[tex]2(2x + 4) + 2(x - 7) = 78[/tex]
[tex]4x + 8 + 2x - 14 = 78[/tex]
[tex](4x + 2x) + (8 - 14) = 78[/tex]
[tex]6x - 6 = 78[/tex]
[tex]6x = 78 + 6[/tex]
[tex]6x = 84[/tex]
[tex]x = \frac{84}{6} [/tex]
[tex]x = 14[/tex]
Unit sales for new product ABC have varied in the first seven months of this year as follows: Month Jan Feb Mar Apr May Jun Jul Unit Sales 148 329 491 167 228 285 441 What is the (population) standard deviation of the data
Answer:
[tex]\sigma = 121.53[/tex]
Step-by-step explanation:
Required
The population standard deviation
First, calculate the population mean
[tex]\mu = \frac{\sum x}{n}[/tex]
This gives:
[tex]\mu = \frac{148+ 329+ 491 +167+ 228+285+ 441}{7}[/tex]
[tex]\mu = \frac{2089}{7}[/tex]
[tex]\mu = 298.43[/tex]
The population standard deviation is:
[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]
So, we have:
[tex]\sigma = \sqrt{\frac{(148 - 298.43)^2 + ..........+ (441- 298.43)^2}{7}}[/tex]
[tex]\sigma = \sqrt{\frac{103387.7143}{7}}[/tex]
[tex]\sigma = \sqrt{14769.6734714}[/tex]
[tex]\sigma = 121.53[/tex]
Express these system specifications using the propositions p “The user enters
a valid password,” q “Access is granted,” and r “The user has paid the
subscription fee” and logical connectives (including negations).
a) “The user has paid the subscription fee, but does not enter a valid
password.”
b) “Access is granted whenever the user has paid the subscription fee and
enters a valid password.”
c) “Access is denied if the user has not paid the subscription fee.”
d) “If the user has not entered a valid password but has paid the subscription
fee, then access is granted.”
Answer:
a) r ⋀~p
b)(r⋀p)⟶q
c) ~r ⟶ ~q
d) (~p ⋀r) ⟶q
Step-by-step explanation:
To solve this question we will make use of logic symbols in truth table.
We are told that;
p means "The user enters
a valid password,”
q means “Access is granted,”
r means “The user has paid the
subscription fee”
A) The user has paid the subscription fee, but does not enter a valid
password.”
Fist part of the statement is correct and so it will be "r". Second part of the statement is a negation and will be denoted by ~p. Since both statements are joined together in conjunction, we will use the conjuction symbol in between them which is "⋀" Thus, we have; r ⋀~p
B) Still using logic symbols, we have;
(r⋀p)⟶q
⟶ means q is true when r and p are true.
C) correct symbol is ~r ⟶ ~q
Since both statements are negation of the question. And also, if ~r is true then ~q is also true.
D) Similar to answer A to C above, applying similar conditions, we have (~p ⋀r) ⟶q
A system of equations is said to be redundant if one of the equations in the system is a linear combination of the other equations. Show by using the pivot operation that the following system is redundant. Is this system equivalent to a system of equations in canonical form?
a) x1 +x2 −3x3 = 7
b) −2x1 +x2 +5x3 = 2
c) 3x2 −x3 = 16
Answer:
prove that The given system of equations is redundant is attached below
Step-by-step explanation:
System of equations
x1 +x2 −3x3 = 7
−2x1 +x2 +5x3 = 2
3x2 −x3 = 16
To prove that the system is redundant we will apply the Gaussian elimination ( pivot operation )
attached below is the solution
NEED ANSWER QUICK WITH STEP BY STEP!!!
Please help me quick I’ll give brainliest
How to solve this problem what do I do
=================================================
Explanation:
We undo the "minus 6" by adding 6 to both sides.
Also, we undo the "+s" by subtracting s from both sides
-----------
So we have these steps
P = r+s-6
P+6 = r+s-6+6 .... adding 6 to both sides
P+6 = r+s
r+s = P+6
r+s-s = P+6-s ..... subtracting s from both sides
r = P + 6 - s
Answer:
P+6-s=r
Step-by-step explanation:
Hi there!
We are given the equation P=r+s-6 and we need to solve for r
To do that, we need to isolate r onto one side, and have everything else on the other.
Here is the equation:
P=r+s-6
start by adding 6 to both sides to clear it from the right side
P+6=r+s
now subtract s from both sides to clear it from the right side
P+6-s=r
now everything that isn't r is on the left side, and r is by itself on the right side. P+6-s=r is the answer.
