Answer:
32
Explanation:
The vapour density of a gas is the number of times a given volume of gas or vapour is as heavy as the same volume of hydrogen at a particular temperature and pressure.
Vapour density = 2 × relative molecular mass of the gas or vapour
Relative molecular mass of SO2 = 32 + 2(16) = 64
Hence;
Vapour density of SO2 = 64/2
Vapour density of SO2 = 32
You are given two aqueous solutions with different ionic solutes (Solution A and Solution B). What if you are told that Solution A has a greater concentration than Solution B by mass percent, but Solution B has a greater concentration than Solution A in terms of molality? Is this possible? If not, explain why not. If it is possible, provide example solutes for A and B and justify your answer with calculations.
Answer:
Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.
It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,
% by mass = mass of solute/mass of solution * 100
Now the formula for molality is,
Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams
Now molality of solution A is,
m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)
m = 2.07
Now the molality of solution B is,
m = 15/58.5 * 1000/85
m = 3.02
Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).
In human cells, a dynamic equilibrium exists between carbonic acid (H2CO3) and carbon dioxide (CO).
H2CO3(aq) = CO2() + H200
When a person exercises, the body's cells metabolize glucose to gain energy. This metabolism also causes an increase in the
concentration of carbon dioxide.
Le Chatelier's principle states that stresses applied to a system in dynamic equilibrium will cause the system to change in order to
alleviate those stresses. According to this principle, how would an increase in carbon dioxide concentration affect the system?
A. There would be a decrease in the concentration of carbonic acid.
В. There would be an increase in the concentration of glucose.
C. There would be an increase in the concentration of water.
There would be an increase in the concentration of carbonic acid.
D There would be an increase in the concentration of carbonic acid.
There would be an increase in the concentration of carbonic acid - this is how an increase in carbon dioxide concentration influences the system.
What is dynamic equilibrium?In chemistry, a dynamic equilibrium lives once a reversible reaction occurs. Substances transition between the reactants and products at equal rates, indicating there is no net change. Reactants and products exist formed at such a rate that the concentration of neither changes. It is a precise example of a system in a steady state. After a time, a reversible reaction in a closed system can get what we call a dynamic equilibrium.
The correct answer is option D.
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Which of the following has the least H+ ions in its solution?
A. Carbonic acid solution with a pH of 4.
B. Ethanoic acid solution with a pH of 6.5
C. Ammonia solution with a pH of 12.
D. Hydrochloric acid solution with a pH of 1.
WILL GIVE BRAINLIEST IF CORRECT!!
Answer:
The answer is D. Hydrochloric acid solution with a pH of 1.
Explanation:
I just took the same quiz
Hydrochloric acid solution with a pH of 1. Hence, option D is correct.
What is an acid?An acid is an electrolyte that hydrolyses in water to release hydrogen ions.
The lower the pH the greater the concentration of H+ ions. Hydrochloric acid with a pH of 1 is a strong acid and is highly ionised in solution. It has the most H+ ions.
Hence, option D is correct.
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Calcula el %m/v de alcohol en una mezcla utilizada para la desinfección de manos formada por: 15 ml de agua (densidad=1g/ml), 105 g de etanol (densidad: 0,798 g/ml) y 4,5 gramos de jabón líquido (densidad= 1,5 g/ml)
Answer:
%m/v =70%
Explanation:
El %m/v es una unidad de concentración que se define como cien veces la división entre la masa de una sustancia (En gramos) y el volumen total en el que esta sustancia se encuentra (en mL).
En el problema, debemos hallar la masa de etanol (Alcohol) y el volumen total de la solución.
