find the complement of 63°​

Answer:

all real numbers

Step-by-step explanation:

The domain is the values that x can take

x can be any real number

answer is

B. 6√2

hope this helps!

Answer:

i would say that the box plot will look somewhat in the middle between 18 and 36 with 36 being the largest and 18 as the smallest

the data will also wont have a major difference in them

hope this helps<3

Answer:

c)

Step-by-step explanation:

please don't trust ;-;

Answer:

The answer is [tex]3^3\times 2^2[/tex].

Step-by-step explanation:

According to the rules of exponents

a^n = a x a x a x .... n times

So,

[tex]3^{2}\times (2^{3}+4)\\\\=9\times (8 +4)\\\\=108\\\\=3^{3}\times 2^{2}[/tex]

Answer:

2x+6>20

2x>20-6

2x/2>14/2

x>7

So your answer would be B

Answer: x=-3

Step-by-step explanation:

Ok let's start by using the distributive property

[tex](-5)(x)+(-5)(7)=-14+2x\\-5x-35=-14+2x[/tex]

Now subtract 2x from both sides

[tex]-5x-35-2x=2x-14-2x\\-7x-35=-14[/tex]

Next add 35 to both sides

[tex]-7x-35+35=-14+35\\-7x=21[/tex]

Finally divide both sides by -7

[tex]\frac{-7x}{-7} =\frac{21}{-7} \\x=-3[/tex]

Answer:

x = -3

Step-by-step explanation:

First, we compute -5(x + 7). -5(x + 7) = -5x - 35. Plugging this into the equation, we have -5x - 35 = -14 + 2x Next, we combine like terms by moving all terms with the variable x to the left side. We have -5x - 2x = -14 + 35. We simplify the equation into -7x = 21. Divide 21 by -7, and we get x = -3.

Answer:

11 unit

Step-by-step explanation:

Applying,

s = √[(y₂-y₁)²+(x₂-x₁)²]...................... Equation 1

Where s = length of the side formed.

From the question,

Given: x₁ = -2, x₂ = 9, y₁ = 5, y₂ = 5

Substitute these values into equation 1

s = √[(9+2)²+(5-5)²]

s = √(11²)

s = 11 unit.

Hence the length of the side formed by the vertices is 11 unit

Answer:

Lily has 63 points and Nala has 49.

Step-by-step explanation:

Since Nala and Lily are playing a dice game where they score points, and after one round, the ratio of Nala's points to Lily's points is 7 to 9, if Nala has 14 more points than Lily, to determine how many points Lily has se you must perform the following calculation:

9 - 7 = 2

14/2 = 7

7 x 7 = 49

7 x 9 = 63

63 - 49 = 14

Therefore, Lily has 63 points and Nala has 49.

Answer:19

Step-by-step explanation: draw the tanks put 6 fish in each tank until you get all 115 in each tank

Answer:

4X+5

Step-by-step explanation:

Dan : X

Harry: X+5

Regan: 2X

X+X+5+2X

Answer:

[tex]Mean = \frac{4x + 5}{3}[/tex]

Step-by-step explanation:

Given:

Dan sold = x

Harry sold 5 more than Dan, that is = x + 5

Regan sold twice as Dan = 2x

[tex]Mean = \frac{ Total \ cars \ sold}{number\ of \ them \ sold \ it }\\\\Mean = \frac{x + ( x+ 5) +2x }{3} = \frac{4x + 5}{3}[/tex]

Answer:

6×-27=-3×

+3×

9/9×=27/9

×=3

Answer:

maybe it is corresponding

Answer: 18.84

Step-by-step explanation:

Formula for circumference of a circle is 2[tex]\pi[/tex]r. Radius is half the diameter so 6/2=3. 2(3.14)(3)= 18.84

Answer:

It will take 48 hours for the entire icicle to melt.

Step-by-step explanation:

12 divided by 1/4 = 48

The linear equation to model the situation is f(x) = -1/4x + 12

Write a linear equation in slope-intercept form to model the situation. An icicle is 12 inches long and melts at a rate of 1/4 inch per hour.

The given parameters are:

The above means that:

A linear equation is represented as:

f(x) = mx + c

Where f(x) represents the function and x represents the number of hours.

So, we have:

f(x) = -1/4x + 12

Hence, the linear equation to model the scenario is f(x) = -1/4x + 12

Read more about rate at:

https://brainly.com/question/4931057

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Answer:

[tex]slope = \frac{2 - ( - 1)}{0 - ( - 1)} \\ = 3 \\ y = mx + c \\ 2 = (0 \times 3) + c \\ c = 2 \\ { \boxed{y = 3x + 2}}[/tex]

Answer:

90 students.

