Find the exact value of the indicated trigonometric function for the acute angle a:
Given: sin a=5/13, Find: cos a and tan a

We want to compute the probability P(A or B) because we could either solve it following path A, path B, or doing both paths.

P(A) = 1/3

P(B) = 2/5

P(A and B) = P(A)*P(B)  assuming A,B are independent

P(A and B) = (1/3)*(2/5)

P(A and B) = 2/15

--------

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 1/3 + 2/5 - 2/15

P(A or B) = 5/15 + 6/15 - 2/15

P(A or B) = (5 + 6 - 2)/15

P(A or B) = 9/15

We could reduce this to 3/5, but it appears your teacher has chosen not to.

Answer:

So the sqrt(46) is between 6 and 7

Step-by-step explanation:

sqrt(46)

5*5 = 25

6*6=36

7*7=49

So the sqrt(46) is between 6 and 7

=========================================================

Explanation:

We can prove this by contradiction.

Let's say

and

A+B = C

We'll show that a contradiction happens based on this.

If A is rational, then A = p/q where p,q are two integers. The q cannot be zero.

If C is rational, then C = r/s for some other integers. We can't have s be zero.

Note the following

A+B = C

B = C - A

B = r/s - p/q

B = qr/qs - ps/qs

B = (qr - ps)/qs

B = (some integer)/(some other integer)

This shows B is rational. But this is where the contradiction happens: We stated earlier that B was irrational. A number cannot be both rational and irrational at the same time. The very definition "irrational" literally means "not rational".

In short, I've shown that if A+B = C such that A,C are rational, then B must be rational as well.

The template is

rational + rational = rational

Therefore, we've shown that if A is rational and B is irrational, then C cannot possibly be rational. C is irrational.

Another template is

rational + irrational = irrational

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\frac{1}{6}[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Box Probability}}\\\\\rightarrow \frac{\text{# of boxed flawed}}{\text{# of boxes checked}} \\\\\rightarrow \frac{3}{18}\\\\\rightarrow \frac{3/3}{18/3}\\\\\rightarrow\boxed{\frac{1}{6}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

d

Step-by-step explanation:

trust me gang

Answer:

the degree is the value of the highest exponent... 4x^3 the exponent is a three

answer "D"

Step-by-step explanation:

Answer:

He has 4/35 of with money left

Step-by-step explanation:

1 - 3/5 - 2/7 = 4/35

This basically answers the question

Answer:

70.20%

Step-by-step explanation:

Since you seem to be in a rush, let's go for a concise answer.

Let's add 146 and 344 to get 490, and do 344 / 490. This gives us the decimal proportion of ice cream cones that was sold. 344 / 490 = 0.70204.

Excellent. To get the percentage, let's multiply 0.70204 by 100 to get 70.204%. Rounding this to the nearest hundredth gives us 70.20%.

Hope this helps!

Note: This question seems to be badly worded, your 42.44% is correct if it's percentage of ice cream bowls in ice cream cones. I'm assuming that it's the percentage of all ice cream. :)

Answer:

? ≈ 37°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos? = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{4}{5}[/tex] , then

? = [tex]cos^{-1}[/tex] ([tex]\frac{4}{5}[/tex] ) ≈ 37° ( to the nearest degree )

Answer:

(-3)

Step-by-step explanation:

follow me if you want

Answer:

x + y = 320

8x + 5y = 1900

Step-by-step explanation:

The equation x + y = 320 represents how 320 tickets were sold in total, from combining the adult and child tickets sold.

Since adult tickets are $8 each, the money from adult ticket sales can be represented by 8x.

The money from child ticket sales can be represented by 5y.

The equation 8x + 5y = 1900 represents how $1900 worth of tickets were sold.

So, the system of equations for the situation is:

x + y = 320

8x + 5y = 1900

Answer:

y = 220

x = 100

Step-by-step explanation:

x + y = 320

8x + 5y = 1900

x = 320 - y

8(320 - y) + 5y = 1900

2560 - 8y + 5y = 1900

2560 -3y = 1900

-2560        -2560

-------------------------

   -3y = -660

   -----    -------

    -3        -3

      y = 220

x + 220 = 320

    -220   -220

----------------------

        x = 100

LOL

Answer:

D. The over 30s have a larger range and interquartile range than the under 30s

Step-by-step explanation:

In a data set, the range is the difference between the maximum and minimum. So, the range for under 30s is 20, while the range for over 30s is 24. Additionally, the interquartile range is the difference between Q3 and Q1. For a boxplot, Q3 is the line where the box ends and Q1 is the line where the box begins. Therefore, the IQR for the under 30s is 8, and the IQR for over 30s is 11. So, D must be correct.

Answer:

x = 17

Step-by-step explanation:

x ^2 = 8^2+ 15^2

√x^2 =√64+225

x=17

Answer:

17cm.

Step-by-step explaination:

The given triangle is a right angled triangle.

