Explanation:
The Ø means "empty set". It's the set with nothing inside it, not even 0.
We can write Ø as { } which is a pair of curly braces with nothing between them.
The rule is that if we union any set A with Ø, then we'll get set A
A U Ø = A
Ø U A = A
In a sense, it's analogous to adding 0. So it's like saying A+0 = A and 0+A = A.
So that's why {6, 11, 15} U Ø = {6, 11, 15}
There's nothing to add onto the set {6, 11, 15}, so we just get the same thing back again.
The mean of 19 numbers is 1600. If 2000 is added in the number. Find the new mean
Answer:
Here's your answer .
hope it helps you
Due to a sale at Macy's you only have to pay 2/3 of the original price of a blouse. your price AFTER the discount $120. What was the original price? Explain how you arrived at this answer.
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Answer:
$180
Step-by-step explanation:
The relationship between the prices is said to be ...
(amount you pay) = 2/3 × (original price)
To find the original price, multiply the equation by the reciprocal of the coefficient of the (original price).
(3/2)×(amount you pay) = (3/2)(2/3)(original price) = (original price)
(3/2)×$120 = original price = $180
x²-7x+5 in the form (x-a)²-b
Answer:
( x - 3.5)² - 29/4
Step-by-step explanation:
Given :-
x² - 7x + 5Writing in ( x - a)² - b form ,
x² - 7x + 5 x² - 7 * 2/2 * x + 5 x² - (7/2) * 2 * x + 5 x² - (7/2)*2*x +(7/2)²-(7/2)²+5( x - 7/2)² + 5 - 49/4( x - 7/2)² + ( 20-49)/4( x - 3.5)² - 29/4Given: x + 2 < -5.
Choose the solution set.
{x | x R, x < -3}
{x | x R, x < 3}
{x | x R, x < -7}
{x | x R, x < 7}
Answer:
C
Step-by-step explanation:
x + 2 < -5
x < - 5 - 2
x < - 7
Answer:
{x| x R, x<-7}
Step-by-step explanation:
=> x+2<-5
=> x<-5-2
=> x<-7
5. In 2015, Texas led the nation in the percentage of people who lacked health insurance (21.6% of the population). It is known that, nationally, 5% of patients account for 50% of the costs of healthcare. These are the “high cost” patients Assume* that: Being a high cost patient and being uninsured are independent characteristics Insured and uninsured people become “patients” at the same rate The uninsured and high cost patients in Texas are evenly distributed across the state, and that high cost patients are evenly distributed across insured and uninsured patient populations a. What is the probability that a patient in a Texas healthcare facility will be a high cost patient who is uninsured?
Answer: 0.108
Step-by-step explanation:
Since the probability of the uninsured is 21.6% of the population, then the probability of insured will be:
= 1 - 21.6%
= 78.4%
The probability of high cost patients is 5%. Therefore, the probability that a patient in a Texas healthcare facility will be a high cost patient who is uninsured will be:
= 5% × 21.6%
= 0.05 × 0.216
= 0.108
Convert.
{} {}
minutes ==equals 888 hours 373737 minutes
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Answer:
517 minutes
Step-by-step explanation:
There are 60 minutes in an hour, so 8×60 = 480 minutes in 8 hours.
In 8 hours 37 minutes, there are ...
480 min + 37 min = 517 minutes
From the table below, determine whether the data shows an exponential function. Explain why or why not.
x
3
2
1
–1
y
8
2
0.5
0.125
a. No; the domain values are at regular intervals and the range values have a common factor 0.25. b. No; the domain values are not at regular intervals although the range values have a common factor. c. Yes; the domain values are at regular intervals and the range values have a common factor 4. d. Yes; the domain values are at regular intervals and the range values have a common factor 0.25.
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Answer:
b. No; the domain values are not at regular intervals although the range values have a common factor.
Step-by-step explanation:
The differences between x-values are ...
-1, -1, -1, -2 . . . . not a constant difference
The ratios of y-values are ...
2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference
The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.
Can someone help asap?
Answers:
sin = -5/13tan = 5/12csc = -13/5sec = -13/12cot = 12/5=============================================
Explanation:
The angle theta is between pi and 3pi/2, excluding both endpoints.
This places theta in the third quadrant (Q3) between 180 degrees and 270 degrees. The third quadrant is in the southwest.
