Heat is most closely related to which kind of energy?

Answers

Answer 1

Answer:

I'm very sure it's thermal energy.

Explanation:

Answer 2

Answer:

thermal energy is the answer


Related Questions

3. The name of the functional group in the following compound
CH3 - CH2 - CH2 - CH-CH2 - CH3
1
CH3 – CH2
a. Methyl
b. Ethyl
C. Propyl
d. Isopropy!

Answers

Answer: a.) Methyl would be the answer.

Explanation:

which is the most fluorescent molecule?

Answers

I think neon....................

Can you watch the video and help me fill in the blanks ? Thank you

Answers

1 = rest
2 = rest
3 = motion
4 = motion
5 = a (net) external force

1. What organ system is responsible for controlling all of the body
functions?

Answers

Answer:

The human brain is the body's control center, receiving and sending signals to other organs through the nervous system and through secreted hormones. It is responsible for our thoughts, feelings, memory storage and general perception of the world. The human heart is a responsible for pumping blood throughout our body

Which statement is accurate about variations?

Organisms with variations that give an advantage are more likely to survive

Organisms with variations are less likely to pass these variations to their offspring

In all cases vanations become more common in a population

In all cases variations affect how likely it is that an organism reproduces

Answers

Answer:

A,C,D

Explanation:

Variations effect the likelyhood of survival for a organism, it can give off an advantage or disadvantage.

Brainliest? pls

How many moles of magnesium nitrate are produced when he reacts 0.34 moles of nitric acid with excess magnesium?

Answers

Jeirurbekwiufbekwididjdeu


8. If 134 L of Nitrogen gas at STP is combined with 99 L of Chlorine gas at STP,
Which is the limiting reactant?
N2 + Cl2 → NCI3
.

Answers

Answer:

Cl₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3Cl₂ —> 2NCl₃

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.

From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.

Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.

The reaction CO2+H2O=H2OCO3 is classified as

Answers

It would be classified as decomposition reaction

when 70.0 grams of mno2 reacted with 128.0 grams of hcl, the reaction resulted in a 62.7% yield of chlorine gas. what is the actual yield of chlorine gas in grams? Mno2 + HCI —> MnCl2 + h2o + cl2​

Answers

Answer:

35.8g of Cl₂ is the yield

Explanation:

Based on the reaction:

MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

1 mole of MnO₂ and 4 moles of HCl react producing 1 mole of Cl₂

To solve this question we must find limiting reactant. with limiting reactant we can find the theoretical yield of Cl₂. As the actual yield is the 62.7% we can find actual yield of Cl₂ in grams:

Moles MnO₂ -Molar mass: 86.9368g/mol-:

70.0g * (1mol / 86.9368g) = 0.805 moles

Moles HCl -Molar mass: 36.46g/mol-:

128.0g * (1mol / 36.46g) = 3.51 moles

For a complete reaction of 3.51 moles of HCl are required:

3.51 moles HCl * (1mol MnO₂ / 4mol HCl) = 0.878 moles MnO₂.

As there are just 0.805 moles of MnO₂, MnO₂ is limiting reactant.

1 mole of MnO₂ produce 1 mole of Cl₂. The theoretical moles of Cl₂ produced are 0.805 moles.

As the yield is of 62.7%, the yield of Cl₂ is:

0.805 moles * (62.7 / 100) = 0.505 moles Cl₂. In grams:

0.505 moles Cl₂ * (70.906g / mol) =

35.8g of Cl₂ is the yield

How do you balance this:
Br2 + H2O + SO2 = HBr + H2SO4

Answers

Answer:

Br2+ 2H2O + SO2= 2HBr + H2SO4

Let's Compare the left side of the equation to the right side of the equation.

Left: Br= 2, H= 2, S= 1, O = 1+2

Right: Br=1, H= 1+2, S=1, O= 4

We can see that only S is balanced and not the other 3 elements.

