The highest temperature is 8.3, in which we call the max.
The lowest temperature is -8.2, which is the min.
Subtract those values to get the range.
Range = max - min = 8.3 - (-8.2) = 8.3 + 8.2 = 16.5
Answer: 16.5 degrees CelsiusWhat is the constant of proportionality in the equation x 2
—- = ——
Y 9
Answer:
The Constant is 9/2
what value of x is in the solution set of -5-15>10+20x
Answer:
-3/2 >x
Step-by-step explanation:
-5-15>10+20x
Combine like terms
-20 > 10 +20x
Subtract 20 from each side
-20 -10 > 10+20x-10
-30> 20x
Divide by 20
-30/20 >20x/20
-3/2 >x
Answer:
-3/2 > x
Step-by-step explanation:
-5 - 15 > 10 + 20x
^ ^
-20
-20 > 10 + 20x
-10 -10
---------------------
-30 > 20x
----- -------
20 20
-3/2 > x
Hope this helped.
find the angle measures given the figure is a rhombus.
Answer:
92
Step-by-step explanation:
180-88
Olivia is fixing her bicycle. She starts fixing it at 9:34 am and finishes at 1 pm. How much
time did she spend fixing her bicycle?
Answer:
3 hours 26 minutes
Step-by-step explanation:
26 minutes(9.34am to 10am)+3 hours(10am to 1pm)=3 hours 26 minutes
The total time that she spend fixing her bicycle is 3 hr 26 minutes
Calculating total timeGiven the following parameters
Time that Olivia starts fixing bicycle= 9:34 am
Time she finishes = 1pm
The total number of hours spent from 9:34am and 12:34pm is 3 hrs. The remaining minutes to 1 pm is 26 minutes.
Hence the total time that she spend fixing her bicycle is 3 hr 26 minutes
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One of the legs of a right triangle measures 12 cm and its hypotenuse measures 20
cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
cm
Submit Answer
attempt 1 out of 2
PLS HELP
Answer:
16
Step-by-step explanation:
First use the Pythagorean theorem a^2+b^2=c^2.
12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.
Step-by-step explanation:
using pythogoras theory
hyp^2=opp^2+adj^2
you have been given the hyp and the opp so lets make the unknown x
20^2=12^2+x^2
400 =144+x^2
make x the subject of the formula
400-144=x^2
266=x^2
x=the square root of 266
The scores of James in his math test are 75, 78, 89, and 71. What score on the next test will make James’ average at least 80 ?
x > 87
x > 87
x < 87
x < 87
Answer: x ≥ 87
Step-by-step explanation:
Set the minimum score on the next test as x & calculate it:
[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]
So they need at least a score of 87 for the average to be 80+.
Answer:
x ≥ 87
Step-by-step explanation:
take a square of arbitary measure assuming its area is one square unit.divide it in to four equal parts and shade one of them.again take one shaded part of that square and shade one fourth of it.repeat the same process continuously and find the sum area of shaded region
Answer:
In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]
The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3
Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).
The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.
Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
Summation formula for geometric progressionThe formula to find the sum of infinite geometric progression is
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
Given
S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]
Using geometric progression
S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]
Using summation formula for geometric progression
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]
= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]
[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0
S = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
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Find m so that the equation msin²x+cos²x=m-1 has a solution on the interval (0;π/4)
msin²x+cos²x=m-1
since the interval are 0 and π/4
Therefore
msin²(0)+cos²(0)=m-1
m(0)+1=m-1
1=m-1
m=2
use π/4 now
msin²(π/4)+cos²(π/4)=m-1
m(1/2)+(1/2)=m-1
m+1=2(m-1)
m+1=2m-2
-m=-3
m=3
Therefore
m=2 or 3
(84)/(12)+(5-7)^(2)-72-6x2
Answer:
[tex]-73[/tex]
Step-by-step explanation:
Note: My explanation is based of the order-of-operations
First, using the order-of-operations, we evaluate the expressions in parentheses. Fully simplifying [tex](5-7)^2[/tex] gives us: [tex](5-7)^2 = -2^2 = 4[/tex].
Next, we do [tex]6\cdot2[/tex] giving us [tex]12[/tex]. So far, our expression is simplified to [tex]\frac{84}{12} + 4 - 72 - 12[/tex].
We also know that [tex]\frac{84}{12}[/tex] is just [tex]7[/tex] so we can replace that value in the expression leaving us with: [tex]7+4-72-12[/tex]. Now, we can solve it in simple steps!
