Consider the transfer function a. By rewriting Eq. (7.283) in the form find a series realization of as a cascade of two first-order systems. b. Using a partial-fraction expansion of , find a parallel realization of . c. Realize in control canonical form.

Answer:

10

Step-by-step explanation:

1x2x2.5=5

5/0.5=10

Answer:

= 40 cubes

Step-by-step explanation:

volume = 2.5×2×1 = 5cm^2

volume of cubes = 0.5×0.5×0.5 = 0.125cm^2

5÷0.125 = 40

= 40 cubes

Answer:

[tex]20^{\circ}[/tex]

Step-by-step explanation:

In any right triangle, the cosine of an angle is equal to its adjacent side divided by the hypotenuse.

Let the angle we want to find be [tex]\theta[/tex]. [tex]\theta[/tex]'s adjacent side is 49 and the hypotenuse of the triangle is 52.

Therefore, we have the equation:

[tex]\cos \theta=\frac{49}{52}[/tex]

Take the inverse cosine of both sides:

[tex]\arccos (\cos \theta)=\arccos(\frac{49}{52})[/tex]

Simplify using [tex]\arccos (\cos \theta)=\theta \text{ for }\theta \in (0, 180^{\circ})[/tex]:

[tex]\theta=\arccos(\frac{49}{52}),\\\theta=19.557214,\\\theta\approx \boxed{20^{\circ}}[/tex]

Step-by-step explanation:

Looking at the graph, if you plot the point (-1,-4) you'll see that the point is on the area(red one, in the graph I attached) the graph covers, you can also put x=-1 and y=-1 to check if it's true or not

Answer:

10^3 kg

Step-by-step explanation:

Think about it that you have the total yield 10^8 kg of rice from 10^5 km^2 of land. You now only want How much does 1 km^2 of land produce. Which can be shown as

10^8/10^5=??/1. To get the denominator to equal one you divide the top and bottom of the first problem by 10^5. 10^8/10^5 is 10^3. So it's 10^3 kg

Answer:

Since −13 is a proper fraction, it cannot be written as a mixed number.

Answer:

/2x+3/=10

2x+3=10 or 2x+3=-10

2x=10-3 or 2x=-10-3

2x=7 or 2x=-13

X=7÷2 or X=-13÷2

X=3.5 or X=-6.5

Answer:

<RQS=103 degrees

<SQT=77

Step-by-step explanation:

19x + 9 = 180  subtract 9 from both sides

19x = 171           divide both sides by 19

x = 9                  replace 9 for x in your original

11 x 9 + 4 = 103

8 x 9 + 5 = 77

Answer:

RQS=103°,SQT=77°

SEE THE IMAGE FOR SOLUTION

Answer:

The answer is 7x²+5x

Step-by-step explanation:

[tex]\sf{}[/tex]

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Answer:

Applying Heron's Formula

[tex]s=\frac{2.89+4.3+6.81}{2}[/tex]

[tex]s_1=7[/tex]

[tex]A_1=\sqrt{7(7-2.89)(7-4.3)(7-6.81)}[/tex]

[tex]A_1=10.56[/tex]

Now, [tex]s_2=\frac{6.81+8.59+7.58}{2}[/tex]

[tex]s_2=11.49[/tex]

[tex]A_2=\sqrt{11.49(11.49-6.81)(11.49-8.59)(11.49-7.59)}[/tex]

[tex]A_2=24.69[/tex]

Total Area:

[tex]10.56+24.69[/tex]

[tex]=35.25[/tex]

OAmalOHopeO

Answer:

183

Step-by-step explanation:

-8(.75)-2(5+-4-4-4)+7(5)(5)

-8(.75) = -6

-6-2(5+-4-4-4)+7(5)(5)

(5+-4-4-4) = (-7)

-6-2(-7)+7(5)(5)

7(5)(5) = 175

-6-2(-7)+175

-2(-7) = 14

-6+14+175=183

Answer:

7

Step-by-step explanation:

Consider the absolute value of the difference , that is

| - 5 - 2 | = | - 7 | = 7

or

| 2 - (- 5) | = | 2 + 5 | = | 7 | = 7

Answer:

7

Step-by-step explanation:

Difference is - sign so the equation is: 2- -5 which is 7. Or

think a number line, -5 is 5 spots to 0, then two more spots to 2 so 5+2=7

Answer:

Hello,

Step-by-step explanation:

h(x) has a minimum at x=  2. (h(x) is turning down at x=2)

I have suppose that h''(2 + ) <0 and h''(2 -) <0

Answer:

39.401

Step-by-step explanation:

Answer:

It is expected that linearization beyond age 20 will be use a function whose slope is monotonously decreasing.

Step-by-step explanation:

The linearization of the data by first order polynomials may be reasonable for the set of values of age between ages from 5 to 15 years, but it is inadequate beyond, since the fourth point, located at [tex](x,y) = (20, 5.5)[/tex], in growing at a lower slope. It is expected that function will be monotonously decreasing and we need to use models alternative to first order polynomials as either second order polynomic models or exponential models.

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Work Shown:

SA = surface area of the rectangular prism (aka block or box)

SA = 2*(LW + LH + WH)

SA = 2*(8*3 + 8*1 + 3*1)

SA = 2*(24 + 8 + 3)

SA = 2*(35)

SA = 70 square feet

This is the amount of wrapping paper you would need to cover all six sides of the box. This assumes that there are no gaps or overlaps.

