Factorise 18a²y - 27ay?

Answers

Answer 1

Answer:

Factorise 18a²y - 27ay

=9ay(2a-3)

Answer 2

Step-by-step explanation:

9ay(2a-3)

hope it is helpful to you


Related Questions

Find the indicated side of the
right triangle.
60°
х
7
30°
x = [?]
Enter

Answers

Here's the solution,

By using Trigonometry :

=》

[tex] \sin(30) = \dfrac{7}{x} [/tex]

=》

[tex] \dfrac{1}{2} = \dfrac{7}{x} [/tex]

=》

[tex]x = 14[/tex]

hence, the value of x = 14 units

Answer:

14

Step-by-step explanation:

Mia's birthday party will cost $12 if she invites 4 guests. What is the maximum number of guests there can be if Mia can afford to spend a total of $15 on her birthday party?

Answers

You find how much each person costs so 12/4 = 3. So every person costs 3 dollars. Then you divide 15/3 and you get 5 so she can invite a max of 5 people

Which statement about the ordered pairs (–2, 9), (0, 9) and (3, 9) is not true?

Answers

Answer:

The slope of these coordinates is 0.

It is a horizontal line.

Step-by-step explanation:

In the past year and a half, Gnarly the dog lost an average of 2/9 pound each month. Today, Gnarly weighs 14 pounds. How much did Gnarly weigh a year and a half ago?

Answers

Answer:

Weight before 18 month = 18 pound

Step-by-step explanation:

Given:

Current weight of dog = 14 pound

Weight lose each month = 2/9 pound

Total number of month = [tex]1\frac{1}{2}[/tex] year = 18 month

Find:

Weight before 18 month

Computation:

Total weight lose = Weight lose each month x Total number of month

Total weight lose = 2/9 x 18

Total weight lose = 4 pound

Weight before 18 month = Current weight of dog + Total weight lose

Weight before 18 month = 14 + 4

Weight before 18 month = 18 pound

HELPPPPP WILLLLL AMRK BRAINLIESTTTTTT

Answers

I think it’s c but I’m sorry if it wrong

Suppose y varies directly with x. Write an equation relating x and y.
y = -22.5 when x = 15
a.
b.
y = -0.75x
2
y=-3
c. y=-1.5x
d. y = 1.5x

Answers

It’s 10 by 2 but the integers should be 12 and the ans should be 11.

A right triangle has a hypotenuse of 15 cm. What is the length for the missing leg if one of the two legs of the triangle is 5?

Answers

Answer:

The other leg is  12 cm  long.

Step-by-step explanation:

c

2

=

a

2

+

b

2

,

where:

c

is the hypotenuse, and  

a

and  

b

are the other two sides (legs).

Let  

a

=

9 cm

Rearrange the equation to isolate  

b

2

. Plug in the values for  

a

and  

c

, and solve.

b

2

=

c

2

a

2

b

2

=

(

15 cm

)

2

(

9 cm

)

2

Simplify.

b

2

=

225 cm

2

81

cm

2

b

2

=

144 cm

2

Take the square root of both sides.

b

=

144 cm

2

Simplify.

b

=

12 cm

Answer:

14.14 cm

Step-by-step explanation:

using the Pythagorean theorem:

?² = 15² - 5² = 225 - 25 = 200

? = √200 = 14.14 cm

help please!!!!!!!!!!!!!!!!!!! very important

Answers

Answer:

i got B for my answer

I don’t know the answer

Answers

Answer:

(a+b) (a-b) =a^2 - b^2

In this question a=2, b=square root of 5

So 2*2=4 square root of 5 times square root of 5 is 5

4-5=-1

Answer:

I believe the answer is -1.

