Find the area of the figure

Please help :)

Answer:

2x=5y+5

Step-by-step explanation:

Let one number be x, other y

Twice a number(2x) is five more(+5) than 5 times the other number(5y),

It means 2x > 5y

By 5 more, so

2x=5y+5

Answer:

Should be (B).

8.5

ED2021

Answer: B

Step-by-step explanation:

The area of the patio not taken up by the fountain is 241ft²

Please find attached an image of the patio

Area of the patio not taken up by the fountain = area of patio - area of fountain

The patio is in a shape of a trapezoid. Thus, the area of the patio can be determined by using the formula for the area of a trapezoid

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Characteristics of a trapezoid

Area of a trapezoid =  0.5 x (sum of the lengths of the parallel sides) x height

Taking a look at the image, we are not provided with the height of the trapezoid, just the parallel sides and the hypotenuse.

Pythagoras theorem can be used to determine the the height of the trapezoid

The Pythagoras theorem : a² + b² = c²

where a = height  

b = base = 20 ft - 12 ft = 8ft

8ft / 2 = 4

c =  hypotenuse

a² + 4² = 25²

a² = 625 - 16

a² = 609

√609 = 24.68 ft

Area of the trapezoid = 0.5 x (20 + 12) x 24.68 = 394.88 ft²

The fountain is in the shape of  a circle.

Area of a circle = πr²

Where : = π = pi = 22/7

R = radius  

The radius would have to determined from the circumference

circumference of a circle = 2πr

14π = 2πr

r = 14π / 2π

r = 7

Area of the circle = [tex]\frac{22}{7}[/tex] × 7²

[tex]\frac{22}{7}[/tex] × 49 = 154 ft²

Area of the patio not taken up by the fountain = 394.88 ft² - 154 ft² = 240.88ft²

To round off to the nearest square, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.

The tenth digit is greater than 5, so one is added to 0. The number becomes 241ft²

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Answer:

[tex]l=56m[/tex]

Step-by-step explanation:

From the question we are told that:

Angle from vertical [tex]\theta =5.6[/tex]

Horizontal Distance [tex]d=107m[/tex]

Angle of elevation [tex]\gamma=28.6[/tex]

Generally the Trigonometric equation for exterior angles is mathematically given by

[tex]Exterior\ angles=\sum of\ two\ interior\ angles[/tex]

Where

[tex]Exterior angles=90 \textdegree +5.6 \textdegree[/tex]

Therefore

[tex]90 \textdegree +\theta \textdegree=\omega+\gamma[/tex]

[tex]90 \textdegree +5.6 \textdegree=\omega+28.6 \textdegree[/tex]

[tex]\omega=67 \textdegree[/tex]

Generally the equation for The Sine rule is mathematically given by

[tex]\frac{sin \omega }{d}=\frac{sin \gamma}{l}[/tex]

[tex]l=\frac{107 sin 28.6}{sin 67 \textdegree }[/tex]

[tex]l=56m[/tex]

Answer:

[tex]y \: \alpha \: {x}^{3} \ \\ y \: = k {x}^{3} \\ where \: y = 7 \: and \:x = 3 \\ y = k {x}^{3} \\ 7 = k ( {3)}^{3} \\ 7 = 27k \\ k = \frac{7}{27} \\ \\ so \: \: y = \frac{7}{27} {x}^{3} \\ \\ y = \frac{7}{27} {4}^{3} \\ y = \frac{448}{27} [/tex]

the required value of y at x = 4 is 16.64.

Given that,
y varies directly as the cube of x. When x = 3, then y = 7.To determine the y when x = 4.

Proportionality is defined as between two or more sets of values, and how these values are related to each other in the sense that are they directly proportional or inversely proportional to each other.

Here,
y is directly proportional to the cube of x i.e
y ∝ x³
y = kx³   - - - - - (1)
where k is proportionality constant,
At x = 3 y = 7
7 = k (3)³
7 / 27 = k
k = 0.26
Put k in equation 1

y = 0.26 x³
Now at x = 4
y = 0.26 * 4³
y = 0.26 * 64
y =  16.64

Thus, the required value of y at x = 4 is 16.64.

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If an answer is not exact then that will be unequal.

