Answer:
Production of some products is highly concentrated in a few countries, China, the leading producer of wheat and ramie in 2013, produces 6% of the world's ramie fiber but only 17% of the world's wheat.
General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.
A researcher studying the nutritional value of a new candy places a 6.70 g
sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.29 ∘C.
If the heat capacity of the calorimeter is 37.60 kJ⋅K−1,
how many nutritional Calories are there per gram of the candy?
Answer:
3.07 Cal/g
Explanation:
Step 1: Calculate the heat absorbed by the calorimeter
We will use the following expression.
Q = C × ΔT
where,
Q: heat absorbedC: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)ΔT: temperature change (2.29 °C)Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ
According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.
Step 2: Convert 86.1 kJ to Cal
We will use the conversion factor 1 Cal = 4.186 kJ.
86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal
Step 3: Calculate the number of Cal per gram of candy
20.6 Cal/6.70 g = 3.07 Cal/g
The following compound can be identified as
Answer:
3: Lactone
Explanation:
Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.
Thus, looking at the question, it has the structure as defined in Lactones.
Thus, we can say that the compound is a Lactone.
what is the hybridisation of the central carbon in CH3C triple bonded to N
Explanation:
the carbon would be sp3 hybridized, and it doesn't matter which carbon, since either of them have a full octet
which of these statements is true about planets? Planets
A. revolve around the sun
B. are spherical in shape
C. rotate in its axis
D. all of the above
Answer:
D. all of the above
Explanation:
A and C are verified by Keplar's laws of planetary motion.
B is verified by the equatorial and polar aces of the Planet.
Answer:
c
Explanation:
they dont have to orbit the sun specifically and are commonly more ovoid than spherical
Question 6 of 25
What is an energy level?
A. The total energy possessed by all the electrons of an atom
B. The energy required to remove an electron from its nucleus
C. The energy contained within the nucleus of an atom
Ο Ο
D. The energy possessed by an electron at a set distance from the
nucleus
SUBMIT
Answer:
The answer is D. The energy possessed by an electron at a set distance from the nucleus.
Explanation:
Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found. Electrons are tiny, negatively charged particles in an atom that move around the positive nucleus at the center.
Energy levels are the fixed amount of energy that a system described by quantum mechanics, such as a molecule, atom, electron, or nucleus, can have.
An energy level is the energy possessed by an electron at a set distance from the nucleus. Therefore, option D is correct.
What is energy level ?Any discrete value from a set of total energy values for a subatomic particle constrained by a force to a finite space or for a system of such particles, such as an atom or a nucleus, is referred to as the energy level, also known as the energy state, in physics.
Since an electron's rotation in a shell is linked to a specific amount of energy. When it moves from one energy level to another, or when it jumps to another shell, the energy changes. As a result, a shell also indicates an electron's energy along with its location, and these are known as energy levels.
The shell or orbital that an electron is in with respect to the atom's nucleus is referred to as its primary energy level.
Thus, option D is correct.
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Identify the compound in the following group that is most soluble in water. Match the words in the left column to the appropriate blanks in the sentences on the right. ResetHelp Of the three compounds butanoic acid, butane, and butanone, the one that is most soluble in water is . This is because its functional group can form the intermolecular forces with polar water.
butanoic acid strongest hydrocarbon butanone butane alcohol carboxylic acid What carboxylic acid is found in each of the following substances? Drag the appropriate descriptions to their respective bins. Reset rancid butter stinging red ants Methanoic acid Butanoic acid Propanoic acid Ethanoic acid Review Co Draw the structure of methyl butanoate, Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms toolbars. H: 129 uxo com H o с + N 1 0 S a CH Br р
Answer:
Following are the responses to the given points:
Explanation:
For question 1:
Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.
For question 2:
Butanoic acid is a rancid buffer.
Methanoic acid is responsible for the stinging red ants
For question 3:
Methyl butanoate's chemical structure.