Step-by-step explanation:

So I distributed,

2 x 2 = 4

[tex]-\sqrt{5}[/tex] x 2 = [tex]-2\sqrt{5}[/tex]

[tex]\sqrt{5}[/tex] x 2 = [tex]2\sqrt{5}[/tex]

[tex]\sqrt{5}[/tex] x [tex]-\sqrt{5}[/tex] = -5

4 [tex]-2\sqrt{5}[/tex] + [tex]2\sqrt{5}[/tex] - 5 = ?

the radicals cancel out and 4 -5 = -1

Change the decimal to a percent. 1.3=

Answers

Answer:

Im pretty sure its 130%

Step-by-step explanation:

.013% I think you move the decimal to the left

When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occur. If the solution contains a metal cation such as Ag+, the flow of electrons will reduce the silver ion, causing solid silver to plate onto the electrode. The amount of metal plated depends on the number of electrons passed. The total charge of a mole of electrons is 96, 485 coulombs (C) and 1 ampere = 1 coulomb/second (C/s).
What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)? Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

A sample of 68 college students yields a mean annual income of $3248 and a standard deviation of $885. Find the margin of error in estimating μ at the 99% level of confidence.

Answers

Answer:

 can put this solution on YOUR website!

margin of error is t(0.995 df=67)*s/sqrt(n)

t=2.65

the margin of error is 2.65*885/sqrt(68)=$284.40

What is the difference of the rational expressions below?
6x _ 5
X-2 X

A. 6x2 -5x - 10
x(x - 2)

B. 6x-5
2X-2

c. 6x^2 -5x +10
x(x-2)

D. 6x-5
-2
I'm

Answers

C.) 6x^2-5x+10/x(x-2)

HELP ME PLEASEEEEEEEEE

Answers

The Answer Is 1.7 Pounds.

Answer:

1.7 pounds

Step-by-step explanation:

7.9 - 6.2= 1.7

which is a graph of the equation y = 2x - 4

Answers

The third graphThe graph has a slope of 2and a y-intercept of -4

Answer:

The 3rd one

Step-by-step explanation:

Find the measure of 43.
43
75
43 = [?]

Answers

Answer:

<3=105°

Step-by-step explanation:

The angle directly to the right of the 75° angle is 105°, as the angles along a straight line add to 180.

<3=105° because they are corresponding angles

Answer:

Solution given:

<3+75=180[co- interior angle]

<3=180°-75°=105°

<3=105°

point a and point b are placed on a number line point a is located at -20 and point b is 5 less then point a Wich statement about point b is true​

Answers

Answer:

Step-by-step explanation:

D beause less then 5 that means it gose down the grid

2. The rectangles below are similar. Solve for the AREA of the larger rectangle. *

Answers

Where are the rectangles I can’t seem them

Is 3/4 closer to 0 or 1?

Answers

Answer:

It is closer to 1

Step-by-step explanation:

3/4 is 1/4 away from 1, whereas 0 is 3/4 away from 3/4. So, 1 is closer.

The fraction 3/4 is closer to 1.

We have,

To determine whether the fraction 3/4 is closer to 0 or 1, we can compare the distances between 3/4 and 0, and between 3/4 and 1.

The distance between 3/4 and 0 is 3/4.

The absolute value of the difference is |3/4 - 0| = 3/4.

The distance between 3/4 and 1 is 1 - 3/4 = 1/4.

Since the distance between 3/4 and 1/4 (which is 1/4) is smaller than the distance between 3/4 and 0 (which is 3/4), we can conclude that 3/4 is closer to 1 than to 0.

In other words, if we were to plot the fractions 0, 3/4, and 1 on a number line, the distance between 3/4 and 1 would be smaller than the distance between 3/4 and 0.

Therefore,

The fraction 3/4 is closer to 1.

Learn more about fractions here:

https://brainly.com/question/24370499

#SPJ2

Mr. Shand had $59.75 in his bank account, but then he bought some new ties and some pancakes. After the purchase, he was in debt $75.10. Which of the following rational numbers best shows the change in Mr. Shand’s account balance?
STEP BY STEP EXPLINATION PLEASE!

Answers

Answer:

Ok so first he bought the road and pancakes with means he speant 134.85 dollars which mean he out himself in the negatives after he bought the his items

Question: Edwin usually makes 20 cookies with this recipe, but only wants 5 cookies.