Masa alcohol:
Ya te la dan en el problema: 105g
Volumen solución:
Volumen agua: 15mL
Volumen etanol: 105g × (1mL / 0.798g) = 131mL
Volumen Jabón líquido: 4.5g × (1mL / 1.5g) = 3mL
Volumen: 15mL + 131mL + 3mL
149mL
Así, el %m/v de alcohol en la solución es:
%m/v = (105g / 149mL) × 100
%m/v =70%
What does empirical fomula means with examples
Answer in the correct significant figures: 31.2 x 4.13*
Answer:
1.29* 10^2
Explanation:
multiply them and then round
Ethane- (-89) Butane- (0) Methanol- (64.7) Hexane- (69) Pentadecane- (270) Heptadecane- (302) a) A mixture of pendtadecane and heptadecane can be separated by______ b) Which pair of compounds are easiest to separate (i) Ethane and Pentadecane (ii) Ethane and Heptadecane (iii) Butane and Hexane (iv) Butane and Heptadecane
Answer:
(ii) Ethane and Heptadecane
Explanation:
The separation of all the species listed in the answer options for the question depends on the molar mass of each specie.
Ethane is a low molecular mass gas. It exists in the gaseous state at room temperature. However, heptadecane appears as a liquid because it has a greater relative molecular mass.
It is very easily to distinguish between the gas, ethane and the liquid heptadecane which is a high molecular mass alkane, hence the answer.
if 193 ml of chlorine gas was collected at 21 celsius, what volume would it have if the temperature dropped to 0 celsius
Answer:
New volume of chlorine gas (V2) = 179 ml (Approx)
Explanation:
Given:
Volume of chlorine gas (V1) = 193 ml
Temperature of chlorine gas (T1) = 21°C = 21 + 273 = 294 k
New temperature of chlorine gas (T2) = 0°C = 0 + 273 = 273 k
Find:
New volume of chlorine gas (V2) = ?
Computation:
Using charle's law
V1 / T1 = V2 / T2
193 / 294 = V2 / 273
V2 = 179.21
New volume of chlorine gas (V2) = 179 ml (Approx)
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
over the next few minutes?
Molecules in both the metal and the surrounding air will start moving at lower speeds.
Molecules in both the metal and the surrounding air will start moving at higher speeds.
The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down
Answer:
d
Explanation:
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Compare the properties of producer and water gas
Answer:
Producer gas and water gas contain carbon monoxide and hydrogen.
Which is the correct definition of metallic bonding? Select one: a. an array of positive ions in a sea of electrons b. complete transfer of valence electrons c. atoms share electrons to to be stable
Answer:
I believe it's A) an array of positive ions in a sea of electrons
which state of matter is Na OH(s)
Explanation:
SOLID
Sodium hydroxide exists in the solid phase at room temperature. You would find it in the lab as hemispherical white solid pellets. The phase of a substance depends on temperature and pressure. As you heat a solid, it will melt and change to the liquid phase.
Balance the chemical equations: 1) ___ N2O5 → ___ N2 + ___ O2 2) _____Fe + _____O2 → _____ Fe2O3 3) _____H2 + _____Cl2 → _____HCl
Answer:
2N2 + 5O2 => 2N2O5
4Fe + 3O2 => 2 Fe2O3
H2 + Cl2 => 2 HCl
A sample of 0.562 g of carbon is burned in oxygen in a bomb calorimeter, producing carbon dioxide. Assume both the reactants and products are under standard state conditions, and that the heat released is directly proportional to the enthalpy of combustion of graphite. The temperature of the calorimeter increases from 26.74 °C to 27.93 °C. What is the heat capacity of the calorimeter and its contents?
Answer:
The correct answer is 15.54 kJ per degree C.
Explanation:
The enthalpy change for one mole of a substance, which combines or burns with the oxygen under the standard conditions, that is, at 25 degree C and 1 bar pressure is known as the standard molar enthalpy of combustion. The amount of heat transferred can be calculated by using the formula, q = mcΔT -------------(i)
Here q is the amount of heat transferred, c is the specific heat, ΔT is the change in temperature, and m is the mass of the substance. As in case of bomb calorimeter, mass if considered constant, thus, for calorimeter the equation mentioned will become, q = cΔT ---- (ii)
The standard molar enthalpy of combustion for carbon is -393.5 kJ/mol, that is, -393.5 kJ per mole of heat is generated by burning one mole of carbon. The molecular mass of carbon is 12 gram per mole.
