Distance formula
[tex]\boxed{\sf AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]
[tex]\\ \sf\longmapsto \sqrt{(6 - 0) {}^{2} + {(8 - 0)}^{2} } \\ \\ \sf\longmapsto \sqrt{ {6}^{2} + {8}^{2} } \\ \\ \sf\longmapsto \sqrt{36 + 64 } \\ \\ \sf\longmapsto \sqrt{100} \\ \\ \sf\longmapsto 10[/tex]
What is the length of AC?
Because all the angles are congruent (the same), this is an equilateral triangle. All equilateral triangles have congruent angles and congruent sides, so all sides has to be 14.
A car travels 52/5 kilometers in 23/4 minutes. What is the unit rate in kilometers per minute?
The unit rate of the car that travels 5 2/5 km in 2 3/4 mins is: 1.96 km/min.
What is Unit Rate?Unit rate can be defined as the ratio of one quantity in comparison to another.
Distance travelled by a car = 5 2/5 km = 5.4 km
Time travelled = 2 3/4 mins = 2.75 mins
Unit rate in km/min = 5.4/2.75
Unit rate in km/min = 1.96 km/min.
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If the mean of a normal distribution is 210, what is the median of the
distribution?
210
B. 315
C. 105
D. 420
Answer:
210
Step-by-step explanation:
In a normal distribtuion mean=mode=median
so 210=median
Need help asapppppppppp
-(2x +y) - 2 ( -x - y)
....................
Answer:
First, we apply the Distributive property and then we combine like terms,
To combine like terms, we add or subtract.
[tex]-(2x +y) - 2 ( -x - y)[/tex]
[tex]=-2x-y+2x+2y[/tex]
[tex]=(-2x+2x)+(-y+2y)[/tex]
[tex]=0+y[/tex]
[tex]=y[/tex]
OAmalOHopeO
Answer:
y is the simplest result here.
Step-by-step explanation:
Perform the indicated multiplication as a first step towards simplifying this expression:
-2x - y + 2x + 2y
-2x and 2x cancel each other out, leaving 2y - y, or just y
If sin A= 0.8, find the positive value of cos A
Answer:
cosA = 0.6
Step-by-step explanation:
Using the Pythagorean identity
sin²A + cos²A = 1 ( subtract sin²A from both sides )
cos²A = 1 - sin²A ( take the square root of both sides )
cosA = ± [tex]\sqrt{1-sin^2A[/tex]
Since only the positive value is required , then
cosA = [tex]\sqrt{1-(0.8)^2}[/tex]
= [tex]\sqrt{1-0.64}[/tex]
= [tex]\sqrt{0.36}[/tex]
= 0.6
Answer:
Answer:
Answer:x = 25°
Answer:x = 25°Step-by-step explanation:
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2}
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 2
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2}
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 2
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )
Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )x = 25°
Does anyone know the equation to this trigonometric function? Step by step?
A general cosine function (we could also use a sine function) is written as:
y = A*cos(k*x + p) + M
We will find that the function of the graph is:
f(x) = 2*cos(2*x + 2.09) - 2
Let's return to the general function:
y = A*cos(k*x + p) + M
A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.
Here we can see that the maximum is 0, and the minimum is -4
The differene is: 0 - (-4) = 4
Then:
A = 4/2 = 2
f(x) = 2*cos(k*x + p) + M.
M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:
M = -2
f(x) = 2*cos(k*x + p) - 2
p is the phase shift.
In the graph, we can see that f(0) = -3, so we have:
f(0) = 2*cos(0 + p) - 2 = -3
cos(p) = -1/2
p = Acos(-1/2) = 2.09
Then we have:
f(x) = 2*cos(k*x + 2.09) - 2
Finally, k is related to the frequency of the function.
We can see that the function does a complete cycle at x = pi
This means that:
f(x) = f(x + pi)
Knowing that the period of a cosine function is 2*pi, then:
k*(x + pi) = k*x + 2*pi
k = 2
Then the equation of the graph is:
f(x) = 2*cos(2*x + 2.09) - 2
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Answer(s):
[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.
I am delighted to assist you at any time.
The graph of h(x) = (x - 3)2 is a translation of the
graph of f(x) ….. blank
by
…. Blank units.
Answer:
right by 3 I think
Step-by-step explanation:
Answer: Right by 3 Units
Step-by-step explanation:
Right on edge 2021
can somene explain this to me please?
Answer:
10/3
Step-by-step explanation:
rate of change = gradient
(17-7)/(6-3) = 10/3
basically difference of y values / difference of x values
8 cm 10 cm 15 cm surface area of a rectangle
Answer:
surface area of a square = 2 ( lb + bh + hl )
given that,
length = 8cm
breadth = 10cm
height = 15 cm
surface area = 2 ( 8* 10 + 10*15 + 15*8 )
= 2 ( 80 + 150 + 120 )
= 2 * 350
= 700 [tex]cm^{2}[/tex]
hope this answer helps you!!