How much is 1/2 teaspoon of vanilla to make 5 cookies?

(PLEASE HELP!!)

Answers

Answer:

1/8 teaspoon of vanilla is needed to make 5 cookies

Step-by-step explanation:

1) 1/2 teaspoon of vanilla makes 20 cookies

2) you only need 5 cookies which is 1/4 as many cookies as before

3) you must 1/4 your recipe

4) 1/2 divided by 4 = 1/8

write the first five terms of the sequence an=3n^2

Answers

Answer:

2,1,0 is the sequence of its terms

A car is running with the velocity of 72km/h . what will be its velocity after 5s if its acceleration is -2m/s square ?

Answers

Answer:

92 km

Step-by-step explanation:

by calculator hope it gelps

92km because that’s what i found in my calculations

pls help
its was on khan academy
i will mark u brainiest!!!

Answers

Answer:

[tex]14 units[/tex]

Step-by-step explanation:

[tex]Solution:-[/tex]

[tex]A(5,1)B(7,1)[/tex]

[tex]\sqrt{(x_{1}-x_{2} ) ^{2}(y_{2} -y_{1}x^{2} }[/tex]

[tex]AB=\sqrt{(7-5)^{2} +(1-1)^{2} }[/tex]

[tex]= \sqrt{2^{2} } =2[/tex]

[tex]BC=\sqrt{7-7^{2}+(6-1)^{2} }[/tex]

[tex]=\sqrt{5^{2} } =5[/tex]

[tex]perimeter=2(AB)+2(BC)[/tex]

[tex]= 2(2)+2(5)\\[/tex]

[tex]= 4+10= 14[/tex]

[tex]-----------[/tex]

hope it helps...

have a great day!!

Describe how to transform the graph of g(x)=ln(x) in the graph of f(x) = ln(-x)-9

Answers

Answer:

the answer is d because it's reflects

One-third of the candidates for a job were 25 years old or younger. Two-sevenths of the candidates were at least 50 years old. If 84 people applied for the job, how many were between 25 and 50?

Answers

Answer:

1/3 * 84 = 28 were under 25

2/7 * 84 = 24 were at least 50

28 + 24 = 52

84-52 = 32 were between 25 and 50

Step-by-step explanation:

Help me with my homework, please

Answers

Answer:

150°

Step-by-step explanation:

We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,

[tex]\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}[/tex]


The product of two numbers is 75
one of the two numbers is a perfect squar. The other is a prime number. Find the sum of the two numbers.

Answers

Answer: 8

Step-by-step explanation: numbers are 5 and 3.

5²·3 =75

Find the mean, median and mode of the following data sets.
1. 79, 84, 92, 81, 86, 77, 95, 80, 88, 84
2. 8, 9, 9, 9, 9, 10, 11, 15
3. 16, 23, 18, 30, 32, 34, 8, 19, 21​

Answers

Answer:

1.

mean= 84.6

median=84

mode=84

2.

mean=10.14

median=9

mode=9

3.

mean=22.3

median=21

mode=phi

Step-by-step explanation:

mean: the sum of of the quantities by their number

median: the median value after rearranging the values

mode: the value that occurs most frequently

in the second question

mean = (8+9+9+9+9+10+11+15)/8

median(even number) =(9+9)/2=9

mode=9

Answer:

for data set 1

1.mean-84.6

2.median-(84+84)/2 = 84

3.mode-84

for data set 2

1.mean-9.25

2.median-(9+9)/2 = 9

3.mode-9

for data set 3

1.mean-22.3

2.median-21

3.mode-no mode with this data set

hope this helped!!

A bin of 5 transistors is known to contain 2 that are defective. The transistors are tested one at a time until both defective transistors have been identified. Denote N1 the number of tests until the first defective is identified and N2 the number of tests until the second defective is identified. (a) Find the joint probability mass function of N1 and N2.

Answers

Answer:

sorry I donot know the answer never mind ok

Other Questions
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