Using Pythagorean Theorem,

a² + b² = c²

Putting the given values in the equation;

(15)² + (8)² = c²

225 + 64 = c²

289 = c²

17² = c² (square root of 289 = 17)

17 = c

c = 17

Therefore, the missing side of the triangle is equal to 17 cm.

Answer:

152

Step-by-step explanation:

Substitute the given value for x.

[tex]8(3(6)+1)\\8(18+1)\\8(19)\\152[/tex]

Answer:

152

Step-by-step explanation:

8(3x+1)

Let x = 6

8(3*6+1)

Multiply inside the parentheses

8(18+1)

Add inside the parentheses

8(19)

Multiply

152

9514 1404 393

Answer:

  D (compute the mean)

Step-by-step explanation:

A box plot is a visual representation of the 5-number summary of a set of data. It is plotted against a number line.

The 5-number summary of the data set is most easily determined from an ordered set of the data, so ordering the data is usually the first step. Since the 5-number summary is plotted against a number line, the next steps are finding the 5-number summary, and creating a suitable number line.

__

The business of adding the data and dividing by the number of data items is a description of computing the mean of the data. That value is not part of the 5-number summary, and is not needed in the creation of the box plot.

Step-by-step explanation:

Part A: Linear Equation.

We can find the slope

[tex] \frac{5 - 15}{1 - 0 } = \frac{ - 10}{1} = - 10[/tex]

So our equation is

[tex]y = - 10x + 15[/tex]

Part B: Exponential Equation

We know that

[tex]15 = a \times b {}^{0} [/tex]

B to the zero power is 1 so

[tex]15 = a[/tex]

This means a =15. Now let find b.

[tex]5 = 15 \times b {}^{1} [/tex]

[tex] \frac{1}{3} = b[/tex]

So the equation is

[tex]y = 15( \frac{1}{3} ) {}^{x} [/tex]

see the attachment hope this helps you

Positive parabola that has a minimum.

It’s positive if it opens upward, negative if it opens downward. It has a minimum if it opens upward, and maximum when it opens downward.

Answer:

n>-4

Step-by-step explanation:

8+n>4

n>4-8

n>-4

Answer:

-4

Step-by-step explanation

Subtract 8 from 4 to get -4.

N = -4

God Bless.

Answer:

A

Step-by-step explanation:

cause it will be more faster just because it is in a solid phase or it is solid

The time taken to hit the ground is 6.25 sec.(Option B)

How to calculate time?

It is given that penny follows the trajectory:

[tex]y = -4.9x^2 + 32x + 425[/tex]

Differentiating it we get:

[tex]\dfrac{dy}{dx} =-9.8x+32[/tex]

At y=425, it is obvious that x=0

So dy/dx at x=0 is 32.

Now the vertical component of the velocity is 32sinФ (where Ф is the angle at which penny is thrown).

Ф[tex]=\tan^{-1}(32)[/tex]

Vertical component=[tex]32*\sin(\tan^{-1}(32))[/tex]=31.98 ft/sec

Now applying the equation of motion: acceleration=-32ft/sec^(2)

u=31.98ft/sec   s=-425   t=?

[tex]s=ut+\frac{1}{2} at^{2}[/tex]

[tex]-425=31.98t-16t^2[/tex]

[tex]16t^2-31.98t-425=0[/tex]

Solving the quadratic equation we get:

t=6.249 sec≅6.25 sec

Therefore, the time taken is 6.25 sec.

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18 people is 25% less people so will take 25% longer

25% of 15 is 3.75

3.75+ 15 = 18.75 days ?

The following are the statement justifications and explanatory reasons ;

(a) AD + DB = AB; Is justified by segment addition postulate

Reason

Segment addition postulate states that let A and B represent two points,

Then a third D can be on the line joining A and B, if and only if the

relationship between the points is according to the equation, AD + DB = AB

only

(b) m∠1 + m∠2 = m∠CDB; Is justified by angle addition postulate

Reason

Angle addition postulate states that given that a point B lies between an angle m∠AOC, then we have;

m∠AOC = m∠AOB + m∠BOC

(c) ∠2 ≅ ∠6; Is justified by vertically opposite angles theorem

Reason

Vertical angles formed by the crossing of two lines are always equal

(d) If D is the midpoint of [tex]\overline{AB}[/tex], then AD = [tex]\dfrac{1}{2}[/tex]×AB; Definition of midpoint

Reason

The midpoint of a line is the point that is of equal distance from both ends of the of the line. It is the point halfway between the endpoints

(e) If [tex]\underset{DF}{\rightarrow}[/tex] bisects ∠CDB then ∠1 ≅ ∠2; Definition of angle bisector

Reason

An angle bisector is a ray or line that divides an angle into two angles that are congruent

(f) m∠ADF + m∠FDB = 180°; Linear pair postulate

Reason

The linear pair postulate states that where we have two angles that form a linear pear (their addition forms a straight line), then the two angles are supplementary  (their sum is 180°)