A difference between two values indicates whether one is smaller, larger, or basically not similar to the other.

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

In other words, inequality is just the opposite of equality for example 2 =2 then it is equal but if I say 3 =6 then it is wrong the correct expression is 3 < 6.

If a value is not equal to the answer of that value then that is called unequal.

For example 2 and 3 then 2 is not equal to 3 so it will be inequal i.e. 2<3.

Hence "If an answer is not exact then that will be unequal".

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Answer:

(cosA+2)(cosA+1)

Step-by-step explanation:

cos^2A+cosA+2cosA+2

=cos(A)(cosA+1)+2(cosA+1)

=(cosA+2)(cosA+1)

Answer:

C

Step-by-step explanation:

32% of 12 =

32/100 x 12

= 3.84

So, C would be the correct choice

I wasn't sure about my answer so used the Gauthmath App

Answer:

[tex]\pi = \frac{22}{7} [/tex]

Use this OK bro.

The shortest length (circumference) of the string is 18.84cm.

The circumference is that certain length that requires to enclose a  circle with respective of a fixed length known as radius. If radius of cylinder be r, then the circumference will be 2πr.

The required length of the string is the circumference of the base of the cylinder.

The radius of the cylinder is 3cm.

Taking π=3.14, the circumference will be : 2*3.14*3cm

=18.84cm

The shortest length of the string is 18.84cm.

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9514 1404 393

Answer:

  69.1 ft

Step-by-step explanation:

The diameter of the circle is 24 ft. The length of the arc is more than twice the diameter, so cannot be less than about 50 ft. The only reasonable choice is ...

  69.1 ft

__

The circumference of the circle is ...

  C = 2πr = 2(3.14)(12 ft) = 75.36 ft

The arc length of interest is 330° of the 360° circle, so is 330/360 = 11/12 times the circumference.

  s = (11/12)(75.36 ft) = 69.08 ft ≈ 69.1 ft

Answer:D

Step-by-step explanation:

Answer:

I want in English

Step-by-step explanation:

I don't know other languages than English

Recall that

[tex]\sin(x)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n+1}}{(2n+1)!}[/tex]

Differentiating the power series series for y(x) gives the series for y'(x) :

[tex]y(x)=\displaystyle\sum_{n=0}^\infty a_nx^n \implies y'(x)=\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty (n+1)a_{n+1}x^n[/tex]

Now, replace everything in the DE with the corresponding power series:

[tex]y'-2xy = 6\sin(3x) \implies[/tex]

[tex]\displaystyle\sum_{n=0}^\infty (n+1)a_{n+1}x^n - 2\sum_{n=0}^\infty a_nx^{n+1} = 6\sum_{n=0}^\infty(-1)^n\frac{(3x)^{2n+1}}{(2n+1)!}[/tex]

The series on the right side has no even-degree terms, so if we split up the even- and odd-indexed terms on the left side, the even-indexed [tex](n=2k)[/tex] series should vanish and only the odd-indexed [tex](n=2k+1)[/tex] terms would remain.

Split up both series on the left into even- and odd-indexed series:

[tex]y'(x) = \displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} + \sum_{k=0}^\infty (2k+2)a_{2k+2}x^{2k+1}[/tex]

[tex]-2xy(x) = \displaystyle -2\left(\sum_{k=0}^\infty a_{2k}x^{2k+1} + \sum_{k=0}^\infty a_{2k+1}x^{2k+2}\right)[/tex]

Next, we want to condense the even and odd series:

• Even:

[tex]\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2k+2}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2(k-1)+1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2k-1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty \bigg((2k+1)a_{2k+1} - 2a_{2k-1}\bigg)x^{2k}[/tex]

• Odd:

[tex]\displaystyle \sum_{k=0}^\infty 2(k+1)a_{2(k+1)}x^{2k+1} - 2\sum_{k=0}^\infty a_{2k}x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2(k+1)}-2a_{2k}\bigg)x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1}[/tex]

Notice that the right side of the DE is odd, so there is no 0-degree term, i.e. no constant term, so it follows that [tex]a_1=0[/tex].

