Elements beyond iron are not formed by a-particle capture. It is believed they are formed by neutron capture. Once the nucleus gets enough neutrons, one neutron converts to an electron and a proton. Show how you can make zinc from copper by neutron capture.

Answer:

a) electrons

b) from Y to X

Explanation:

positive protons are the cores of atoms in relative to electrons very, very heavy.

the outer electrons of atoms can move, under certain conditions, away from the atom, leaving it electrically unbalanced -> positively charged

there can also be a surplus of electrons on many surfaces, leading to a static negative charge. you know this when you are charged and you discharge with an object or another person, electrically balancing the two bodies charge.

electrons are also much smaller. they are the "things" to move, let it be trough the air or trough a wire, while the heavy protons will stay in place (unless the materials is melted of course, extreme heat brakes the bounds between atoms relatively well)

Answer:Earth's protective magnetic bubble, called the magnetosphere, deflects most solar particles. ... The International Space Station cruises through low-Earth orbit, within Earth's protection, and the station's hull helps shield crew members from radiation too.☘

have a nice day

Answer:

The given molecules are:

a. C6H13NH2

b. CH3OH

c. CH4

d. C5H11OH

e. CO2

Explanation:

The hydrogen bond is a weak electrostatic force of attarction that exists between covalently bonded hydrogen (of -OH or -NH2 or HF) with a highly electronegative atom like N,O and F.

Hydrogen bonding is of two types:

Intermolecular hydrogen bond (exists between two molecules)

Intramolecular hydrogen bond(exists within a molecule).

For example intermolecular hydrogen bond in water is shown below:

Among the given options,

a. C6H13NH2 has -NH2 linkage which leads to hydrogen bond formation.

b. CH3OH has -OH bond and it leads to hydrogen bond fomation.

d. C5H11OH has also -OH bond and it leads to hydrogen bond fomation.

Reamining molecules, CH4 and CO2 do not form hydrogen bond.

Hence, answer is:

options a,b,d.

Answer:

Mean

Explanation:

The mean of a series of measurements is calculated when all the measurements are added up and then divided by the number of measurements taken, as follows:

As there are 4 measurements, the mean is:

Answer:

A

Explanation:

Answer:

ok

Explanation:

Answer:

2.00 × 10⁻³ g

Explanation:

Step 1: Write the balanced decomposition reaction

2 NaHCO₃ ⇒ Na₂CO₃ + CO₂ + H₂O

Step 2: Calculate the moles corresponding to 0.0118 g of Na₂CO₃

The molar mass of Na₂CO₃ is 105.99 g/mol.

0.0118 g × 1 mol/105.99 g = 1.11 × 10⁻⁴ mol

Step 3: Calculate the moles of H₂O produced with 1.11 × 10⁻⁴ moles of Na₂CO₃

The molar ratio of Na₂CO₃ to H₂O is 1:1. The moles of H₂O produced are 1/1 × 1.11 × 10⁻⁴ mol = 1.11 × 10⁻⁴ mol.

Step 4: Calculate the mass corresponding to 1.11 × 10⁻⁴ moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

1.11 × 10⁻⁴ mol × 18.02 g/mol =  2.00 × 10⁻³ g

Answer:

The Tundra Climate

Explanation:

:) hope this helps

Answer:

D. The planet that is closer to the Sun

Answer:

Number of mole in H2O = 5.4 moles

Explanation:

Given:

Mass of H2O = 97.3 gram

Find:

Number of mole in H2O

Computation:

We know that molar mass of H2O = 18 g/mole

So,

Number of mole = Given Mass / Molar mass

Number of mole in H2O = Mass of H2O / Molar mass of H2O

Number of mole in H2O = 97.3 / 18

Number of mole in H2O = 5.4055

Number of mole in H2O = 5.4 moles

Answer:

D

Explanation:

Answer: The mass of P-32 left from the original sample is 32.07 mg

Explanation:

All radioactive decay processes follow first-order reactions.

Calculating rate constant for first order reaction using half life:

[tex]t_{1/2}=\frac{0.693}{k}[/tex] .....(1)

[tex]t_{1/2}[/tex] = half life period = 14.3 days

k = rate constant = ?

Putting values in equation 1:

[tex]k=\frac{0.693}{14.3days}\\\\k=0.0485days^{-1}[/tex]

The integrated rate law equation for first-order kinetics:

[tex]k=\frac{2.303}{t}\log \frac{a}{a-x}[/tex] ......(2)

Given values:

a = initial concentration of reactant = 175 mg

a - x = concentration of reactant left after time 't' = ? mg

t = time period = 35.0 days

Putting values in equation 2:

[tex]0.0485days^{-1}=\frac{2.303}{35.0 days}\log (\frac{175}{a-x})\\\\\log (\frac{175}{a-x})=\frac{0.0485\times 35.0}{2.303}\\\\\log (\frac{175}{a-x})=0.737\\\\\frac{175}{a-x}=10^{0.737}\\\\a-x=\frac{175}{5.457}=32.07mg[/tex]

Hence, the mass of P-32 left from the original sample is 32.07 mg

Answer:

a

Explanation:

a

Answer:

B. Isotopes of the element.

Explanation:

Isotopes are basically atoms of the same element that contain the same number of protons, but a different number of neutrons.