Algebra pleaseeeeeee help
Answer:
Step-by-step explanation:
Remark
I have to assume that you know calculus. It is the only way the problem can be done that I know of. If you don't, I'm not sure how you will do this.
The curve is of y = e^(-2x) + x^2 - 3
The curve crosses the y axis when x = 0. The y value is
y = e^0 + x^2 - 3
yint = 1 + 0 - 3
yint = -2
The slope at point (0,-2) is
y' = -2e^(-2x) +2x
y' = -2 at point A
Therefore the normal will have a slope
m1 * m2 = - 1
The slope of the curve C at A = -2
The equation of the tangent line at A = -2x - 2
Call this m1
m2 = slope of the normal
-2 * m2 = -1
m2 = 1/2
Equation of the line (l) =
y = 1/2 x - 2
The graph is shown below. Notice the two lines actually look like they are at a 90 degree angle.
Nike is offering a 30% discount on shirts. A shirt at the store has an original cost of $25. What is the cost of the shirt, in dollars, after the discount
Answer:
$17.5
Step-by-step explanation:
original price of shirt=$25
discount on shirt=30%
discount on shirt in $=$25*30%
discount on shirt=$7.5
cost of shirt after discount=origanl price-discount
=$25-$7.5
=$17.5
The volume of a prism is the product of its height and area of its base, V = Bh. A rectangular prism has a volume of 16y4 + 16y3 + 48y2 cubic units. Which could be the base area and height of the prism?
a base area of 4y square units and height of 4y2 + 4y + 12 units
a base area of 8y2 square units and height of y2 + 2y + 4 units
a base area of 12y square units and height of 4y2 + 4y + 36 units
a base area of 16y2 square units and height of y2 + y + 3 units
Answer: 4. A base area of 16y^2 square units and height of y^2 + y + 3 units
Step-by-step explanation:
Using the distributive property; you can see that 16y^2(y^2+y+3)=
16y^4+16y^3+48y^2
Answer:
D. a base area of 16y2 square units and height of y^2 + y + 3 units
Step-by-step explanation:
Ed22
if you get 76% on a 50 question test how many questions did you get wrong?
Answer:
100% - 76% = 24%
24% = 0.24
0.24*50 = 12
You got 12 questions wrong.
Step-by-step explanation:
Please mark brainliest!
Number of questions that got wrong are 12 .
Given,
76% on a 50 question test.
Here,
Let total percentage value be 100%.
Then,
100% - 76% = 24%
24% questions got wrong.
Number of questions that got wrong out of 50 will be ,
24% of 50
= 0.24*50
= 12
Therefore 12 questions got wrong.
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A candybar box is in the shape of a triangular prism. the volume of the box is 1,200 cubic centimeters.
Part A; what is the height of the base. show your work.
Part B; What is the approximate amount of the cardboard used to make the candybox? Explain how you got your answer.
In ΔRST, m∠R = 92° and m∠S = 71°. Which list has the sides of ΔRST in order from shortest to longest?
Answer:
RS, RT, ST
Step-by-step explanation:
We require the third angle in the triangle
∠ T = 180° - (92 + 71)° = 180° - 163° = 17°
The shortest side is opposite the smallest angle
∠ T = 17° → opposite side RS
The longest side is opposite the largest angle
∠ R = 92° → opposite side ST
Then sides from shortest to longest is
RS, RT, ST
which kind of triangle is shown.
1. obtuse isosceles
2. acute equilateral
3. obtuse scalene
4. right scalene
Answer: 2, acute equilateral
Step-by-step explanation:
the image shows a triangle with all 3 sides congruent and 3 acute angles
recurring decimals to fractions and give Convert the following she answer a simplest form 0•28 when 8 is recurring
Answer:
13/45
Step-by-step explanation:
x = .2888888888
100(x + .2888888)
100x + 28.8888
10x + 2.88888
90x = 26
x = 26/90 = 13/45
……………….pls and thx——————-
Answer:
14 yards shorter
Step-by-step explanation:
Use Pythagoras' Theorem
a²+b²=c²
16²+63²=4225
√4225= 65yd
The diagonal line (c) is 65 yards long
16 + 63 = 79 yd
It would be 14 yards shorter (79-65)
Jason counted by 6's aloud and Lawton counted by 4's aloud. What is the first number they will both say?
