Find the sum : (i) 23123, 11001 and 21302 (iii) 21031, 12301 and 32211 (v) 21003, 12346 and 21220 (ii) 32101, 12301 and 1032 (iv) 301242, 123310 and 10002

We know

Sum of two interior angles =exterior angle

[tex]\\ \sf\longmapsto 2x+x=3x[/tex]

[tex]\\ \sf\longmapsto 3x=3x[/tex]

[tex]\\ \sf\longmapsto x=1[/tex]

Answer:

Hello,

Step-by-step explanation:

[tex]Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}[/tex]

Answer:

17

Step-by-step explanation:

T4 = 4² + 1

T4 = 4² + 1 = 17

Yip yip that's all

Answer:

# of cases: 11

Additional units: 2

Step-by-step explanation:

If each case can hold 8 units, and we want to find the total # number of cases, we have to divide the # of units (8) for one case by the total # units (90).

As you can see, after dividing by 8, we have a total of 11 cases and a remainder of 2 units. The remainder will be the # of additional units because we cannot have another case filled with 8 units.

The expected value, E(x) of the given observation is 185

The expected value is the mean of the overall observed value or random value. In other words, it is the average of the observed values.

The given parameters can be represented as:

[tex]\begin{array}{cccc}x & {100} & {200} & {300} \ \\ P(x) & {40\%} & {35\%} & {25\%} \ \end{array}[/tex]

The following formula calculates the expected value:

[tex]E(x) =\sum x * P(x)[/tex]

So, we have:

[tex]E(x) = 100 * 40\% + 200 * 35\% + 300 * 25\%[/tex]

[tex]E(x) = 40 + 70 + 75[/tex]

[tex]E(x) = 185[/tex]

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Answer:

just show the questions i will help

Step-by-step explanation:

It looks like you want to find

[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt[/tex]

Substitute u = -t ⁶ and du = -6t ⁵ dt. Then

[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt = \frac16 \int (-6t^5) \times (-t^6) e^{-t^6}\,\mathrm dt = \frac16 \int ue^u \,\mathrm du[/tex]

Integrate by parts, taking

f = u   ==>   df = du

dg = eᵘ du   ==>   g = eᵘ

Then

[tex]\displaystyle \frac16 \int ue^u \,\mathrm du = \frac16\left(fg-\int g\,\mathrm df\right) \\\\ =\frac16 ue^u - \frac16\int e^u\,\mathrm du \\\\ =\frac16 ue^u - \frac16 e^u + C \\\\ =-\frac16 t^6 e^{-t^6} - \frac16 e^{-t^6} + C \\\\ =\boxed{-\frac16 e^{-t^6} \left(t^6+1\right) + C}[/tex]

The 8 will end up in the "ones place".

When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.

We need to find the 8 will end up in which place

A negative divided by a negative is positive, then;

2380/ 10 = 238

Therefore, The 8 will end up in the _ ones_ place.

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Answer:

8. SU = 24

9. TU = 16√3

Step-by-step explanation:

Recall: SOH CAH TOA

8. Reference angle (θ) = 30°

Opposite = 8√3

Adjacent = SU

Apply TOA,

Tan θ = Opp/Adj

Substitute

Tan 30° = 8√3/SU

Tan 30° × SU = 8√3

SU = 8√3/Tan 30°

SU = 8√3/(1/√3) (tan 30° = 1/√3)

SU = 8√3*√3/1

SU = 8*3

SU = 24

9. Reference angle (θ) = 30°

Opposite = 8√3

Hypotenuse = TU

Apply SOH,

Sin θ = Opp/Hyp

Substitute

Sin 30° = 8√3/TU

Sin 30° × TU = 8√3

TU = 8√3/sin 30°

TU = 8√3/(½) (sin 30° = ½)

TU = 8√3 × 2/1

TU = 16√3

Answer:

Hence the required probability is, 3/4

Step-by-step explanation:  

At the shelter, he likes :  

a male coolie, a female coolie, a male boxer, a female boxer, a male beagle, a female beagle, a male Labrador, and a female Labrador.  

Let, A denote the event of selecting a male coolie and B denote the event of selecting a male Labrador.  

P(A) = 1/8 = P(B)  

Here the probability of selecting a puppy except A & B is,  

P(AUB)c = 1 - P(AUB) = 1 - { P(A) + P(B) } = 1 - 1/8 - 1/8 = 3/4

Hey there!