Step-by-step explanation:

279-9=270, and 270 divided by 9 is 90.

[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{1}{2} + \frac{1}{3} [/tex]

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]

[tex]= \frac{3}{6} + \frac{2}{6} [/tex]

Now that the denominators are equal, we can add them.

[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

Answer:

Similar by SAS

Step-by-step explanation:

If you multiply the two given sides by 3/2 you will get the sides for the large triangle

3/2  * 10 = 30 / 2 = 15

3/2 * 24 = 72 / 2 = 36

Therefore they are similar by SAS postulate for similarity. Notice that the right angle is between the legs of the triangle. That is the main qualification that allows you to use SAS for similarity.

Find the other two angles of both the triangles, if they were similar then the triangles are similar

Answer:

a) (4,7/2)

Step-by-step explanation:

Midpoint Formula:

[(-1+9)/2], [(2+5)/2]

(8/2, 7/2) = (4, 7/2)

Answer:

x=4,−2

Step-by-step explanation:

Because Step 1. Move all terms to one side.

{x}^{2}-2x-8=0

x

2

−2x−8=0

2 Factor {x}^{2}-2x-8x

2

−2x−8.

1 Ask: Which two numbers add up to -2−2 and multiply to -8−8?

-4−4 and 22

Step 2. Rewrite the expression using the above.

(x-4)(x+2)

(x−4)(x+2)

and going to;

(x-4)(x+2)=0

(x−4)(x+2)=0

And Step 3. Solve for xx.

1 Ask: When will (x-4)(x+2)(x−4)(x+2) equal zero?

When x-4=0x−4=0 or x+2=0x+2=0

2 Solve each of the 2 equations above.

x=4,-2

x=4,−2

x=4,-2

Our Answer is:

x=4,−2

I Hope It's Helps

Answer:

2 and -4

tso numbers when added gives -2 and 8 incase it's not clear enough.

Answer:

After the third bounce the ball reaches a height of less than 50cm.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient between consecutive terms is always the same, and it's called common ratio. The nth term of a geometric sequence is given by:

[tex]A_n = A_0(r)^{n}[/tex]

In which [tex]A_0[/tex] is the first term and r is the common ratio.

A ball is dropped from a height of 5m.

This means that [tex]A_0 = 5[/tex]

After each bounce it rises to 35% of its previous height.

This means that [tex]r = 0.35[/tex]

Thus

[tex]A_n = A_0(r)^{n}[/tex]

[tex]A_n = 5(0.35)^{n}[/tex]

After how many bounces does the ball reach a Height of less than 50cm?

50cm = 0.5m. This is n for which [tex]A_n = 0.5[/tex]. Thus

[tex]A_n = 5(0.35)^{n}[/tex]

[tex]0.5 = 5(0.35)^{n}[/tex]

[tex](0.35)^n = \frac{0.5}{5}[/tex]

[tex](0.35)^n = 0.1[/tex]

[tex]\log{(0.35)^n} = \log{0.1}[/tex]

[tex]n\log{0.35} = \log{0.1}[/tex]

[tex]n = \frac{\log{0.1}}{\log{0.35}}[/tex]

[tex]n = 2.19[/tex]

Rounding up:

After the third bounce the ball reaches a height of less than 50cm.

Answer:

oiie4546

Step-by-step explanation:

Answer:

16/49

Step-by-step explanation:

2/ 7÷ 7/8

Copy dot flip

2/7 * 8/7

Multiply the numerators

2*8 =16

Multiply the denominators

7*7 = 49

numerator over denominator

16/49

Answer:

[tex]\frac{16}{49}[/tex]

Step-by-step explanation:

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

Answer:

122 squared cm

Step-by-step explanation:

[tex]6*12=72[/tex]

[tex]10*5=50[/tex]

[tex]72+50=122[/tex]

Hope this helps

Answer:

122 squared cm

Step-by-step explanation:

First we split the figure into 2

12 x 6

And,

10 x 5

12 x 6 = 72

and

10 x 5 = 50

Now we add 72 + 50 = 122

Answer:

-6 and -1

Step-by-step explanation:

The excluded values are the values of x that satisfy [tex]2x^{2} + 14x + 12 = 0[/tex]

Let us solve the equation [tex]2x^{2} + 14x + 12 = 0[/tex]

It's a quadratic equation

Thus, let us calculate the discriminant Δ

Δ [tex]= 14^{2} - 4 .2.12 = 100[/tex]

the discriminant is greater than 0, so the equation has two solutions

[tex]x = \frac{-14 - 10}{4} = \frac{-24}{4} = -6[/tex]  or  [tex]x = \frac{-14+10}{4} = \frac{-4}{4} = -1[/tex]

the excluded values are -6 and -1