Plot point A at the origin. 12 units to the left of this point, will be point B. So B is at (-12,0). Then five units lower is point C at (-12,-5). Refer to the diagram below. Notice how triangle ABC is a right triangle.
The angle theta will be the angle BAC, or simply angle A.
Since cos(theta) = -12/13, this indicates that
AB = -12 = adjacent
AC = 13 = hypotenuse
Technically, AB is should be positive, but I'm making it negative so that we can then say
cos(angle) = adjacent/hypotenuse
cos(theta) = AB/AC
cos(theta) = -12/13
------------------
If you apply the pythagorean theorem, you should find that BC = 5, which I'll make negative since we're below the x axis. Then we can say
sin(theta) = opposite/hypotenuse
sin(theta) = BC/AC
sin(theta) = -5/13
------------------
If you divide sine over cosine, then you'll get 5/12. The 13's cancel out. This is the value of tangent.
Or you could say
tan(theta) = opposite/adjacent
tan(theta) = BC/AB
tan(theta) = (-5)/(-12)
tan(theta) = 5/12
------------------
To find csc, aka cosecant, you apply the reciprocal to sine
sin = -5/13 which means csc = -13/5
sec, or secant, is the reciprocal of cosine
cos = -12/13 leads to sec = -13/12
and finally cotangent (cot) is the reciprocal of tangent
tan = 5/12 leads to cot = 12/5
------------------
Note: everything but tan and cot is negative in Q3.
Pls help quick:
The following figures are not drawn to scale but
AB and CD (if present in the picture) are straight lines. Find x:
Step-by-step explanation:
2x+60°= 110°
2x= 110-60
2x= 50
x= 25°
when a number is added to 1/5 of itself, the result is 24. the equation that models this problem is n+1/5n=24. what is the value of n?
What is 35 degrees Celsius in Fahrenheit equal
Answer:
95°Fahrenheit
hipe this helps you
Greatest to least 2,250 2,700 2,450 2,500
Answer:
sorting;
2,7002,5002,450 2,250greatest = 2,700
least = 2,250
HAVE A NİCE DAY
Step-by-step explanation:
GREETINGS FROM TURKEY ツ
simplify 6 x + 3y /3
Answer:
6x + y
Step-by-step explanation:
6x + 3y/3
6x + y
Answer:
6x + y
Step-by-step explanation:
6x + 3y / 3
cancel 3y by 3
6x + y
Consumers Energy states that the average electric bill across the state is $39.09. You want to test the claim that the average bill amount is actually different from $39.09. What are the appropriate hypotheses for this test
The null hypothesis is [tex]\mu = 39.09[/tex]
The symbol [tex]\mu[/tex] is the Greek letter mu
The alternate hypothesis is [tex]\mu \ne 39.09[/tex] telling us we have a two-tailed test here. The "not equal" is directly tied to the keyword "different" given in the instructions. In other words, mu being different from 39.09 directly leads to [tex]\mu \ne 39.09[/tex]
So either mu is 39.09 or it's not 39.09
You can use H0 and H1 to represent the null and alternate hypotheses respectively.
----------------------
Summary:
The two hypotheses are
H0: [tex]\mu = 39.09[/tex]
H1: [tex]\mu \ne 39.09[/tex]
This is a two tailed test.
HELPPP PLEASEEE! I tried everything from adding to dividing, subtracting, multiplying but still no correct answer. Can someone help me out here please? I am not sure where to start either now. Thank you for your time.
How can you use transformations to graph this function?
Answer:
What function?
Step-by-step explanation:
SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi/h. At what rate is the distance between the cars increasing two hours later
Answer:
The rate at which the distance between the cars increasing two hours later=52mi/h
Step-by-step explanation:
Let
Speed of one car, x'=48 mi/h
Speed of other car, y'=20 mi/h
We have to find the rate at which the distance between the cars increasing two hours later.
