FIND AC! PLS HELP!!

Answer:

A

Step-by-step explanation:

because when i dentify graph theres y an x

The feasible region of the result is defined by the system of inequalities.

Correct response:

The system of inequalities shown in the graph is given by the option B.

B. y ≤ x + 1

y ≤ x² - 3·x

Please find attached the possible graph of the inequality

The possible graph obtained from a similar question has a straight line portion and a quadratic portion.

Points on the straight line are; (0, 1), (3, 4), and (5, 6)

Therefore;

[tex]Slope \ of \ the \ line = \dfrac{6 - 1}{5 - 0} = 1[/tex]

Equation of the line is; y - 1 = 1 × x

Therefore;

y = x + 1

The shaded region is below the line which gives;

Points on the quadratic graph are; (0, 0), (4, 4), and (2, -2).

The general form of a quadratic equation is; y = a·x² + b·x + c

Therefore, we have;

0 = a × 0 + b × 0 + c

Which gives;

c = 0

4 = a × 4² + b × 4 = 16·a + 4·b

-2 = a × 2² + b × 2 = 4·a + 2·b

4 = 16·a + 4·b...(1)

-2 = 4·a + 2·b...(2)

Multiplying equation (2) by 2 and subtracting from equation (1) gives;

2 × -2 = 2 × (4·a + 2·b) = 8·a + 4·b

-4 = 8·a + 4·b

4 - (-4) = 16·a + 4·b - (8·a + 4·b) = 8·a

8 = 8·a

[tex]a = \dfrac{8 }{8} = 1[/tex]

a = 1

-2 = 4 × 1 + 2·b

2·b = -2 - 4 = -6

[tex]b = \dfrac{-6}{2} = \mathbf{ -3}[/tex]

Which gives;

y = 1·x² - 3·x = x² - 3·x

The line is a solid line and shaded region is the region under the graph which gives;

Therefore;

The inequalities in the graph are given by option B.

B. y ≤ x + 1

y ≤ x² - 3·x

Learn more about graph of inequalities here:

https://brainly.com/question/6749279

Answer:

x = - 3, x = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given

(2x - 1)(x + 3) = 0

Equate each factor to zero and solve for x

x + 3 = 0 → x = - 3

2x - 1 = 0 ⇒ 2x =  1 ⇒ x = [tex]\frac{1}{2}[/tex]

Answer:

x = 0.5 and -3

Step-by-step explanation:

(2x - 1)(x + 3) = 0

We are solving for the two x values (since this is a polynomial)

(2x-1) = 0/(x + 3)

2x - 1 = 0

2x = 1

x = 1/2 = 0.5

And the second x value

(x + 3) = 0 / (2x - 1)

x + 3 = 0

x = -3

Step-by-step explanation:

p = 2×( l+w)

p = 2×l + 2×w

=> 2×w = p - 2×l

w = (p - 2×l) / 2

w = (11 - (2×2.8))/2

= (11- 5.6)/2

= 5.4 /2

= 2.7 cm

Answer:3

Step-by-step explanation:

Just count from -1 to positive 2 the dot doesn’t move

Answer:

3

Step-by-step explanation:

The maximum value of the function is 3.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The maximum value of a function is the highest output value that the function can attain over its entire domain.

Now,

From the graph,

The y-values are called the output.

The y-value is from -∞ to 3 and 3 to -∞.

This means,

The range of the function is -∞ to 3 and 3 to -∞.

Now,

The highest output is 3.

Thus,

The maximum value of the function is 3.

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ2

Hi there!

So we are given that:-

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

[tex] \large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}[/tex]

Substitute tan theta = 7/24 in.

[tex] \large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }[/tex]

Evaluate.

[tex] \large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}[/tex]

Reminder -:

[tex] \large \displaystyle{ sec \theta = \frac{1}{cos \theta} }[/tex]

Hence,

[tex] \large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}[/tex]

Because in QIII, cos<0. Hence,

[tex] \large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}[/tex]

Using the Pythagorean Theorem

[tex] \large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }[/tex]

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

[tex] \large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}[/tex]

Thus, the hypotenuse side is 25. Using the cosine ratio:-

[tex] \large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}} [/tex]

Therefore:-

[tex] \large \displaystyle{cos \theta = \frac{24}{25} }[/tex]

Because cos<0 in Q3.

[tex] \large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}[/tex]

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

Answer:

f the answer to the question is A

Answer:b

Step-by-step explanation:

Answer:

$409.86

Step-by-step explanation:

To find the price after marking it up, 230 x 0.65 = 149.5

230 + 149.5 = 379.5

Usually we add tax after the discount/markup.

379.5 x 0.08 = 30.36

379.5 + 30.36 = $409.86

Hope this helps!

