can you solve it please

Answer:

1) B: Increase its length

2) True

3) True

Explanation:

1) Columns are compressive members and are subjected to primarily compressive stresses.

Now, there is what we call slender Ness ratio in columns which is basically used to check the ability of a column to resist buckling.

The formula is;

Slenderness ratio = Effective length of column/radius of gyration

Thus, the longer the column the more the Slenderness ratio and the more likely it is to buckle.

Thus, increasing the length is what makes columns likely buckle.

2) Compressive strength is the ability of a material to withstand loads that may reduce size or make the material crush under load.

Now, increasing the compressive strength simply means more ability to withstand loads that may lead to crushing under load.

Ultimate compressive strength is the maximum amount of compressive stress that a material can take before it crushes under load. Thus, increasing the ultimate compressive strength means it is less likely to crush under its own weight.

3) There are different factors that affect moment of inertia and they are;

- the mass of the body

- axis of rotation of the body

- shape and size of the body.

However, for area moment of inertia, what is most relevant to us is the shape of the body in question since we are dealing with area and not how big it is.

Answer: check answers in pictures (2 p)

The resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

Resistance is a measure of an electrical circuit's resistance to current flow. Resistance is measured in ohms, which is represented by the Greek letter omega.

Full-scale deflection current = 0.015 A

Full-scale deflection current for 20 A = 20/0.015 = 1333.33 times full-scale deflection current

The current through the meter coil is given by:

Ic = Im * (Rm / (Rm + Rs))

At full scale, Ic = 1333.33 * 0.015 A = 20 A, Rm = 1.5 Ohm, and Rs = 3.5 Ohm.

Therefore:

20 A = Im * (1.5 Ohm / (1.5 Ohm + 3.5 Ohm))

Im = 20 A * (3.5 Ohm / 5 Ohm)

Im = 14 A

The current through the shunt resistor is therefore:

Ish = Im - Ic

Ish = 14 A - 20 A

Ish = -6 A

Since the shunt resistor is in parallel with the meter, its resistance can be calculated using the following formula:

Rs = Rm * (Im / Ish - 1)

Substituting the values, we get:

3.5 Ohm = 1.5 Ohm * (14 A / (-6 A) - 1)

3.5 Ohm = 1.5 Ohm * (-1.333 - 1)

3.5 Ohm = 1.5 Ohm * (-2.333)

Rs = 1.5 Ohm * (14 A / (-6 A) - 1) / (-2.333)

Rs = 2.528 Ohm

Therefore, the resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

Now, let's find the resistance required for a full-scale deflection of 250 V:

Full-scale deflection current = 0.015 A

Resistance required for full-scale deflection of 250 V = 250 V / 0.015 A

Resistance required for full-scale deflection of 250 V = 16666.67 Ohm

This resistance is in parallel with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm || Rext

Rtotal = (Rm * Rext) / (Rm + Rext)

Substituting the values, we get:

Rtotal = (1.5 Ohm * 16666.67 Ohm) / (1.5 Ohm + 16666.67 Ohm)

Rtotal = 1.43 Ohm

This resistance is in series with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm + Rext + Rs

Substituting the values we get:

1.43 Ohm = 1.5 Ohm + 16666.67 Ohm + Rs

Rs = 1.43 Ohm - 1.5 Ohm - 16666.67 Ohm

Rs = -16666.74 Ohm

Thus, the calculated value of Rs is negative, it means that the shunt resistor must be used instead of a series resistor to achieve a full-scale deflection of 250 V.