After 2 hours,
Distance traveled by one car
[tex]x=48\times 2=96 mi[/tex]
Using the formula
[tex]Distance=Time\times speed[/tex]
Distance traveled by other car
[tex]y=20\times 2=40 mi[/tex]
Let z be the distance between two cars after 2 hours later
[tex]z=\sqrt{x^2+y^2}[/tex]
Substitute the values
[tex]z=\sqrt{(96)^2+(40)^2}[/tex]
z=104 mi
Now,
[tex]z^2=x^2+y^2[/tex]
Differentiate w.r.t t
[tex]2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]
[tex]z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}[/tex]
Substitute the values
[tex]104\frac{dz}{dt}=96\times 48+40\times 20[/tex]
[tex]\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}[/tex]
[tex]\frac{dz}{dt}=52mi/h[/tex]
Hence, the rate at which the distance between the cars increasing two hours later=52mi/h
Multiply the polynomial 4x(2x+3) (show work pls)
Answer:
8^2+12x
Step-by-step explanation:
4x(2x+3)
=4x times 2x+4x times 3
=4 times 2xx+4 times 3x
Answer:
8x^2 +12x
Step-by-step explanation:
Step 1) Multiply each term in the parentheses by 4x
4xx2x+4xx3
Step 2) Calcuate the product
8x^2 +12x
Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linearly independent solutions to the corresponding homogeneous equation for t > 0.
ty'' + (2t - 1)y' - 2y = 7t2 e-2t y1 = 2t - 1, y2 = e-2t
Recall that variation of parameters is used to solve second-order ODEs of the form
y''(t) + p(t) y'(t) + q(t) y(t) = f(t)
so the first thing you need to do is divide both sides of your equation by t :
y'' + (2t - 1)/t y' - 2/t y = 7t
You're looking for a solution of the form
[tex]y=y_1u_1+y_2u_2[/tex]
where
[tex]u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]
[tex]u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]
and W denotes the Wronskian determinant.
Compute the Wronskian:
[tex]W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}[/tex]
Then
[tex]u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t[/tex]
[tex]u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}[/tex]
The general solution to the ODE is
[tex]y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}[/tex]
which simplifies somewhat to
[tex]\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}[/tex]
Describe how the graph of y = |x - 2| - 5 is a transformation of the graph of y = |x|. Use terms such as "shifted", "reflected", "stretched", or "compressed".
Answer:
The original graph was shifted 2 units to the left and 5 units down.
Step-by-step explanation:
y = |x|
From this, we go to: y = |x - 2|.
When we want to shift a function f(x) a units to the left, we find f(x - a). So first, the graph was shifted 2 units to the left.
y = |x - 2|.
From this, we go to: y = |x - 2| - 5.
Shifting a function f(x) down b units is the same as finding f(x) - b, so the second transformation was shifting the graph 5 units down.
Exam V Psych 2317 Name: _____________________________
Attention: Read carefully each sentence and choose the best answer (2 points each)
1) While comparing a sample to a population, which design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
2) While comparing two samples of different individuals, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
3) While comparing the same individuals two times, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
4) While comparing three samples of different individuals with an interest in one variable, which design is appropriate?
please help me now I need it please this is calculuse
Answer:
none of these
Step-by-step explanation:
Because of high tuition costs at state and private universities, enrollments at community colleges have increased dramatically in recent years. The following data show the enrollment (in thousands) for Jefferson Community College for the nine most recent years.
Year Period (t) Enrollment (1,000s)
2001 1 6.5
2002 2 8.1
2003 3 8.4
2004 4 10.2
2005 5 12.5
2006 6 13.3
2007 7 13.7
2008 8 17.2
2009 9 18.1
Required:
a. What type of pattern exists in the data?
b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.
c. What is the forecast for year 10?
Answer:
a. A linear pattern exists in the data.
b. The parameters for the line that minimizes MSE for this time series are as folows:
ß1 = Estimated slope = 1.4567
ß0 = Estimated intercept = 4.7165
Also, we have:
MSE = Mean squared error = 0.4896
c. Forecast for year 10 is 19,280.
Step-by-step explanation:
a. What type of pattern exists in the data?
Note: See Sheet1 of the attached excel file for the line graph.
From the line graph, it can be observed that a linear pattern exists in the data.
b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.