Thus, the number of moles of carbon equivalent to 0.562 grams of carbon can be determined as,
Number of moles of carbon = mass / molecular mas
= 0.562 grams / 12 gram per mole
= 0.047 mol
The heat generated by burning 0.562 grams or 0.047 mole will be,
q = ΔH° × number of moles
= (-393.51 kJ/mol) × 0.047 mol
= -18.49 kJ, the negative sign shows that the heat is produced.
To find heat capacity of calorimeter, put the value of q as -18.49 kJ, for ΔT as (27.93 °C - 26.74 °C) in the equation (ii)
18.49 kJ = c × (27.93 - 26.74)
c = 18.49 kJ/1.19 °C
c = 15.54 kJ/°C
describe melting of a solid
8.310x10^2 – 7.210x10^1
[?]x10^[?]
Answer:
[tex]7.589\times 10^{2}[/tex]
Explanation:
The expression can be solved mathematically as follows:
1) [tex]8.310\times 10^{2}-7.210\times 10^{1}[/tex] Given
2) [tex]8.310\times 10^{1+1} - 7.210\times 10^{1}[/tex] Definition of sum
3) [tex](8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1}[/tex] [tex]a^{m+n} = a^{m}\cdot a^{n}[/tex]/Associative property
4) [tex](8.310\times 10^{1}-7.210)\times 10^{1}[/tex] Distributive property
5) [tex](83.100-7.210)\times 10^{1}[/tex] Multiplication
6) [tex]75.89\times 10^{1}[/tex] Subtraction.
7) [tex](7.589\times 10^{1})\times 10^{1}[/tex] Multiplication/Associative property
8) [tex]7.589\times (10^{1}\times 10^{1})[/tex] Associative property
9) [tex]7.589\times 10^{2}[/tex] [tex]a^{m+n} = a^{m}\cdot a^{n}[/tex]/Result
Explain the different between a molecule and a compound.
Answer:
-A molecule is the smallesr part is compound whereas a compound is the combination of two or more atoms in a fixed proportion by wiehgt.
- A glass of water is an example of compound but a small portion of water can be called molecule.
How would removing invasive species from an
ecosystem help reduce the chances of a native
species becoming extinct?
A
The native species would go extinct
sooner.
B
The native species would no longer be
infected by diseases
C
The native species would be better adapt
for survival.
D
The native species would not have to
compete for necessary resources,
The correct answer is D. The native species would not have to compete for necessary resources
Explanation:
Invasive species, which include any living organism that is not native in an ecosystem, contribute to the extinction of native species as they compete for resources such as food, shelter, etc. with native species. For example, the Asian Carp, which was introduced to lakes in the U.S. consumes plankton, which reduces the amount of plankton available for native fish. In this context, by removing invasive species native species would not have to compete for resources and their chances to extinct will fall.
Which of the following elements has a complete outer shell of electrons? A. Iron (Fe) B. Hydrogen (H) C. Neon (Ne) D. Nitrogen (N)
Answer:
The answer is Neon
Answer:
neon
Explanation:
neon has a complete outer 2n shell
Which is not a characteristic of all metals? Select one: a. soft and easy to cut b. Good electrical conductors c. Ductile and malleable
Which of the following is a characteristic property of noble gases? A. They only react with each other B. They do not react chemically C. They react violently in water D. They react violently in air.
Answer:
B.They do not react chemically
Explanation:
This is because all noble gases haves full outer shell therefore they don’t participate in bonding.They are referred to as inert which means unreactive.
Answer:
They do not react chemically
Explanation:
Chemical change example
Answer: burning paper
Explanation:
The paper burns in air to form smoke and ash. which makes it a chemical change.
