find the volume of the triangular prism. thank you

The order of Rotational symmetry is 2 (option B) for the given figure.

It is basically the number of times we obtain the initial(or same) figure in a single rotation of 360°.

The rotational symmetry of a shape demonstrates that when an object is rotated on its axis, the form of the object examines the same. Many geometrical shapes emerge to be symmetrical when they exist rotated 180 degrees or with some angles, clockwise or anticlockwise. Some of the examples exist as squares, circles, hexagons, etc.

If we rotate the picture by 90°or 270°, then it wont match the initial figure.

If we rotate the picture by 180° from initial, it will match the figure.

If we further rotate it by 180°( full 360° completed) , it will again match.

Hence, it matches 2 times in a single rotation.

Therefore it has rotational symmetry of order 2.

To solve more questions about rotational symmetry refer:

https://brainly.com/question/16883531

#SPJ2

Answer:

(4x4) + (6x11) = 82 for area

4+4+10+11+7+6= 42

Step-by-step explanation:

You can calculate this by calculating the two squares separately, and on the bottom line, it is 10, so just subtract 4 to make the rectangle on the right, separate from the square on the left. (for area)

Answer:

45 degrees

Step-by-step explanation:

the 2 angles are supplementary (add up to 180 degrees)

180-135=45

Answer:

Does the answer help you?

Answer:

b^27

Step-by-step explanation:

Answer:

A. b^27

You multiply 9x3 and you get 27 with the base "b"

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

y = x^2 +2x - 8

Factor

y = ( x+4)(x-2)

The zeros are

x+4 = 0  x-2 = 0    

x= -4    x= 2

(-4,0)  (2,0)

The axis of symmetry is 1/2 way between the zeros

(-4+2)/2 = -2/2 = -1

x = -1

The x coordinate of the vertex is at the axis of symmetry

The y value is found by substituting x=-1

y = (-1+4) (-1-2)= 3*-3 = -9

Vertex ( -1,-9)

The domain is all real numbers

The range is from -9 up

y≥ -9  since it opens upward

Answer:

Part 1

The number of baseball players that are to split the profits = 9 baseball payers

The amount of money each player earned = $326

Let x represent the total amount of money raised, and given that each baseball player received equal amount of the profits we have the following division equation;

[tex]The \ division \ equation \ is , \dfrac{x}{9} = \$ \, 326[/tex]

Part 2

Solving for the variable, gives;

x = 9 × $ 326 = $2,934

The amount of profits from the fundraiser, x = $2,934

Part 3

The amount, A, each of the 9 players will earn from the profit of $2,934 raised in the fund raiser is given as follows;

A = $2,934/9 = $326

∴ The amount each of the 9 players will earn, A = $326, therefore the answer corresponds to the value in the question and is therefore, correct

Step-by-step explanation:

Answer:

[tex]58.99[/tex]

Step-by-step explanation:

[tex] \tan(61) = \frac{o}{a} \\3.74 = \frac{x}{17} \\ x = 17 \times 3.74 \\ = 58.99[/tex]

Answer:

m=4

Step-by-step explanation:

m = y2 - y1/x2 - x1

(y2=8, y1=0, x2= 2, x1=0)

m = y2 -y1/x2 - x1

= 8 - 0/2 - 0

= 8/2

=4

Answer:

4/8= 2/4=1/2= 50%

Step-by-step explanation:

4 out of the 8 new cars have a fuel efficiency of less than 27 mpg. that is is 50%

Answer:

impossible

Step-by-step explanation:

The sum of the internal angles of the regular polygon and the theorem n-sided polygon is equal to: (n-2)×180° (n is greater than or equal to 3 and n is an integer)

when n=3，The internal angle sum is 180°

Answer:

y=-4x+16

Step-by-step explanation:

Okay, so a perpendicular line has an opposite reciprocal slope.

The slope for the first line is x/4, but I like to write it as 1/4x, since it's easier to look at.

The opposite reciprocal for 1/4x is -4x

So far, we have y=-4x+ [  ]

To find the remaining b value, we can use the given point intersection.

plug in the x and y values given (4, -1) and solve for b.

The equation for the perpendicular line is y=-4x+16

Answer: The graph DOES represent a function.

Explanation: If you use a vertical line in the function and it only intersects once, that means it is a function. If it intersects twice, it is not a function.

See examples:

Answer:

Y = 8 + 2d

Step-by-step explanation:

Y = 8 + 2d where d is miles traveled

Answer:

y = 2d + 8

Brainliest, please!

Step-by-step explanation:

y = mx + b

m = slope, b = y-intercept

The flat rate of $8 is the y-intercept, and the slope is $2.

y = 2x + 8

We can change x to d to match the context of this problem.

y = 2d + 8

Use the Pythagorean theorem

? = sqrt(52^2 + 19^2)

? = sqrt(2704 + 361)

? = sqrt(3065)

Answer: sqrt(3065)

Answer:

(2, 0) and (0, 4) are coordinates in the form of (x, y)

(2, 0) -> x = 2, y = 0

(0, 4) -> x = 0, y = 4

Answer:

4 TOPPING WITH 5 CENTS LEFT

Step-by-step explanation:

A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so

3.5-0.75=2.75 (1 topping

2.75-0.75=2 (2 topping

2-0.75=1.25 (3 topping

1.25-0.75=0.5 (4 topping

there for you can get 4 toppings with 5 cents left over

Answer:

804.2 km³

Step-by-step explanation:

Volume of a cylinder: πr²h

r = radius, h = height

[tex]\pi r^2h\\\pi(8)^2(4)\\\pi(64)(4)\\\pi(256)\\804.2[/tex]

Answer: 290

Step-by-step explanation:

[tex]First\ integer\ on\ line\ n\ is:\ \dfrac{n^2}{2}-\dfrac{n}{2}+1 \\\\For \ line\ 17\ : \dfrac{17^2}{2}-\dfrac{17}{2}+1 =137\\\\\\Last \ integer\ on\ line\ n\ is:\ \dfrac{n*(n+1)}{2} \\\\For\ line\ 17:\ \dfrac{17*(17+1)}{2} =153\\\\Sum=137+153=290[/tex]

I have not say the equation in u(n+3) for the recurrence,

the resolution of the equation caracteristic and the resolution of a system of 3 equations with 3 variables.

