Find 'x' in the following ​

Answers

Answer 1

First we have to find angle D

As it is a quadrilateral

[tex]\\ \sf\longmapsto <A+<B+<C+<D=360[/tex]

[tex]\\ \sf\longmapsto 45+50+35+<D=360[/tex]

[tex]\\ \sf\longmapsto 130+<D=360[/tex]

[tex]\\ \sf\longmapsto <D=360-130[/tex]

[tex]\\ \sf\longmapsto <D=230°[/tex]

Now

[tex]\\ \sf\longmapsto <D+x=360[/tex]

[tex]\\ \sf\longmapsto x+230=360[/tex]

[tex]\\ \sf\longmapsto x=360-230[/tex]

[tex]\\ \sf\longmapsto x=130°[/tex]

Answer 2

Answer:

x = 130

Step-by-step explanation:

Sum of all the angle of quadrilateral = 360°

50 + 45 + 35 + ∠ADC = 360

                130 + ∠ADC = 360

                         ∠ADC = 360 - 130

                         ∠ADC = 230

x = Reflex ∠ADC

  = 360 - 230

  = 130


Related Questions

Help please
Which points lie in the third quadrants? check all that apply.
A. Point F
B. Point B
C. Point C
D. Point D
E. Point E

Answers

Answer:

A. Point F

Step-by-step explanation:

Quadrant I is the top right, Quadrant II is the top left, Quadrant III is the bottom left, and Quadrant IIII is the bottom right. SO basically, the order of quadrants is counterclockwise.

If we look at the bottom left (Quadrant III), we see there is only one point there; point F.

Hope this helps!

If there is something wrong, please let me know.

Find x round your answer to the nearest integer.

Answers

Answer:

C

Step-by-step explanation:

Note that x is opposite to the given angle and we are also given the hypotenuse.

Since we have an angle and the side opposite to it and the hypotenuse, we can use the sine ratio. Recall that:

[tex]\displaystyle \sin \theta =\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

The opposite side is x, the hypotenuse is 15, and the angle is 53. Substitute:

[tex]\displaystyle \sin 53^\circ = \frac{x}{15}[/tex]

Solve for x:

[tex]x=15\sin 53^\circ[/tex]

Use a calculator (make sure you're in Degrees Mode!). Hence:

[tex]x=11.9795...\approx 12[/tex]

Our answer is C.

Answer:

C. 12

Step-by-step explanation:

Pythagoras Theorem

Please Help!

Use the Parabola tool to graph the quadratic function. f(x)=3x^2−6x+5 Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

Answers

you didn't tell wich program to use and did not include any pictures.

anyways, I graphed the function with desmos (free to use as app and on website)

so that u can see what the graph should look like.

variance based on the zoom is okay of course.

Find the value of x and HE in the triangle

Answers

Answer:

EH = HF by the perpendicular bisector theorem

equation:

3x=x+4

or, 3x-x=4

or, 2x=4

or, x=2

so, HE = 6

Answered by GAUTHMATH

how many candy bars did team sell if they collected $1,00.00

plz help
ASAP

Answers

Answer:

E) 125 boxes

F) 800 candy bars

Step-by-step explanation:

E)

3,125/1.25 = 2500

2500/20 = 125

F)

1000/1.25 = 800

I believe it’s 40 but I may be wrong

9x²+bx+100 as a perfect square​

Answers

Step-by-step explanation:

9x²+bx+ 100

(3x)²+ bx + 10²

(3x)² + 10² + bx

(3x)² + 10² + bx

Find the average (mean) of the given set of data.

22,15,31,40,27

Answers

Answer:

27

Step-by-step explanation:

Hi there!

We are given this set of data:

22, 15, 31, 40, 27

And we want to find the average (or the mean) of the set

To find the mean, we add up all of the values of the data set and then divide it by how many pieces of data we have

So first, add 22, 15, 31, 40 and 27 together

22+15+31+40+27=135

We have 5 pieces of data, so divide 135 by 5

135/5=27

The mean is 27

Hope this helps!

