Answer:
4300 x 12= 51600
20/100 x 51600
10,320 Rs (also pay bohat kam hai :D )
The sum of 'n' terms of an arithmetic sequence is 4n^2+3n. What is the first term, the common difference, and the sequence?
Answer:
d=8 and a=7
Step-by-step explanation:
The sum of a arithmetic sequence is given by (n/2)*(2a+(n-1)d). Comparing coefficients with the given Sn, we have; a-d/2=3 and d/2=4, d=8 and a=7. The sequence is 7, 15, 23, 31, 39
please help I have 3 mins left
Answer:
the first one is 3.7 x 10^-4
and the second one is 3.7 x 10^4
explanation:
when we have decimals we are going backward,
therefore "0.00037" would be a negative number
to find the scientific notation form, we have to move the decimal over to the left untill we get 3.7
it took 4 moves to the right to get to 3.7, and since were dealing with decimals it will be negative,
so the first one is 3.7 x 10^4
the second one however is not a decimal so it will be a positive exponent.
now remember that there is always a decimal after a number we might just not see it.
so, going from the very end of the number it takes us 4 moves to the left to get to 3.7
so,
the second one will be 3.7 x 10^4
hope this helped :)
Một đài khí tượng thủy văn muốn xem xét khả năng dự báo thời tiết của mình. Từ số liệu thống kê chỉ ra rằng: xác suất dự báo có nắng trong ngày không mưa là 0,95; có nắng trong ngày mưa là 0,8; xác suất một ngày sẽ không mưa là 0,6. a. Tính xác suất dự báo ngày sẽ có nắng. b. Biết đã có dự báo là ngày có nắng, tính xác suất để ngày đó là ngày không mưa.
Answer:
ask in English then I can help u
Write the expression as a single trigonometric function.
cos 5x cos 6x- sin 5x sin 6x
Answer:
[tex]\cos(11x)[/tex]
Step-by-step explanation:
Given
[tex]\cos 5x\ \cos 6x- \sin\ 5x \sin 6x[/tex]
Required
Express as a single function
In trigonometry, we have:
[tex]\cos(A + B) = \cos A\cos B - \sin A \sin B[/tex]
By comparison, we have
[tex]\cos(5x + 6x) = \cos 5x\cos 6x - \sin 5x \sin 6x[/tex]
[tex]\cos(11x) = \cos 5x\cos 6x - \sin 5x \sin 6x[/tex]
Find the x- and y-intercept of the line
X+4y=36
A particle is moving such that its height h at time t is given by h(t) = 2 + 8t - 3t^2 + 1/5t^3. The average velocity of the particle on the period [0,3] is
[tex]\\ \Large\sf\longmapsto h(t)[/tex]
[tex]\\ \Large\sf\longmapsto 2+8t-3t^2+\dfrac{1}{5}t^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+8(3)-3(3)^2+\dfrac{1}{5}(3)^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+24-3(9)+\dfrac{27}{5}[/tex]
[tex]\\ \Large\sf\longmapsto 26-27+5.4[/tex]
[tex]\\ \Large\sf\longmapsto -2+5.4[/tex]
[tex]\\ \Large\sf\longmapsto h(t)=3.4m[/tex]
A construction crane lifts a bucket of sand originally weighing 145 lbs at a constant rate. Sand is lost from the bucket at a constant rate of .5lbs/ft. How much work is done in lifting the sand 80ft?
Answer: [tex]10,000\ lb.ft[/tex]
Step-by-step explanation:
Given
Initial weight of the bucket is [tex]145\ lb[/tex]
It is lifted at constant rate and rate of sand escaping is [tex]0.5\ lb/ft[/tex]
At any height weight of the sand is [tex]w(h)=145-0.5h[/tex]
Work done is given by the product of applied force and displacement or the area under weight-displacement graph
from the figure area is given by
[tex]\Rightarrow W=\int_{0}^{80}\left ( 145-0.5h \right )dh\\\\\Rightarrow W=\left | 145h-\dfrac{0.5h^2}{2} \right |_0^{80}\\\\\Rightarrow W=\left [ 145\times 80-\dfrac{0.5(80))^2}{2} \right ]-0\\\\\Rightarrow W=11,600-1600\\\\\Rightarrow W=10,000\ lb.ft[/tex]
round to the nearest Ten-thousand: 849,708
Answer:
850,000
Step-by-step explanation:
Answer: 850,000
Concept:
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
Solve:
8 = Hundred thousands
4 = Ten thousands
9 = One thousands
7 = Hundreds
0 = Tens
9 = Ones
Since the values before the ten thousands place, which would be the one thousands place, is greater than 5, then we should round up.
