Can someone please help me with my maths question​

Step-by-step explanation:

what to find then??.........

Answer:

your slope would be 4.5.... so go up 4 and to the right 5. the y-intercept is 650 so that is where your line would start instead of at 0... hope this helped :)

Step-by-step explanation:

The exponential function gotten from the table is given by y = 650(1.045)ˣ

An exponential function is in the form:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multipliers.

Let y represent the bacteria population after x hours.

The class started out with 650 bacteria cells.

Growth rate = 4.5%

The exponential function gotten from the table is given by y = 650(1.045)ˣ

After 30 hours:

Find out more on exponential function at: https://brainly.com/question/12940982

Answer:

To find the leading coefficient, first expand the function:

[tex]y= -(x+3)^{2} -5\\\\y=-(x^{2} +6x+9)-5\\\\y=-x^{2} -6x-9-5\\\\y=-x^{2} -6x-14[/tex]

The leading coefficient is the coefficient of the highest-order term, which, in this case, would be the -1 from -x².

To find the vertex: see image below

Vertex = (-3, -5)

9514 1404 393

Answer:

  (a)  42.3°

Step-by-step explanation:

Side 'a' is the shortest of three unequal sides, so angle A will be the smallest angle in the triangle. Its measure can be found from the Law of Cosines.

  a² = b² +c² -2bc·cos(A)

  cos(A) = (b² +c² -a²)/(2bc) = (21² +25² -17²)/(2·21·25) = 777/1050

  A = arccos(777/1050) ≈ 42.3°

The measure of angle A is about 42.3°.

_____

Additional comment

The smallest angle in a triangle can never be greater than 60°. This lets you eliminate choices that exceed that value.

Answer:

 (a)  42.3°

Step-by-step explanation:

Answer:

B 0

Step-by-step explanation:

r is a horizontal line

horizontal lines are of the form y= constant

The slope for horizontal lines are 0

Parallel lines have the same slope.

Answer:

B 0

Step-by-step explanation:

the slope of a line is the rise divided by the run, or the Y increase divided by the X increase. the fact that the Y value does not increase makes the slope 0

Answer:

3−42+7+16

Step-by-step explanation:

if its simplify

Answer:

x = 10

Step-by-step explanation:

smaller triangle / bigger triangle = 20 / 28

hence,

3x / (4x+2) = 20/28

28(3x) = 20(4x+2)

84x = 80x + 40

4x = 40

x = 10

Answer:

y= 3x+8

Step-by-step explanation:

not a 100% sure...

sry if its wrong

(try using Math-way, its rly helpful)

Answer:

Step-by-step explanation:

y=mx+b

To find slope: -4+1/-4+3

Slope=3

y=3x+b

Plug in either points ,as an example, i'll plug in (-3,-1)

-1=3(-3)+b

-1=-9+b

8=b

Finished formula: y=3x+8

Answer:

900 is the correct awnser

Answer:

59.04°

58.31 inches

Step-by-step explanation:

The solution triangle is attached below :

Since we have a right angled triangle, we can apply trigonometry to obtain the angle ladder makes with the ground;

Let the angle = θ

Tanθ = opposite / Adjacent

Tanθ = 50/30

θ = tan^-1(50/30)

θ = 59.036°

θ = 59.04°

The length of ladder can be obtained using Pythagoras :

Length of ladder is the hypotenus :

Hence,

Hypotenus = √(adjacent² + opposite²)

Hypotenus = √(50² + 30²)

Hypotenus = √(2500 + 900)

Hypotenus = 58.309

Length of ladder = 58.31 inches

Answer:

59°

58.3 inches

Step-by-step explanation:

Here is the full question :

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground. The angle made by the ladder with the ground is degrees, and the length of the ladder is inches.

Please check the attached image for a diagram explaining this question

The angle the ladder makes with the ground is labelled x in the diagram

To find the value of x given the opposite and adjacent lengths, use tan

tan⁻¹ (opposite / adjacent)

tan⁻¹  (50 / 30)

tan⁻¹ 1.667

= 59°

the length of the ladder can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

√(50² + 30²)

√(2500 + 900)

√3400

= 58.3 inches

The options for the box and whisker plots aren't given ; however using technology, a box and whisker plot could be generated from the data.