[tex]\boxed{\large{\mathbf{\blue{ANSWER~:) }}}}[/tex]

Data=22,15,31,40,27no of data=5sum of data=22+15+31+40+27=135

we know that,

[tex]\boxed{\sf{mean=\dfrac{sum ~of~ data}{no~ of~ data } }}[/tex]

According to the question,

[tex]{\sf{mean=\dfrac{135}{5 } }}[/tex]

[tex]\sf{ mean=27 }[/tex]

Therefore,

the average (mean) of the given set of data.(22,15,31,40,27) is 27.

the points 9a b,3 lie on the line y=2 out of 3 x-7

Answers

Answer:

a=1/10, b=17/6

Step-by-step explanation:

IF you mean the points (9,a), (b,3) lie on the line y=2/(3x-7),

then a=2/(3*9-7)=1/10;

3=2/(3b-7)

b=17/6

can somebody please help me with this (geometry)

Answers

angle 2 is also 35 since they are alternate interior angles

What's the maximum area you can get for a rectangle with two sides along the x and y axes, and the opposite vertex in the first quadrant along the line y = 20 – 4x?

Answers

Answer:

Remember that a triangle rectangle of length L and width W has an area:

A = W*L

In our rectangle, we have two sides along the x and y axes.

So one of the vertices of our triangle rectangle is the point (0, 0)

And the other vertex, is along the line:

y = -4x + 20

So, if the opposite vertex is at the point:

(x₁, y₁)

We can define the length as the difference between the x-values of each vertex.

L = (x₁ - 0) = x₁

And the width, similarly, as:

W = (y₁ - 0) = y₁

Such that the point (x₁, y₁) is a solution for the equation y = -4x + 20, then we have:

y₁ = -4x₁ + 20

Then we can rewrite the width as:

W = -4x₁ + 20

Now, we can write the area of our rectangle as:

A = (x₁)*(-4x₁ + 20)

A = -4*x₁^2 + 20*x₁

Now we want to maximize the area, notice that the area is given by a quadratic equation with a negative leading coefficient.

Thus, the maximum will be at the vertex of that quadratic equation.

Remember that for a general quadratic equation:

y = a*x^2 + b*x + c

The x-value of the vertex is:

x = -b/(2*a)

so, in our case, the x-value of the vertex will be:

x₁ = -20/(-4*2) = 20/8 = 5/2

Now we can evaluate this in our area equation:

A = -4*(5/2)^2 + 20*(5/2)  = 49.36

This is the maximum area of the rectangle.

need help with this problem

Answers

Answer:

OA⊥OC

∴∠AOB+BOC= 90°

5x+8+6n-6=90

11x+2=90

x=90-2/11

x=88/11

x=8

∠BOC=6x-6

=6(8)-6

=48-6

∠BOC=42°

------------------------------

Hope it helps...

Have a great day!!

Answer:

[tex]<BOC = 42[/tex]

Step-by-step explanation:

In this problem, it is given that lines (AO) and (OC) are perpendicular. This means that when the lines intersect, the four angles formed each have a measure of (90) degrees. As per the given diagram, angles (<AOR) and (<ROC) add up to make (<AOC). Thus, one can form the following equation and solve for (x).

[tex](<AOR) + (<ROC) = (<AOC)[/tex]

Substitute,

[tex](6x-6)+(5x+8)=90[/tex]

Simplify,

[tex]11x+2=90[/tex]

Inverse operations,

[tex]11x+2=90[/tex]

[tex]11x=88\\\\x=8[/tex]

Substitute this into the equation for the measure of angle (<BOC) to find the numerical angle measure:

[tex]<BOC = 6x-6\\x = 8\\\\= 6(8)-6\\\\=48-6\\\\=42[/tex]

∛3x+7=∛2x+1
solve it please

Answers

Answer:

x = -6

Step-by-step explanation:

cube each side :

3x + 7 = 2x + 1

solve for x:

x = -6

The height of a rocket a given number of seconds after it is released is modeled by h (t) = negative 16 t squared + 32 t + 10. What does t represent? the number of seconds after the rocket is released the initial height of the rocket the initial velocity of the rocket the height of the rocket after t seconds The function V(r) = four-thirds pi r cubed can be used to find the volume of air inside a basketball given its radius. What does V(r) represent?

Answers

Answers:

t is the number of seconds after the rocket is released

V(r) is the volume of the ball with radius r.