Therefore, the rounded value would be [tex]\boxed{850,000}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
a recent survey shows that 66% of college students have a cat and 37% have a HBO subscription. Assuming these two events are independent, what is the probability that a randomly selected student has neither a cat nor HBO
Answer:
[tex]P(C'\ and\ H') =0. 2178[/tex]
Step-by-step explanation:
Let
[tex]C \to[/tex] Student with cat
[tex]H \to[/tex] Student has HBO sub
[tex]P(C) = 66\% \\ P(H) = 37\%[/tex]
Required
[tex]P(C'\ and\ H')[/tex]
This is calculated as:
[tex]P(C'\ and\ H') = P(C') * P(H')[/tex]
Using complement rules, we have:
[tex]P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)][/tex]
So, we have:
[tex]P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%][/tex]
[tex]P(C'\ and\ H') = [33\%] * [66\%][/tex]
[tex]P(C'\ and\ H') =0. 2178[/tex]
Please help!!!!
CE is tangent to this circle, CD is a radius and ECB=48 what is BAC
Answer:
48degrees
Step-by-step explanation:
From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;
<B = <C
<CBD + <BCD + <D = 180
<BCD + <BCD + <D =180
2<BCD + <BDC = 180
Get <BCD;
<BCD+ <ECB = 90
<BCD + 48 = 90
<BCD = 90 - 48
<BCD = 42degrees
Get <BDC
2<BCD + <BDC = 180
2(42)+ <BDC = 180
84 + <BDC = 180
<BDC = 180 - 84
<BDC = 96
Since angle at the centre is twice that at the circumference, then;
<BAC = 1/2(<BDC )
<BAC = 96/2
<BAC = 48degrees
Here's the result of this question
The point (-2,7) has undergone the following transformations:
1. Translated 1 unit up and 4 units left
Then
2. Reflected about the c-axis
Then
3. Rotated 90° anticlockwise about the origin
A) Its final coordinates are (3,-1)
B) Its final coordinates are (8,-6)
C) Its final coordinates are (-8,6)
D) Its final coordinates are (-3,1)
Answer:
B) Its final coordinates are (8,-6)
Step-by-step explanation:
1. Translated 1 unit up and 4 units left
(-2,7) becomes (-6, 8)
2. Reflected about the x-axis
(-6,8) becomes (-6, -8)
3. Rotated 90° anticlockwise about the origin
(-6, -8) becomes (8, -6) because when rotating 90 degrees anticlockwise about the origin, point A (x,y) becomes point A' (-y,x). In other words, switch the x and y and make y negative.
Based on a random sample of 50, a 95% confidence interval for the population proportion was computed. Holding everything else constant, which of the following will reduce the length of the confidence interval by half? (CHECK ALL THAT APPLY): A. Quadruple the sample size. B. Change the confidence level to 68%. C. Double the sample size. D. Change the confidence level to 99.7%. E. Decrease the sample proportion by half.
The length of the confidence interval is the margin of error, which is the ratio of the standard deviation and the square root of sample size. Hence, to reduce the length of confidence interval by half, Quadruple the sample size.
Recall :
Margin of Error = σ/√nEvaluating an hypothetical scenario :
Let standard deviation, σ = 2
Sample size = 50
Margin of Error = 2/√50 = 0.554
Using Quadruple of the sample size : (50 × 4) = 200 samples
Margin of Error = 2/√200 = 0.277(0.227 ÷ 0.554) = 0.5
Therefore, increasing the sample size, reduces the margin of error. Hence, using quadruple the sample size, will reduce the margin of error by half.
Learn more : https://brainly.com/question/13403969
Question 17 of 25
Solve the inequality. Enter the answer as an inequality that shows the value of
the variable; for example f>7, or 6 < w. Where necessary, use <= to write s
and use >= to write .
V-(-5) <-9
Answer here
I
SUBMIT
Answer:
v-(-5)<-9
v- remove brackets -5
v- -5= -4 +5 ( opposite operation)
v- = -4
v< -4
7. Solve for x: x/6 - y/3 = 1
Please give steps!
Use the point-slope form from the previous question and fill-in the following table of values.
The point-slope equation went through the following 2 points: (0, -1) and (1, 2)
(0, -1)
(1, 2)
(2, )
(3, )
Answer:
Step-by-step explanation:
Slope of line through (0,-1) and (1,2) = (-1 - 2)/(0 - 1) = 3
Point-slope equation for line of slope 3 that passes through (0,-1):
y+1 = 3(x-0)
When x = 2:
y+1 = 3(2-0)
y = 3·2 - 1 = 5
When x = 3:
y+1 = 3(3-0)
y = 3·3-1 = 8
Domain and range of g(x)= 5x-3/2x+1
Solve for domain and range?
The figure shows an equilateral triangle with its sides as indicated. find the length of each side of the triangle .