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Answer:

a)  [tex]m_e= 3.05 Kg[/tex]

b)  [tex]\rho=1072.3kg/m^3[/tex]

c)  [tex]m_e= 3.05 Kg[/tex]

Explanation:

From the question we are told that:

Beaker Mass [tex]m_b=1.20[/tex]

Liquid Mass [tex]m_l=1.85[/tex]

Balance D:

Mass [tex]m_d=3.10[/tex]

Balance E:

Mass [tex]m_e=7.50[/tex]

Volume [tex]v=4.15*10^{-3}m^3[/tex]

a)

Generally the equation for Liquid's density is mathematically given by

[tex]m_e=m_b+m_l+(\rho*v)[/tex]

[tex]\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}[/tex]

[tex]\rho=1072.3kg/m^3[/tex]

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

[tex]m_d=m- (\rho *v )[/tex]

[tex]m=3.10+ (1072.30 *4.15*10^{-3}m^3 )[/tex]

[tex]m=18.10kg[/tex]

c)

Generally the equation for E's Reading at A pulled is mathematically given by

[tex]m_e=m_b+m_l[/tex]

[tex]m_e = 1.20 + 1.85[/tex]

[tex]m_e= 3.05 Kg[/tex]

Answer:

Newton per square meter (N/m2)

Explanation:

Required

Unit of ultimate tensile strength

Ultimate tensile strength (U) is calculated using:

[tex]U = \frac{Ultimate\ Force}{Area}[/tex]

The units of force is N (Newton) and the unit of Area is m^2

So, we have:

[tex]U = \frac{N}{m^2}[/tex]

or

[tex]U = N/m^2[/tex]

Hence: (c) is correct

Answer:

[tex]V_z=9.1v[/tex]

[tex]V_{zo}=8.74V[/tex]

[tex]I=10mA[/tex]

[tex]R=589 ohms[/tex]

Explanation:

From the question we are told that:

Zener diode Voltage [tex]V_z=9.1-V[/tex]

Zener diode Current [tex]I_z=9 .A[/tex]

Note

[tex]rz = 40\\\\IZK= 0.5 mA[/tex]

Supply Voltage [tex]V_s=15[/tex]

Reduction Percentage [tex]P_r= 50 \%[/tex]

Generally the equation for Kirchhoff's Voltage Law is mathematically given by

[tex]V_z=V_{zo}+I_zr_z[/tex]

[tex]9.1=V_{z0}+9*10^{-3}(40)[/tex]

[tex]V_{zo}=8.74V[/tex]

Therefore

[tex]At I_z-10mA[/tex]

[tex]V_z=V_{z0}+I_zr_z[/tex]

[tex]V_z=8.74+(10*10^{-3}) (40)[/tex]

[tex]V_z=9.1v[/tex]

Generally the equation for Kirchhoff's Current Law is mathematically given by

[tex]-I+I_z+I_l=0[/tex]

[tex]I=10mA+\frac{V_z}{R_l}[/tex]

[tex]I=10mA+\frac{9.1}{0}[/tex]

[tex]I=10mA[/tex]

Therefore

[tex]R=\frac{15V-V_z}{I}[/tex]

[tex]R=\frac{15-9.1}{10*10^{-3}}[/tex]

[tex]R=589 ohms[/tex]

In heavy traffic areas, you should wave pedestrians across the street if there is no crosswalk: False.

A crosswalk can be defined as the marked or specially paved part of a road that is characterized by heavy traffic, so as to enable pedestrians have right of way to cross the street because drivers are required by traffic law to stop for them.

However, a driver or other road users in heavy traffic areas shouldn't wave pedestrians across the street if there is no crosswalk

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Answer:

[tex]U=\pm 0.382N[/tex]

Explanation:

From the question we are told that:

Resolution: 0.25 N

Range: 0 to 100 N

Linearity error: within 0.20 N over range

Hysteresis error: within 0.30 N over range

Generally the equation for Stage Uncertainty is mathematically given by

[tex]U=\sqrt{u_0^2+u_T^2}[/tex]

Where

[tex]u_0=Zero\ order\ uncertainty[/tex]

[tex]u_0=\pm 0.5*0.25[/tex]

[tex]u_0=\pm=0.125[/tex]

And

u_T=Total instrumental Uncertainty

[tex]u_T=\sqrt{l_e^2+h_e^2}[/tex]