====================================================

Explanation:

There isn't much to say in terms of explanation. These variables are simply definitions.

Determine the number of real solutions of -2x^2+ 5x – 3 = 0.
2
1 (double root)
5
0

Answers

Answer:

[tex]{ \tt{ - 2 {x}^{2} + 5x - 3 = 0 }} \\ { \tt{2 {x}^{2} - 5x + 3 = 0}} \\ { \tt{(2x - 3)(x - 1) = 0}} \\ { \tt{x = \frac{3}{2} \: and \: 1}}[/tex]

Answer:

2 i think

Step-by-step explanation:

sorry if im wrong

out of 500 bulbs, 0.2 are defective. how many are defctive

Answers

Answer:

100

Step-by-step explanation:

0.2*500=100

100 bulbs 500•0.2=100

A hundred chickadees can eat 100 kg of seeds in 100 days. How many kg of seeds can 10 chickadees eat in 10 days?

Answers

Answer:

1 kg

Step-by-step explanation:

Number of chickadees = 100

Quantity of seed eaten = 100 kg

Number of days = 100

Quantity of seeds each chickadee eats per day =Number of chickadees ÷ Quantity of seed eaten ÷ Number of days

= 100 ÷ 100 ÷ 100

= 1 ÷ 100

= 0.01 kg of seed

How many kg of seeds can 10 chickadees eat in 10 days?

= Quantity of seeds each chickadee eats per day × number of chickadee × number of days

= 0.01 kg × 10 × 10

= 1 kg

10 chickadees eat 1 kg of seeds in 10 days

Can someone help me with this math homework please!

Answers

Common difference = 2nd term - first term = -22.5-(-18)= -22.5+18 = -4.5

PLEASE HELP I BEG ASAP UWILL GET MARKED BRANLIEST

Answers

Answer:

3 C

4 B

5 B

6C

Step-by-step explanation:

3. the negative of the functiin reflects the original function on the x axis

4. multiplying by a number greater than 1 increases the slop of the original function

5. subtracting from x translates the function to the right

6. subtracting from f(x) translates the function down

Dwight wants to build a new rectangular beet farm, but he is first making a list of items he needs to purchase from the store. Dwight decides he will get 160 feet of
fencing to go around the farm that will have a length of 50 feet.
a. Find the width of the farm that Dwight wants to make. Include units.
b. Dwight decides that he will plant 1 beet seed for every square foot of land in this farm and he does not want to purchase any extra seeds. Exactly how many beet seeds should he purchase? Include units.

Answers

Answer:welcome

Step-by-step explanation: sorry I jsit really needed the points

WILL GIVE BRANLIEST AND BE SOOO HAPPY PLEASE HELP!!! 30 POINTS SHARE YOUR SMARTNESS!!

Answers

Answer:

s4 = 270

18+36+72+144 = 270

-- convergent sums to a single value

Step-by-step explanation:

Answer:

S4 = 270

Step-by-step explanation:

The 4th partial sum of the sequence is the sum of the first 4 terms:

S4 = a(1) + a(2) + a(3) + a(4)

Because the sequence is geometric any term can be written in terms of the previous one:

a(n) = r a(n - 1)

And more importantly in terms of the first term a(1) so that

a(2) = r a(1)

a(3) = r a(2) = r^2 a(1)

a(4) = r a (3) = r^3 a(1)

Then the 4th partial sum is

S4 = a(1) + r a(1) + r^2 a(1) + r^3 a(1)

S4 = a(1) (1 + r + r^2 + r^3)

With a a(1) = 18 and r = 2 we have

S4 = 18 (1 + 2 + 4 + 8) = 270

Therefore, the 4th partial sum is 270

Hello I’m trying to solve this problem I just don’t know how to do it.

BUT if someone could help and show me step by step that would be great I’m not trying to ask for the answer

I’m just trying learn how to solve it and so step by step there no rush Thank you

Answers

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

calculate the value of x in circle O. *show your work*​

Answers

Answer:

Step-by-step explanation:

The central angle is twice as big as any angle sharing the endpoints  with the central angle of a chord where the angle is not below the smaller sector.

