Write and equation for a line that is parallel to the line 4y + 3x = 12

Answer:

A) 20+3m = 5m

Step-by-step explanation:

20+3m = 5m

20 = 2m

m = 10

after each girl has walked dogs for 10 miles, their amount they charge would be equal

Tonya would charge: 20+3(10) = 20+30 or $50

Beth would charge: 5(10) or $50

Answer:

6 seconds after launch.

Step-by-step explanation:

You should make sure  there aren't odd symbols in your question when you post it.

Assuming it is just the equation -5x^2 + 20x + 60, if you graph it you can see the path of the ball.  at x=0 this is the starting point It then hits the ground when it touches the x axis.  So this is finding zeroes of a quadratic.

You could do this several ways; find a way to factor it, guess and check, the quadratic formula or completing the square.  I will complete the square as that is what I am most used to.  If you would like to see another let me know.

The first step in completing the square is making sure the x^2 has a coefficient of 1, so now it has -5 so we have to factor out -5 from the equation.

-5x^2+20x+60 = -5(x^2 - 4x - 12)

Now you only really need to focus on the factored expression, but I will continue writing everything.  The next step is to find (b/2)^2 where b is the coefficient of the x term.  In this case -4.  so (b/2)^2 = (-4/2)^2 = 4.

Again, focusing on x^2 - 4x - 12 you want to add and subtract (b/2)^2 from that expression.  since you are adding and subtracting you are not changing the value, but we can use this.

-5(x^2 - 4x - 12) = -5(x^2 - 4x - 12 + 4 - 4)

Here you want to rearrange it a bit.  Originally c was the constant term, -12, now you want it to be the positive (b/2)^2, which is positive 4. also you can combine the two other constant terms.  the original c and -(b/2)^2, but I will hold off for now so I don't do too much at once.

-5(x^2 - 4x - 12 + 4 - 4) = -5(x^2 - 4x + 4 - 12 - 4)

Now you focus on x^2 - 4x + 4.  Hope fully you recognize this is the same as (x-2)^2.  This always happens at this step of the process.  also notice -2 = b/2.  Using only variables here are the first steps.

ax^2 + bx + c

a(x^2 + (b/a)x + (c/a))

a(x^2 + (b/a)x + (c/a) + (b/(2a))^2 - (b/(2a)^2)

a(x^2 + (b/a)x + (b/(2a))^2 + (c/a) - (b/(2a))^2)

a((x + b/(2a))^2 + (c/a) - (b/(2a))^2)

Again, being able to make x^2 - 4x + 4 into (x-2)^2 or x^2 + (b/a)x + (b/(2a))^2 into (x + b/(2a))^2 willa lways happen.  this is because if you expand (x + b/(2a))^2 you always get x^2 + (b/a)x + (b/(2a))^2.

Now I would combine the -12-4

-5(x^2 - 4x + 4 - 12 - 4) = -5((x - 2)^2 - 12 - 4) = -5((x - 2)^2 - 16)

If you redistribute the -5 you get vertex form, but I am going to stop here  because I will just undo that in the next step.  So this is the form you want.  Finally we can find when it equals 0.  So, you set this equal to 0 and use algebra to solve.

-5((x - 2)^2 - 16) = 0

Divide both sides by -5

(x-2)^2 - 16 = 0

add 16 to both sides

(x-2)^2 = 16

Take the square root of both sides, but also count botht he positive and negative version of the answer.  the reason is both 2 and -2 squared get you 4.

x - 2 = +/-4

I am using +/- to indicate I am using both positive and negative 4.  Now though add 2 to both sides.  since you have +/- 4 you are going to get two different results.  -4+2 and 4+2

x = -2 and 6.

now, the question wants times after x=0 (the start) so you only get 6.  so x=6, or in other words 6 seconds after launch.

Let me know if you have any questions.

Answer:

6

Step-by-step explanation:

sorry no step by step explanation because I’m in a rush please mark me as brainliest bye have a great day !!! :D

Answer:

[tex]{ \tt{ - \frac{3}{8} + \frac{1}{6} }} \\ { \bf{l.c.m \: of \: 8 \: and \: 6 = 24}} \\ { \tt{formular = \frac{(l.c.m \times denominator \div numerator)}{l.c.m} }} \ \\ \\ = \frac{(24 \times 8 \div - 3) + (24 \times6 \div 1)}{24} \\ = - \frac{5}{24} [/tex]

Answer:

a = 32

b= 27

c = 9

Step-by-step explanation:

a= 5+ b from the second equation

c= b/3 from the third equation

substitute the above equations to the first equation then solve for b your answer will be 27

substitute the value of b in the second equation you will solve for a

perform the same substitution to the third equation you will get the answer for c