Where

l_e=Error of linearity

h_e=Error due to hysteresis

Hence

[tex]u_T=\sqrt{0.20^2+0.30^2}[/tex]

[tex]u_T=\pm 0.36[/tex]

Therefore

[tex]U=\sqrt{(0.125)^2+0.36^2}[/tex]

[tex]U=\pm 0.382N[/tex]

Answer:

inductive reasoning

Explanation:

Inductive reasoning is one of the type of reasoning method in which generalized consequences are derived from limited observations. By observing few data, general conclusions are drawn. The conclusions drawn are false in inductive reasoning. In the given situation, the conclusion drawn by the elevator repairer has been drawn by inductive reasoning. His observation of some cables led him to draw the conclusion about all the cables. The result of the reasoning is false.

Answer:

The new length of the rod is 182 cm.

Explanation:

Given that a rod that was originally 100-cm-long experiences a strain of 82%, to determine what is the new length of the rod, the following calculation must be performed:

100 x 1.82 = X

182 = X

Therefore, the new length of the rod is 182 cm.

Answer:

I think ( MOV Metal oxide varistors )

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.

Answer:

The answer is below.

Explanation:

Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:

1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.

2. ECC can work well and at a faster rate on a small-capacity device compared to RSA

3. It uses offer speedier SSL handshakes that enhance security

4. It offers fast signatures

5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.

6. Relatively quick encryption and decryption

Answer:

Required pump power = - 11.205 kW

Explanation:

Pi = 600 kPa

Zi ( initial height ) = - 5m

P2 = 200 kPa

Ze ( top floor above ground level ) = 150m

Flowrate = 0.01 m^3/s = 10 kg/s

Temperature = 10°C  ( assumed value )  remains constant

calculate the value of pumping power required ( i.e. work done )

Applying the energy equation

Hi + 1/2(vi)^2 + gZi = He + 1/2(Ve)^2 + gZe + W

given negligible internal/kinetic  energy  difference in "h's = the pv terms

W = ( Pi Vi - Pe V2 ) + g( Zi - Z2 )

   = ( (600 * 0.001)  - (200 * 0.001) ) + (9.81/1000) ( - 5 - 150 )

   = - 1.1205 Kg/kJ

required pump power = flowrate * -1.1205

                                     = 10 * ( - 1.1205 ) = - 11.205 kW

Answer:

i) when circuit is unloaded : R1 + R2 = 2kΩ.

ii) when 5V output voltage is applied :  R1 = 1 kΩ , R2 =  1 kΩ

iii) when 2.5 v output voltage is applied : R1 = 1500 Ω,  R2 = 500 Ω

iv) when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

Explanation:

Current drawn from source under loaded condition ≤ 5 mA

source voltage = 10 v ,  required output = 5 v , 2.5 v

attached below is the sketch of the circuit

Resistance values

i) when the circuit is unloaded

Req = R1 + R2 = 2 kΩ  ( Req = Vs / I  = 10 / 5*10^-3 = 2 kΩ )

ii) when  output voltage = 5 v

we will apply voltage divider rule

R1 = 1 kΩ ,

R2 =  1 kΩ

iii) When the output voltage = 2.5 v

applying voltage divider rule

R1 = 1500 Ω

R2 = 500 Ω

iv) when the load is connected to each tap one at a time

i.e. when the resistance are in parallel

when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

attached below is the detailed solution to the given problem

If the integral is

[tex]\displaystyle \int \frac{\ln(3x^2)}{x^5}\,\mathrm dx[/tex]

substitute u = ln(3x ²) and du = 6x/(3x ²) dx = 2/x dx.

Then x ² = exp(u)/3 and x ⁴ = exp(2u)/9.

