Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC

Answer:

1) 10/15=2/3

2) You would have to make certain that they have the same three interior angles.

Step-by-step explanation:

1) 10/15=2/3

2) You would have to make certain that they have the same three interior angles.

Answer:

7^8

Step-by-step explanation:

Answer:7^8

Step-by-step explanation:

Answer:

Option (A)

Step-by-step explanation:

To find the value of 'a' we will use the tangent-chord theorem,

"Angle formed by the chord and a tangent to the circle measure the half of the intercepted minor arc"

Angle 'a' is formed between the chord and the tangent.

Measure of the intercepted arc = (2 × 52)°

Therefore, measure of the angle 'a' = [tex]\frac{104}{2}[/tex]

a = 52°

Therefore, Option (A) will be the correct option.

Answer:

887/990

Step-by-step explanation:

0.8959595....

895.95 - 8.95 = 887

1000 - 10 = 990

Answer:

[tex]\huge\boxed{x = \frac{887}{990}}[/tex]

Step-by-step explanation:

The number given is 0.895..........

Let x = 0.895........

Then

10x = 8.95.......   --------(1)

1000x = 985.95........   --------(2)

Subtracting (1) from (2)

1000x - 10x = 985.95..... - 8.95......

990 x = 887

Dividing both sides by 990

[tex]x = \frac{887}{990}[/tex]   (In simplest form)

Answer:

1 is not even and it is a factor of 8

Answer:

1

Step-by-step explanation:

Factors of 8

1,2,4,8

1 is an odd number

This proves that Alice is wrong :(

Hope this helps....

Have a GOOD DAY !!!

Answer:

so first you do

12800*.12 which is  1536

so $1536 for 1 year

for 3 years multiply it by 3

1536*3=

$4608

so 4608+12800 =

17408 is totall

Mark brainliest

White figure Area = 128[tex]\pi[/tex]

White surface area = appro. 301

Yellow area = 320[tex]\pi[/tex]

Yellow Surface area = approx. 653

Area found with = 2πrh+2πr2

Surface Area found with = 2πrh+2πr2

You need to memorize them for tests

Hope that helped!!! k

Answer:

x = 11

BC = 23

AD = 29

EF = 26

Step-by-step explanation:

Given:

Trapezoid ABCD, having,

median = EF = 4x - 18

base BC = x + 12

base AD = 3x - 4

Required:

Part I: value of x

Part II: Length of BC, AD, and EF.

Solution:

Part I: Value of X

The median length of a trapezoid is said to be the ½ of the sum of the 2 bases of the trapezoid.

Therefore, EF = ½(BC + AD)

4x - 18 = ½((x + 12) + (3x - 4)

4x - 18 = ½(x + 12 + 3x - 4)

4x - 18 = ½(x + 3x +12 - 4)

4x - 18 = ½(4x + 8)

Multiply 2 by both sides

2(4x - 18) = 4x + 8

8x - 36 = 4x + 8

Add 36 to both sides

8x - 36 + 36 = 4x + 8 + 36

8x = 4x + 44

Subtract 4x from both sides

8x - 4x = 4x + 44 - 4x

4x = 44

Divide both sides by 4

x = 11

Part II:

BC = x + 12 = 11 + 12 = 23

AD = 3x - 4 = 3(11) - 4 = 33 - 4 = 29

EF = 4x - 18 = 4(11) - 18 = 44 - 18 = 26

The right question is:

[tex]\frac{1}{2}x - 3y = 9[/tex]

[tex]5x + y = 28[/tex]

Answer:

[tex]x = 6[/tex]

[tex]y = -2[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{2}x - 3y = 9[/tex]

[tex]5x + y = 28[/tex]

Required

Solve for x and y

Make y the subject of formula in the second equation

[tex]y = 28 - 5x[/tex]

Substitute [tex]y = 28 - 5x[/tex] in the first equation

[tex]\frac{1}{2}x - 3(28 - 5x) = 9[/tex]

Open the bracket

[tex]\frac{1}{2}x - 3*28 - 3*- 5x = 9[/tex]

[tex]\frac{1}{2}x - 84 + 15x = 9[/tex]

Collect Like Terms

[tex]\frac{1}{2}x + 15x = 9+ 84[/tex]

[tex]\frac{x}{2} + 15x = 9+ 84[/tex]

[tex]\frac{x+30x}{2} = 93[/tex]

[tex]\frac{31x}{2} = 93[/tex]

Multiply both sides by 2

[tex]2 * \frac{31x}{2} = 93 * 2[/tex]

[tex]31x = 186[/tex]

Divide both sides by 31

[tex]\frac{31x}{31} = \frac{186}{31}[/tex]

[tex]x = \frac{186}{31}[/tex]

[tex]x = 6[/tex]

Recall that [tex]y = 28 - 5x[/tex]

So;

[tex]y = 28 - 5 * 6[/tex]

[tex]y = 28 - 30[/tex]

[tex]y = -2[/tex]

Hence;

[tex]x = 6[/tex] and [tex]y = -2[/tex]

Answer:

Step-by-step explanation:

[tex] \frac{1}{2} ( - 4 - 2n) = - 17[/tex]

First of all try to see if there are fractions in the equation .