I Will Mark Brainliest
Answer:
21
Step-by-step explanation:
All three sides are equal
2x-7 = x+y-9 = y+5
Using the last two
x+y-9 = y+5
Subtract y from each side
x+y-9-y = y+5-y
x-9 = 5
Add 9 to each side
x -9+9 = 5+9
x=14
We know the side length is
2x-7
2(14) -7
28-7
21
The side length is 21
help with math it would help with summer school
Answer:
[tex]A). \ \ \frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
Step-by-step explanation:
Given;
radius of the circle, r = 9 inches
the part of the circle cut out = one-forth of the complete circle
the angle of the sector cut out θ= ¹/₄ x 360 = 90⁰
Area of the complete circle = πr² = π x 9² = 81π in²
Area of the sector cut out = [tex]= \frac{\theta }{360} \pi r^2 = \frac{90}{360} \pi (9^2) = \frac{1}{4} \times 81\pi = \frac{81 \pi}{4} = \frac{(72\pi + 9\pi)}{4} \ in^2[/tex]
Therefore, the only correct option is A. [tex]\frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
Let S be a sample of size 31 from a normally distributed population Omega . It is given that the average of the data in S is 120 and the standard deviation is 18. Construct a 90% confidence interval [a, b] for the population mean based on the data in the sample.
Answer:
48 NO seña hfjxsmisns sisbxbd
Step-by-step explanation:
nzhejsbxbddndbhwksdyanvxydjd4mnnneknwnennnnnnIf (x^2−1)/(x+1) = 3x + 5, then x + 3 =
(A) -3
(B) -2
(C) 0
(D) 2
(E) 4
A $22,000 loan was taken out. If $24,805 is due at the end of the loan after being compounded daily at 2.5%, how many
years was the loan for? (Round to the nearest tenth of a year)
Provide your answer below
9514 1404 393
Answer:
4.8 years
Step-by-step explanation:
Solving the compound interest formula for the number of years gives ...
t = log(A/P)/(n·log(1 +r/n))
where principal P invested at rate r compounded n times per year produces value A after t years.
t = log(24805/22000)/(365·log(1 +0.025/365)) ≈ 4.800
The loan was for 4.8 years.
HURRY PLEASE!!!!!!
Line AB has a slop of 1/2
What would the slope of line CD have to be if we knew CD was perpendicular to AB?
2
-2
1/2
-1/2
Answer:
-2
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals
Take the slope of AB = 1/2
-1/(1/2)
-1 * 2/1
-2
The slope of a line perpendicular is -2
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
please help this is due soon
Convert 2546 in base 10 to base 5
Answer:
40141
Step-by-step explanation:
Erica’s family is moving away from California. They decided to have a moving sale and sell each item for 70% off the price they originally paid for it. The sofa had an original price of $799, and the love seat had an original price of $549. What is the total cost of both items after the discount?
Find the sale price by multiplying the original price by 70% then add the two prices together to get the total.
799 x 0.70 = 559.30
549 x 0.70 = 384.30
Total: 559.30 + 384.30 = $943.60
The height of the triangle is 4 meters longer than twice its base. find the height if the area of the triangle is 80 square meters. The height must be ___meters
Answer:
The height is 20 meters
Step-by-step explanation:
First set up the equation (Area)80=bh/2 then set up another equation, (height) h=4+2b (base). After this you can substitute h in the equation to end up with 80=(b(2b+4))/2 simplify it to get 80=b^2+2b then solve. The base is 8 meters, plug into the formula that we made before and you find the height is 20 meters.
A turboprop plane flying with the wind flew 1,200 mi in 4 h. Flying against the wind, the plane required 5 h to travel the same distance. Find the rate of the wind and the rate of the plane in calm air.
Answer:
30 and 270 respectively
Step-by-step explanation:
Let the speed of plane in still air be x and the speed of wind be y.
ATQ, (x+y)*4=1200 and (x-y)*5=1200. Solving it, we get x=270 and y=30
Dylan has a coworker who is always showing up late and then not finishing his work on time. It's frustrating the other members of the team. What can he do that might help the situation? a) Complain about the coworker to other team members O b) Ask his coworker if he understands his job responsibilities c) Tell his boss that the coworker is slacking off O d) Complete his coworker's work for him
2. Solve the following:
a. When six is added to four times a number the result is 50. Find the number.
b. The sum of a number and nine is multiplied by -2 and the answer is -8. Find the
number
10
m in
Step-by-step explanation:
a) let number=x
four times a number=4x
Condition:
4x+6=50
4x=50-6
4x=44
x=44/4
x=11
b) Condition:
x+9×-2=-8
x-18=-8
x=-8+18
x=10
Note:if you need to ask any question please let me know.