Answer:
1
Step-by-step explanation:
5÷1000=0.005
0.005 ≈ 1 (1 is the nearest whole number)
Hope this helps!
The number 5 divided by 1,000 is approximately 0 when rounded to the nearest whole number.
To divide 5 by 1,000, we simply perform the division:
5 ÷ 1,000 = 0.005
Now, to round the result to the nearest whole number, we examine the first decimal place. Since it is less than 5, we round down to the nearest whole number.
Thus, the rounded result is 0.
Rounding is a process used to simplify numbers to a certain level of precision. When rounding to the nearest whole number, we look at the digit to the right of the decimal point (the first decimal place). If this digit is 5 or greater, we round up to the next whole number. If it is less than 5, we round down to the current whole number.
In this case, 0.005 is less than 0.5, so we round down to 0.
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3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
g-2 < 7
I need to write this in words
Hi there!
g-2<7
g minus two is less than seven
Hope it helps! Feel free to ask if you have any query. :)
~An excited gal
[tex]MagicalNature[/tex] here to help
combine like the like terms
34w - 4g + 4g - 36w
the answer is -2w (i have the write at least 20 words to dont worry about this)
Answer:
-2w
Step-by-step explanation:
Like terms have same variable.
34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g
= - 2w + 0 = -2w
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
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The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.
Answer: 9 triangles
Step-by-step explanation:
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.
Answer:
95m
Step-by-step explanation:
312 - 61 - 61 = 190
190/2 = 95
9 DNG AKUM
Solve for x :
N
M
5
U7
X+7
D 8 G
K 35 J
Answer:
x = 49
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are in proportion, that is
[tex]\frac{DN}{KJ}[/tex] = [tex]\frac{DG}{KM}[/tex] , substitute values
[tex]\frac{5}{35}[/tex] = [tex]\frac{8}{x+7}[/tex] ( cross- multiply )
5(x + 7) = 280 ( divide both sides by 5 )
x + 7 = 56 ( subtract 7 from both sides )
x = 49
This is a graphing problem and I am trying to find the x-intercepts and the y-intercepts. Please show me the full steps. I really appreciate it thank you.
Answer:
y-intercept: y = 3/4no x-interceptsStep-by-step explanation:
To find the y-intercept, set x=0 and evaluate the function.
f(0) = -3/(0 -4) = 3/4
The y-intercept is (0, 3/4).
__
To find the x-intercept(s), set f(x) = 0 and solve for x.
0 = -3/(x^2 -4)
0 = -3 . . . . . . . . . . multiply by (x^2 -4), x ≠ ±2
There are no values of x that will make this true. There are no x-intercepts.
_____
Additional comments
In general, you find the x-intercepts of a rational function by finding the zeros of the numerator. Here, the numerator is -3, so cannot ever be zero.
I find a graphing calculator to be a useful tool for showing where to look for x-and y-intercepts. The attached graph shows y=0 (the x-axis) is a horizontal asymptote, so there are no x-intercepts.
Can someone help me with this please
Answer:
y=1/2x
Step-by-step explanation:
Answer:
10
9
8
7
6
5
4
3
2
1
0 1 2 3 4 5 6 7 8 9 10
Step-by-step explanation:
So the arrow is pointing at 10 and 5
Answer 10 5
Not 5
its 10 5
So the answer is 10 5
Express the tan G as a fraction in simplest terms.
Answer:
[tex]\frac{\sqrt{70} }{5}[/tex]
Jonah earns $3 an hour working after school and $4 an hour working on Saturdays. Last week he earned $43, working a total of 13 hours. How many hours did he work on Saturday?
Answer:
9 hours worked after school and 4 hours worked on saturday
Step-by-step explanation:
x = amount of hours worked after school
y = amount of hours worked on saturday
x + y = 13 or x = 13 - y
and
3x + 4y = 43
plug:
3 · (13 - y) + 4y = 43
39 - 3y + 4y = 43
y = 4
plug:
x = 13 - y
x = 13 - 4 = 9
9 hours worked after school and 4 hours worked on saturday
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
Which integer can you multiply by itself to get 400 as the square number?
a. 10
b. 20
c. 30
d. 40.
Answer:
20
Step-by-step explanation:
20*20 = 400
OR
[tex]20 {}^{2} = 400[/tex]
Help me plz i wanna make an an A
Please I need help ASAP. Can someone help me?
Answer: The second bubble thing is correct you have picked the wrong one.
PLEASE HELP!!! I NEED THIS DONE AS SOON AS POSSIBLE 20 points Make a table of order pairs for the equation y=-1/3+4 then plot two points to graph the equation
Answer:
ok so.u grit da he on 40/ rock cause u got a andriodnh on gf
labron has $15,300 of total liabilities and $52,580 of total assets.what is his net worth
Answer:
.......................
C+X=G
what is X?
this is a literal equation.
Answer:
x=g-c
Step-by-step explanation:
A side of a square is 2 inches. Using the area formula A = s determine the area of the square.
Answer:
A = 576 square inches
Step-by-step explanation:
s = 2⁴ inches
A (Area) = s²
A (Area) = (2⁴)²
A = 2^8
A = 576
What does changing the “a” variable do to the graph of a quadratic?
Answer:
makes it slope
Step-by-step explanation:
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
what is the percentage discount when a stereo is reduced from $258 to $199?
If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?
Step-by-step explanation:
= f( g(2) )
= 3(2x + 1) + 1
= 6x + 3 + 1
= 6x + 4
= 6(2) + 4
= 12 + 4
= 16
f(g(2)) = 16
Before deciding whether to fly or drive, the family decided to estimate a budget of $1,400 for airfare. One airline has
several different airfares and charges $25 round-trip for each bag that is checked. Since there are 4 members of the
family and each person would check 1 bag, Luis wrote the equation 4(t + 25) = 1,400 to find the maximum cost
per ticket, t, that will fit their budget.
What is the maximum cost per ticket that will be in their budget?
325
I hope that helps
In a certain chemical, the ratio of zinc to copper is 3 to 14. A jar of the chemical contains 630 grams of copper. How many grams of zinc does it contain?
Answer:
135 grams of Zinc
Step-by-step explanation:
zinc:copper
3:14
3/14=x/630
x=135