If so try to find the LCM of the fractions and multiply the equation through by the LCM.

If there is only one fraction multiply through by the denominator of the fraction to eliminate the fraction

If there are brackets try to solve the terms in the bracket first

For the above equation there is only one fraction which is 1/2 so we multiply through by the denominator that's 2

That's

[tex]2 \times \frac{1}{2} ( - 4 - 2n) = - 17 \times 2[/tex]

[tex] - 4 - 2n = - 34[/tex]

Try to make the unknown variable the subject

That's

[tex] - 2n = - 34 + 4[/tex]

Simplify

[tex] - 2n = - 30[/tex]

Divide both sides by -2 to make n stand alone

That's

[tex] \frac{ - 2n}{ - 2} = \frac{ - 30}{ - 2} [/tex]

We have the final answer as

Hope this helps you

You need to see if it passes the vertical line test, then graph it to see if it is but is a function tho.

Answer:

1,-1,4,-3 so D

Step-by-step explanation:

0 = x^4 - x^3 -13x^2 + x + 12

x = 1,-1,4,-3

The final answer is -3,-1,1 and 4

The biquadratic equation is of the form ax⁴+bx³+cx²+dx+e and hence

The sum of roots is -b/a, the sum of the product of two roots is c/a, the sum of the product of three roots is -d/a, and the product of all four roots is e/a.

There is no specific method of solving a biquadratic equation, hence we use the trial and error method and also some form of the root.

So finding f(1) = 1-1-13+1+12 = 0 hence 1 is a root.

finding f(-1) = 1-(-1)-13-1+12 = 0 hence -1 is also a root.

So let other roots be p,q

Now we can use sum of roots formula which is p+q+1-1= 1, hence p+q=1

product of roots p*q*1*-1=12, pq= -12 substituting p = -12/q

-12/q+q = 1, multiplying q on both sides

q²-12=q, q²-q-12=0, q²-4q+3q-12 = 0, q(q-4q)+3(q-4)=0

(q-4)(q+3) = 0 hence the roots are 4,-3 also

Hence 1,-1,4, and -3 are the roots of the equation.

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Answer:

4

Step-by-step explanation:

factoring , using square roots , completing the square and the quadratic formular

Answer:

See below.

Step-by-step explanation:

The four main ways to solve a quadratic equation are:

1) Factoring, 2) Completing the Square, 3) Graphing, and 4) Quadratic Formula.

Each method has it's own pros and cons.

1) Factoring. You should factor when the given equation is easily factor-able or already factored. For instance:

[tex]0=x^2-4x-12\\0=(x+7)(x-1)[/tex]

These problems are easily factored so factoring is preferred here. However, factoring will not always work.

2) Completing the Square. You complete the square if you are able to complete the perfect square trinomial with only integers. For instance:

[tex]x^2-2x-7=0\\(x^2-2x+1)-7-1=0\\(x-2)^2-8=0[/tex]

However, you wound't use completing the square if:

[tex]x^2-3x+2=0\\(x^2-3x+9/4)+2-9/4=0[/tex]

The perfect square trinomial includes fractions so you would use alternative methods here (and factoring works here!).

Despite the complexity of completing the square, if done correctly, it works every time. However, sometimes, it can be time-consuming.

3) Graphing. Graphing (if on paper) is time-consuming. You would only use graphing when you only need an approximation. Unless directed to, you probably won't need to use graphing.

However, if you have a graphing calculator, graphing the equation can allow you to check your answer. So, graphing won't get you precise answer, but it will allow you to check your answer is necessary.

4) Quadratic Formula. Use the quadratic formula if the equation isn't factor-able and completing the square is too tedious. For instance:

[tex]4.1x^2-3x-7=0\\[/tex]

This doesn't seem factor-able and completing the square will take a while. Graphing won't get the exact answer, so the quadratic formula is the only avenue left.

The quadratic method, like completing the square, will always work.

Only con is that you need to memorize the formula.

Answer:

The answer is 7

Length of all the the three segments is equal to the length of the line segment AD

Answer:

Solving 5x + y = 5 and - 3x + 2y = 6 gives (4/13,45/13) Similarly solve other combinations by observing graph to get other coordinates. From the figure we have obtained coordinates of corners as:

Step-by-step explanation:

The Solution for the linear equation is ( 6, -7)

First order equations include linear equations. In the coordinate system, the linear equations are defined for lines. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (i.e., only one variable). Multiple variables may be present in a linear equation.