The integral is transformed to

[tex]\displaystyle \int \frac{\ln(3x^2)}{x^5}\,\mathrm dx = \int \frac{\ln(3x^2)}{2x^4} \times \dfrac2x \,\mathrm dx \\\\ = \int \frac{u}{2\times\dfrac{e^{2u}}9}\,\mathrm du \\\\ = \frac92 \int ue^{-2u}\,\mathrm du[/tex]

Integrate by parts:

[tex]f = u \implies \mathrm df = \mathrm du \\\\ \mathrm dg = e^{-2u}\,\mathrm du \implies g = -\dfrac12 e^{-2u}[/tex]

[tex]\displaystyle \int ue^{-2u}\,\mathrm du = fg - \int g\,\mathrm df \\\\ = -\dfrac12 ue^{-2u} + \displaystyle \frac12 \int e^{-2u}\,\mathrm du \\\\ = -\frac12 ue^{-2u} - \frac14 e^{-2u} + C[/tex]

Then

[tex]\displaystyle \frac92 \int ue^{-2u}\,\mathrm du = -\frac94 ue^{-2u} - \frac98 e^{-2u} + C[/tex]

which in terms of x would be

[tex]\displaystyle \int \frac{\ln(3x^2)}{x^5}\,\mathrm dx = -\frac94\times\frac{\ln(3x^2)}{9x^4} - \frac98 \times \frac1{9x^4} + C \\\\ = \boxed{-\frac{\ln(3x^2)}{4x^4}-\frac1{8x^4}+C}[/tex]

Answer:

. 1. Type of building

2. Location of emergency

3. Extent of emergency

Explanation:

1. The kind of building in which people find themselves could be a factor that can be used to make this decision. a lot of buildings can be easily affected by disasters such as explosions or tornadoes the extent of the effect is dependent on how the building is constructed. in some situations it is better to shelter in, while in others it is best to evacuate.

2. Another factor to be considered is the location or area where this is happening it is good to consider this so that people can be safely moved given that help can be easily accessed or if best to stay in.

3. The last is the extent of what is happening. The risk involved is one way of making the choice to evacuate or to stay.

The factors that affect the decision on whether to evacuate or shelter in place include:

It should be noted that the building where an individual lives play a vital role during emergencies. Buildings that have poor foundations can easily be affected during emergencies.

Another factor that should be considered is the location where the emergency is taking place. Lastly, the extent of the emergency can determine if the person should stay or not.

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Answer:

0.75

Explanation:

From this question above we have the following information

A = probability of investment in mutual fund= 0.6

B = probability of investment in government fund = 0.3

C = probability of investing in both the mutual fund and the government= 0.15

Where to find the probability of this investor investing in either of these two

= Prob(a) + prob(b) - prob(c)

= 0.6 + 0.3 - 0.15

= 0.9 - 0.15

= 0.75

Answer:

320 m

Explanation:

To find the side length of the current park, x, we solve the quadratic equation for the area of the park

x² + 200x = 166400

x² + 200x - 166400 = 0

We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x

So, we re-write the expression as

x² + 200x - 166400 = 0

x² + 520x - 320x - 166400 = 0

We write out the factors of the expression,

x² + 520x - 320x - 320 × 520 = 0

Factorizing the expression, we have

x(x + 520) - 320(x + 520) = 0

(x + 520)(x - 320) = 0

x + 520 = 0 or x - 320 = 0

x = -520 or x = 320

Since x is not negative, we take the positive answer.

So, x = 320 m

Answer:

ROLAP  is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )

Explanation:

ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).

Advantages of ROLAP ( reasons for the use of ROLAP )

Answer:

mark me as a brainleast

Explanation:

209781

Answer: Hello the question is incomplete below is the missing part

Question:  determine the temperature, in °R, at the exit

answer:

T2= 569.62°R

Explanation:

T1 = 540°R

V2 = 600 ft/s

V1 = 60 ft/s

h1 = 129.0613  ( value gotten from Ideal gas property-air table )

first step : calculate the value of h2 using the equation below

assuming no work is done ( potential energy is ignored )

h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778

∴ h2 = 136.17 Btu/Ibm

From Table A-17

we will apply interpolation

attached below is the remaining part of the solution

Answer:

A) L = 0.388 μm

B) D = 3.78 mm

Explanation:

We are given;

Characteristics impedance; Z_o = 75 ohms

Nominal capacitance; C = 69pF/m = 69 × 10^(-12) F/m

dielectric constant; k = 2.23

Inner diameter of conductor; d = 0.584 mm

A) Now formula for Characteristics impedance is given as;

Z_o = √(L/C)

Where L is the inductance per metre.