Answer:

5/12

Step-by-step explanation:

Deje que el chocolate total se represente como 1

La cantidad de tarta de chocolate que le llega a Teresa es:

1 - (1/3 + 1/4)

Mínimo común denominador = 12

1 - (4 + 3/12)

1 - 7/12

= 5/12

La cantidad o fracción de la tarta de chocolate que le queda a Teresa es 5/12

Answer:

a) 1/4

b) 1/6

c) 1/12

Step-by-step explanation:

Let S be the sample space.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

n(s) =12

Events

A: coin with head and die with prime number .

B:coin with head and die with composite number.

C:coin with tail and die with even prime number.

a) A={H2,H3,H5}

n(A) = 3

P(A) =n(A)/n(S)

=3/12

= 1/4

b) B={H4,H6}

n(B)= 2

P(B) = n(B)/n(S)

= 2/12

= 1/6

c) C ={T2}

n(C) = 1

P(C) = n(C)/n(S)

= 1/12

Answer:

19, 22

Step-by-step explanation:

Because this is an arithmetic sequence, we know there is a constant difference between each value.

To find that difference, lets take two consecutive values, (10 and 13) and subtract them.

13 - 10 = 3

We see the same number if we used

16 - 13 = 3

So the pattern here, is each number + 3.

16 + 3 = 19

19 + 3 = 22

22 + 3 = 25

etc.

Answer:

go to scan an solve on brainly and it should bring up the answer, your welcome

Step-by-step explanation:

here is the answer to your question

Answer:

Step-by-step explanation:

[tex]\frac{-3x}{2}[/tex] = 5

multiply both sides by 2

2 ( [tex]\frac{-3x}{2}[/tex] = 5 )

-3x = 10

divide both sides by  [tex]\frac{-1}{3}[/tex]

[tex]\frac{-1}{3}[/tex] ( -3x = 10 )

x = [tex]\frac{-10}{3}[/tex]

got it?

Answer:

x = -10/3

Step-by-step explanation:

2(-3x/2) = (5)2

-3x = 10

-----    ---

-3     -3

x = -10/3

======================================================

Explanation:

He answered 5/7 of the 35 short-answer questions correctly. So he got (5/7)*35 = 25 of those questions correct. At 2 marks each for these questions, he earned 25*2 = 50 points from this group alone.

There are 35 short-answer questions and 15 long-answer questions. That's 35+15 = 50 questions total.

We're told that he answered 60% of all the questions correctly. So he answered 0.60*50 = 30 questions correctly.

Earlier we found that he answered 25 short-answer questions, which must mean he got 30-25 = 5 long-answer questions done correctly. At 4 marks a piece, Keith earns 5*4 = 20 points in this group.

So overall, he earned 50+20 = 70 points from both types of questions.

---------------------

If he got all answers correct, then he would earn 35*2 = 70 points from the short-answer questions and 15*4 = 60 points from the long-answer questions. That's a total of 70+60 = 130 points to get a perfect score.

The ratio of his score to the perfect score is 70:130 which reduces to 7:13 when dividing both parts by the GCF 10.

9514 1404 393

Answer:

  70/130 . . . . reduces to 7/13

Step-by-step explanation:

The problem statement describes 2 kinds of quiz questions, and different relations regarding the numbers of questions answered correctly. The problem asks for the number of marks Keith had relative to the total number of marks.

This means you need to find Keith's marks and the available marks for each question type (4 numbers).

Because of the way the problem tells you the number of long-answer questions answered, additional computations are required to find the total number of questions Keith answered and the number of short-answer questions Keith answered. (The difference of these is the number of long-answer questions answered.) That's 3 more computations.

You have to keep in mind the purpose of each computation and how it fits in to the final result. This is why we label the intermediate results.

Short Answer Marks

There were 35 short-answer questions for 2 marks each. That's a total of ...

  (35)(2) = 70 . . . . marks for all short-answer questions

Keith got 5/7 of those, so got ...

  (5/7)×70 = 50 . . . . Keith's marks for short-answer questions.

__

Long Answer Marks

There were 15 long-answer questions for 4 marks each. That's a total of ...

  (15)(4) = 60 . . . . marks for all long-answer questions

The total number of questions on the quiz was 35 +15 = 50. Keith answered 60% of them, so answered ...

  0.60×50 = 30 . . . . total number of questions Keith answered

We know Keith answered (5/7)(35) = 25 short-answer questions, so must have answered 30-25 = 5 long-answer questions. His marks for those were ...

  (5)(4) = 20 . . . . Keith's marks for long-answer questions

__

Total Marks

Then the total number of marks for all answers on the quiz is ...

  short marks + long marks = 70 +60 = 130 . . . available marks

And Keith's overall score was ...

  (Keith's short marks + Keith's long marks)/(available marks)

  = (50 +20)/130 = 70/130 . . . . Keith's score ratio for the quiz

Answer:

C  router

Step-by-step explanation:

Answer: yes, because any triangle with the ratio of whole number 3:4:5 is a right triangle

Step-by-step explanation:

Answer:

B: 0.25 = 1/4

Step-by-step explanation:

Queremos encontrar otra representación del número 0.25

Notar que hay dos decimales luego de la coma, por lo que podemos multiplicar este número y dividir por 100.

