is the required solution.
malnourishment is harmful during
Answer:
People who are in good health at the beginning of a hunger strike "are usually at little risk of dying from malnutrition for at least six to eight weeks," the guidelines state. But people who are ill can die from malnutrition in as little as three weeks. Malnutrition during pregnancy can be quite harmful. Maternal malnutrition during pregnancy can affect the wellbeing and development of the baby. Malnutrition is when the baby and in this case, the mother do not receive adequate nourishment during pregnancy. It means the baby, in the mother’s womb does not get enough nutrients to grow.
Hope this helps!
A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the ground. How far, in meters, from the deck does the ball land on the ground?
Answer:
2.605m
Explanation:
Using the formula for calculating Range (distance travelled in horizontal direction)
Range R = U√2H/g
U is the speed = 4.8m/s
H is the maximum height = ?
g is the acc due to gravity = 9.8m/s²
R = 3.5m
Substitute into the formula and get H
3.5 = 4.8√2H/9.8
3.5/4.8 = √2H/9.8
0.7292 = √2H/9.8
square both sides
0.7292² = 2H/9.8
2H = 0.7292² * 9.8
2H = 5.21
H = 5.21/2
H = 2.605m
Hence the height of the ball from the ground is 2.605m
A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to find the acceleration of the sled?
You need to first measure the angle of descent, i.e. the angle the hill makes with the ground. Then identify the forces acting on the sled, split them up into horizontal and vertical components, or into components that are parallel and perpendicular to the hill, and use Newton's second law to determine the components of the sled's acceleration vector.
There are at least 2 forces acting on the sled:
• its weight, pointing downward with magnitude W = m g
• the normal force, pointing perpendicular to the hill and away from the ground with mag. N
The question doesn't specify, but there might also be friction to consider, indicated in the attachment by the vector F pointing parallel to the slope of the hill and opposing the direction of the sled's motion with mag. F.
Splitting up the forces into parallel/perpendicular components is less work. By Newton's second law, the net force (denoted with ∑ or "sigma" here) in a particular direction is equal to the mass of the sled times its acceleration in that direction:
∑ (//) = W (//) = m a (//)
∑ (⟂) = W (⟂) + N = m a (⟂)
where, for instance, W (//) denotes the component of the sled's weight in the direction parallel to the hill, while a (⟂) denotes the component of the sled's acceleration perpendicular to the hill. If there is friction, you need to add -F to the first equation.
If the hill makes an angle of θ with flat ground, then W makes the same angle with the hill so that
W (//) = -m g sin(θ)
W (⟂) = -m g cos(θ)
So we have
-m g sin(θ) = m a (//) → a (//) = -g sin(θ)
-m g cos(θ) + N = m a (⟂) → a (⟂) = 0
where the last equality follows from the fact that the normal force exactly opposes the perpendicular component of the weight. This is because the sled is moving along the slope of the hill, and not into the air or into the ground.
Then the acceleration vector is
a = a (//)
with magnitude
||a|| = a = g sin(θ).
Answer:
To find the acceleration, you do 20N/50kg = 0.4 m/s^2
Explanation:
example: a = F/m = 10/2 = 5 m/s2
Bob can run the 100 meter dash in 25 seconds. What is his speed?
Answer:
4 meters a second
Explanation:
100/25
plzz mark brainiest
A 0.85-kg arrow flies through the air at a speed of 19 m/s. What is the momentum of the arrow?
16 kg m/s
22 kg m/s
160 kg m/s
360 kg m/s
Answer:
16 kg m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.85 × 19 = 16.15
We have the final answer as
16 kg m/sHope this helps you
A block is released from rest at the top of a hill of height h. If there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed v.
Answer:
v / √2
Explanation:
A blocked from rest at the top of a hill of height h it there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed. The block is released from rest at the top of another hill with a rough surface and height h. if one-half of the initial mechanical energy of the block Earth System is lost due to friction as the block descends the hill, the block will reach the bottom of the hill with a speed of?
Solution:
For the first block block, its potential energy at the top of the hill when it is at rest is converted to kinetic energy after release with a velocity v.
The kinetic energy = (1/2)mv², where m is the mass of the block.
For the other block placed on the top of the rough hill, the mechanical energy (kinetic energy) is halved due to the roughness of the hill. If u is the speed of this block at the bottom of the hill then:
kinetic energy of block on the rough hill = (1//2)mu²
Hence:
(1//2)mu² = half of main system kinetic energy
(1//2)mu² = 1/2 * (1/2)mv²
mu² = (1/2)mv²
u² = (1/2)v²
u = √(v²/2)
u = v / √2
Hence the speed at the bottom of the rock of the block placed on the rough surface is v / √2
After food is consumed, chemical nutrients are absorbed into the blood. The blood then carries these nutrients to the body's cells where the nutrients enter mitochondria. Which reaction must occur next for the cell to carry on other activities?