2*62 = x

x = 124

What is another name for a relation that has each element in its domain paired with exactly one element in its range?​

Answers

A function is a relation in which each element of the domain is paired with exactly one element of the range.

Find one rational number between 1 and 2.

Answers

There are infinitely many rational no.s between two no.s

one rational number between 1 and 2 is

11/10

Help please ! Thank you!

Answers

:) :) :) :) :) :) :) :) :) :) :) :) :)

Consider the three triangular pyramids.

Pyramid 1
Pyramid 2
Pyramid 3

Triangular pyramid 1. The base has a base of 12 meters and height of 2 meters. The height of the pyramid is 10 meters.

Triangular pyramid 2. The base has a base of 6 meters and height of 4 meters. The height of the pyramid is 10 meters.

Triangular pyramid 3. The base has a base of 12 meters and height of 4 meters. The height of the pyramid is 5 meters.

Which statement about their volumes is true? (Recall the formula V = one-third B h.)

O All three pyramids have the same volume.
O All three pyramids have different volumes.
O Only pyramids 1 and 2 have the same volume.
O Only pyramids 1 and 3 have the same volume.

Answers

9514 1404 393

Answer:

  (a) All three pyramids have the same volume

Step-by-step explanation:

The triangular base has an area of ...

  B = 1/2bh . . . . where b is the base of the triangle and h is its height.

The volume of the pyramid is ...

  V = 1/3BH . . . . where B is the area of the base, and H is the height of the pyramid.

Combining these equations gives ...

   V = 1/3(1/2bh)H = 1/6bhH

__

Pyramid 1 volume

  V1 = 1/6(12 m)(2 m)(10 m) = 40 m³

Pyramid 2 volume

  V2 = 1/6(6 m)(4 m)(10 m) = 40 m³

Pyramid 3 volume

  V3 = 1/6(12 m)(4 m)(5 m) = 40 m³

All three pyramids have the same volume.

for which values of X will the rational expressions below the undefined?

Answers

Answer:

x≠-7

Step-by-step explanation:

The function will be undefined when the denominator is zero

x+7≠ 0

x≠-7

Please help solve 1, and 2

Answers

Answer:

Step-by-step explanation:

1). WXYZ is a rectangle,

  Properties of a rectangle,

  i). Opposite sides are equal and parallel.

  ii). All interior angles measure 90°.

  iii). Diagonals are equal in measure.

a). WY = ZX = 30

 Therefore, ZT = [tex]\frac{1}{2}(ZX)[/tex]

                    [tex]ZT=15[/tex]

b). WY = ZX = 45

c). Since, WY = ZX,

    (4b - 16) = (3b + 5)

    4b - 3b = 16 + 5

     b = 21

2). GOAT is a rhombus and m∠OGA = 35°,

    a). m∠TGA = m∠OGA = 35°

    b). m∠GXO = 90°

    c). m∠GXT = 90°

    d). Since adjacent angles of a rhombus are supplementary,

         m∠OGT + m∠GTA = 180°

         70° + m∠GTA = 180°

         m∠GTA = 110°

         m∠GTO = [tex]\frac{1}{2}(m\angle GTA)[/tex]

                        = [tex]\frac{1}{2}(110^{\circ})[/tex]

                        = 55°

     e). Since, opposite angles of a rhombus are equal,

          m∠OGT = m∠OAT = 70°

     f). m∠GOA = m∠GTA = 110°

The height of a baseball in feet can be found by the equation -4.982 – 20t + 1000. How far has the
baseball traveled at t = 6?

Answers

Answer:

875.018

Step-by-step explanation:

To solve this, we must plug in 6 for our t value. So, we have the equation:

-4.982 - 20(6) + 1000

Following the rules of PEMDAS, we have:

-4.982 - 120 + 1000 = 875.018

How many amount will be reqyired to plaster on the four walls at the rate of Rs 315per square meter?find it​

Answers

Incomplete question

Let the area be = 100 square meter

Cost of plaster = Rs 315 per square meter

No of walls = 4

Total area = 400 square meter

Then cost = 400 × 315

= Rs 1,26,000

Answered by Gauthmath must click thanks and mark brainliest

Sorry need pointsssss :-p
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