I'll try to make each element balance.

For Br; I'll multiply by 2 on the left to make it equal to the right.

For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.

For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.

How does increasing the pressure affect the reaction rate? A. The activation energy of the reaction is changed. B. The concentration of reactants is changed. C. The temperature of the reaction is changed. D. The phase the reactants are in is changed​

Answers

Answer:

Explanation:

b

The rate of the reaction determines the product formation and depends on various factors. The increase in pressure will change the concentration of reactants. Thus, option B is correct.

What is the reaction rate?

The rate of the reaction is the speed at which the chemical reaction moves in a direction to yield products. The reaction rate is influenced by the surface area of the substance, temperature, and concentration.

The pressure directly affects the concentration which in turn affects the reaction rate. The increased pressure raises the concentration and more collisions will occur between the particles resulting in a fast rate of reaction.

Therefore, the increase in pressure increases the concentration and reaction rate.

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1. If I have 5 moles of a gas at a pressure of 7.6 atm and a volume of 12 liters, what is the temperature?

Answers

Answer:

221.22K or -51°C

Explanation:

We will be using the Ideal Gas Law to calculate the temperature of the gas. It is a mathematical relationship that describes the behavior of ideal gas ample for any combo of varying pressure, volume, temperature, and # of moles (n). It is derived by combing Boyle's Law, Charles' Law, Gay-Lussac's & Avogadro's Law.

Note: As always, remember that temperature must be in Kelvin not Celsius when using this equation.

Ideal Gas Law: [tex]PV = nRT[/tex], where P = pressure, V = volume (in Liters), n = # of moles, R = the ideal gas constant, and T = temperature (in Kelvin).

Based on the problem, we are given the pressure, volume, and # of moles. We are asked to find the temperature. What about R you ask? Well, R is a constant that is the value of 1 mole of gas at STP. R has various values depending on the pressure units. In this case, our pressure is in atm so the R value = 0.0821.

Onto the math - all that needs to be done now is to plug and chug. Plug in the given values to find the temperature:

Set up: [tex](7.6 atm)(12L) = (5 mol)(0.0821 L*atm/(mol*K))(T)[/tex]

==> [tex]T = \frac{(7.6 atm)(12L)}{(5 mol)(0.0821 L*atm/(mol*K))}[/tex]

==> T = 221.17K

The answer is 221.17K. To convert into Celsius, subtract by 273.15 to get -50.99 or -51°C.

Which of the following molecules are Polar? Select all that apply.
Group of answer choices
A.CH3Cl
B.HF
C.O2
D.PF5
E.HCN
F.SeBr6
G.H2S

Answers

The molecule that is polar is B C G

what is heat of reaction​

Answers

Answer:

Explanation:

The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. ... The heat of reaction or reaction enthalpy is typically expressed as molar enthalpy in kJ/mol or as specific enthalpy in kJ/kg or kJ/L.

Answer:

The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. ... The heat of reaction or reaction enthalpy is typically expressed as molar enthalpy in kJ/mol or as specific enthalpy in kJ/kg or kJ/L.

Explanation:

PLEASE ASNWR ASAP
If I have a 50 liter container that holds 45 moles of gas at a pressure of 2.66 x 104 mmHg, what is the
temperature inside the container? ** convert pressure to atm**

Answers

34.95 atm

lol i hope i’m not too late



If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yield of the reaction

Answers

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

[tex]SiO_2+3C\rightarrow SiC+2CO[/tex]

[tex]SiO_2[/tex] is the limiting reagent as it limits the formation of product and [tex]C[/tex] is the excess reagent.

According to stoichiometry :

60.08 g of [tex]SiO_2[/tex] produce = 40.11 of [tex]SiC[/tex]

Thus 50.0 of [tex]SiO_2[/tex] will produce=[tex]\frac{40.11}{60.08}\times 50.0=33.4[/tex]  of [tex]SiC[/tex]

 Experimental yield of SiC = 27.9 g

Percent yield = [tex]\frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%[/tex]

Thus  percent yield of the reaction is 83.5 %

The percent yield of 83.5 % of 50.0 g of silicon dioxide is heated with an excess of carbon, and 27.9 g of silicon carbide is produced in the reaction.