A second-order reaction has a half-life of 12 s when the initial concentration of reactant is 0.98 M. The rate constant for this reaction is ________ M-1s-1. A) 12
Answer: 0.085 (Ms)⁻¹
Explanation: Half life = 12 s
is the initial concentration = 0.98 M
Half life expression for second order kinetic is:
k = 0.085 (Ms)⁻¹
The rate constant for this reaction is 0.085 (Ms)⁻¹ .
Fill in the left side of this equilibrium constant equation for the reaction of acetic acid HCH3CO2 with water.
______ = Ka
Answer:
The left side equation is:
[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]
Explanation:
For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is
[tex]HCH_{3}COO + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H_{3}O[/tex]
The left side of this equilibrium constant equation will be written as shown below:
[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]
Granite is heterogeneous?
Answer:
yes it is Heterogeneous.
2. For each of the ionic compounds in the table below, name the compound and explain the rule that you
used in formulating your name for the compound.
Name:
Rule for naming compound:
-PbF4
-NH4NO3
-Li2S
Answer:
2
Explanation:
Lead(|V) fluoride
Ammonium Nitrate
Lithium sulfide
For the rules, I don't know what you were taught. I just do it intuitively since I have done so much chemistry.
The first one the roman numerals represents the charge of the lead which much match the 4- charge from the 4 fluorides.
The second one is just two polyatomic ions which you just have to remember.
The last one is the typical ionic compound naming technique i guess.
Write a complete, balanced equation for the following reactions:
e) The heating of sodium carbonate (teachers note: produces sodium oxide and carbon dioxide).
f) chromium (III) hydroxide plus sulfuric acid (teachers note: You figure out products).
g) aluminum metal plus chlorine gas (teachers note: produces aluminum chloride).
Please explain as well, thanks!
Answer:
Solution given:
e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide
Solution given:
Balanced chemical equation:
[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]
when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide
f) chromium (III) hydroxide plus sulfuric acid
Balanced chemical equation:
[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]
When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.
g) aluminum metal plus chlorine gas
[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]
When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.
e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide
Solution given:
Balanced chemical equation:
[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]
when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide
f) chromium (III) hydroxide plus sulfuric acid
Balanced chemical equation:
[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]
When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.
g) aluminum metal plus chlorine gas
[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]
When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.
You have 10 pounds of egg whites. You need 6oz to make one serving of cosomme. How many servings can you make?
Answer:
I think you can make 26, hope this helped.
Explanation:
The half-life period for a first order reaction is independent of
1) rate constant
2) Concentration
Answer:
2 concentrations
Explanation:
Gogle - " The half-life of a reaction is the time required for a reactant to reach one-half its initial concentration or pressure. For a first-order reaction, the half-life is independent of concentration and constant over time. "
How many grams of S206 are in 17.7 moles of S206?
Answer:
2721.02 g
Explanation:
you need the molar mass of the compound to solve this
S2O6's molar mass: 2(S) + 6(O)
Sulfur (S) molar mass: 32.06
Oxygen (O) molar mass: 15.99
2(32.06) + 6(15.99) --> 64.12 + 95.94 = 160.06 g/mol
We want to know how much of it is in 17.7 moles, so you perform the following stoichiometry
160.06 g/mol * 17.7 mol
mol units cancel out and we are left with g.
160.06 * 17.7 = 2721.02 g of S2O6 in 17.7 moles of it
Answer: The correct answer is 2721.02 g
Based on the electron configuration of the two atoms, predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound.
Lithium 1s^22s^1
Chlorine 1s^22s^22p^6 3s^23p^5
Answer:
Option A. 1:1
Explanation:
From the question given above, the following data were obtained:
Li => 1s² 2s¹
Cl => 1s² 2s²2p⁶ 3s²2p⁵
Lithium (Li) will form compound with Cl by losing 1 electron as shown below:
Li —> Li⁺ + e¯ ..... (1)
Cl on the other hand will accept 1 electron from Li to form the chloride ion, Cl¯ as shown below:
Cl + e¯ —> Cl¯ ...... (2)
Combining equation 1 and 2, we have:
Li + Cl + e¯ —> Li⁺ + Cl¯ +
Cancel e¯ from both side
Li + Cl —> Li⁺Cl¯
Thus, the ratio of metallic cation (+) to non-metallic anion (-) in the compound is 1:1
Please help a brother out!