Answer:b
Explanation:b
4. A Ferrari travels 350km in 2 hours. What was it's
s speed?
an object increases its velocity from 22 m/s to 36 m/s in 5s.what is the acceleration of the object
Answer:
2.8 m/s²
Explanation:
v=v0+at <=> 36 = 22 + a×5 <=> 5a = 36-22 <=> 5a = 14 <=> a = 14/5 <=>
<=> a = 2.8 m/s²
I mon runs a distance of 10km in 5 ms
he overage speed
Note: Your question inputs seem a little odd. But, I am assuming that you really mean '10km in 5 ms'.
Answer:
The Average speed = 15000 / 0.005 = 3000000 m/s
Explanation:
Average speed can be calculated by dividing the total distance covered by the total time.
Average speed = Total Distance / Total time
Given
Total distance = 15km = 15(1000) = 15000 m Total time = 5 ms = 0.005 seconds
Thus,
Average speed = Total Distance / Total time
Average speed = 15000 / 0.005 = 3000000 m/s
Please do all of i will give you brainlest and thanks to best answer plz do it right
Answer:
winter solstice i think
Explanation:
Answer:
a/ solar eclipse
Explanation:
because the moon is on the left side of earth
A stretched spring attached to two fixed points is compressed on one end and released, as shown. The resulting wave travels back and forth between the two fixed ends of the spring until it comes to a stop. This is an example of _____ .
a Transverse wave
b
longitudinal wave
c
surface wave
d
electromagnetic wave
Answer:
B. Longitudinal wave
Explanation:
It's the only option that makes sense. Hope this helped :)
THIS IS SOOO IMPORTANT PLS HELP I’LL GIVE BRAINIEST
Describe the evidence of chemical changes that occurred during the etching process in:
a. your circuit board.
b. the copper chloride etching solution.
Give at least one piece of evidence for parts a & b--> Have at least one full sentence for each answer.
Answer:
Chemical etching is a process of printed circuit board (PCB) manufacturing that provides many advantages over mechanical methods.
Explanation:
There's one! UvU hope this helped in whatever you're in for! <3
Good Luck!
6th grade science I mark as brainliest.
Answer:
divide 10 by 50.
Explanation:
Because its time over speed 10/50
5 meter/ second
I think it's helpful
follow me and don't forget to Mark me as brainlist please
100 points if u help me and get it right this needs to be done in 3 min hurry to get ur 100 points
Calculate the kinetic energy of a 50 kg cart moving at a speed of 6.9 m/s.
Answer:
35
Explanation:
c7z ya boiiiiiiiiiiiiiiiiii
A 0.17 kg ball of dough is thrown straight up into the air with an initial speed of 12 m/s. The acceleration of gravity is 9.81 m/s 2 . a) What is its momentum at its maximum height? Answer in units of kg · m/s
Answer:
The momentum of the ball at the maximum height is zero (0 kg.m/s).
Explanation:
Given;
mass of the ball, m = 0.17 kg
initial velocity of the ball, u = 12 m/s
acceleration due to gravity, g = 9.81 m/s²
At maximum height the final velocity of the ball, v = 0
Momentum of the ball at the maximum height is given as;
P = mv
P = (0.17)(0)
P = 0 kg.m/s
Therefore, the momentum of the ball at the maximum height is zero (0).
A driver of a car traveling at 15.0 m/s applies the brakes, causing a uniform acceleration of -2.0 m/s squared. How long does it take the car to accelerate to a final speed of 10.0 m/s? How far has the car moved during the braking period?
Answer:
a) 2.5secs
b) 31.25m
Explanation:
a) From the question, we are given;
Initial speed u = 15m/s
Final speed v = 10.0m/s
Acceleration =-2.0m/s²
Required
How long it takes take the car to accelerate (Time t)
Using the equation of motion
v = u+ at
10 = 15+(-2)t
10 = 15-2t
10-15 = -2t
-5 = -2t
t = 5/2
t = 2.5secs
Hence it takes the car 2.5secs to accelerates.
b) We are to find distance S
Using the equation
S = ut + 1/2at²
S = 15(2.5)+1/2(-2)(2.5)²
S = 37.5-6.25
S = 31.25m
Hence the car as moved by 31.25m during the breaking period.