Answer:

Step-by-step explanation:

Given :

45, 44, 47, 49, 45, 47, 42, 39, 45, 42, 44

Using technology, the box and whisker plot generated for the data is attached below.

The 5 - number summary is also given below :

Minimum: 39

Median: 45

First quartile: 42

Third quartile: 47

Interquartile Range: 5

Maximum: 49

Outliers: none

Answer:

Step-by-step explanation:

Answer:

[tex]{ \tt{1 \: mg = 1 \times {10}^{ - 3} \: g}} \\ { \tt{75 \: mg = (75 \times 1 \times {10}^{ - 3} ) \: g}} \\ { \bf{ = 75 \times 10 {}^{ - 3} \: grams}} \\ { \bf{ = 0.075 \: grams}}[/tex]

Answer:

[tex] ({a + b})^{2} [/tex]

[tex](a + b)(a + b)[/tex]

[tex] {a}^{2} + 2ab + {b}^{2} [/tex]

hope this help you

Answer: Circumference of circle = 27.004 inches

              Area of circle = 58.0586 inches²

Step-by-step explanation:

Diameter of circle = 8.6 inches

Pi ([tex]\pi[/tex]) = 3.14

Circumference of circle (With diameter) = [tex]\pi \\[/tex]d ([tex]\pi[/tex]×diameter)

                                                                = 3.14 × 8.6

                                                                = 27.004 inches

Area of circle (With diameter) = [tex]\pi[/tex][tex]d^{2}[/tex]/4

                                                 = 3.14 × 8.6 × 8.6 / 4

                                                 = 3.14 × 73.96 / 4

                                                 = 58.0586 inches²

Answer:

B

Step-by-step explanation:

half × base × height

height × length

Answer: B

Step-by-step explanation:

Triangle)

25 - 7 = 18

[tex]A=\frac{1}{2}(b)(h)\\A=\frac{1}{2}(18)(17)\\A=153cm^2[/tex]

Rectangle)

[tex]A=b(h)\\A=7(17) = 119cm^2[/tex]

Total)

[tex]153+119=272 cm^2[/tex]

Answer:

40 girls 20 boys i think / guess

Step-by-step explanation:

Answer:

20/40

Step-by-step explanation:

i hope it help

Step-by-step explanation:

From both the cases we can say that √n is either a natural number or an irrational number. Hence the correct option is (d)Either a natural number or an irrational number. Note: Before solving this type of question we should have proper knowledge of natural numbers, rational numbers and irrational numbers.

Answer:

D

Step-by-step explanation:

(the above graph depicts a horizontal line that intersects the y axis at -2)

(so, y = -2)

Answer:

0

Step-by-step explanation:

Horizontal line x axis is 0 while the vertical y axis is undefined.

Answer:

$5.00

Step-by-step explanation:

$3.50+$1.50=$5.00

Answer:

j = 10.1

Step-by-step explanation:

The difference between 9.5 and 11.3 is

11.3 - 9.5 = 1.8

This is split into 3 divisions, that is

1.8 ÷ 3 = 0.6

Then

j = 9.5 + 0.6 = 10.1

Answer:

Hello,

answer 22

Step-by-step explanation:

[tex]\dfrac{1}{j} +\dfrac{1}{k} =\dfrac{1}{3} \\\\\dfrac{k+j}{j*k} =\dfrac{1}{3} \\\\\\3k+3j=j*k\\\\k(3-j)=-3j\\\\k=\dfrac{3j}{j-3} \\\\k=\dfrac{3j-9+9}{j-3} \\\\k=3+\dfrac{9}{j-3} \\\\\\j-3\ must\ be \ a divisor\ of\ 9 ==> 1,3,9\\\\j-3=1 ==> j=4 , k=3+\dfrac{9}{1} =12\\\\j-3=3 ==> j=6 , k=3+\dfrac{9}{3} =6\\\\j-3=9 ==> j=12 , k=3+\dfrac{9}{9} =4\\\\\sum\ k=12+6+4=22\\[/tex]