Hope this helps!
For this problem what I did was add all the measurements and I got 48 m. However, it is wrong. How do I go about solving the perimeter then?
9514 1404 393
Answer:
66 m
Step-by-step explanation:
The perimeter is the sum of the measures of all of the sides. There are two side measures that are missing from the diagram.
The missing horizontal measure is ...
17 m - 8 m = 9 m
The missing vertical measure is ...
16m -7 m = 9 m.
If you add these to the sum you already calculated, you will get the correct answer:
48 m + 9 m + 9 m = 66 m . . . perimeter of the figure
_____
If you're paying attention, you see that the sum of the measures of the two shorter horizontal segments is the same as the measure of the longer horizontal segment. Likewise, the sum of the measurements of the two shorter vertical segments is the same as that of the longer vertical segment.
In other words, the perimeter of this (and any) L-shaped figure is the same as the perimeter of a rectangle having the same horizontal and vertical dimensions as the long sides of the figure.
P = 2(17 m +16 m) = 2(33 m) = 66 m
Can someone help me please..
Answer:
Quadratic formula
Step-by-step explanation:
The function is quadratic because it is a parabola. Exponential functions shoot either upwards or downwards rapidly, and it is clearly not linear due to it's curve. It also isn't piecewise because the function never stops or starts irregularly.
Please explain absolute values?
Answer:
the magnitude of a real number without regard to its sign.
Step-by-step explanation:
For example, |-3| would just be a 3 in general, no negative sign in the front.
hope this answers your confusion.
PLESE HELP WITH ANSWER. rewrite the function in the given form
s hard and too long I'm only of class 13
Help me with moth of these questions please
Answer:
10. CD + DE = CE
11. BC + CE = BE
Step-by-step explanation:
10. CD and DE lie on a straight line, therefore, CD + DE = CE based on the segment addition postulate.
11. BC and CE lie on a straight line, therefore, BC + CE = BE based on the segment addition postulate.
Jose bought a piece of fabric that was 5.6 meters long. From that, he cut 0.4
meter. How much fabric is left?
Answer:
Jose has 5.2 meters of fabric left.
Step-by-step explanation:
5.6 - 0.4 = 5.2
2.7.2 : Checkup - Practice Problems
Anyone know this question?
Answer:
[tex](f + g)(4) = 191[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x^2 - 5x + 15[/tex]
[tex]g(x) = 6x^2 + 7x - 8[/tex]
Required
[tex](f + g)(4)[/tex]
First, calculate [tex](f + g)(x)[/tex]
This is calculated as:
[tex](f + g)(x) = f(x) + g(x)[/tex]
So, we have:
[tex](f + g)(x) = 5x^2 - 5x + 15+6x^2 + 7x - 8[/tex]
Collect like terms
[tex](f + g)(x) = 5x^2 +6x^2 - 5x+ 7x + 15 - 8[/tex]
[tex](f + g)(x) = 11x^2 + 2x + 7[/tex]
Substitute 4 for x
[tex](f + g)(4) = 11*4^2 + 2*4 + 7[/tex]
[tex](f + g)(4) = 191[/tex]
I WILL MARK BRAINLIEST PLEASE HELP! This graph represents f(x), and g(x) = -7x + 8.
Which statement about these functions is true?
A.
Function f(x) is increasing, and g(x) is decreasing.
B.
Function f(x) is decreasing, and g(x) is increasing.
C.
Functions f(x) and g(x) are both decreasing.
D.
Functions f(x) and g(x) are both increasing.
Answer:
A
Step-by-step explanation:
ITS OPTION (A)
PLZ MARK ME BRAINLIEST..
The accompanying data represent the homework scores for material for a random sample of students in a college algebra course.
36
47
54
58
60
66
66
68
69
70
72
75
77
77
78
78
78
79
79
79
79
79
80
82
84
85
86
86
86
87
89
89
91
92
92
93
93
94
96
99
(a) Construct a relative frequency distribution with a lower class limit of the first class equal to 30 and a class width of 10.
(b) What is the probability a randomly selected student fails the homework (scores less than 70)? (The standard deviation is 13.64)
Simplify your answer to two decimal places.
Answer:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
[tex]P(x < 70) = 0.225[/tex]
Step-by-step explanation:
Given
[tex]Lower = 30[/tex]
[tex]Width = 10[/tex]
Solving (a): The relative frequency table
First, we construct the frequency table using the given parameters.