What is the chemical balance of the equation?

The chemical equations are balanced when the reactants react to form products. The reactants and products react in proper ratios and if they are not in ratio then we balance them by adding the required quantity in the reactants and the products.

The given balanced equation is

[tex]\rm SiO_2+3C---- > SiC+2CO[/tex]

[tex]SiO_2[/tex] is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry

60.08 g [tex]SiO_2[/tex] of  produce = 40.11 of [tex]SiC[/tex]

Thus 50.0 of  [tex]SiO_2[/tex] will produce=  [tex]\dfrac{40.11}{60.08} \times 50=33.4\ SiC[/tex]

The experimental yield of SiC = 27.9 g

The percentage yield will be calculated as

[tex]\rm Percentage \ Yield = \frac{Experimental\ yield}{Theoretical \ yield }\times 100[/tex]

[tex]\rm Percentage \ yield =\dfrac{27.9}{33.49} \times 100=83.5[/tex]

Thus the percent yield of 83.5 % of 50.0 g of silicon dioxide is heated with an excess of carbon, and 27.9 g of silicon carbide is produced in the reaction.

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A 0.10M NH3 solution is 1.3% ionized, calculate the hydrogen ion concentration

Answers

Answer:NH3 + H2O <==> NH4+ + OH-

0.10 x 0.013 = 0.0013 M (this is the hydroxide concentration)

Kw = [H+] [H-]

1.00 x 10^-14 = (x) (0.0013)

x = 7.7 x 10^-12 M

Explanation:

Pleaseee helpppp!!!!!!!!

Answers

Answer:

a covalent would be the two that are nonmetals

Characterize EACH of the three given statements as being TRUE or FALSE and then indicate the collective true-false status of the statements using the choices. (1) Water's boiling point is much higher than expected, based on comparison with other substances, because of hydrogen bonding. (2) In the gaseous state, disruptive forces and cohesive forces are of about the same magnitude. (3) As liquid surface area increases, the rate of evaporation of a liquid increases.

Answers

Answer:

The correct answer is - 1 and 3 are true.

Explanation:

Hydrogen bonds require a lot of energy to be broken as these bonds are relatively strong intermolecular forces which makes the boiling point of liquid like water very high, as it requires a lot of heat to break the intermolecular bonds holding the water molecules together.

An increase in the surface area of the liquid also increases the rate of evaporation as it takes place among the molecules of the liquid on the surface.

arrange the following group of atoms in order of increasing atomic size:B,Al,Ga​

Answers

Answer:

Al,Ga,B

Explanation:

Now since i helped you can you help me with this plz

Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.

Boron ( B )

Aluminium ( Al )

Gallium ( Ga )

2. What human-related environmental
factors might also be affecting the
growth of the toxic algae?

Answers

Answer:

Polution

Explanation:

Wind energy is a renewable natural resource
True
False

Answers

this is true, wind energy is a renewable natural resource c:

how many molecules of sodium chloride are in 2.5 moles??

Answers

Answer:

1.5x1024

Explanation:

what is the mass of 3.2 moles of NaCl??

Answers

Answer:

116.88554 grams

Explanation:

*sweating profusely*

i had to look it up

Answer:

187.01686400000003 grams

Explanation:

A truck accelerates at a rate of 14 m/s2 . The truck weighs 17000 kg. What is the amount of force
necessary for the truck to accelerate at this rate?

Answers

Answer:

238000 N

Explanation:

Use F=ma

Mass= 17000 kg

Accel.= 14 m/s²

The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: In the analysis of a 1.54-g sample, 0.0596 g of barium iodate was recovered. Express the results of this analysis as percent potassium iodide.