Answer:
Choice 'B'
Explanation:
Choice B => SCl₂ => 2 bonded pairs + 2 nonbonded pairs => 4 electron pairs => AX₄ parent => tetrahedral parent, but the shape is defined only by what's bonded to the central element that is, sulfur bonded to two Cl substrates. The electron pairs will assume positions in space (to minimize repulsion forces) like a regular tetrahedron (AX₄) but will have an AX₂E₂ geometry which is a Bent Geometry.
Suggest searching molecular geometry images online. Look for derivatives of AX₄ geometries. Example: H₂O (AX₂E₂ bent geometry; also a derivative of AX₄ tetrahedral parent geometry).
The product of the following reaction is
``````````````````````````````````
must undergo addition because they have easily broken π bonds. ____________ rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom. ____________ are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon. ____________ have good leaving groups and therefore readily undergo substitution and elimination reactions. In hydroboration, the boron atom bonds to the ____________ substituted carbon.
Answer:
Alkenes, Markovnikov's, Alkenes, Alkyl halides, and less.
Explanation:
Alkenes must undergo addition because they have easily broken π bonds.
Markovnikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.
Alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.
Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.
In hydroboration, the boron atom bonds to the less substituted carbon.
Consider the reaction of 2-chloro-2-methylpentane with sodium iodide.
Assuming no other changes, how would it affect the rate if one simultaneously doubled the concentration of 2-chloro-2-methylpentane and sodium iodide?
A) No effect.
B) It would double the rate.
C) It would triple the rate.
D) It would quadruple the rate.
E) It would increase the rate five times.
Answer:
Explanation:
The reaction between 2 chloro- 2 methyl pentane and sodium iodide takes place through SN2 mechanism . iodide ion is the nucleophile which attacks the substrate . The rate of such reaction depends upon concentration of both the nucleophile and the substrate .
Hence rate of reaction will be increased by 2 x 2 = 4 times.
option D ) is correct.
Explanation:
The given reaction represents the reaction between a tertiary alkyl halide that is 2-chloro-2-methylpentane and a nucleophile that is NaI.
This reaction favors SN1 mechanism which has order one.
So, the given reaction follows first-order kinetics.
For a first-order reaction, the rate law is:
rate =k [A]
That means the rate of the reaction is dependent on the concentration of reactants.
So, when the concentration of the reactant is doubled then, the rate of the reaction is also doubled.
Among the given options the correct answer is option B) It would double the rate.
X = atomic number - number of core electrons
Which of the following explains the identity of X and its trends down a group?
A. X is the effective nuclear charge, and it remains constant down a group.
B. X is the screening constant, and it remains constant down a group.
C. X is the effective nuclear charge, and it increases down a group.
D. X is the screening constant, and it increases down a group.
Based on the expression given in the question, X is the effective nuclear charge, and it increases down a group.
What is an effective nuclear charge?Effective nuclear charge is the net nuclear charge that an electron in an atom experiences, after subtracting the nuclear charge shielded by other electrons.
The effective nuclear charge is denoted by Zeff and can be calculated by subtracting the number of shielding electrons from the atomic number.
Therefore, based on the expression given in the question, X is the effective nuclear charge, and it increases down a group.
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Hydrogen gas and fluorine gas will react to form hydrogen fluoride gas. What is the standard free energy change for this reaction
Answer:
[tex]\Delta G=-541.4kJ/mol[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:
[tex]H_2+F_2\rightarrow 2HF[/tex]
Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:
[tex]\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol[/tex]
Regards!