Answer:

Two choices are correct answer.

y = x   and y = 1/4 x

Step-by-step explanation:

We have given four equations.  

We have to choose the equations that are direct variation function.  

Direct variation function is defined as the relation where one variable vary constant times to the other variable.  

let two variables are x and y.  

y = kx   where k is constant.  

Comparing given equation , we notice that  

y = x is direct variation function where k = 1.  

y = 1/4 x is direct variation function where k = 1/4.

Answer:

∠ ELM = 149°

Step-by-step explanation:

∠ KLM = ∠ KLE + ∠ ELM  , substitute values

17x - 1 = 20 + 15x - 1

17x - 1 = 15x + 19 ( subtract 15x from both sides )

2x - 1 = 19 ( add 1 to both sides  )

2x = 20 ( divide both sides by 2 )

x = 10

Then

∠ ELM = 15x - 1 = 15(10) - 1 = 150 - 1 = 149°

Answer:

domain is { - 1, 0, 1 }

Step-by-step explanation:

The domain are the values of the input x

Substitute the value from the range y into the equation and solve for x

y = 1

2x + 3 = 1 ( subtract 3 from both sides )

2x = - 2 ( divide both sides by 2 )

x = - 1

-------------------------------

y = 3

2x + 3 = 3 ( subtract 3 from both sides )

2x = 0 , then

x = 0

-------------------------------

y = 5

2x + 3 = 5 ( subtract 3 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Then the domain is { - 1, 0, 1 }

Answer:

C. Kiometers per hour. I think

Answer:

17.02939

Step-by-step explanation:

Step-by-step explanation:

[tex]area \: of \: a \: triangle = \frac{1}{2} \times base \times height \\ \\ base = \frac{a}{2} cm \\ {h}^{2} + {( \frac{a}{2} )}^{2} = {a}^{2} \\ \\ h = \sqrt{ {a}^{2} - \frac{ {a}^{2} }{4} } \\ \\ area \: of \: triangle = \frac{1}{2} \times b \times h \\ = \frac{1}{2} \times \frac{a}{2} \times \sqrt{ {a}^{2} - \frac{ {a}^{2} }{4} } \\ \\ = \frac{a}{4} \times \sqrt{ {a}^{2} - \frac{ {a}^{2} }{4} } [/tex]

Answer:

The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.

Step-by-step explanation:

2(5m−4)−3(m−5)2=−3m2+40m−83

Add 3m^2 to both sides.

−3m2+40m−83+3m2=−3m2+40m−83+3m2

40m−83=40m−83

Subtract 40m from both sides.

40m−83−40m=40m−83−40m

−83=−83

−83+83=−83+83

0=0

If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.

Answer:

D. 72 [tex]in^2[/tex]

Step-by-step explanation:

The square is 36 in2

The 2 triangles are both 18 in2.

36+18+18=72 in2

I hope this helps!

pls ❤ and give brainliest pls

Answer:

Area is 72 in²

Step-by-step explanation:

= Area of three triangles + area of square.

[tex]{ \bf{ = 3 \times ( \frac{1}{2} b \times h) + (s \times s)}}[/tex]

substitute:

[tex]{ \sf{ = ( \frac{1}{2} \times 6 \times 6) + 2( \frac{1}{2} \times 6 \times 3) + (6 \times 6)}} \\ = { \sf{18 + 18 + 36}} \\ = { \sf{ {72 \: in}^{2} }}[/tex]

Answer:

Option a, 13

if you solve it, you get 13 as the answer

³√(5x-1)=4

or, 5x-1=64

or, 5x=65

or, x=13

Answer:

70 feet

Step-by-step explanation:

If the miniature model has size of 1 inch, the real statue will be 10 feet in size. So if the model is 7 inch in size, the real statue will be 70 feet in size.

Answer:

I think option b i.e 7 is right but not sure

Answer:

t3 = 8, t5 = 14

Step-by-step explanation:

t3 = 2 + (3-1) × 3

t3 = 2 + (2) × 3

t3 = 2 + 6

t3 = 8

t5 = 2 + (5-1) × 3

t5 = 2 + (4) × 3

t5 = 2 + 12

t5 = 14

Answer:

very easy how fo you know this question oppps

Answer:

Its 2.5 percent ladd enjoy

Step-by-step explanation:

Answer:

2 per team and 2 left

Step-by-step explanation:

10 can't split into 4 evenly so, you can only give 2 to each team causing there to be 2 left.

4*2 = 8

10-8 = 2

f(x+1)=3x+4

[tex]\\ \sf\longmapsto f(y)=3(y-1)+4[/tex]

[tex]\\ \sf\longmapsto f(y)=3y-3+4[/tex]

[tex]\\ \sf\longmapsto f(y)=3y+1[/tex]

[tex]\\ \sf\longmapsto f(x)=3x+1\checkmark[/tex]

[tex]\\ \sf\longmapsto f(3)[/tex]

[tex]\\ \sf\longmapsto 3(3)+1[/tex]

[tex]\\ \sf\longmapsto 9+1[/tex]

[tex]\\ \sf\longmapsto 10[/tex]