Note: See Sheet2 of the attached excel file for all the calculations to obtain the following:
Sample size = 9
Total of X = 45
Total of Y = 108
Mean of X = Total of X / Sample size = 45 / 9 = 5
Mean of Y = Total of X / Sample size = 108 / 9 = 12
SSxx = Total of (X - Mean of X)^2 = 60
SSyy = Total of (Y - Mean of Y)^2 = 130.74
SSxy = Total of (X - Mean of X) * (Y - Mean of Y) = 87.40
Therefore, we have:
ß1 = Estimated slope = SSxy/SSxx = 87.4 / 60 = 1.4567
ß0 = Estimated intercept = Mean of Y – (ß1 * Mean of X) = 12 - (5 * 1.4567) = 4.7165
Therefore, the parameters for the line that minimizes MSE for this time series are as folows:
ß1 = Estimated slope = 1.4567
ß0 = Estimated intercept = 4.7165
Regression equation which also used in the attached excel is as follows:
Y = ß0 + ß1X =
Y = 4.7165 + 1.4567X …………………. (1)
SSE = Sum of squared error = Total of (Y - Y*)^2 = 3.4273
Therefore, we have:
MSE = Mean squared error = (SSE/(n-2)) = (3.4273 / (9 - 2)) = 0.4896
c. What is the forecast for year 10?
This implies that X = 10
Substitute X = 10 into equation (1), we have:
Y = 4.7165 + (1.4567 * 10) = 19.28
Since it is 1,000s, we have:
Y = 19.28 * 1,000 = 19,280
Therefore, forecast for year 10 is 19,280.
The point-slope form of a line that has a slope of -2 and passes through point (5,-2) is shown below.
y+2=-2(x-5)
What is the equation in slope-intercept form?
O y=-2x+12
O y=-2x+8
O y=-22-7
O y=-2x-3
Savait
Answer:
y = -2x + 8Step-by-step explanation:
The equation in slope-intercept form: y = mx + b
y + 2 = -2(x - 5)
y + 2 = -2x + 10 {subtract 2 from both sides
y = -2x + 8
If you have 3/8 of one pie, what does the denominator tells you ?
Step-by-step explanation:
There was originally 8 pieces of pie.
Answer:
if you have 3/8 of one pie, the denominator tells you that the pie was divided into 8 piece.
GM projected that 3% of their cars produced this year will be defective. If GM produced 1,698 cars that were defective, how many cars did GM produce this year
Answer:
56600 cars
Step-by-step explanation:
Below is the calculation of number of cars produced.
The percentage of cars that is defected = 3%
Number of cars that are defective = 1698 cars
The number of cars produced in a year = 1698 / 3%
The number of cars produced in a year = 56600 cars
After heating a fixed volume of gas at 50 psia from 300° R to 600°R, its pressure will be:
Answer:
100 psia
Step-by-step explanation:
Applying,
Pressure law,
P/T = P'/T'................. Equation 1
Where P = initial pressure, P' = Final pressure, T = initial temperature, P' = Final temperature.
make P' the subject of the equation
P' = PT'/T............ Equation 2
From the question,
Given: P = 50 psia, T = 300°R = (300×5/9)K = 166.66 K, T' = 600°R = (600×5/9)K = 333.33 K
Substitute these values into equation 2
P' = (50×333.33)/166.66
P' ≈ 100 psia
P ≈ 100 psia
A weight clinic recorded the weight lost (in pounds) by each client of a weight control clinic during the last year, and got the following data: 35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57 Assume you created the frequency grouping in intervals of 10 starting at 1. What is the percentile in the next to highest group
Answer:
Class interval ____, Frequency _ C/frequency
1 - 10 ____________ 1 _________ 1
11 - 20 ___________ 4 _________ 5
20 - 30 __________ 6 _________ 11
31 - 40 ___________3 _________ 14
41 - 50 ___________ 1 _________ 15
51 - 60 ___________ 1 _________ 16
Step-by-step explanation:
Given the data :
35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57
Class interval ____, Frequency _ C/frequency
1 - 10 ____________ 1 _________ 1
11 - 20 ___________ 4 _________ 5
20 - 30 __________ 6 _________ 11
31 - 40 ___________3 _________ 14
41 - 50 ___________ 1 _________ 15
51 - 60 ___________ 1 _________ 16
The next to highest frequency group has a frequency of 4 and the highest frequency of 6
Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16
a car travels 10 km southeast and 15 km in a direction 60 degrees north of east. find the magnitude and direction
Answer:
the car travels 10km then 15km 60* north of east
Step-by-step explanation:
PLEASE HELP, according to this function, which is a true statement???????
Answer:
function ar true in the mach on which
Answer:
i think three one is right answer...