Hiii I think the answer might be 3.3 seconds,not exaclty sure tho
HELP PLZZZ!!!! Hurry
3. What does doubling the number of coils do to the strength of the electromagnet?
4. What does doubling the voltage do to the strength of the electromagnet?
5. Using the graph, predict how many paper clips a 7.5 V battery would pick up for both the 25-
coil electromagnet and the 50-coil electromagnet.
6. Calculate the slope of the 25-coilline and the 50-coil line to determine the average number of
paper clips that a 1 V battery would pick up.
Answer:
3. When the number of turns, N is doubled, the strength of the electromagnet is also doubled
4. Doubling the voltage, doubles the strength of the electromagnet
5. The number of paper clips a 7.5 V battery would pick is approximately 28 paper clips
The number of paper clips a 7.5 V battery would pick is 59 paperclips
6. For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is approximately 7 paperclips
For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is 16 paperclips
Explanation:
3. The Magnetomotive Force, MMF = The Number of Turns on the Coil, N × The Current I Flowing in the Coil, I
∴ MMF = N × I
When the number of turns, N is doubled, the magnetomotive force, MMF is also doubled, and the strength of the electromagnet is doubled
4. Given that the voltage, V applied to the coil = The current, I flowing × The resistance, R of the coil, we have
V = I × R
Therefore, for a given constant resistance in the coil, doubling the voltage, doubles the current and therefore doubles the strength of the electromagnet
5. The average slope for the 25-coil electromagnet = (23 - 12)/(6 - 3) = 3.[tex]\bar 6[/tex]
The number of paper clips a 7.5 V battery would pick = 12 + (7.5 - 3) × 11/3 = 28.5 paperclips ≈ 28 paper clips
The average slope for the 50-coil electromagnet = (48 - 26)/(6 - 3) = 7.[tex]\bar 3[/tex]
The number of paper clips a 7.5 V battery would pick = 26 + (7.5 - 3) × 22/3 = 59 paperclips
6. The slope calculated from a start point of approximately 0.4 V, is given as follows;
The slope for the 25-coil electromagnet = (12 - 6)/(3 - 0.4) = 30/13
Therefore, for the 25-coil electromagnet, the average number of paper clips a 1 V battery would pick = 6 + (1 - 0.4) × 30/13) = 96/13 ≈ 7 paperclips
The slope for the 50-coil electromagnet = (26 - 13)/(3 - 0.4) = 5
Therefore, for the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick = 13 + (1 - 0.4) × 5 = 16 paperclips
3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well.
4. Doubling the voltage doubles the electromagnet's strength.
5. The number of paper clips selected by a 7.5 V battery is 59.
6. For a 50-coil electromagnet, a 1 V battery would pull up around 7 paperclips on average. The average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.
What is electromagnet?The magnetic field of an electromagnet is created by an electric current. Electromagnets are caused from conducting wire wriggled into a coil.
A magnetic field is created in the hole by a current passing through the wire.
The magnetic field production is increased by;
1) increasing the number of turns
2) increase the area of the loop
3) by moving the magnet faster
Answer for the following given options as follows;
3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well. Because the no of coils in the circuit is directly proportional to the strength of electromagnet.
4. From the ohm's law principal doubling the voltage twice the current and hence the electromagnet's strength for a given constant resistance in the coil increases.
5. For the 25-coil electromagnet, the average slope is ;
[tex]\rm m_{avg}= \frac{23-12}{6-3} \\\\ m_{avg}= 3[/tex]
The number of paper clips selected by a 7.5 V battery is;
[tex]\rm n = 12+ (7.5-+3)\times \frac{11}{3}\\\\n = 28.5[/tex]
For the 50-coil electromagnet, the average slope;
[tex]\rm (m_{avg})_{50}= \frac{48-26}{6-3} \\\\\ \rm (m_{avg})_{50}= 7[/tex]
The number of paper clips selected by a 7.5 V battery is;
[tex]\rm N = 26+(7.5-3) \times \frac{22}{3} \\\\ N= 59[/tex]
The following is the slope determined from a starting position of around 0.4 V:
For the 25-coil electromagnet, the slope is;
[tex]\rm m_{25}=\frac{12-6}{3-0.4} \\\\\ m_{25}=\frac{6}{2.6} \\\\ m_{25}=\frac{30}{13}[/tex]
As a result, the average number of paper clips a 1 V battery would choose for the 25-coil electromagnet is;
[tex]\rm N_{25}=6+ (1-0.4)\times \frac{30}{13} \\\\ N_{25}=\frac{96}{13} \\\\ N_{25}= 7 \ paperclip[/tex]
For the 50-coil electromagnet, the slope is;
(26 - 13)/(3 - 0.4) = 5.