Answer: The correct option is enough solvent to make 1.00 L of solution

Explanation:

A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]Molarity=\frac{Moles}{Volume}[/tex] .......(1)

We are given:

Molarity of solution = 0.500 M

Moles of solute = 0.500 moles

Putting values in equation 1, we get:

[tex]0.500mol/L=\frac{0.500mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.500mol}{0.500mol/L}=1.00L[/tex]

Hence, the correct option is enough solvent to make 1.00 L of solution

Explanation:

Correct option is

B

CH

3

COOH

Empirical formula of Glucose C

6

H

12

O

6

= C

1

H

2

O

1

Now, Empirical formula of CH

3

COOH=C

1

H

2

O

1

As empirical formula is the simplest whole number ratio of number of different types of atoms present in the given molecular formula.

Answer:

A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.

Answer:

O HCl will be completely used up while Zn will remain in excess.

Explanation:

In reactions involving two reactants, if one of them is the limiting reactant then the other one has to be the reactant in excess.

Meaning that in this case, the reaction will proceed until HCl is completely used up, and a certain amount of Zn will remain (thus being the reactant in excess).

Answer:

d. HNO3 + NaOH → NaNO3 + H2O

Explanation:

Hello there!

In this case, according to the given chemical reactions, it turns out necessary for us to recall the definition of neutralization reaction as those whereby an acid reacts with a base, that is why a, b and c are not within the aforementioned description.

In such a way, we infer the reaction is d. HNO3 + NaOH → NaNO3 + H2O since HNO3 is the acid and NaOH the base.

Regards!

Answer:

0.27 atm

Explanation:

At 25ºC, Kp = 2.9 x 10⁻³ for the reaction NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g). In an experiment carried out at 25ºC, a certain amount of NH₄OCONH₂ is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.

Step 1: Make an ICE chart

Solid and liquids are ignored in ICE charts.

       NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g)

I                                            0             0

C                                        +2x           +x

E                                          2x             x

Step 2: Write the pressure equilibrium constant expression (Kp)

Kp = [NH₃]² × [CO₂]

Kp = (2x)² × x

2.9 × 10⁻³ = 4 x³

x = 0.090 atm

Step 3: Calculate the pressures at equilbrium

pNH₃ = 2x = 2(0.090 atm) = 0.18 atm

pCO₂ = x = 0.090 atm

The total pressure is:

P = 0.18 atm + 0.090 atm = 0.27 atm

Explanation:

the answer is in the Image above

The radius of the potassium atom is [tex]2.27\times 10^{-4} \mu m[/tex].

Explanation:

Given:

The radius of potassium atom =[tex]2.27\times 10^{-7} mm[/tex]

To find:

The radius of potassium atom in micrometers.

Solution:

The radius of potassium atom =[tex]2.27\times 10^{-7} mm[/tex]

In 1 millimeter there are 1000 micrometers.

[tex]1 mm = 1000 \mu m[/tex]

Then in [tex]2.27\times 10^{-7} mm[/tex]:

[tex]=2.27\times 10^{-7} \times 1000\\=2.27\times 10^{-4} \mu m[/tex]

The radius of the potassium atom is [tex]2.27\times 10^{-4} \mu m[/tex].

Learn more about conversions here:

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Answer:

i think its A

Answer:

11.1 cm

Explanation:

First we convert 58.1 pounds into grams:

Then we calculate the volume of the gold cube, using the given density:

26353.69 g ÷ 19.3 g/mL = 1365.48 mL

With the volume of a cube we can calculate the side length:

Answer:

2 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above, we can see clearly that 1 L of O₂ reacted to 2 L of H₂O.

This implies that 2 L of H₂O can be obtained by the reaction of 1 L of O₂.

Thus, option 3 gives the correct answer to the question.

The question is incomplete, the complete question is:

The element tin has the following number of electrons per shell: 2.8. 18, 18, 4. Notice that the number of electrons in the outer shell of a tin atom is the same as that for a carbon atom. Therefore, what must be true of tin? Tin is a polar atom and can bind to other polar atoms. Tin has a high molecular weight to give tin-containing molecules greater stabilty. All of the above Tin conform single covalent bonds with other elements, but not double or triple covalent bonds Tincan bind to up to four elements at a time

Answer:

Tin can bind to up to four elements at a time

Explanation:

Certain important points were made in the question about tin and one of them is that tin is an element in the same group as carbon hence it has the same number of valence electrons as carbon.

Carbon is always tetra valent. The tetra valency of carbon is the idea that carbon forms four bonds.

If tin has the same number of valence electrons as carbon, then, tin can bind to up to four elements at a time

Answer:

27.3 kJ/mol

Explanation:

Step 1: Given data

Step 2: Calculate the enthalpy of vaporization of this liquid

We will use the Clausius–Clapeyron equation.

ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)

ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)

ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

Answer:

897154.2 J

Explanation:

Applying,

q = mcΔT.............. Equation 1

Where q = amount of energy released, m = mass of water, c = specific heat capacity of water, ΔT = Change in temperature

From the question,

Given: m = 2.25 kg = 2250 g, c = 4.184 J/g°C, ΔT = (4.2-99.5) = -95.3°C

Substitute these values into equation 1

q = 2250(4.184)(-95.3)

q = -897154.2 J

q =

Hence the amount of heat released is 897154.2 J