Can anyone please help me out?

The width of the actual garden patio according to the scale drawing is 14 meters.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the scale of 1 cm : 2 m

For a patio of 7 cm, then:

Actual patio = 7 cm / (1 cm/ 2m) = 14 m

The width of the actual garden patio according to the scale drawing is 14 meters.

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Answer:

C. 11x² - 3x

Step-by-step explanation:

(12x² - 5x) - (x² - 2x)

12x² - 5x - x² + 2x

12x - x² - 5x + 2x

11x² - 3x

Answer:

a = -6

b = 1

Step-by-step explanation:

The gradient of the tangent to the curve y = ax + bx^3, will be:

dy/dx = a + 3bx²

at (2, -4)

dy/dx = a+3b(2)²

dy/dx = a+12b

Since the gradient at the point is 6, then;

a+12b = 6 ....1

Substitute x = 2 and  y = -4 into the original expression

-4 = 2a + 8b

a + 4b = -2 ...2

a+12b = 6 ....1

Subtract

4b - 12b = -2-6

-8b = -8

b = -8/-8

b = 1

Substitute b = 1 into equation 1

Recall from 1 that a+12b = 6

a+12(1) = 6

a = 6 - 12

a = -6

Hence a = -6, b = 1

Answer:

A) quadratic

Step-by-step explanation:

ax2 + bx+c=0

Since the highest power of the equation is 2

A) quadratic -2

B) quartic- 4

C) linear- 1

D) cubic-3

Answer:

15/16 (93.75%)

Step-by-step explanation:

List of Possible Combinations:

BBBB, BBBG, BBGB, BBGG, BGBB, BGBG, BGGB, BGGG, GBBB, GBBG, GBGB, GBGG, GGBB, GGBG, GGGB, GGGG

As you can see, only 1 out of 16 of the possible combinations is all boys. This means that the chance of at least 1 girl among the 4 children is 15 out of 16 (15/16) or 93.75%

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]

Step-by-step explanation:

You didn't put the graph, but you can compare between your graphs and the picture.

Brainliest please

The graph that represents this inequality y ≥ 4x − 3 is attached below.

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.

We are given that the inequality is;

y ≥ 4x − 3

The slope of the inequality is 4.

The equation of the red line is y = 4x − 3  

The shading is above the line and the line is solid, that means  y is greater than or equal 4x − 3

The graph of this inequality y ≥ 4x − 3 is attached below.

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Answer:

the number before the first variable (first term)

Step-by-step explanation:

this appears to be an incomplete question. The numerical coefficient of a term is the number before the variable.

the constant is the number without a variable.

In an arithmetic sequence, every pair of consecutive terms differs by a fixed number c, so that the n-th term [tex]a_n[/tex] is given recursively by

[tex]a_n=a_{n-1}+c[/tex]

Then for n ≥ 2, we have

[tex]a_2=a_1+c[/tex]

[tex]a_3=a_2+c = (a_1+c)+c = a_1 + 2c[/tex]

[tex]a_4=a_3+c = (a_1 + 2c) + c = a_1 + 3c[/tex]

and so on, up to

[tex]a_n=a_1+(n-1)c[/tex]

Given that [tex]a_3=126[/tex] and [tex]a_{64}=3725[/tex], we can solve for [tex]a_1[/tex]:

[tex]\begin{cases}a_1+2c=126\\a_1+63c=3725\end{cases}[/tex]

[tex]\implies(a_1+63c)-(a_1+2c)=3725-126[/tex]

[tex]\implies 61c = 3599[/tex]

[tex]\implies c=59[/tex]

[tex]\implies a_1+2\times59=126[/tex]

[tex]\implies a_1+118 = 126[/tex]

[tex]\implies \boxed{a_1=8}[/tex]

Answer:

a1 = 24

an = an-1 × 1/2, n >1

Step-by-step explanation:

a geometric sequence is a sequence where we multiply every previous term by a certain factor to create the next term.

so, we multiply 24 by something to get 12.

and then 12 by the same something to get 6.

and then 6 by the and something to get 3.

do you see the pattern ? hmmm ?

right, we always divide by 2 (or multiply by 1/2).

the starting value a1 = 24

so,

an = an-1 × 1/2, n>1

or

[tex]an = a1 \times {(1 \div 2)}^{n - 1} [/tex]

n>1

Answer:

option D (5 6 8 9) is the answer

Answer:

X [tex]\Longrightarrow -8\Longrightarrow -1\Longrightarrow 1\Longrightarrow 8[/tex]

Y[tex]\Longrightarrow 5\Longrightarrow 6\Longrightarrow 8\Longrightarrow 9[/tex]

[tex]Answer\hookrightarrow D)[/tex]

-------------------------

Hope it helps...

Have a great day!!

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Answer: 80

Step-by-step explanation:

Answer:

the measurement of N is D, 81.

Step-by-step explanation:

The angle measurement of a Right Angled Triangle is 90 degrees. And based off the angle dimension given in the image above ( 9 degrees ), you need to subtract 90 ( the angle dimension of the triangle) with the angle dimension given (9 degrees) which gets you to an answer of 81 degrees.