Answers

Answer: The percentage of potassium iodide in the sample is 2.63 %.

Explanation:

The chemical equation for the reaction of iodide ions with bromine gas follows:

[tex]I^-+3Br_2+3H_2O\rightarrow 6Br^-+IO_3^-+6H^+[/tex]                (i)

The chemical equation for the reaction of iodate ions with barium ions follows:

[tex]Ba^{2+}+2IO_3^-\rightarrow Ba(IO_3)_2[/tex]                 ......(ii)

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of barium iodate = 0.0596 g

Molar mass of barium iodate = 487.13 g/mol

Using equation 1:

[tex]\text{Moles of barium iodate}=\frac{0.0596 g}{487.13 g/mol}\\\\\text{Moles of barium iodate}=1.22\times 10^{-4} moles[/tex]

By Stoichiometry of the reaction (ii):

1 mole of barium iodate is produced by 2 moles of iodate ions

So, [tex]1.22\times 10^{-4} moles[/tex] of barium iodate will be produced by [tex]\frac{2}{1}\times 1.22\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodate ions

By the stoichiometry of the reaction (i):

1 mole of iodate ions are produced by 1 moles of iodine ions

So, [tex]2.44\times 10^{-4} moles[/tex] of iodate ions will be produced by [tex]\frac{1}{1}\times 2.44\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodine ions

Moles of potassium iodide = Moles of iodide ions = [tex]2.44\times 10^{-4}[/tex]

Since, the molar mass of potassium iodide = 166 g/mol

Using equation 1:

[tex]\text{Mass of potassium iodide}=2.44\times 10^{-4}mol\times 166 g/mol\\\\\text{Mass of potassium iodide}=0.0405 g[/tex]

To calculate the percentage by mass of a substance, the equation used is:

[tex]\text{Percent by mass}=\frac{\text{Mass of a substance}}{\text{Mass of solution}}\times 100[/tex]

Mass of a solution = 1.54 g

Mass of potassium iodide = 0.0405 g

Using above equation:

[tex]\text{Percent potassium iodide}=\frac{0.0405 g}{1.54g}\times 100\\\\\text{Percent potassium iodide}=2.63\%[/tex]

Hence, the percentage of potassium iodide in the sample is 2.63 %.

Expressing the results of potassium iodide in percentage = 2.63%

The chemical reaction of iodine ions with Bromine gas can be expressed as :

I⁻  + 3Br₂  + 3H₂O  -- > 6Br⁻ + IO₃ + 6H⁺ ----- ( 1 )

Chemical reaction between iodate ions with barium ions  can be expressed as :  Ba²⁺  + 2IO⁻₃ ------> Ba ( IO₃ )₂   --------- ( 2 )

Step 1 : Calculate the number of Barium iodate moles

mass of Barium iodate = 0.0596 g

molar mass of Barium iodate = 487.13 g/mol

from equation ( 1 )

moles of Barium iodate = ( 0.0596 ) / ( 487.13 ) = 1.22 * 10⁻⁴ moles

also from equation ( 1 ) the moles of potassium iodide = moles of iodide ions

= 2.44 * 10⁻⁴

molar mass of potassium iodide = 166 g/mol

Next step : Determine the mass of potassium iodide

moles of potassium * molar mass

= 2.44 * 10⁻⁴  * 166 g/mol  = 0.0405 g

Final step : Determine the percentage of potassium iodide in the solution

Percentage = ( mass of potassium iodide / mass of solution ) * 100

                   = ( 0.0405 / 1.54 ) * 100

                   = 2.63%

Hence we can conclude that potassium iodide in percentage = 2.63%

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calculate the value of (Ag+) in a saturated solution of AgCl in distilled water

Answers

Answer:

[tex][Ag^+]=1.3x10^{-5}M[/tex]

Explanation:

Hello there!