(g) ∠ADF and ∠4 are supplements, then m∠ADF + m∠4 = 180°; Definition of supplementary angle

Reason

Supplementary angle are defined as angles that when added together, have a sum of 180°

(h) If ∠4 is complementary to ∠5, and ∠6 is complementary to ∠5, then ∠4 ≅ ∠6; Transitive property

Reason

Transitive property states that given three real numbers, a, b, and c, if a = b and c = b, then a = c

Learn more about angle properties postulates, and theorems here;

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I am trying to simplify a difference quotient with the form

f(x+h)−f(h)/h

if f(x)=2/x2 I have attempted to cancel out the denominator of the numerator by the least common denominator method. I know that I can solve this using implicit differentiation, but am trying to use the difference quotient to get the partial derivative

Here is my work so far:

f(x+h)−f(x)(h)

=f(2/(x+h)2)−f(2/x2)h

=(2/(x+h)2)−(2/x2)h

here I multiply by the LCD

=(2(x2)−2(x+h)2)/(x2(x+h)2)h

Here I expand out the top and cancel out 2x2

=(2x2−(2x2+4xh+2h2))/(x2(x+h)2)h

=−(4xh+2h2)/(x2(x+h)2))h

Here I think I should multiply by 1/h to get rid of the h on the bottom

I end up with:

=4xh+2h2hx2(x+h)2

factor out an h

=−4x+2hx2(x+h)2

Answer:

x^2 + 10

Step-by-step explanation:

f(x) = 2x ^ 2 + 3

g(x) = x ^ 2 - 7

(f - g)(x) =2x ^ 2 + 3 - (x ^ 2 - 7 )

Distribute the minus sign

             =2x ^ 2 + 3 - x ^ 2 + 7

Combine like terms

            = x^2 + 10

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

[tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex] in the list of fractions [tex]\frac{18}{45}, \frac{14}{30} , \frac{x}{y} \frac{10}{25}, \frac{8}{20}, \frac{16}{40}[/tex].

Equivalent fractions represent the same value even though they look different.

We know we can find an equivalent fraction of a given fraction by or dividing both the numerator and denominator of the given fraction with the same number (maybe LCM or HCF of the numerator or denominator).

[tex]\frac{18}{45}=\frac{18/9}{45/9}=\frac{2}{5}[/tex] (since [tex]9[/tex] is HCF of [tex]18, 45[/tex])

[tex]\frac{14}{30}=\frac{14/2}{30/2}=\frac{7}{15}[/tex] (since [tex]2[/tex] is HCF of [tex]7, 15[/tex])

[tex]\frac{10}{25} =\frac{10/5}{25/5} =\frac{2}{5}[/tex] (since [tex]5[/tex] is HCF of [tex]10, 25[/tex])

[tex]\frac{8}{20} =\frac{8/4}{20/4} =\frac{2}{5}[/tex] (since [tex]4[/tex] is HCF of [tex]8, 20[/tex])

[tex]\frac{16}{40} =\frac{16/8}{40/8} =\frac{2}{5}[/tex] (since [tex]8[/tex] is HCF of [tex]16, 40[/tex])

Thus, [tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex].

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Answer:

3rd option, 2√10

Step-by-step explanation:

x²=4×10

or, x=√(4×10)

or, x=2√10

Answer: C, 2√10

Step-by-step explanation:

Answer:

The probability of choosing a girl is 1/2.

The probability of choosing an A student who is a BOY is 5/28.

1/2 = 14/28, and 14/28 + 5/28 = 19/28. This can be simplified to 0.68

Thus, the answer is B. 0.68

Let me know if this helps!

The required probability of choosing a girl or an A student is 0.82. Option A   is correct.

Given that,
In a math class of 28 students, 14 boys and 14 are girls. On a unit test, 5 boys and 9 girls made an A grade.
A student is chosen at random from the class. What is the probability of choosing a girl or an A student is to be determined.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Total sample space = 28
Number of girls = 14
Number of boys = 14
Number of girls A grade student  = 9

probability of a girl = 14/28 = 0.5
probability of A grader girl  = 9 / 28 = 0.32
Now the probability of choosing a girl or an A grader girl student,
= 0.32 + 0.5
= 0.82

Thus, the required probability of choosing a girl or an A student is 0.82. Option A  is correct.

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Answer:

1(6+13mn+7m^2n^2)

Step-by-step explanation:

The coefficients and variables in this equation have a common factor of 1, therefore the equation will go back to it's original state if you use 1 as the common factor.

I hope this helps and sorry if am wrong

Answer:

A) (√3-√2)/(√3+√2)

Step-by-step explanation:

i think so

Answer:

12

Step-by-step explanation:

F(x)=x^2−2x+4

Let x = |-4| = 4

F(|-4|)=4^2−2(4)+4

     = 16 -8+4

    = 8+4

     = 12