A right pyramid with a square base just means that it isn't slanted all funny. If you create a triangle with a point on one of the edges of the base, the center of the base, and the top of the pyramid, it would be a right triangle.

To find the volume of a right pyramid, you just take the base area, multiply it by the height, and then divide by three.

However, we are looking for the height. We have been given, so we will just go backwards.

252×3=756 (multiply instead of divide)

6×6=36 (base is a square, so you just square 6. This is our base area)

756/36=21

So, the vertical height of the pyramid is 21 cubic centimeters.

Have a wonderful day! :D

Answer: infinitely many

Answer:

C.

Step-by-step explanation:

A P E X

Answer:

Not sure but I think it's 3.75

Answer:

q=6

Step-by-step explanation:

3+9+5+7+Q=5Q

5Q-Q=24

Q=6

Answer:

x=145°

Step-by-step explanation:

180 = 35 + x

x = 180-35

x= 145°

Answer:

D

Step-by-step explanation:

Graph it

9514 1404 393

Answer:

Step-by-step explanation:

Let n represent the number of non-cardholder tickets sold. Then total revenue is ...

  2.00n +1.25(578 -n) = 880.00

  0.75n + 722.50 = 880.00

  0.75n = 157.50 . . . . . . . . . . . subtract 722.50

  n = 210 . . . . . . . . . . . . . . . divide by 0.75. Number of non-cardholder tickets

  578 -n = 368 . . . . . number of cardholder tickets

368 cardholder and 210 non-cardholder tickets were sold.

Answer:

The answer is 82.2  

Step-by-step explanation

hope this helps

Answer:

(b) 829 seconds

(c) 13.8 minutes

Step-by-step explanation:

(b) 2.48×10⁸/2.99×10⁵ = 829 seconds

(c) 829/60 = 13.8 minutes

The logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

-------------

-------------

The original function is:

[tex]y = f(x) = e^{0.4x}[/tex]

To find the inverse function, first, we exchange y and x, so:

[tex]e^{0.4y} = x[/tex]

Now, we have to isolate y, and we start applying the natural logarithm to both sides of the equality. So

[tex]\ln{e^{0.4y}} = \ln{x}[/tex]

[tex]0.4y = \ln{x}[/tex]

[tex]y = \frac{\ln{x}}{0.4}[/tex]

Thus, the logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

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Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

Answer:

6000 hope this helps

if the question is 5,422 then the round figure is 5000

but the question is 5,821 its above 5500 will be 6000

Answer:

%17.80

Step-by-step explanation:

17.8% is the probability that more than 4 are wearing their seat belts.

It is a branch of mathematics that deals with the occurrence of a random event.

Given that Police estimate that 25% of drivers drive without their seat belts.

If they stop 6 drivers at random we need to find the probability that more than 4 are wearing their seat belts.

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not.

he drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so P=0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

[tex]P(X=x)=C_{n,x} p^{x} (1-p)^{n-x}[/tex]

[tex]P(X=6)=C_{6,6} 0.75^{6} (1-0.75)^{0} =0.1780[/tex]

Hence, 17.8% is the probability that more than 4 are wearing their seat belts.

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Using the hypothesis test for one sample mean, There is NO SIGNIFICANT EVIDENCE to support the typist's claim

[tex]H_{0} = 45\\H_{1} < 45\\\\[/tex]

The test statistic :

T = (x - μ) ÷ (s/√(n))

T = (43 - 45) ÷ (15/√70)

T = - 2 ÷ 1.7928429

T = -1.12

At α = 0.05

Pvalue :

Degree of freedom, df = 70 - 1 = 69

Pvalue = 0.1333

Decision region :

Reject [tex]H_{0}[/tex] if Pvalue < α

0.1333 > 0.05

Since Pvalue > α We fail to reject the Null

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Translate the given point and line together so that you get a new point and a new line that passes through the origin. This turns the problem into finding the distance between the new point,

p = (4, 4, -4) - (-1, 1, 3) = (5, 3, -7)

and the new line,

r*(t) = r(t) - ⟨-1, 1, 3⟩ = ⟨2t, 2t, -3t⟩

Let p = ⟨5, 3, -7⟩, the vector starting at the origin and pointing to p. Then the quantity ||p - r*(t)|| is the distance from the point p to the line r*(t).