In this case, according to the dissociation of silver chloride in aqueous solution, we can write:

[tex]AgCl(s)\rightarrow Ag^+(aq)+Cl^-(aq)[/tex]

Whereas the equilibrium expression is:

[tex]Ksp=[Ag^+][Cl^-][/tex]

And the solubility product constant is  1.7 x10⁻¹⁰; thus, by inserting x as the concentration of both silver and chloride ions as they are the same at equilibrium, we obtain:

[tex]1.7x10^{-10}=x^2\\\\x=\sqrt{1.7x10^{-10}} \\x=1.3x10^{-5}M[/tex]

Which is also equal to the concentration silver ions at equilibrium in a saturated solution because we considered the Ksp.

[tex][Ag^+]=1.3x10^{-5}M[/tex]

Best regards!

Arrange the following 0.10 M solutions from most acidic to most basic. Justify your rankings.
KOH

KNO3

KCN

NH4Cl

HCl

Answers

KOH is an alkali metal hydroxide and so would be a strong base. HCl is a hydrogen halide in solution, which would be a strong acid (the exception would be HF). There are no other strong bases or acids in this list, so these two substances will comprise our bookends.

KNO3 is a salt produced during the neutralization reaction between KOH and HNO3; the former is (as we just noted) a strong base, and the latter is a strong acid. The salt consisting of the conjugate acid and base of a strong base and acid, respectively, produces a neutral solution in water. So, the KNO3 would be neutral.

KCN in solution consists of the ions K+ and CN-; K+, as we just went through, is the conjugate acid of KOH, a strong base. CN- is the conjugate base of HCN, a weak acid in solution. Since the resultant salt, KCN, is the neutralization product of a strong base and a weak acid, it will be slightly basic in solution (the CN- is a stronger base than K+ is as an acid). So, the KCN solution would be slightly basic.

NH4Cl dissociates in solution to give NH4+ and Cl-. NH4+, as the conjugate acid of the weak base ammonia, NH3, will donate an H+ in water. Cl- is the conjugate base of a strong acid, HCl. The neutralization product of a strong acid (HCl) and a weak base (NH3) would be slightly acidic. So, the solution of NH4Cl would be slightly acidic.

Ranking the solutions from most acidic to most basic (note: it’s important that the solutions have the same concentrations), we get:

HCl (strong acid)
NH4Cl (weak acid salt)
KNO3 (neutral salt)
KCN (weak basic salt)
KOH (strong base).

What process is represented by this redox equation?
C6H12O6 + 602 -> 6H20 + 6CO2

A. Rusting
B. Photosynthesis
C. Cellular respiration
D. Combustion

Answers

The redox equation C6H12O6 + 6O2 -> 6H2O + 6CO2 represents the process of cellular respiration. Option C

Cellular respiration is a biochemical process that occurs in living organisms, including plants and animals, to convert organic compounds, such as glucose (C6H12O6), into usable energy in the form of adenosine triphosphate (ATP). It is the primary process by which cells derive energy to carry out their functions.

In the given equation, glucose (C6H12O6) is being oxidized, losing electrons, and releasing carbon dioxide (CO2) as a byproduct. This oxidation process results in the production of energy-rich molecules, such as ATP.

Additionally, oxygen (O2) is being reduced, accepting the electrons from glucose and combining with hydrogen (H) to form water (H2O). This reduction process allows for the transfer of electrons and the generation of energy.

The process of cellular respiration is essential for the survival and functioning of organisms, as it provides the necessary energy for various metabolic activities, growth, and maintenance of cellular processes.

It is a fundamental metabolic pathway found in both plants and animals, enabling them to extract energy from organic molecules through the oxidation of glucose or other fuel sources.

Therefore, option C, cellular respiration, is the correct answer that represents the process described by the given redox equation.

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what is an example of an electrolyte solution?

Answers

Answer:

nacl with water

they are capable of conducting electricity

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