Answer:

D represents a proportional relationship

Step-by-step explanation:

Proportional graphs always intersect with zero

Answer:

-2,2

Step-by-step explanation:

Let

[tex]y_1=4x^2-c^2[/tex]

[tex]y_2=c^2-4x^2[/tex]

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

[tex]y_1=y_2[/tex]

[tex]4x^2-c^2=c^2-4x^2[/tex]

[tex]4x^2+4x^2=c^2+c^2[/tex]

[tex]8x^2=2c^2[/tex]

[tex]x^2=c^2/4[/tex]

[tex]x=\pm \frac{c}{2}[/tex]

Now, the area bounded by two curves

[tex]A=\int_{a}^{b}(y_2-y_1)dx[/tex]

[tex]A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx[/tex]

[tex]\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx[/tex]

[tex]\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx[/tex]

[tex]\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}[/tex]

[tex]\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{c^3}{3})[/tex]

[tex]\frac{32}{3}=2(\frac{2}{3}c^3)[/tex]

[tex]c^3=\frac{32\times 3}{4\times 3}[/tex]

[tex]c^3=8[/tex]

[tex]c=\sqrt[3]{8}=2[/tex]

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

9514 1404 393

Answer:

Step-by-step explanation:

a) For payments made at the beginning of the period, the annuity is called an "annuity due." The formula in the first attachment tells how to compute the payment for a given present value ($500,000), number of periods (N=10), and interest rate (i=0.08).

  pmt = $500,000/(1 +(1 -(1 +i)^(-N+1))/i) = $500,000/(1 +(1 -(1.08^-9))/.08)

  pmt ≈ $68,995.13 . . . . annual payment

__

b) After the first payment, the account balance is ...

  $500,000 -68,995.13 = $431,004.87

After subsequent payments, the account balance will be ...

  $431,004.87×1.08 -68,995.13 = $396,490.13 . . . after 2nd payment

  $396,490.13×1.08 -68,995.13 = $359,214.21 . . . after 3rd payment

The payment amount that can be made in perpetuity is the amount of the monthly interest on this balance:

  X = $359,214.21 × (0.08/12) = $2394.76

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

3000

growth

2.2%

Step-by-step explanation:

Answer:

Step-by-step explanation:

Combination of 4 out of 5 + 7 = 12 is:

Combination of 1 man and 3 women is:

Required probability:

Correct choice is B

Answer:

The rate of change of f(x) is faster than the rate of change of g(x).

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

*Note:

Rate of Change is determined by slope.

Step 1: Define

f(x) = 3x + 5

↓ Compare to y = mx + b

Slope m = 3

g(x) = 2x + 5

↓ Compare to y = mx + b

Slope m = 2

Step 2: Answer

We can see that the slope of f(x) is greater than g(x).

∴ the rate of change of f(x) would be greater than g(x).

Step-by-step explanation:

here's the answer to your question

Answer: Distance = 11

Step-by-step explanation:

Concept:

Here, we need to know the idea of the distance formula.

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

Solve:

Find the distance between A and B, where:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]Distance=\sqrt{(4+7)^2+(-4+4)^2}[/tex]

[tex]Distance=\sqrt{(11)^2+(0)^2}[/tex]

[tex]Distance=\sqrt{121+0}[/tex]

[tex]Distance=\sqrt{121}[/tex]

[tex]Distance=11[/tex]

Hope this helps!! :)

Please let me know if you have any questions

what? ;-;.............

Answer:

The solutions are w=0 ,7

Step-by-step explanation:

3w^2 – 21w = 0

Factor out 3w

3w(w-7) =0

Using the zero product property

3w=0  w-7=0

w =0    w=7

The solutions are w=0 ,7

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Answer:

52 is (a)

55 is.( d)

56. is (d)

Given:

The rational function is:

[tex]f(x)=\dfrac{5-x}{x^2+5x+6}[/tex]

To find:

The points on the graph at the function value [tex]f(x)=3[/tex].

Solution:

We have,

[tex]f(x)=\dfrac{5-x}{x^2+5x+6}[/tex]

Substituting [tex]f(x)=3[/tex], we get

[tex]3=\dfrac{5-x}{x^2+5x+6}[/tex]

[tex]3(x^2+5x+6)=5-x[/tex]

[tex]3x^2+15x+18=5-x[/tex]

Moving all the terms on one side, we get

[tex]3x^2+15x+18-5+x=0[/tex]

[tex]3x^2+16x+13=0[/tex]

Splitting the middle term, we get

[tex]3x^2+3x+13x+13=0[/tex]

[tex]3x(x+1)+13(x+1)=0[/tex]

[tex](3x+13)(x+1)=0[/tex]

Using zero product property, we get

[tex](3x+13)=0\text{ or }(x+1)=0[/tex]

[tex]x=-\dfrac{13}{3}\text{ or }x=-1[/tex]

Therefore, the required values are [tex]-\dfrac{13}{3},-1[/tex].