[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]
The relative frequency (RF) is calculated as:
[tex]RF = \frac{Frequency}{Total}[/tex]
Using the above formula to calculate the relative frequency, the relative frequency table is:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
Solving (b): [tex]P(x < 70)[/tex]
To do this, we add up the relative frequencies of classes less than 70.
i.e.
[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]
So, we have:
[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]
[tex]P(x < 70) = 0.225[/tex]
In how many ways can a sample of 6 keyboards be selected so that exactly two have an electrical defect
Answer:
15ways
Step-by-step explanation:
This is a combination question since combination has to do with selection. Hence the number of ways sample of 6 keyboards can be selected so that exactly two have an electrical defect is expressed as;
6C2 = 6!/(6-2)!2!
6C2 = 6!/4!2!
6C2 = 6×5×4!/4!×2
6C2 = 6×5/2
6C2 = 30/2
6C2 = 15
Hence this can be done in 15ways
Keith used the following steps to find the inverse of f, but he thinks he made an error.
Nine children are to be divided into an A team, a B team and a C team of 3 each. The A team will play in one league, the B team in another, the C team in a third league. How many different divisions are possible
Answer:
The answer is "840".
Step-by-step explanation:
Following are the number of ways in which selecting a team A by 9 children:
[tex]= ^{9_{C_{3}}\\\\\\[/tex]
[tex]=\frac{9!}{3! \times 6!} \\\\=\frac{9\times 8\times 7\times 6!}{3 \times 2\times 1\times 6!}\\\\=\frac{9\times 8\times 7}{3 \times 2\times 1}\\\\=\frac{3\times 4\times 7}{1}\\\\=\frac{84}{1}\\\\=84[/tex]
Following are the number of ways in which selecting a team B by remaining 6 children:
[tex]= ^{6}_{C_{3}}[/tex]
[tex]= \frac{6!}{(3! \times 3!)}\\\\= \frac{6!}{(3\times 2\times 1 \times 3!)}\\\\= \frac{6\times 5 \times 4 \times 3!}{(3\times 2\times 1 \times 3!)}\\\\= \frac{ 5 \times 4 \times 3!}{3!}\\\\= 5 \times 4 \\\\=20[/tex]
Following are the number of ways in which selecting a team C by remaining 3 children:
[tex]= ^{3}_{C_{3}}\\\\=\frac{3!}{3!}\\\\= 1[/tex]
Following are the number of ways in which making 3 teams by 9 children:
[tex]= \frac{(84 \times 20 \times 1)}{3!}\\\\= \frac{(84 \times 20 )}{6}\\\\= 14 \times 20\\\\= 280\\\\[/tex]
(Note: we've split by 3! Because it also is necessary to implement three teams between themselves)
Now 3 leagues have to be played. One is going to be run by each team.
That is the way it is
Different possible divisions
[tex]= 280 \times 3!\\\\= 280 \times (3 \times 2 \times 1)\\\\= 840[/tex]
If (3x − 2)(3x + 2) = ax2 − b, what is the value of a?
(3x-2)(3x+ 2)
Multiply each term in one set of parentheses by the other terms:
3x x 3x =9x^2
3x x 2 = 6x
-2 x 3x = -6x
-2 x 2 = -4
Combine to get:
9x^2 + 6x - 6x -4
Combine like terms:
9x^2 - 4
The value of a would be 9.
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
(3x − 2)(3x + 2) = ax2 − b⠀⠀⠀⠀[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
⠀what is the value of a?⠀⠀⠀[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
At first we have to solve the value of (3x-2)(3x+2)
[tex]\sf{(3x-2)(3x+2) }[/tex] [tex]\sf{3x(3x+2)-2(3x+2) }[/tex] [tex]\sf{9x^{2}+6x-6x-4 }[/tex] [tex]\sf{9x^{2}-4 }[/tex]According to the question,
[tex]\sf{ (3x − 2)(3x + 2) = ax^{2} − b }[/tex] [tex]\sf{9x^{2}-4=ax^{2}-b }[/tex] [tex]\sf{9x^{2}=ax^{2}~and~-4=-b }[/tex] [tex]\sf{a=9~and~b=4 }[/tex]⠀⠀⠀
[tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
Hence,
The value of a is 9
What is the smallest three-digit number that is divisible by 3? Explain how you know without multiplying or dividing.
hlw guys plz help me which set is this.for examples: A u B , A u B u C...like that..plz help me
Answer:
answer is;AnBnC ( common place for all)
HAVE A NİCE DAY
PLEASE HELP ASAP! So the answer I got for this problem is 50.26. Can someone make sure that is the correct answer? Please let me know how to solve this problem if it is wrong.