1) [tex]7+4=11[/tex]
3) [tex]11-72=-61[/tex]
4) [tex]-61-12=-73[/tex]
Our answer is [tex]-73[/tex]
Hopefully this helped you out! Please (please) tell me if their is a mistake in the solution and I will correct it as fast as possible for me.
What is the measure of m?
5
15
E
n
m = [?]
====================================================
Explanation:
The two smaller triangles are proportional, which lets us set up this equation
5/n = n/15
Cross multiplying leads to
5*15 = n*n
n^2 = 75
----------
Apply the pythagorean theorem on the smaller triangle on top, or on the right.
a^2+b^2 = c^2
5^2+n^2 = m^2
25+75 = m^2
100 = m^2
m^2 = 100
m = sqrt(100)
m = 10
The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value of a population?
To obtain an estimate of a parameter of a population, we use confidence intervals.
Confidence intervals:
The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.
Thus, you should select the highest sample size in the options.
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Which inequality is represented by this graph?
OA. y<-1/5x+1
OB. y>= -1/5x+1
OC. y<= -1/5x+
OD. y>-1/5x+1
Answer:
Option A is correct
Step-by-step explanation:
Hope it is helpful....
Marla noticed that her friend Ron had three times as many pieces of candy as she did. She told him, "If you give me seven pieces of your candy, we'll have exactly the same number of pieces." Ron responded, "I didn't know that until you mentioned it. But I'll make you a deal: If you can show me how to solve this puzzle using algebra, I'll give you the seven pieces. "One minute later, Ron was shocked to see that Marla had solved it perfectly. Can you do the same?
Answer:
This question seems to be asking for the work, so I put it below.
Anyhow, Marla had 3.5 candies, and Ron had 10.5.
Step-by-step explanation:
x = 3x - 7 (lets set this as "a") { a = 3x - 7}
x + 7 = 3x -7 + 7
x + 7 = 3x
( x + 7 ) / 3 = 3/3x
( x + 7 ) / 3 = x = *(same as "a") {a}
( x + 7 ) / 3 = 3x - 7
( x + 7 ) / 3 * 3 = ( 3x - 7 ) * 3
x + 7 = 9x - 21
x - x + 7 = 9x - x - 21
7 = 8x - 21
7 + 21 = 8x - 21 + 21
28 = 8x
28 / 8 = 8/8x
3.5 = x
We can plug this back into the original equation and find that it is correct because:
x = 3x - 7
x = 3.5 =====
3.5 = 3( 3.5 ) - 7
3.5 = 10.5 - 7
3.5 = 3.5
Answer:
Marla has 7 and Ron has 21
Step-by-step explanation:
lets take
no. of candies Marla has as "x"
and no. of candies Ron has will be "3x"
Marla says if Ron gives her seven candies, they will have the same no. of candies
so your equation will be -
x + 7 = 3x - 7 (as Marla gets the candy, Ron loses the candy)
3x - x = 7 + 7
2x = 14
∴x = 7
and 3x = 3 x 7 = 21
YOUR WELCOME
find the radius of a circle for which an arc 6 cm long subtends an angle of 1/3 radians at the center?
plz some one can help to solve the question??
Step-by-step explanation:
Eueydhhdgdgdbdbddbdbhd
Answer:
Hello,
[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]
Step-by-step explanation:
[tex]Formula: \ L=\theta*R\\[/tex]
[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]
A girl bought x kg of green apples and 3 kg of red apples. What was the total mass of all the apples she bought
Answer:
Total = x+3 kg
Step-by-step explanation:
Green apples = x kg, Red apples = 3 kg
f(x) = 2x + 7 with domain: x = {2, 3, 5, 9}
Answer:
2(2)+7=11
2(3)+7=13
2(4)+7=15
2(5)+7=17
2(9)+7=25
Step-by-step explanation:
2(2)+7
4+7=11
2(3)+7
6+7=13
2(4)+7
8+7=15
2(5)+7
10+7=17
2(9)+7
18+7=25
divide 12by8 and 4by3
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto PN
Answer:
Step-by-step explanation:
Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB
=> MP là đường trung bình của tam giác DAB => MP//BD và MP=[tex]\frac{1}{2}[/tex]BD (1)
Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC
=> QN là đường trung bình của tam giác DBC => QN//BD và QN=[tex]\frac{1}{2}[/tex]BD (2)
Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN
và độ dài MP = độ dài QN = [tex]\frac{1}{2}[/tex]BD
=> vecto MP = vecto QN
Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN
evaluate the expression. check all possible sets that the solution may belong in. 40-5^2
Answer:
15
Step-by-step explanation:
following PEMDAS, we don't have () so we move on to exponents
5^2 is equal to 5 x 5 which is 25
40-25=15
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{40 - 5}\mathsf{^2}\\\\\\\large\textsf{5}\mathsf{^2}\\\large\textsf{= 5}\times\large\textsf{5}\\\large\textsf{= \bf 25}\\\\\\\large\textsf{= 40 - 25}\\\\\\\large\textsf{= \bf 15}\\\\\\\\\\\\\boxed{\boxed{\huge\textsf{Therefore your answer is: \bf 15}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\textsf{Amphitrite1040:)}[/tex]
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
lvan earned $8 each time he walks his neighbor's dog. he already walked the dog 5 times.