0.25 = 0.25*1 = 0.25*(100/100) = (0.25*100)/(100) = 25/100

Ahora tenemos el número escrito como una fracción, la cual debemos simplificar.

25/100

Podemos ver que tanto el numerador como el denominador son multiplos de 5, por lo que podemos dividir ambos por 5:

25/100 = (25/5)/(100/5) = 5/20

Nuevamente, ambos son multiplos de 5, por lo que podemos dividir ambos por 5.

5/20 = (5/5)/(20/5) = 1/4

así tenemos:

0.25 = 25/100 = 5/20 = 1/4

0.25 = 1/4

La opción correcta es B.

Answer:

A

Step-by-step explanation:

5 is 50/1000, and 1/2% is equal to 5/1000

Answer:

A) 55/ 1,000

5 1/2% = 11 / 200 = 55/ 1,000

Answer:

10

Step-by-step explanation:

First, we need to find the sum of the 15 consecutive numbers. The formula to finding the average of a set of numbers is the sum of the terms divided by the number of terms. So to find the sum, you do 15x15 because the average is 15 and there are 15 numbers. 15x15=225, so you know the sum of the consecutive numbers is 225. Let X be equal to the first consecutive number of the 15 consecutive numbers.

X+(X+1)+(X+2)+(X+3)....+(X+14)=225

=15X+(105)=225

=15X=225-105

=15X=120

=X=8

So the first consecutive number of the 15 is 8. Therefore, the second consecutive number is 9, the third is 10, and so on. The question asks for the average of the first five numbers, which is 8, 9, 10, 11, and 12.

The summation formula is [tex]S=(\alpha_{1}+\alpha_{n})\frac{n}{2\\}[/tex].

[tex]S=(\alpha_{1}+\alpha_{n})\frac{n}{2\\}\\ S=(8+12)\frac{5}{2}\\ S=(20)2.5\\ S=50[/tex]

So the sum of the first five consecutive numbers is 50. Since there are 5 numbers, you do 50÷5=10. Therefore, the answer is 10.

Answer & Step-by-step explanation:

We will only get a tornado if there is already a thunderstorm materializing

0.80 * 0.14 = 0.112

Probability of a tornado = 11.2%

There is a 100 - 14 = 86% chance of a tornado not being produced.

0.80 * 0.86 = 0.688

Probability of a storm and no tornado = 68.8%

Answer:

$9.04 /gal

Step-by-step explanation:

1 gallon = 128 oz

8 * 4.23 oz = 33.84 oz

$2.39 /33.84 oz = .0707 $/oz

 .0707 $/oz * 128 = $9.04 $/gal

Answer:

Through any three collinear points, there is exactly one plane.False [ i.e. non collinear points]

A segment is part of a line between two points on the line called the endpoints.False[I.e. mid point]

If there is a line and a point not on the line, then there exists exactly one line through the point

that is parallel to the given line.True

The midpoint of a segment is equidistant from the endpoints.True

If two angles are supplementary to the same angle, then the angles must be obtuse.True

If two angles form a linear pair, then the angles are complementary.False [I.e. supplementary]

Answer:

Below.

Step-by-step explanation:

The second term should be positive.

The last term should be -1 1/2 not -1 1/4.

He did not correctly multiply -8 and -2.

Answer:

b,c,d

Step-by-step explanation:

(.*_*)hope this helps(- _-.)

Answer: 0. 92 = 92%

100% = 500

92% = 500 × 92/100 = 460

Step-by-step explanation:

Answer:

Step-by-step explanation:

There are a couple of ways you could solve this problem. B is one of them.

The correct answer is going to be Small hypotenuse / Large hypotenuse = tree / building height

Let the tree equal x

100/220 = x / 176           Multiply both sides by 176

100 * 176 / 220 = x

x = 80

Notice that 80 is almost 1/2 of 176 so the answer should be right since 100 is nearly 1/2 of 220

Given:

The slope of a line is [tex]-\dfrac{3}{4}[/tex].

To find:

The lines in the options are parallel, perpendicular or neither parallel nor perpendicular to the given line.

Solution:

We know that the slopes of parallel lines are equal.

The slope of line Q and the slope of given line are same, i.e., [tex]-\dfrac{3}{4}[/tex]. So, the line Q is parallel to the given line.

The slope of a perpendicular line is the opposite reciprocal of the slope of the line because the product of slopes of two perpendicular lines is -1.

The slope of a line is [tex]-\dfrac{3}{4}[/tex]. It means the slope of the perpendicular line must be [tex]\dfrac{4}{3}[/tex]. So, the line N is perpendicular to the given line.

The slopes of line M and P are neither equal to the slope of the given line nor opposite reciprocal of the slope of the line.

Therefore, the lines M and P are neither parallel nor perpendicular.

Answer:

I am not sure.

Step-by-step explanation:

I've never been to summer school so- :/