given the diagram, what is m

EF is tangent to the circle we'll assume; otherwise there's no progress.

Call the center C. ECD is isosceles, formed from two radii and the chord.

Angle CED is complementary to DEF

CED = 90 - 65 = 25 degrees

CDE is congruent, isosceles triangle and all that: CDE=25

That leaves DCE=180-25-25=130 degrees

That's the measure of arc DE as well:

Answer: 130 degrees, choice A

Answer:

130

Step-by-step explanation:

Answer:

C.  y axis

Step-by-step explanation:

y axis is the answer

Answer:

y = 25

Step-by-step explanation:

Given y = kx and k = 5 then

y = 5x ← equation of variation

When x = 5 , then

y = 5 × 5 = 25

Answer:

A. It acts perpendicular to an object

Answer:

you need to solve for 'X'

mean 49 = 55 + 42 + 32 +48 + 55 + X

49 = (232+X) / 6

49 * 6 = 232 + X

294 = 232 + X

294 - 232 = X

62 = X

so therefore X is 62

Step-by-step explanation:

please give me a brainliest

Answer:

A - True

B - False

C - True

D - False

E - True

Step-by-step explanation:

Answer:

4.8 miles per hour.

Step-by-step explanation:

Average speed=Total distance/Time taken

=26.2miles/5.5hour

=4.8 miles per hour

Answer:

Part 1;

(0, 0)

Part 2;

(0, 2.5)

Step-by-step explanation:

Part 1

The given system of inequalities is presented as follows;

f(x) < x + 4; f(x) > -x - 3; and f(x) < 5

We check each of the points as follows;

The point (0, 0) in the inequality f(x) < x + 4, gives;

f(0) < 0 + 4

f(0) = 0 < (is less than) 0 + 4 = 4

Therefore, (0, 0) is a solution of the inequality f(x) < x + 4

The point (0, 0) in the inequality f(x) > -x - 3, gives;

f(0) < -0 - 3

f(0) = 0 > (is larger than) -0 - 3 = -3

Therefore, (0, 0) is a solution of the inequality f(x) > -x - 3

The point (0, 0) in the inequality f(x) < 5, gives;

f(0) < 5

f(0) = 0 < (is less than) 5

Therefore, (0, 0) is a solution of the inequality f(x) < 5

The point (-6, 0) in the inequality f(x) > -x - 3, gives;

f(-6) = -6 - 3 = 3

The point (-6, 0) with y = 0 < (is less than) f(-6) = 3, therefore (-6, 0) is not a solution to (not included in the graph of) the inequality f(x) > -x - 3 and therefore to the system of inequalities because at x = -6, the values of f(x) > -x - 3 are larger than 3

The point (-3, 4) in the inequality f(x) < x + 4, gives;

f(-3) = -3 + 4 = 1

The point (-3, 4) with y = 4 < (is larger than) f(-2) = 1, therefore (-3, 4) is not a solution to (not included in the graph of) the inequality f(x) < x + 4  and therefore to the system of inequalities because at x = -3, the values of f(x) < x + 4 are less than 1

The point (4, 6) is not a solution to (not included in the graph of) the inequality f(x) < 5  and therefore to the system of inequalities because f(x) is larger than 5 for all x

Therefore, the point which is part of the solution set of the system of inequalities is (0, 0)

Part 2

The given system of inequalities are, f(x) ≥ 2·x + 2; f(x) ≤ -4·x + 3; and f(x) ≤ 6·x + 5

Plotting the given system of inequalities on MS Excel the point which is part of the solution is given by points which are within the triangular intersection area of the three inequalities, with coordinates, (1/6, 7/3), (-3/4, 1/2), and (-1/5, 19/5)

Therefore, the points, (0, 0), (-2.5, 0) are not solutions because, the y-value of the solution area are all higher than the line y = 0

The point (0. 6.5) is not a solution because the points in the triangular solution area all have x-values lesser than x = 6.5

The point which is part of the solution by examination is the point (0, 2.5) which is a point between the lines y = 19/5 = 3.8, y = 1/2, x = -3/4, and x = 1/6.

Answer:

Solution given;

<ABD=<BAC+<ACB

Since exterior angle of a triangle is equal to the sum of two opposite interior angle

26x+20=19x-15+9x+25

solve like terms

26x+20=28x+10

subtracting both by 10

26x+20-10=28x+10-10

Subtracting both side by 26x

10=28x-26x

2x=10

dividing both side by 2

2x/2=10/2

x=5

Now

<ABD=26*5+20=l50°

The value of <ABD is 150°

Answer:

57°,123°,57°,123°

Step-by-step explanation:

as vertical angles are equal

so one angle=114/2=57°

other angle=180-57=123°

Answer:

pic pls

Step-by-step explanation:

Answer:

da

Step-by-step explanation:

option A.55°

Answer:

Solution given:

<x+<y=<z

exterior angle of a triangle is equal to the sum of two opposite interior angle

4n-18+n+8=133-6n

5n+6n=133+10

11n=143

n=143/11

n=13

exterior angle =133-6*13=55°

option A.55°

The profit percentage = 16.3%

Answer:

12. d= 14, C=14π, A=49π

13. r= 13, d=26, A=169π

14. r=9, C=18π, A=81π

15. r=10, d=20, C=20π

Step-by-step explanation:

Answer:

[tex]-1\leq x<\infty[/tex]

Step-by-step explanation:

We want to convert the interval [-1, ∞) to inequality notation using x as the variable.

The interval [-1, ∞) reads: "All real numbers between -1 and positive infinity."

In other words, it is all numbers greater than or equal to -1 and less than positive infinity.

Therefore:

[tex]-1\leq x<\infty[/tex]

Note that we do not use "or equal to" for the infinity as we can never really "equal" infinity.