As a result, the average number of paper clips picked by a 1 V battery is;
[tex]\rm N'_{50}= 13+ (1-0.14)\times 5 \\\\ N'_{50}=16[/tex]
Hence,the average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.
To learn more about the electromagnets, refers to the link:
https://brainly.com/question/23727978
#SPJ5
Will mark brainiest!!!
1. A __ is caused by a sudden shift in the ocean crust which displaces the water. *
2. A tsunamis is possible, but unlikely at a __ plate boundary where two plates are moving sideways past each other. *
3. A Shallow __ is a good indicator of tsunamis, but sends data very slowly and cannot detect earthquakes. *
4. Tsunamis are common at __ plate boundaries, since large earthquakes release the built up pressure, resulting in a quick vertical movement of the plate. *
5. The Indonesian Earthquake of 2004 had a 9.1__, which was the third largest ever recorded in human history. *
All possible answers:
A. Earthquake
B. Tsunami
C. Magnitude
D. Sensor
E. Transform
F. Convergent
G. Divergent
Answer:
1. Tsunami
2.Divergent
3.Sensor
4.Convergent
5.Magnitude
Explanation:
Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a 20.0° with the horizontal. If the 7.0-kg sled is pulled across 10.0 meters, what is the work done by Karla?
Answer:
W = 1418.9 J = 1.418 KJ
Explanation:
In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:
W = F.d
W = Fd Cosθ
where,
W = Work Done = ?
F = Force = 151 N
d = distance covered = 10 m
θ = Angle with horizontal = 20°
Therefore,
W = (151 N)(10 m) Cos 20°
W = 1418.9 J = 1.418 KJ
18. Which would be the most reliable source of information to use for a history report? (2 points)
O An encyclopedia
O A magazine article
O A newspaper
A TV show
Answer:
encyclopedia most reliable I think
A red 120 kg bumper car moving at 4 m/s collides with a green 100 kg bumper car moving at 3 m/s. The red bumper car bounces off at 2 m/s. What is the green car's final velocity?
Without the comma, the above sentence appears to be asking if the ______ actually ate bob.
a.friend
b.bird
Answer:
b. bird
i am pretty sure this is right, but i cant be sure bcause i know what the sentence is.
why does diamond sparkles stars twinkles?
Answer:
Because they want attention
When you push a box with 20 N of force, what force does the box apply back on you?
The opening to a cave is a tall, 30.0-cm-wide crack. A bat is preparing to leave the cave emits a 30.0 kHz ultrasonic chirp. How wide is the "sound beam" 100. M outside the cave opening? Use v sound= 340. M/s.
Answer:
The value is [tex]w = 7.54 \ m[/tex]
Explanation:
From the question we are told that
The length of the crack is [tex]a = 0.3 \ m[/tex]
The frequency is [tex]f = 30.0 \ kHz = 30 *10^{3} \ Hz[/tex]
The distance outside the cave that is being consider is [tex]D = 100 \ m[/tex]
The speed of sound is [tex]v_s = 340 \ m/s[/tex]
Generally the wavelength of the wave is mathematically represented as
[tex]\lambda = \frac{v}f}[/tex]
=> [tex]\lambda = \frac{340 }{30*10^{3}}[/tex]
=> [tex]\lambda = 0.0113 \ m/s[/tex]
Generally for a single slit the path difference between the interference patterns of the sound wave and the center is mathematically represented as
[tex]y = \frac{ n * \lambda * D}{a}[/tex]
=> [tex]y = \frac{ 1 * 0.0113 * 100}{0.3}[/tex]
=> [tex]y = 3.77 \ m[/tex]
Generally the width of the sound beam is mathematically represented as
[tex]w = 2 * y[/tex]
=> [tex]w = 2 * 3.77[/tex]
=> [tex]w = 7.54 \ m[/tex]
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
A eureka can of mass 100g and cross-section area 100cm2 is filled with water of density 1g/cm3. A piece of metal of mass 20g and density 8g/cm3 is lowered into the can. ( height of can 10cm ) calculate:
a) the total mass of can before the metal was lowered.
b) the volume of water that overflowed
c) the final mass of can and its content
Answer:
Explanation:
a)
Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.
100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]
Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....
[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg
Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....
1000g + 100g = 1100g or 1.1kg
b)
The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....
20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]
c)
Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.
[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.
100g + 997.5g + 20g = 1117.5g or 1.1175kg