Let u be such that ||p - r*(t)|| is minimized. At the value t = u, the vector p - r*(t) is orthogonal to the line r*(t), so that

(p - r*(u) ) • r*(u) = 0

I've attached a sketch with all these elements in case this description is confusing. (The red dashed line is meant to be perpendicular to r*(t).)

Solve this equation for u :

p • r*(u) - r*(u) • r*(u) = 0

p • r*(u) = r*(u) • r*(u)

and x • x = ||x||² for any vector x, so

p • r*(u) = ||r*(u)||²

⟨5, 3, -7⟩ • ⟨2u, 2u, -3u⟩ = (2u)² + (2u)² + (-3u)²

10u + 6u + 21u = 4u ² + 4u ² + 9u ²

17u ² - 37u = 0

u (17u - 37) = 0

==>   u = 0   or   u = 37/17

We ignore u = 0, since the dot product of any vector with the zero vector is 0.

Then the minimum distance distance between the given point and line is

||p - r*(u)|| = ||⟨5, 3, -7⟩ - 37/17 ⟨2, 2, -3⟩|| = √(42/17)

Step-by-step explanation:

a1. The shape will be a vertical or horizontal line.

a2. The shape will be shaped like a diagonal line increasing as we go right.

a3. The shape will be shaped like a diagonal line decreasing as we go right.

a4. The shape will be shaped like a U facing upwards.

a5.The shape will be shaped like a U facing downwards.

a6. The shape will look like a S shape and it increases as we go right.

a7. The shape will look like a S shape and it decreases as We go right.

a8. The shape look like a W shape and it facing upwards.

a9. The shape look a W shape facing downwards.

We are given function.

[tex]x {}^{5} - 3x {}^{4} - 5x {}^{3} + 5x {}^{2} - 6x + 8[/tex]

b. We can test by the Rational Roots Test,

This means a the possible roots are

plus or minus(1,2,4,8).

c. If we apply Descrates Rule of Signs,

d. Use Desmos to Graph the Function. Some roots are (-2,1,4).

e.

[tex](x {}^{2} + 1) (x - 1)(x - 4)(x + 2)[/tex]

f. The complex zeroes are

i and -i

Polynomial [tex]f(x) = x^{5} -3x^{4} - 5x^{3} + 5x^{2} - 6x + 8[/tex] in factor form: (x-1)(x+2)(x-4)(x-i)(x+i)

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

Shape of the graph for the following polynomial:

Finding zeros of the polynomial given:

[tex]f(x) = x^{5} -3x^{4} - 5x^{3} + 5x^{2} - 6x + 8[/tex]

By factor theorem, if f(t) = 0, t is a zero of the polynomial.

Taking t = 1.

f(1) = 1 - 3 - 5 + 5 - 6 + 8 = 0

(x - 1) is a factor of the polynomial f(x).

Divide f(x) by (x-1) using long division to find the other factors.

f(x)/(x-1) = [tex]x^{4} -2x^{3}-7x^{2} -2x-8[/tex] is also a factor of f(x).

Factorizing it further:

g(x) = [tex]x^{4} -2x^{3}-7x^{2} -2x-8[/tex]

g(-2) = 16 + 16 - 28 + 4 - 8 = 0

(x + 2) is a factor of g(x) and thus f(x).

g(x)/(x+2) = [tex]x^{3} - 4x^{2} +x - 4[/tex] is a factor of f(x).

Factorizing it further:

k(x) = [tex]x^{3} - 4x^{2} +x - 4[/tex]

k(4) = 64 - 64 + 4 - 4 = 0

(x - 4) is a factor of k(x) thus of f(x).

k(x)/(x-4) = [tex]x^{2} +1[/tex]

Factorizing it further:

l(x) = [tex]x^{2} +1[/tex] = (x + i)(x - i)

Zeros of f(x) = 1, -2, 4, ±i

Rational zeros :  1, -2, 4

Positive real zeros: 1, 4

Negative real zeros: -2

Complex zeros: ±i

Polynomial in factor form: (x-1)(x+2)(x-4)(x-i)(x+i).

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Answer:

16

Step-by-step explanation:

1) Find out r of the sequence. The first term(a1) is 16384, the second term (a2) is 8192.

8192=16384*r. r= 0.5

2) Use the rule that an=a1*r^(n-1)

a11=a1*r^10

a11= 16384*((0.5)^10)= 16384/ (2^10)=16.