The sum of all possible values for k is 22.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

1/j + 1/k= 1/3

Simplifying the fraction

(k+ j)/ kj= 1/3

3k + 3j = kj

k(3- j) = -3j

k = -3j/ (3- j)

k= 3j/ (j-3)

k = 3j + 9 - 9 / (j-3)

k = 3 + 9/ (j-3)

Since (j-3) must be divisor of 9.

j- 3 = 1---> j=4, k= 3 +9 = 12

j- 3 = 3---> j=6, k= 3 +9/3 = 6

j- 3 = 9---> j=12, k= 3 +9/9 = 4

So, The sum is = 12+ 6 + 4 = 22

Learn more about Fraction here:

https://brainly.com/question/10354322

#SPJ6

Answer:

4x+y=-32

Step-by-step explanation:

given,

slope (m) = -4

point: (-8,0)

as we know the slope intercept form of the line is, y=mx+b, b=y-mx, now we put x=-8, y=0 to find b [because the point is given (-8,0) so it must satisfy the equation]

so,

b = 0-(-4)×(-8) = -32

y=mx+b

or, y=-4x-32

or, 4x+y=-32

(this is the standard form of the line)

Using the equation y - y1 = m(x - x1)

y - 0 = -4(x - (-8))

y = -4(x + 8)

y = -4x - 32

Answer:

[tex]\boxed {\boxed {\sf 8.7}}[/tex]

Step-by-step explanation:

We are asked to find the length of the third side in a triangle, given the other 2 sides.

Since this is a right triangle (note the small square in the corner of the triangle representing a 90 degree /right angle), we can use the Pythagorean Theorem.

[tex]a^2 + b^2 =c^2[/tex]

In this theorem, a and b are the legs of the triangle and c is the hypotenuse.

We know that the unknown side (we can say it is a) and the side measuring 5 are the legs because they form the right angle. The side measuring 10 is the hypotenuse because it is opposite the right angle.

Substitute the values into the formula.

[tex]a^2 + (5)^2 = (10)^2[/tex]

Solve the exponents.

[tex]a^2 + 25=100[/tex]

We are solving for a, so we must isolate the variable. 25 is being added to a. The inverse operation of addition is subtraction, so we subtract 25 from both sides.

[tex]a^2 +25-25=100-25[/tex]

[tex]a^2=100-25[/tex]

[tex]a^2 = 75[/tex]

a is being squared. The inverse of a square is the square root, so we take the square root of both sides.

[tex]\sqrt {a^2}= \sqrt{75}[/tex]

[tex]a= \sqrt{75}[/tex]

[tex]a= 8.660254038[/tex]

Round to the nearest tenth. The 6 in the hundredth place tells us to round the 6 up to a 7 in the tenth place.

[tex]a \approx 8.7[/tex]

The length of the third side is approximately 8.7

Using Pythagorean theorem

[tex]\boxed{\sf B^2=H^2-P^2}[/tex]

[tex]\\ \sf \longmapsto B^2=10^2-5^2[/tex]

[tex]\\ \sf \longmapsto B^2=100-25[/tex]

[tex]\\ \sf \longmapsto B^2=75[/tex]

[tex]\\ \sf \longmapsto B=\sqrt{75}[/tex]

[tex]\\ \sf \longmapsto B=\sqrt{25\times 3}[/tex]

[tex]\\ \sf \longmapsto B=5\sqrt{3}[/tex]

[tex]\\ \sf \longmapsto B=5\times 1.732[/tex]

[tex]\\ \sf \longmapsto B=8.66[/tex]

[tex]\\ \sf \longmapsto B\approx 8.7[/tex]

Answer:

1. a. 2

b. -½

c. y - 3 = -½(x - 8) => point-slope form

y = -½x + 7 => slope-intercept form

2. a. -1

b. 1

c. y - 5 = 1(x - 3) => point-slope form

y = x + 2 => slope-intercept form

Step-by-step explanation:

1. (8, 3) and (10, 7):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (8, 3) = (x_1, y_1) [/tex]

[tex] (10, 7) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]

Gradient = [tex] \frac{4}{2} [/tex]

Gradient = 2

b. The gradient of the line perpendicular to this line = the negative reciprocal of 2

Negative reciprocal of 2 = -½

c. The equation of perpendicular line if it passes through the first point, (8, 3):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (8, 3)

Slope (m) = -½

Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - 3 = -½(x - 8) => point-slope form

We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:

Thus:

y - 3 = -½(x - 8)

y - 3 = -½x + 4

y - 3 + 3 = -½x + 4 + 3

y = -½x + 7

2. (3, 5) and (4, 4):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (3, 5) = (x_1, y_1) [/tex]

[tex] (4, 4) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]

Gradient = [tex] \frac{-1}{1} [/tex]

Gradient = -1

b. The gradient of the line perpendicular to this line = the negative reciprocal of -1

Negative reciprocal of -1 = 1

c. The equation of perpendicular line if it passes through the first point, (3, 5):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (3, 5)

Slope (m) = 1

Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).

Thus:

y - 5 = 1(x - 3) => point-slope form

We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:

Thus:

y - 5 = 1(x - 3)

y - 5 = x - 3

y - 5 + 5 = x - 3 + 5

y = x + 2

Answer: MATH

Step-by-step explanation:

Answer:

answer for the question is

x = 1

y = 4

subject is math btw if you are asking about that

Answer:

9.) y=-2x-4

10.)y=2/3x

Step-by-step explanation:

Parallel lines have the same slope, different intercepts

9.) The slope is -2x

To find the parallel line

y-(-4)=-2(x-0)

y+4=-2x

y-4=-2x-4

y=-2x-4

10.) You must first put the equation in slope-intercept form.

-2x+2x+3y=2x+12

3y=2x+12

Divide by 3

3y/3=2x/3+12/3

Simplify

y=2/3x+4

Slope = 2/3x

y-2=2/3(x-3)

y-2=2/3x-6/3

y-2=2/3x-2

y-2+2=2/3x-2+2

y=2/3x

Answer:

39°

Step-by-step explanation:

The angle adjacent to 115° in the lower triangle = 180° - 115° = 65°

angle on circle in lower triangle

= 180° - (65 + 76)°  ← angle sum in triangle

= 180° - 141° = 39°

Angles on the circle subtended from the same arc are congruent, then

shaded angle = 39°

Answer:

3b (3a - 4b)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

9ab - 12b² ← factor out 3b from each term

= 3b(3a - 4b) → C

Answer:

[tex]x = 34^\circ[/tex]

Step-by-step explanation:

Note that ∠TSU and ∠PSR are vertical angles. Hence:

[tex]m\angle TSU = m\angle PSR[/tex]

∠PSR is the sum of ∠PSQ and ∠QSR. Hence:

[tex]\displaystyle m\angle TSU = m\angle PSQ + m\angle QSR[/tex]

We know that ∠TSU measures 4x and ∠QSR measures 3x. Thus:

[tex](4x) = m\angle PSQ + (3x)[/tex]

Solve for ∠PSQ:

[tex]m\angle PSQ = x[/tex]

Next, ∠PQS and ∠RQS form a linear pair. Thus:

[tex]m\angle PQS + m\angle RQS = 180^\circ[/tex]

∠RQS measures 68°. Thus:

[tex]m\angle PQS +(68^\circ) = 180^\circ[/tex]

Solve for ∠PQS:

[tex]m\angle PQS = 112^\circ[/tex]

The interior angles of a triangle must total 180°. So, for ΔPQS:

[tex]\displaystyle m\angle SPQ + m\angle PQS + m\angle PSQ = 180^\circ[/tex]

Substitute in the known values:

[tex](x) + (112^\circ) + (x) = 180^\circ[/tex]

Simplify:

[tex]2x = 68^\circ[/tex]

And divide. Hence:

[tex]x = 34^\circ[/tex]