Scientists from different fields are trying to understand how the global climate is reacting to the changes caused in nature, and by human activities. They have come up with conflicting interpretations. Which of these is the most likely outcome of differences in interpretations made by scientists on the issue of global climate?
Answer:
New ideas would be created and tested
Explanation:
All old ideas would be discarded.
Scientific evidence would be weakened.
New ideas would be created and tested.
The limitations of science would be evident.
In science, old ideas are usually improved or modified and not entirely discarded. The old ideas form the basis for new ideas after extensive reviews. Differences in the interpretations made by scientists on any particular phenomenon give rooms for reviews. The reviews often generate new ideas or hypotheses and these can be tested using relevant experimental procedures according to the scientific method.
Hence, the correct answer would be that new ideas would be created and tested.
Plz help me...!!! I need this answer by today!....
What is the weight of a 98 kg astronaut on the Mars where the value of the gravitational pull is 3.711 m/s2?
What is his mass on earth? What is his weight on Venus where the gravitational pull is 8.87 m/s2?
Answer:
Explanation:
given mass on earth =98 kg
gravitational pull on mars =3.711 m/s2
gravitational pull on venus =8.87 m/s2
weight of the body on mars =weight on earth/9.81 m/s2 *3.711 m/s2
W=98 kg*3.711 /9.81m/s2
W=37.07 kg
weight on the venus =weight on earth*8.87 m/s2 /9.81 m/s2
W= 98 kg*7.87 m/s2/9.81 m/s2
W=78.62 kg
A mixture of gasoline and air explodes when it encounters a spark. This is
known as
O A. a synthesis reaction
O O O
B. a precipitation reaction
C. fuel efficiency
o
D. a combustion reaction
SUBMI
Answer:
D. A combustion reaction
Explanation:
Answer the question in attachment and can I ask from which country you are.
I am new on this app.
✌️✌️☺️☺️
Answer:
1: exothermic
2:hydrated iron (III) oxide
3:reactants
4:precipitate
5: hydrogen gas
Answer:1.exothermic
2.hydrated iron (III) oxide
3.reactants
4.precipitate
5. hydrogen gas
If alkali A has a pH value of 13 and alkali B has a pH value of 9, explain which is most likely to be used in indigestion tablets as a remedy for excess stomach acid. *
Answer:
Alkalai B
Explanation:
B because its a weak alkali ie baking soda ph 8.3(sodium bicarbonate)which is used as a remeady of heartburns and stomach acids.
PLEASE HELP!! What direction do you predict the addition of a base to the solution containing bromophenol blue will drive the equilibrium? Explain your prediction in terms of Le Châtelier's principle.
Answer:
Below is the clarification of that same particular question.
Explanation:
Le Chatlier's theory states that whenever an equilibrium mechanism is disrupted by environmental influences, the program responds by changing the supplies information of its constituents in a somewhat way that the disturbance is invalidated and reaches a stable equilibrium during that disrupted stage, with concentrations of stability differently than ever before.Bromothymol blue seems to be a phenolic subs lone which always allows it to act throughout aqueous solutions as an acidic solution. Being such an acid (weak), it should not add to rapid, as well as introduces a balance with its accompanying but mostly disconnected form.For that kind of weak diprotic predictor, the standard economic statement can indeed be published as:
⇒ [tex]H_2In_(aq)\rightleftharpoons In^{2-} +2H^+[/tex]
It could be conclusively proven from either the theory of Le Charlier whereby, that whenever a strong acid becomes applied, the full disorientation of one or the other, through equilibrium formation, induces an increase throughout the medium's proton concentrations.Likewise, it absorbs the protons throughout the media to split water that whenever a solution is added. So, particle concentration throughout the medium is decreasing. To accommodate for this transition, the equilibrium reacts by moving to the correct i.e. causing further dissociation of the optimistic predictor into their dianion through protons, thereby attempting to nullify that perturbation.3.0 cm x 4.0 cm x 1.0 cm
[?]cm^3
Explanation:
Hi there!!
you asked to multiply these all right,
you can simply multiply it ,
=3cm × 4 cm × 1cm
= 12cm^2×1cm (4×3=12)
= 12cm^3 (12×1=12)
Therefore, theanswer is 12 cm^3.