Step-by-step explanation:

a-b=5<=>a=5+b (1)

b:c=3<=>b=3c (2)

a+b+c=68<=>5+b+3c+c=68<=>5+3c+3c+c=68

<=>7c=63<=>c=9

Fill in (2), we have b=3c=3.9=27

and in (1), we have a=5+b=5+27=32

So, a=32, b=27, c=9

Answer:

22.09

Step-by-step explanation:

Given the expression ln(x-2)^2=6

Take exponent of both sides

e^ln(x-2)^2=e^6

(x-2)² = e^6

(x-2)² = 403.43

x - 2 = √403.43

x - 2= 20.09

x = 20.09 + 2

x = 22.09

Hence the value of x is 22.09

Answer:

13π m

Step-by-step explanation:

circumference of a circle = 2πr

=2*π*6.5

=13π m

Answer:

13[tex]\pi[/tex] m

Step-by-step explanation:

The formula for circumference is 2r[tex]\pi[/tex], so...

2r[tex]\pi[/tex]

2(6.5)[tex]\pi[/tex]

=13[tex]\pi[/tex]

Answer:

3 meters

Step-by-step explanation:

Assuming the window is rectangular

A = l*h

18 = 6*h

Divide each side by 6

18/6 = 6h/6

3 = h

Answer:

Luca

Step-by-step explanation:

Juan 566/734 = 0.7711

Luca 7/9= 0.7777

Luca has a greater percentage

Answer:

[tex]g = 18p[/tex] --- A

[tex]g = 10p[/tex] ---- B

Step-by-step explanation:

Given

[tex]Package\ A: 18\ soda[/tex]

[tex]Package\ B: 10\ soda[/tex]

Required

The equation of both packages

The given details represent the number of sodas in each package.

So, the equation of A is:

[tex]g = 18p[/tex]

And the equation of B is:

[tex]g = 10p[/tex]

Answer:

Max

Step-by-step explanation:

the function given that h = -16t³+64t+10

the general function Equation:

h = at²+bt+c

=> t at the highest point is defined by t = -b/2a

= -64/2(-16) = -64/-32 = 2 second

the total times that the ball hits the ground

= 2× 2 seconds = 4 seconds.

so, Max is right

Answer:

Solution given:

Let h=0=when the ball hit the ground,the height=0.

h= -16t^2 + 64t + 10.

0=16t²-64t-10

8t²-32t-5=0

∆=[tex] \frac{32±\sqrt{32²+4*5*8}}{2*8}=\frac{8±\sqrt{74}}{4}[/tex]

taking positive

t1=[tex] \frac{8+\sqrt{74}}{4}=4.15seconds[/tex]

t2=[tex] \frac{8-\sqrt{74}}{4}(t2<O)(neglected)[/tex]

So

t=4.15seconds closer to 4seconds.So

Max is closer.

It is 34.90

Step-by-step explanation:

Your welcome!

Answer: y = 1/4x - 1.

Step-by-step explanation: This line has a slope (rise over run) of 1/4, and a y-intercept of -1. Plugging those values into slope-intercept form (y = mx + b) gives you the answer.

Answer:

volume=1243.44 cm^3

Step-by-step explanation:

volume of a cone=πr^2h

=3.14*(6)^2*111

=3.14*36*11

=1243.44 cm^3

Answer:

V=414.69cm³

Step-by-step explanation:

use v=πr²h/3

pie is 22/7 so when you fix in your values you will get the answer

Sara's results probably do have a higher mean, if we take into account how William is way more willing to pay 20 dollars. Honestly, I think you got your chosen answers right! Just my opinion, as someone inexperienced.

Given:

Kiosk is the combination of a cylinder and a cone.

Diameter of cylinder and cone = 5 m

Height of the cylinder = 3 m

Height of the cone = 2 m

To find:

The volume of the kiosk.

Solution:

We know that the radius is half of the diameter. So,

Radius of cylinder and cone = [tex]\dfrac{5}{2}[/tex] m

                                               = [tex]2.5[/tex] m

Volume of the cylinder is:

[tex]V_1=\pi r^2h[/tex]

Where, r is the radius and h is the height of the cylinder.

Putting [tex]\pi =3.14, r=2.5, h=3[/tex] in the above formula, we get

[tex]V_1=(3.14)(2.5)^2(3)[/tex]

[tex]V_1=(3.14)(6.25)(3)[/tex]

[tex]V_1=58.875[/tex]

Volume of a cone is:

[tex]V_2=\dfrac{1}{3}\pi r^2h[/tex]

Where, r is the radius and h is the height of the cone.

Putting [tex]\pi =3.14, r=2.5, h=2[/tex] in the above formula, we get

[tex]V_2=\dfrac{1}{3}(3.14)(2.5)^2(2)[/tex]

[tex]V_2=\dfrac{1}{3}(3.14)(6.25)(2)[/tex]

[tex]V_2\approx 13.083[/tex]

The volume of the kiosk is the sum of volume of cylinder and the volume of cone.