Answer:
12
Step-by-step explanation:
The first number they will both say = L.C.M of (6,4)
=> L.C.M of (6,4) is 12
The first number they will both say is 12
in a right triangle the two sides are 10 and 5. find all possible values for the third side.
hint: there are two possibilities
Answer:
1. about 11.18
2. about 8.66
Step-by-step explanation:
1. 5^2 + 10^2= 125
square root of 125 equals about 11.18
2. 10^2-5^2=75
square root of 75 equals about 8.66
what is the answer ，and how do you solve it .please help
Answer:
10
Step-by-step explanation:
2000/ 2x = 10
Multiply each side by 2x
2000/ 2x = 10 *2x
2000 = 20x
Divide by 20
2000/20 = 20x/20
100 = x
Take the square root of each side
sqrt(100) = sqrt(x)
10 = sqrt(x)
A train travelling at 30km/hour reaches a tunnel which is 9 times as long as the train. If the train takes 2 minutes to completely clear the tunnel, how long is the train?
Answer: 111.1 m
Step-by-step explanation:
(30*2)/60 = 1 km ( the tunnel length is 1 Km.)
1 Km = 1000 m.
1000/9 = 111.1 m.
Find the height of the triangle
Answer:
The height is 12 cm
Step-by-step explanation:
Hi there!
We are given a triangle with the 3 sides marked as 15, 20, and 25 and we want to find the height of it (marked as x in the problem).
This problem can seem a bit difficult, but let's see if the triangle is a right triangle first off.
One way to figure out if it is a right triangle is to apply the converse of the Pythagorean theorem.
Let's label the sides, where a is the shortest side, b is the second shortest side, and c is the longest side:
a=15
b=20
c=25
Now square a and b, then add the result together. If it's the same as c squared, then the triangle is a right triangle
15²+20²=25²
225+400=625
625=625
So we can safely say that the triangle is a right triangle
This makes the problem way easier, as there are 2 ways to find the area of a right triangle:
The first way is to multiply the legs (the sides that make up the right angle) together, then divide the result by 2
The other way is to multiply the height and the hypotenuse (the side OPPOSITE to the right angle) together, and then divide the result by 2
First, we need to figure out which sides are the legs, and which side is the hypotenuse
By the triangle inequality theorem, the hypotenuse of a right triangle is the longest side, which means that the 25 cm side is the hypotenuse, and that leaves 15 cm and the 20 cm sides as the legs
So let's find the area of the triangle using the legs
A=[tex]\frac{15*20}{2}[/tex]=[tex]\frac{300}{2}[/tex]=150
So the area of the triangle is 150 cm²
However, as mentioned above, we can also find the area of the triangle by multiplying the hypotenuse by the base, then dividing the result by 2
Which means that the area is also:
A=[tex]\frac{25x}{2}[/tex] cm²
As these both equal the area of the triangle, we can set them equal to each other. This is possible via a property known as transitivity (if a=b and b=c, then a=c)
[tex]\frac{25x}{2}=150[/tex]
Multiply both sides by 2
25x=300
Divide both sides by 25
x=12 cm
So the height of the triangle is 12 cm
Hope this helps!
Is it the answer option D?
Answer:
D
Step-by-step explanation:
graph it
Evaluate the line integral 2 + x2y ds where c is the upper half of the circle x2 + y2 = 1.
Parameterize C by
r(t) = 〈x(t), y(t)〉 = 〈cos(t), sin(t)〉
with 0 ≤ t ≤ π. Then the line integral is
[tex]\displaystyle \int_C (2+x^2y)\,\mathrm ds = \int_0^\pi (2+\cos^2(t)\sin(t))\left\|\mathbf r'(t)\right\|\,\mathrm dt \\\\ = \int_0^\pi (2+\cos^2(t)\sin(t)) \,\mathrm dt = \boxed{\frac23+2\pi}[/tex]
In the paper airplane shown, ABCD = EFGH, M
Answer:
it should be 90 I could be wrong
Circles in the Coordinate Plane
Acellus
Complete the equation of this circle:
A
1
Answer: [tex](x-3)^2 + (y-2)^2 = 16[/tex]
Explanation:
The center of this circle is point A(3,2). These coordinates are the (h,k) values.
The radius is r = 4
Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.
how do we know a given number in the radical is whether rational or irrational
number is described as rational if it can be written as a fraction (one integer divided by another integer). A number is irrational if it cannot be written as a fraction. The decimal form of an irrational number does not terminate or recur.
solve for x. you must show all of your work to receive credit.
Answer:
x = 6
Step-by-step explanation:
The tangent- tangent angle WVU is half the difference of the measure of the intercepted arcs. , that is
5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - (23x - 5) )
5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - 23x + 5)
5x + 17 = [tex]\frac{1}{2}[/tex] (14x + 10) ← multiply both sides by 2 to clear the fraction )
10x + 34 = 14x + 10 ( subtract 14x from both sides )
- 4x + 34 = 10 ( subtract 34 from both sides )
- 4x = - 24 ( divide both sides by - 4 )
x = 6