Hope it helps..
A 1.30 L buffer solution consists of 0.107 M butanoic acid and 0.345 M sodium butanoate. Calculate the pH of the solution following the addition of 0.075 moles of NaOH . Assume that any contribution of the NaOH to the volume of the solution is negligible. The Ka of butanoic acid is 1.52×10−5 .
Answer:
The pH of the solution following the addition of 0.075 moles of NaOH is 5.7.
Explanation:
The equation of the buffer solution is the following:
C₄H₇O₂H(aq) + H₂O(l) ⇄ C₄H₇O₂⁻(aq) + H₃O⁺(aq) (1)
The pH of the buffer solution can be found using the Henderson-Hasselbalch equation:
[tex] pH = pKa + log(\frac{[NaC_{4}H_{7}O_{2}]}{[C_{4}H_{8}O_{2}]}) [/tex] (2)
The NaOH added will react with butanoic acid tot produce sodium butanoate:
C₄H₇O₂H(aq) + OH⁻(aq) ⇄ C₄H₇O₂⁻(aq) + H₂O(l) (3)
[tex] n_{C_{4}H_{7}O_{2}H}_{i} = C*V = 0.107 M*1.30 L = 0.139 moles [/tex]
[tex] n_{C_{4}H_{7}O_{2}^{-}} = 0.345 M*1.30 L = 0.449 moles [/tex]
[tex] n_{NaOH} = 0.075 moles [/tex]
[tex] n_{C_{4}H_{7}O_{2}H} = 0.139 moles - 0.075 moles = 0.064 moles [/tex]
[tex] n_{C_{4}H_{7}O_{2}^{-}} = 0.449 moles + 0.075 moles = 0.524 moles [/tex]
[tex]C_{C_{4}H_{7}O_{2}H} = \frac{0.064 moles}{1.30 L} = 0.049 M[/tex]
[tex] C_{C_{4}H_{7}O_{2}^{-}} = \frac{0.524 moles}{1.30 L} = 0.403 M [/tex]
Now, from equation (1) we have:
C₄H₇O₂H(aq) + H₂O(l) ⇄ C₄H₇O₂⁻(aq) + H₃O⁺(aq)
0.049 - x 0.403 + x x
[tex] Ka = \frac{[C_{4}H_{7}O_{2}^{-}][H_{3}O^{+}]}{C_{4}H_{7}O_{2}H} [/tex]
[tex]1.52 \cdot 10^{-5} = \frac{(0.403 + x)x}{0.049 - x}[/tex]
[tex]1.52 \cdot 10^{-5}*(0.049 - x) - (0.403 + x)x = 0[/tex]
By solving the above equation for x we have:
x = 1.85x10⁻⁶ = [H₃O⁺]
So, the concentration of butanoic acid and sodium butanoate is:
[tex][C_{4}H_{7}O_{2}^{-}] = 0.345 + 1.85 \cdot 10^{-6} = 0.345 M[/tex]
[tex][C_{4}H_{7}O_{2}H] = 0.049 - 1.85 \cdot 10^{-6} = 0.049 M[/tex]
Finally, from equation (2) we have:
[tex] pH = pKa + log(\frac{[NaC_{4}H_{7}O_{2}]}{[C_{4}H_{8}O_{2}]}) [/tex]
[tex]pH = -log(1.52 \cdot 10^{-5}) + log(\frac{0.345}{0.049}) = 5.7[/tex]
Therefore, the pH of the solution following the addition of 0.075 moles of NaOH is 5.7.
I hope it helps you!