[tex]V=V_1+V_2[/tex]

[tex]V=58.875+13.083[/tex]

[tex]V=71.958[/tex]

[tex]V\approx 72[/tex]

Therefore, the volume of the kiosk is 72 cubic meter.

Answer:

Te diagonal of a kite will form a parallelogram.

explanation:

Kite properties include (1) two pairs of consecutive, congruent sides, (2) congruent non-vertex angles and (3) perpendicular diagonals. Other important polygon properties to be familiar with include trapezoid properties, parallelogram properties, rhombus properties, and rectangle and square properties.

hope it helps

Mark me as brainlist

Answer:

[tex]y=-3(x-5)^2+4[/tex]

Step-by-step explanation:

Hi there!

Given the vertex of a parabola and a point, it's easiest to organize the equation in vertex form:

[tex]y=a(x-h)^2+k[/tex] where the vertex is located at [tex](h,k)[/tex] and a is a numerical value

1) Plug the vertex into the equation

[tex]y=a(x-h)^2+k[/tex]

Plug in the vertex (5,4)

[tex]y=a(x-5)^2+4[/tex]

2) Solve for a

[tex]y=a(x-5)^2+4[/tex]

Plug in the given point (3,-8) and solve for a

[tex]-8=a(3-5)^2+4\\-8=a(-2)^2+4\\-8=4a+4[/tex]

Subtract 4 from both sides

[tex]-8-4=4a+4-4\\-12=4a[/tex]

Divide both sides by 4

[tex]\frac{-12}{4} = \frac{4a}{4} \\-3=a[/tex]

Therefore, a=-3. Plug this back into [tex]y=a(x-5)^2+4[/tex]:

[tex]y=-3(x-5)^2+4[/tex]

I hope this helps!

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  [tex]\dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)[/tex]

_____

Additional comment

I find it easy to remember the rules of exponents by remembering that an exponent signifies repeated multiplication. It tells you how many times the base is a factor in the product.

  [tex]2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}[/tex]

Multiplication increases the number of times the base is a factor.

  [tex](2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5[/tex]

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  [tex]\dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1[/tex]

Answer:

the answer is 55

Step-by-step explanation:

if you have a straight line each side equals 180 degrees so take 60+65 which equals 125 then do 180-125 and you get 55

Answer:

y = 2*x + 4

Step-by-step explanation:

We know that a linear function can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

We know that if this line passes through the points (x₁, y₁) and (x₂, y₂) the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

So, here we know that our line must pass through the points (-2,0) and (0, 4)

Then the slope of this line is:

a = (4 - 0)/(0 - (-2))

a = 4/2 = 2

Then our line is something like:

y = 2*x + b

Now, to find the value of b we can use one of these two points, for example if we use the point (-2, 0), we know that, when x = -2, we must have y = 0.

0 = 2*(-2) + b

0 = -4 + b

4 = b

Then the equation for our line is:

y = 2*x + 4

Answer:

The median is $42, or B.

Step-by-step explanation:

Our numbers are :

42, 51, 38, 49, and 40.

The first step to finding the median is ordering the numbers from least to greatest.

38, 40, 42, 49, 51.

Now we find the number perfectly in the middle - that's 42, between 49 and 40. The median is $42, or B.

Please mark brainliest!

Answer:

45ml

Step-by-step explanation:

10 kg needs 18mL

So, 1kg = 1.8ml

25kg needs = 1.8kg/ml x 25 kg

25 kg dog would need 45ml.

Answer:

45 ml

Step-by-step explanation:

Weight of the dog and quantity of medicine is in Direct proportion.

Let the quantity required for 25 Kg dog =x

10 : 18 :: 25 : x

Product of extremes = product of means

10 * x = 18 * 25

[tex]x = \frac{18 * 25}{10}\\\\x = 9 * 5 \\\\x = 45[/tex]

Answer:

D.

is the correct answer

Answer:

x<=-3

Step-by-step explanation:

2x-5/x-2 <= 1

Multiply both sides by x-2

2x-5<=x-2 (anything times 1 is that number.)

add 5 to both sides

2x<=x-3

subtract x from both sides

x<=-3

Answer:

Step-by-step explanation:

[tex]\frac{2x-5}{x-2} \leq 1\\case ~1. both ~numerator~and~denominator \geq 0\\x\neq 2\\2x-5\leq x-2\\x\leq 3\\so~0\leq x<2U2<x\leq 3\\case~2.\\both~numerator~and~denominator<0\\2x-5\geq x-2\\x>3\\which~is~rejected~as~it~gives~both~2x-5~and ~x-2>0[/tex]