How many more times does her need to walk the dog to earn enough money to buy a game that costs $88
__? more times
Help please and thank you
Answer:
x = y² - 7
Step-by-step explanation:
the inverse function is simply an exchange of x and y (and then the simplification happens to transform the whole expression back into a form y = ....)
(Picture) Could someone help me solve this I need to use Inverse Operations but I don't fully understand? I'll mark brainliest, 10 Points.
Answer:
[tex]x = - 8[/tex]
Step-by-step explanation:
First,Step write the given equation.
[tex] \frac{x}{2} + 7 = 3[/tex]
In Algebra, we learn how to solve for a missing term called a variable. We must use inverse operations to undo terms to isolate our variable. Inverse operations means that we do the opposite of the given.
Opposite of Addition is Subtraction, vice versa.Opposite of Multipication is Division, vice versa.For example, say we have a equation
[tex]x + 2 = 3[/tex]
We would subtract 2 from both sides. E.g( remember the golden rule of algebra). What we do to one side, we do the other. This applies when we solving for a variable.
This means that
[tex]x = 1[/tex]
And if we substitute 1 in for x, it is indeed true.
[tex]1 + 2 = 3 = 3[/tex]
Now, back to the question.
[tex] \frac{x}{2} + 7 = 3[/tex]
First, we subtract 7 from both sides to get rid of the 7 on the left side. Also remeber to undo terms that aren't included in the variable when solving these problems.
So now we got
[tex] \frac{x}{2} = - 4[/tex]
Then we multiply 2 by both sides since that the opposite of division.
[tex] \frac{x}{2} \times 2 = x = -4 \times 2 = - 8[/tex]
So this means that
[tex]x = - 8[/tex]
If we plug this in, this is true.
[tex] \frac{ - 8}{2} + 7 = 3[/tex]
what does the rational form of the ratio a:b look like
Answer:
a/b
Step-by-step explanation:
The rational form of a:b or simply a/b is in the simplest form.
Answer:
Step-by-step explanation:
the answer is option 2 from the above sheet
what is the equation in slope intercept form 3 y - 9= 12x please help fast
Answer:
Step-by-step explanation:
Slope intercept form is y = mx + b where m is the slope and b is the y intercept SO
y = mx + b
3y - 9 = 12x
3y = 12x + 9 (divide by common denominator 3)
y = 4x + 3
The lengths of the sides of a triangle are 3, 3, 312. Can the tangle be a right triangle?
Answer:
Yes it can be right angle triangle
Find the length of each side and the
perimeter.
(5n -17) cm
(2n + 1) cm
n cm
7n-16
Step-by-step explanation:
Sry can u give me the picture
The amount of money lana earns for tutoring is proportional to the time she spends tutoring. She earns $24 for tutoring 1 1/2 hours. what is the constant of proportionality for the relationship between dollars earned and number of hours?
Answer:
y=16x
Step-by-step explanation:
24=1 1/2x=3/2x
x=24*(2/3)=16
y= total money earned; x=number of hours worked
tan30°+cos30°÷tan30°×cos30°
Answer:
{1/√3+1/2} ÷{1/√3× 1/2}
(2+√3)/2√3÷(1/2√3)2+√3+1 /2√3(2+1 )+√3 /2√33 +√3 /2√3can someone pls help w finding the x and y intercepts of this?
y=x^2-2x
Answer:
y-intercept is 0, x-intercept is 0 and 1
Step-by-step explanation:
For y-intercept, x=0 :
[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]
For x-intercept, y=0 :
[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]