Answer:

-80\112 = -5\7

we divided both numbers by 16

Step-by-step explanation:

here's the answer to your question

[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]

Now

[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]

We know

[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]

[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]

Answer:

Given, A={p,q,r}.

Now, possible subsets of A are ,{p},{q},(r) {p,q}.

(q,r) (p,r) (p,q,r)

find the square root and of 1+i√3​  

Answer:

0 is the answer . The explanation is in the attachment .

Answer:

1 / 5

Step-by-step explanation:

Given the outcome of number cube spin : 2, 5, 3, 5, 1, 2, 3, 3, 4, 6

The experimental probability of an event, A is given as :

P(A) = number of times A occurs / total number of trials

Therefore, the experimental probability of getting 2 ;

P(getting 2) = Number of times 2 occurs / total number of trials

P(getting 2) = 2 / 10 = 1/5

Answer:

100000 = 8 (4) ^t

Step-by-step explanation:

We are multiplying by 4 each time

y = a (4)^t

The initial amount is 8

y = 8 (4)^t

We want to get to 100000

100000 = 8 (4) ^t

Answer:

B

8 ⋅ 4^t  = 100,000

Step-by-step explanation:

Answer:

[tex]\sqrt[2]{8}[/tex]

Step-by-step explanation:

Remember the basic format of a fraction raised to a fractional exponent:

[tex]a^\frac{b}{c}=\sqrt[b]{a^c}[/tex]

Some terms to keep in mind are the following:

(a) is the base

(c) is the exponent

(b) is the index

Apply this information to the given problem:

[tex]2^\frac{3}{2}[/tex]

In this case, (2) is the base, and the index; (3) is the exponent. Apply the general format of the fraction exponent to change the expression from an exponent to a radical.

[tex]2^\frac{3}{2}=\sqrt[2]{2^3}[/tex]

Simplify the term under the radical:

[tex]\sqrt[2]{2^3}=\sqrt[2]{8}[/tex]

• {4, 7, 12, 19, … }

has 1st differences

7 - 4 = 3

12 - 7 = 5

19 - 12 = 7

and 2nd differences

5 - 3 = 2

7 - 5 = 2

• {-1, 2, 7, 14, …}

1st differences:

2 - (-1) = 3

7 - 2 = 5

14 - 7 = 7

2nd differences:

5 - 3 = 2

7 - 5 = 2

• {-2, -8, -18, -32, …}

1st differences:

-8 - (-2) = -6

-18 - (-8) = -10

-32 - (-18) = -14

2nd differences:

-10 - (-6) = -4

-14 - (-10) = -4

Answer:

Hello,

Step-by-step explanation:

I  am  going to explain the method with the 1th:

[tex]\begin{array}{ccccc}n & u_n&u_{n+1}-u_{n}&u_{n+2}-2u_{n+1}+u_{n}&v_{n}\\1&4&&6\\2&7&3&9\\3&12&5&2&14\\4&19&7&2&21\\...&&&\\\end{array}\\\boxed{u_{n+2}=2u_{n+1}-u_{n}+2}\\[/tex]

[tex]Let\ say\\v_{n}=u_{n}+2\\v_{n+2}=u_{n+2}+2=(2u_{n+1}-u_{n}+2)+2=2(v_{n+1}-2)-(v{n}-2)+4\\v_{n+2}=2v_{n+1}-v{n}+2\ (1)\\v_{n+3}=2v_{n+2}-v{n+1}+2\ (2)\\(2)-(1)==> \boxed{v_{n+3}=3v_{n+2}-3v_{n+1}+v_n}\\[/tex]

[tex]Caracteristic\ equation:\\P(r)=r^3-3r^2+3r-1=0\\P(r)=(r-1)^3\\v_n=\alpha+\beta*n+\gamma*n^2\\v_1=6 ==> \alpha+\beta*1+\gamma*1=6\\u_2=9 ==> \alpha+\beta*2+\gamma*4=9\\u_3=14 ==> \alpha+\beta*3+\gamma*9=14\\[/tex]

[tex]\begin{bmatrix}1&1&1\\1&2&4\\1&3&9\end{bmatrix}*\begin{bmatrix}\alpha\\\beta\\\gamma\end{bmatrix}=\begin{bmatrix}6\\9\\14 \end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\1&2&4&9\\1&3&9&14\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&2&3&3\\0&2&8&8\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&1&4&4\end{bmatrix}\\\\[/tex]

[tex]\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&0&0\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&0&0&5\\0&1&0&0\\0&0&1&1\end{bmatrix}\\[/tex]

[tex]\alpha=5\\\beta=0\\\gamma=1\\\boxed{v_n=5+0*n+1*n^2}\\\boxed{u_n=5+0*n+1*n^2-2}\\\begin{array}{ccccc}n & u_n\\1&5+1-2=4\\2&5+4-2=7\\3&5+9-2=12\\4&5+16-2=19\\...&...\\\end{array}\\[/tex]