Given:

2x + y = 5.......................(1)

and, 3x + 2y = 4....................(2)

Multiply the equation (1) by 2 we get

4x + 2y = 10 ....................(3)

Solving Equation (2) and (3), we get

  3x  +  2y  = 4      

  4x  +  2y  = 10

-         -           -

_____________

    -x = -6

      x= 6

and, y= 5- 2x = 5-2(6) = -7

Hence, the solution is (6, -7)

Learn more about linear equation here:

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Answer:

[tex]\huge \boxed{y=14x}}[/tex]

Step-by-step explanation:

x=0.5, y=7

x=1, y=14

x=1.5, y=21

x= 2, y=28

Let’s take the first equation.

y = 14x

y = 14(0.5) = 7

When x is 0.5, y is 7.

y = 14(1) = 14

When x is 1, y is 14.

y = 14(1.5) = 21

When x is 1.5, y is 21.

y = 14(2) = 28

When x is 2, y is 28.

Answer: L = V/bh

b= V/Lh and h= V/Lb

Step-by-step explanation: V = Lbh or V= lwh is also used for the Basic form for the Volume of a cube or rectangular prism is

Volume = Length × breadth × height

The volume will be expressed as cubic units such as cubic meters cubic feet. Sometimes abbreviations are used like cm^3 for cubic centimeters.

When you know the Volume, and you need to find a missing dimension, just make a fraction with the V in the numerator and the dimensions you know in the denominator. This means you are dividing the Volume by the area of the dimensions you have been given to find the missing dimension.

Answer:

Area = 2127.1 cm^2  (to the tenth)

Step-by-step explanation:

We may be missing the length of a side at the top of the picture.

However, we are given "a", so the sides of a regular hexagon can be calculated.

The side of a regular hexagon given "a" is

s = 2a/sqrt(3) = 28.61

Perimeter of hexagon

= 6s

Area of hexagon

= a*perimeter/2

= a*6s/2

= 3as

= 3a*2a/sqrt(3)

=2sqrt(3)a^2

= 2*sqrt(3)*24.78^2

= 2127.1 cm^2  (to the tenth)

330

20 * 6 equals 120 that is the cost price

and 3/5 of the 15 flowers is 9 which was sold for 7

and the remaining that is 15 - 9 that's 6 sold for 50 each

now times it by 70 * 9 equals 630 50 * 6 equals 300 so 630 - 300 equals to 330 that is the profit

I hope this helps

Answer:

66

Step-by-step explanation:

The money he spent:

20 x 6 = 120

=> The number of flowers he bought:

=> 15 x 20 = 300

3/5 of 300 = 900/5 = 180

So, he sold 180 flowers for 70cents.

=> 180 x 70 = 12600 cents

=> 126  dollars

The remaining for 50 cents

=> 2/5 x 300 = 600 / 5 = 120

So, he sold 120 flowers for 50 cents

=> 120 x 50 = 6000 cents

=> 60 dollars

He got a total of 60 + 126 = 186 dollars.

He spent 120 dollars in the starting to buy the flowers.

=> 186 - 120

=> 66 dollars

So, he gets a profit of 66 dollars.

Answer:

[tex]\sqrt{\frac{x+2}{-4} }+3=y[/tex] d=(-infinity,-2) r=(3,+infinity)

Step-by-step explanation:

i did the math

Answer:

D. 100°

Step-by-step explanation:

Refer to picture attached

Lines QP and QR are tangent to radius of circle.

Triangles ΔQPO and ΔQRO are right triangles and line QO bisects angles of ∠PQR and ∠POR.

So as per sum of angles in right triangle, we have:

Then:

Correct answer choice is D. 100°

Answer:

the answer would be shape b

Answer:

B

Step-by-step explanation:

Answer:

$1200

Step-by-step explanation:

Since the value of the car depreciates $325 a year.

After 4 years it would be 1300, becuase $325 × 4 = $1300.

So, $2500 - $1300 = $1200

Answer: 80/1000 • 20

Answer:

Screenshots attached! Hope it helps :)

Answer:4/12

Step1- 3 times 4 is 12

Step2- count how many twelvths are shaded

Step3- 4 twelvths are shaded

Answer: 4/12

Answer:

C. 1/3 square yard

Step-by-step explanation:

Given:

To find:

Solution:

The shaded region is a rectangle. Area of a rectangle is the product of the length and width:

Answer choice: C. 1/3 square yard

Answer:

t= 0

Step-by-step explanation:

Using the rules of logarithms

log x + log y = log(xy)

[tex]log_{b}[/tex] 1 = 0

Given

[tex]log_{x}[/tex] a + [tex]log_{x}[/tex] [tex]\frac{1}{a}[/tex] = t ,then

[tex]log_{x}[/tex] (a × [tex]\frac{1}{a}[/tex] ) = t

[tex]log_{x}[/tex] 1 = t , thus

t = 0