Answer:

Let ten's place digit =x and unit place digit =y

Number=10x+y

x+y=5 ...(i)

10x+y−9=10y+x

9x−9y=9x−y=1 ...(ii)

from (i) and (ii) we get,

x=3,y=2

∴Number=10×3+2=32.

Step-by-step explanation:

Hope it helps!

Answer:

x = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]\frac{1}{x} + \frac{1}{3x} = 4[/tex] (Multiply everything by LCM)

[tex]3x*\frac{1}{x} + 3x*\frac{1}{3x}=3x*4[/tex] (Simplify the fractions)

[tex]3+1=12x\\4=12x\\x=4/12\\x=\frac{1}{3}[/tex]

Answer:

The last one is the answer

Answer: For each hour that Michelle drove, she travelled an additional 50 miles.

Step-by-step explanation:

Test each option to see its accuracy

Calculate the slope:

[tex](x_{1}, y_{1}) = (7, 0)\\(x_{2}, y_{2}) = (0, 350)\\ \\\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{350-0}{0-7} =\frac{350}{-7} =-50[/tex]

This means that Michelle drove 50 miles per hour.

The other three options are wrong because if you bring in:

into your function- y = -50x + 350, you would not get the stated miles.

Answer:

[tex]x=1[/tex]

[tex]y=2[/tex]

Step-by-step explanation:

[tex]y=x^2+3x-2[/tex] , [tex]y+3=5x[/tex]

Replace all occurrences of [tex]y[/tex] in [tex]y+3=5x[/tex] with [tex]x^2+3x-2.[/tex]

[tex](x^2+3x-2)+3=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Add [tex]-2[/tex] and 3.

[tex]x^2+3x+1=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from both sides of the equation.

[tex]x^2+3x+1-5x=0[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from 3x.

[tex]x^2-2x+1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite 1 as [tex]1^2[/tex].

[tex]x^2-2x+1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

[tex]2x=2[/tex] · [tex]x[/tex] · [tex]1[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite the polynomial.

[tex]x^2-2[/tex] · [tex]x[/tex] · [tex]1[/tex] [tex]+[/tex] [tex]1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Factor using the perfect square

trinomial rule [tex]a^2-2ab+b^2=(a-b)^2,[/tex]

where a = x and b = 1.

[tex](x-1)^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Set the [tex]x-1[/tex] equal to 0.

[tex]x-1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Add 1 to both sides of the equation.

[tex]x=1[/tex]

[tex]y=x^2+3x-2[/tex]

Replace all occurrences of [tex]x[/tex] in

[tex]y=x^2+3x-2[/tex] with 1.

[tex]y=(1)^2+3(1)-2[/tex]

[tex]x=1[/tex]

[tex]y=2[/tex]

Answer:

6/7 inches

Step-by-step explanation:

If 7 stamps fit perfectly, we can find the width of each stamp by dividing the width of the frame by 7:

= 6/7

So, the width of each stamp is 6/7 inches

Answer:

42

Step-by-step explanation:

Perimeter is [tex]2l+2w[/tex]

Answer: 42

Hope this helped! Please mark brainliest :)

Answer:

0.395

Step-by-step explanation:

We need to solve the given expression.

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}-\dfrac{1}{2}\times\dfrac{1}{4}+\dfrac{4}{5}\times \dfrac{7}{5}[/tex]

We can also write it as :

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}+\dfrac{4}{5}\times \dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}(\dfrac{-3}{4}+\dfrac{7}{5})-\dfrac{1}{2}\times\dfrac{1}{4}[/tex](Distributive property is used)

So,

[tex]=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{8}\\\\=\dfrac{13}{25}-\dfrac{1}{8}\\\\=0.395[/tex]

So, the value of the given expression is equal to 0.395.

Answer:

The median is 9

Step-by-step explanation:

The median is the number in the middle. The middle of this is 8 and 10, so you plus them and divide by to 2, then it gives 9, so the median is 9.

4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?

a. What are they asking for?

how big was the original group?

b. identify all the necessary numbers.

28,5

c. write the equation or problem in numeric form.

x=28*5

d. solve the math.

x=140

e.write the answer

. the original group contains 140 people.

5. If he difference is 589 and the subtrahend is 339,what is the minuend?

a. What are they asking for?

what is the minuend?

b. identify all the necessary numbers.

589,339

c. write the equation or problem in numeric form.

x=589-339

d. solve the math.

x=250

e.write the answer.

minuend=250

6. If the quotient is 17 and the dividend 765, what is the divisor?

a. What are they asking for?

what is the divisor?

b. identify all the necessary numbers.

17,765

c. write the equation or problem in numeric form.

x=765/17

d. solve the math.

x=45

e.write the answer.

divisor is 45.

4. Solution

a. How big was the original group?

b. 28 and 5

c. x = 28×5

d. x = 140

e. There are 140 people in original group.

5. Solution

a. What is the minuend?

b. 589 and 339

c. x = 589-339

d. x = 250

e. The minuend is 250.

6. Solution

a. What is the divisor?

b. 17 and 765

c. x = 765/17

d. x = 45

e. Hence, 45 is the divisor.

Hello,

[tex]0\leq a\leq 1 \Longrightarrow 0*a\leq a*a\leq 1*a \Longrightarrow 0 \leq a^2 \leq a\\\\0\leq a^2\leq a \Longrightarrow \sqrt{0} \leq \sqrt{a^2} \leq \sqrt{a} \\\\The\ function\ y=x^2\ is\ increasing\\\\Answer A\\\\ex: a=0.5 \\\\a^2=0.25\\\\\sqrt{a}=\dfrac{\sqrt{2}}{2}\approx{0.7071...}\\\\and\ 0.25\leq 0.5 \leq 0.7071...[/tex]