The even series vanishes, so that

[tex](2k+1)a_{2k+1} - 2a_{2k-1} = 0[/tex]

for all integers k ≥ 1. But since [tex]a_1=0[/tex], we find

[tex]k=1 \implies 3a_3 - 2a_1 = 0 \implies a_3 = 0[/tex]

[tex]k=2 \implies 5a_5 - 2a_3 = 0 \implies a_5 = 0[/tex]

and so on, which means the odd-indexed coefficients all vanish, [tex]a_{2k+1}=0[/tex].

This leaves us with the odd series,

[tex]\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1} = 6\sum_{k=0}^\infty (-1)^k \frac{x^{2k+1}}{(2k+1)!}[/tex]

[tex]\implies 2(k+1)a_{2k+2} - 2a_{2k} = \dfrac{6(-1)^k}{(2k+1)!}[/tex]

We have

[tex]k=0 \implies 2a_2 - 2a_0 = 6[/tex]

[tex]k=1 \implies 4a_4-2a_2 = -1[/tex]

[tex]k=2 \implies 6a_6-2a_4 = \dfrac1{20}[/tex]

[tex]k=3 \implies 8a_8-2a_6 = -\dfrac1{840}[/tex]

So long as you're given an initial condition [tex]y(0)\neq0[/tex] (which corresponds to [tex]a_0[/tex]), you will have a non-zero series solution. Let [tex]a=a_0[/tex] with [tex]a_0\neq0[/tex]. Then

[tex]2a_2-2a_0=6 \implies a_2 = a+3[/tex]

[tex]4a_4-2a_2=-1 \implies a_4 = \dfrac{2a+5}4[/tex]

[tex]6a_6-2a_4=\dfrac1{20} \implies a_6 = \dfrac{20a+51}{120}[/tex]

and so the first four terms of series solution to the DE would be

[tex]\boxed{a + (a+3)x^2 + \dfrac{2a+5}4x^4 + \dfrac{20a+51}{120}x^6}[/tex]

Answer:

The expected number of offspring is 2

Step-by-step explanation:

The given parameters can be represented as:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.24} & {0.25} & {0.19} & {0.17} & {0.15} \ \end{array}[/tex]

Required

The expected number of offspring

This implies that we calculate the expected value of the function.

So, we have:

[tex]E(x) = \sum x * P(x)[/tex]

Substitute known values

[tex]E(x) = 0 * 0.24 + 1 * 0.25 + 2 * 0.19+ 3 * 0.17 + 4 * 0.15[/tex]

Using a calculator, we have:

[tex]E(x) = 1.74[/tex]

[tex]E(x) = 2[/tex] --- approximated

Answer:

Does the answer help you

Answer:

1. x = 7

2. 270x+274

Explanation:

see attached filed for step by step reasoning

Using the z-distribution, it is found that the 99% confidence interval to estimate the treatment effect of buproprion (placebo-treatment) is (-0.234, -0.024).

The confidence interval is:

[tex]\overline{x} \pm zs[/tex]

In which:

In this problem, we are given that z = 2.576, s = 0.0407. The sample mean is the difference of the proportions, hence:

[tex]\overline{x} = \frac{28}{162} - \frac{82}{272} = -0.129[/tex]

Then, the bounds of the interval are given by:

[tex]\overline{x} - zs = -0.129 - 2.576(0.0407) = -0.234[/tex]

[tex]\overline{x} + zs = -0.129 + 2.576(0.0407) = -0.024[/tex]

The 99% confidence interval to estimate the treatment effect of buproprion (placebo-treatment) is (-0.234, -0.024).

More can be learned about the z-distribution at https://brainly.com/question/25890103

Answer:

0.03

Step-by-step explanation:

Answer:

554.7

Step-by-step explanation:

The pay=25.8*14+(25.8)*5*1.5=554.7

Answer:

2 with 3 left over

Step-by-step explanation:

17 divided by 2 is 14 with 3 remaining

Answer:

2 pies

Step-by-step explanation:

Answer:

1.3846

Step-by-step explanation:

Answer:

[tex](a+b)^{2} =a^{2}+2ab+b^{2}[/tex]

[tex](1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)[/tex]

Therefore, [tex]w^{2} +6w+9[/tex] makes a perfect squared.

Answer:

Option d (7.84 or less) is the right alternative.