Answer:
Step-by-step explanation:
every thing looks good, except the question says "round" and soooooo, if you are rounding to the 2nd decimal place, then the next two decimal places are 54, or 50.2654 so, to round that, round up , so your final answer would look like 50.27 :) see?
9514 1404 393
Answer:
50.24 inches (or 50.2 inches)
Step-by-step explanation:
The formula for circumference in terms of radius is ...
C = 2πr
Using the given values for radius and for pi, the circumference is ...
C = 2(3.14)(8 in) = 50.24 in
__
Additional comment
If you use a more accurate value of pi, the rounded value is 50.27 in. That is not the value requested by this problem. It helps to follow directions.
If you like, you can round to 50.2, since only one decimal place is required in the result.
A professor creates a histogram of test scores for 26 students in a statistics course. What is the probability of a student having scored between 65 and 100
Complete Question
Complete is Attached Below
Answer:
Option D
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=26[/tex]
Student scoring [tex]65-100 n'=12[/tex]
Generally the equation for probability of a student having score between 65 and 100 is mathematically given by
[tex]P(65-100)=\frac{12}{26}[/tex]
[tex]P(65-100)=12/26[/tex]
[tex]P(65-100)=0.462[/tex]
Option D
According to the Venn Diagram below and given that P(A) = .4 as well as
P(B) = .3 what is P(AUB)?
Hello,
P(A)=0.4
P(B)=0.3
P(AUB)+P(A∩B)=P(A)+P(B)
P(AUB)=0.4+0.3-0.1=0.6
Answer C
The correct answer is option (C).
P(A ∪ B) = 0.6
Formula to find P(A ∪ B):If A, B are two different events then P(A U B) = P(A) + P(B) - P(A ∩ B)
We have been given, P(A) = 0.4, P(B) = 0.3
From given Venn diagram,
P(A ∩ B) = 0.10
Now, P(A U B) = P(A) + P(B) - P(A ∩ B)
⇒ P(A U B) = 0.4 + 0.3 - 0.10
⇒ P(A ∪ B) = 0.6
Therefore, the correct answer is option (C) .6
Learn more about here:
https://brainly.com/question/1605100
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Please explain the misleading
There are more compact cars (4*10 = 40) compared to trucks (2*10 = 20); however, the pictogram might make it appear that there are more trucks because the individual truck icon is larger compared to an individual compact car icon.
To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.
In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.
A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).
Round 36.319 to the nearest tenth
Peter organizes morning hikes for his friends every Saturday. When the hiking trail is 3 km long, 19 friends join him and when the trail is 5 km long, only 7 friends tag along. There exists a linear relationship between the distance of the hiking trail (in km) and the number of friends who tag along. The number of friends depend on the distance of the trail. Determine how many friends will tag along to a hiking trail of 2 km.
Answer:
25
Step-by-step explanation:
x = distance of the hike
y = number of friends coming along
so, we are looking for a linear relationship between these two.
y = ax + b
we need to find the factor a and the constant offset b.
19 = a×3 + b
7 = a×5 + b
7 - b = a×5
a = (7-b)/5
19 = (7-b)×3/5 + b
19 = (21 - 3b)/5 + b
95 = 21 - 3b + 5b
74 = 2b
b = 37
a= (7-37)/5 = -30/5 = -6
so, the relationship is
y = -6x + 37
for 2km hiking
y = -6×2 + 37 = -12 + 37 = 25 friends
We have just performed a one-way ANOVA on a given set of data and rejected the null hypothesis for the ANOVA F test. Assume that we are able to perform a randomized block design ANOVA on the same data. For the randomized block design ANOVA, the null hypothesis for equal treatments will ________ be rejected.
Answer:
The answer is "sometimes".
Step-by-step explanation:
A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.
Find the perimeter of a football field which measures 90m by 60m
Hello!
[tex]\large\boxed{P = 300m}[/tex]
Use the following formula for the perimeter:
P = 2l + 2w, where:
l = length
w = width
Therefore:
P = 2(90) + 2(60)
Simplify:
P = 180 + 120 = 300 m
Answer:
well how about you use common sense 100 yards long on each side 200 yards then add 5o yards since the the that is how wide it is then add another 50 and you get 300 yards then convert that to meters