Making L the subject, we have;

L = (Z_o)²C

L = 75² × 69 × 10^(-12)

L = 0.388 × 10^(-6) m

L = 0.388 μm

B) To get the outer diameter, we will use the formula;

Z_o = (138/√k) log(D/d)

Where;

D is outer diameter.

Thus, Plugging in the relevant values;

75 = (138/√2.23) × log (D/0.584)

log (D/0.584) = 0.81158611538

(D/0.584) = 10^(0.81158611538)

D/0.584 = 6.48016576435

D = 6.48016576435 × 0.584

D = 3.78 mm

Answer:

σ1, σ2 and σ3.

Explanation:

The three principal stresses are labelled or written as σ1, σ2 and σ3. The σ1 is the maximum principal stress or most tensile stress, σ2 is the intermediate principal stress and σ3 is the minimum or most compressive principal stress. Principal stresses are the maximum and minimum extensional stresses present in an object. The principal directions have no shear stresses connected with them.

Answer:

a) [tex]\mu=3.3[/tex]

b)  [tex]Q=1440.7KJ/Kmol[/tex]

c)  [tex]W=1872.9KJ/Kmol[/tex]

Explanation:

From the question we are told that:

Initial Temperature [tex]T_1=325k[/tex]

initial Pressure [tex]P_1=2 bar[/tex]

Final Pressure [tex]P_2=4 bar[/tex]

iso-thermal expansion [tex]T_2=250k[/tex]

a)

Generally the equation for Coefficient of performance is mathematically given by

[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]

[tex]\mu=\frac{250}{325-250}[/tex]

[tex]\mu=3.3[/tex]

b)

Generally the equation for Heat Expansion is mathematically given by

[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]

Where

R=Gas constant

[tex]R=8.314462618[/tex]

Therefore

[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]Q=1440.7KJ/Kmol[/tex]

c)

Generally the equation for work input is mathematically given by

[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]

[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]W=1872.9KJ/Kmol[/tex]

The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol

Given Data:

Isothermal expansion occurs at 250K.

This is calculated as

COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]

[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]

Therefore; In isothermal process du = 0

R = 8.314 AkJ/K.mol

Q = 8.314 * 250 In(4/2)

Q = 1440.71kJ/K.mol

W[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]

The work input is 1872.92kJ/K.mol

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Answer:

very good thx

Explanation:

Answer:

True ❤️

-Solid by solid can make Cylindrical wire doubles Strengths in tension

Explanation:

https://www.chegg.com/homework-help/questions-and-answers/iron-core-wish-design-transformer-part-dc-power-supply-moderately-high-current-rating-volt-q53186459?trackid=83dbc34cec2e&strackid=3efc9f324415

Answer:

[tex]W= 208 KJ[/tex]

Explanation:

From the question we are told that:

Take in Temperature [tex]T_1=400C=>673K[/tex]

Take Out Temperature  [tex]T_2=120+>393K[/tex]

Heat [tex]Q=500kJ[/tex]

Generally the equation for Carnot Engine Efficiency is mathematically given  by

 [tex]n_c=\frac{T_1-T_2}{T_1}[/tex]

 [tex]n_c=\frac{673-393}{673}[/tex]

 [tex]n_c=0.4[/tex]

Where

 [tex]n_c=\frac{W}{Q}[/tex]

 [tex]W = Q*n_c[/tex]

 [tex]W= 500 * 0.4[/tex]

 [tex]W= 208 KJ[/tex]