Step-by-step explanation:

Given:

[tex]\sigma^2=1936[/tex]

[tex]\sigma = \sqrt{1936}[/tex]

   [tex]=44[/tex]

Random sample,

[tex]n = 121[/tex]

The level of significance,

= 0.95

or,

[tex](1-\alpha) = 0.95[/tex]

        [tex]\alpha = 1-0.95[/tex]

[tex]Z_{\frac{\alpha}{2} } = 1.96[/tex]

hence,

The margin of error will be:

⇒ [tex]E = Z_{\frac{\alpha}{2} }(\frac{\sigma}{\sqrt{n} } )[/tex]

By putting the values, we get

        [tex]=1.96(\frac{44}{\sqrt{121} } )[/tex]

        [tex]=1.96(\frac{44}{11} )[/tex]

        [tex]=1.96\times 4[/tex]

        [tex]=7.84[/tex]    

Answer:

.3

Step-by-step explanation:

Take path A = .5

Then Path D = .6

P(a and D) = .5 *.6 = .3

Answer:

19.5

Step-by-step explanation:

let burger be x and fries be y

2x+y = 6.5

6x+3y = 3(2x+y) =3(6.5) =19.5

Answer:

650 calls

Step-by-step explanation:

so since you have 18$ per month plus 5 cents per call you would do

18+0.5n(n represent the number of calls)= the total fee of $50.50 cents.

thus,now you need to figure out how much the phone calls were without the monthly fee so you would do:

50.50-18=32.50

so 32.50 is the price of all the phone calls

then you divide 32.50 by 0.05 which equals to 650

meaning that n=650

hope I helped!

Answer:

Riverbed Cosmetics and Martinez Fashion

March 18, 2020:

Debit Investment in Martinez Fashion $2,580,000

Credit Cash $2,580,000

To record the acquisition of 10% of the 215,000 shares of common stock

June 30, 2020:

Debit Cash $7,400

Credit Dividend Income $7,400

To record dividend income received ($74,000 * 10%).

December 31, 2020:

Debit Investment in Martinez Fashion $215,000

Credit Unrealized Gain $215,000

To record the unrealized gain from the increase in share price.

Situation 2:

Marin, Inc. and Seles Corporation

January 1, 2020:

Debit Investment in Seles Corporation $84,510

Credit Cash $84,510

To record the 30% of Seles's 31,300 shares acquired at a total cost of $9 per share.

June 15, 2020:

Debit Cash $10,980

Credit Investment in Seles Corporation $10,980

To record the 30% of $36,600 dividends paid to all stockholders.

December 31, 2020:

Debit Investment in Seles Corporation $24,030

Credit Retained Earnings $24,030

To record the company's share of the net income.

Step-by-step explanation:

a) Data and Analysis:

Riverbed Cosmetics and Martinez Fashion

March 18, 2020: Investment in Martinez Fashion $2,580,000 Cash $2,580,000 10% of the 215,000 shares of common stock

June 30, 2020: Cash $7,400 Dividend Income $7,400 ($74,000 * 10%)

December 31, 2020: Investment in Martinez Fashion $215,000 Unrealized Gain $215,000

Situation 2:

Marin, Inc. and Seles Corporation

January 1, 2020: Investment in Seles Corporation $84,510 Cash $84,510

30% of Seles's 31,300 outstanding shares of common stock at a total cost of $9 per share

June 15, 2020: Cash $10,980 Investment in Seles Corporation $10,980

30% of $36,600 paid to all stockholders.

December 31, 2020: Investment in Seles Corporation $24,030 Retained Earnings $24,030

Answer:

24 papers belongs to women

Explanation:

The jump from 13 to 39 is "times 3" when comparing the diagonal segments. So the jump from 5 to 'a' must also be "times 3" to keep the sides in the same proportion. Therefore, a = 3*5 = 15.

Or we could solve it like so

13/39 = 5/a

13a = 39*5 ... cross multiplying

13a = 195

a = 195/13 .... dividing both sides by 13

a = 15

Answer:

4%

Step-by-step explanation:

item cost x sales tax rate = sales tax

460 x sales tax rate = 18.40

sales tax rate = 18.40/460

sales tax rate = .04 or 4%