How did the work of Dmitri Mendeleev differ from that of John Newlands in the development of the periodic table?
Answer: Mendeleev predicted elements that would later be discovered.
Which does not result in deviations from linearity in a Beer's law plot of absorbance versus concentration?a. light losses at the cell interface b. all are sources of nonlinearity c. stray radiation d. equilibrium between different forms of the analyte e. a wide bandwidth relative to the width of the absorption band
Answer:
a
Explanation:
Beer-Lambert Law shows the relationship between the factors affecting the absorbance of a sample in relation to the concentration. These factors are:
the concentration c, path length (l), and the molar absorptivity (ε).
As a result, more radiation is assimilated as the concentration rises, and the absorbance rises as well. However, the longer the path length, the increase in the number of molecules and the higher the absorbance.
Thus, the straight-line equation for Beer-Lambert's law is:
A = εcl
From the above explanation, the option that doesn't relate to the deviations from linearity of Beer's law plot is in Option (a).
5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
color (the name indium is derived from the word indigo). The emitted photons that give rise to this
color
have energies of 4.405 x 10^-19J. Calculate the wavelength of this radiation in nanometers.
Answer:
[tex]\lambda=451nm[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:
[tex]E=\frac{hC}{\lambda }[/tex]
Thus, we solve for the wavelength as shown below:
[tex]\lambda=\frac{hC}{ E}[/tex]
And finally plug in the energy, Planck's constant and speed of light to obtain:
[tex]\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm[/tex]
Regards!
How many atom in protons
Answer:
Its atomic number is 14 and its atomic mass is 28. The most common isotope of uranium has 92 protons and 146 neutrons. Its atomic number is 92 and its atomic mass is 238 (92 + 146).
from where the baby plant gets nutrition while its under ground?
Explanation:
The "baby" plant grows entirely from stored energy and food from the cotyledons until it reaches sunlight
what must occur for a change to be a chemical reaction?
Manganese-56 is a beta emitter with a half-life of 2.6 hr. What is the mass of manganese-56 in a 49.7-mg sample of the isotope after 10.4 hr?
Answer:
3.11 mg
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 2.6 hr
Original amount (N₀) = 49.7 mg
Time (t) = 10.4 hr
Amount remaining (N) =.?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 2.6 hr
Time (t) = 10.4 hr
Number of half-lives (n) =?
n = t / t½
n = 10.4 / 2.6
n = 4
Thus, 4 half-lives has elapsed.
Finally, we shall determine the amount remaining. This can be obtained as illustrated below:
Original amount (N₀) = 49.7 mg
Number of half-lives (n) = 4
Amount remaining (N) =.?
N = 1/2ⁿ × N₀
N = 1/2⁴ × 49.7
N = 1/16 × 49.7
N = 0.0625 × 49.7
N = 3.11 mg
Therefore, the amount remaining is 3.11 mg
Which type of element is almost always found as a single atom in nature?
O A. Alkaline earth metal
O B. Halogen
c. Noble gas
D. Oxygen family element
Noble gas elements are almost always found as a single atom in nature.
What is inert gas?An inert gas is a gas that does not undergo chemical reactions under a set of given conditions. The noble gases often do not react with many substances and were historically referred to as inert gases.
All noble gases have the maximum number of electrons in their outer shell; i.e. 2 electrons for helium and 8 for the other five.
Noble gases are monoatomic, which means they exist as single atoms. This is because of their electronic stability.
Thus, noble gas elements are almost always found as a single atom in nature. Hence, option C is correct.
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Which of the following is TRUE?
A.The equivalence point is where the amount of acid equals the amount of base during any acid-base titration.
B. At the equivalence point, the pH is always 7
C. An indicator is not pH sensitive
D.A titration curve is a plot of pH vs. the [base]/[acid] ratio
E. none of these is true
Answer:
D. a titration curve is a plot of pH vs. the [base]/[acid] ratio
