Hello I need the answer fast pls The tennis courts are 3 blocks west and 2 blocks south of Miguel’s house. The bike path is 5 blocks east and 2 blocks south of Miguel’s house. How many blocks are the tennis courts from the bike path?

Answer:

m = [tex]\frac{y+4}{x+5}[/tex]

Step-by-step explanation:

y-(-4) = m(x-(-5))

Simplify, distribute the negative sign outside of the parenthesis, remember negative times negative equals positive

y + 4 = m (x + 5)

Inverse operations, divide the equation by the value inside of the parenthesis

[tex]\frac{y+4}{x+5}[/tex] = m

Answer:

m=y+4x/x+5 your welcome !!

Answer:

10 and 42

Step-by-step explanation:

The difficulty with word problems is translating them into math.

Let's do that

---------------------

The sum of a number and two times a smaller number is 62.

let's call the bigger number b, and the smaller number s

b + 2s = 62

Three times the bigger number exceeds the smaller number by 116

3b = s + 116

-----------------------

Now manipulate one of the equations to isolate the variable

3b = s + 116

Subtract 116 from both sides

3b - 116 = s

substitute for s = 3b - 116 in

b + 2s = 62

b + 2(3b - 116) = 62

Distribute

b + 6b - 232 = 62

combine like terms

7b = 294

Divide both sides by 7

b = 42

to find s plug in b = 42 into

b + 2s = 62

42 + 2s = 62

subtract 42 from both side

2s = 20

divide both sides by 2

s = 10

Answer:

acute

Step-by-step explanation:

it is acute because it is less than 90 degrees

Answer:

One solution

Step-by-step explanation:

3(x – 2) = 22 – x

Distribute

3x - 6 = 22 -x

Add x to each side

3x-6+x = 22-x+x

4x -6 =22

Add 6 to each side

4x-6+6 = 22+6

4x = 28

Divide by 4

4x/4 = 28/4

x = 7

Answer:

One solution

Step-by-step explanation:

Solve for x to determine how many solutions it has

3(x - 22) = 22 - x

Distribute the 3

3x - 66 = 22 - x

Add x to both sides

4x - 66 = 22

Add 66 to both sides

4x = 88

Divide both sides by 4

x = 22

The equation has only one solution, the solution being 22

Answer:

I don't know what to say to someone who is a high school diploma Android to the other side of the kingdom of the crystal skull and bones

Answer:

4x²+21x-2

  (OR)

2x²-x-6

Step-by-step explanation:

According to the Question,

Given, The difference Between two trinomials is x²-10x+2 & If one of the trinomials is 3x²-11x-4.

Let, Two Trinomials are P(x) = A  &  Q(x) = 3x²-11x-4

Then, P(x) - Q(x) = x²-10x+2

Put Value, We get

A - (3x²-11x-4) = x²-10x+2

A = x²-10x+2 + (3x²-11x-4)

A = x²-10x+2 + 3x²-11x-4

A = 4x²+21x-2

(OR)

If we Let, Two Trinomials are Q(x) = A  &  P(x) = 3x²-11x-4

Then, P(x) - Q(x) = x²-10x+2

Put Value, We get

(3x²-11x-4) - A = x²-10x+2

A = 3x²-11x-4 - (x²-10x+2)

A = 3x²-11x-4 - x²+10x-2

A = 2x²-x-6

Answer:

£11.25

Step-by-step explanation:

The formula to calculate simple interest is given as:

Simple Interest = Principal × Rate × Time

Principal = Amount deposited in the bank = £100

Interest rate = 2.25%

Time in years = 5 years

Hence,

Simple Interest = £100 × 2.25% × 5

= £11.25

Therefore, the interest that will have been paid after 5 years is £11.25

Answer:

angle KPN=95 degree

Step-by-step explanation:

angle KPN = angle JPO (because they are vertically opposite angles)

Now,

angle JPO+angle LOP=180 degree(being co interior angles)

angle JPO + 85 =180

angle JPO =180-85

angle JPO =95

since angle JPO is equal to KPN ,angle KPN is 95 degree

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is given by the equation:

[tex]y=-16x^2+165x+69[/tex]

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let y = 0 and solve for x:

[tex]0=-16x^2+165x+69[/tex]

We can use the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = -16, b = 165, and c = 69.

Substitute:

[tex]\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}[/tex]

Hence, our solutions are:

[tex]\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40[/tex]

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

Answer:

10.71

Step-by-step explanation:

the person below was correct!

Answer:

Last image.

Step-by-step explanation:

So, we know that the orginal graph is of [tex]\sqrt[7]{x}[/tex]

We need to find the graph of [tex]-\sqrt[7]{x}-8[/tex]

First off, we see a negative in front of the root.

This means that all the values will be flipped across the x axis.

This removes the first two answer graphs, for they are of the postive root.

Next, we have a -8 following the root.

So, when another number is inside of the root(example: [tex]\sqrt[7]{x-6}[/tex]) You are going to add 6 to the x axis, basically shifting everything to the right(postive). If it was a postive 6 inside the root, we would move it left(negative)

This is not what is being done in our graph, I just wanted to explain this for future graphing.

Now, when a number is outside the root, such as the one above, then it shifts the y axis. In this case we have a -8 outside the root. This means that the graph will be shifted down(negative) by 8.

This eliminates the 3rd graph image, leaving the last graph answer shown below.

Hope this helps!

Answer:

D.

[tex]y = - 4x - 5[/tex]

Step-by-step explanation:

This is because the slopes are the same

Given:

z be inversely proportional to the cube root of y.

When y =0.064, then z =3.

To find:

a) The constant of proportionality k.

b) The value of z when y = 0.125.​

Solution:

a) It is given that, z be inversely proportional to the cube root of y.

[tex]z\propto \dfrac{1}{\sqrt[3]{y}}[/tex]

[tex]z=k\dfrac{1}{\sqrt[3]{y}}[/tex]              ...(i)

Where, k is the constant of proportionality.

We have, z=3 when y=0.064. Putting these values in (i), we get

[tex]3=k\dfrac{1}{\sqrt[3]{0.064}}[/tex]

[tex]3=k\dfrac{1}{0.4}[/tex]

[tex]3\times 0.4=k[/tex]

[tex]1.2=k[/tex]

Therefore, the constant of proportionality is [tex]k=1.2[/tex].

b) From part (a), we have [tex]k=1.2[/tex].

Substituting [tex]k=1.2[/tex] in (i), we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{y}}[/tex]

We need to find the value of z when y = 0.125.​ Putting y=0.125, we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{0.125}}[/tex]

[tex]z=\dfrac{1.2}{0.5}[/tex]

[tex]z=2.4[/tex]

Therefore, the value of z when y = 0.125 is 2.4.

Proportional quantities are either inversely or directly proportional. For the given relation between y and z, we have:

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

[tex]p = kq[/tex]

where k is some constant number called constant of proportionality.

This directly proportional relationship between p and q is written as

[tex]p \propto q[/tex]  where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n are two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n}[/tex]

or

[tex]n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n}\\\\or\\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

For the given case, it is given that:

[tex]z \propto \dfrac{1}{^3\sqrt{y}}[/tex]

Let the constant of proportionality be k, then we have:

[tex]z = \dfrac{k}{^3\sqrt{y}}[/tex]

It is given that when y = 0.064, z = 3, thus, putting these value in equation obtained above, we get:

[tex]k = \: \: ^3\sqrt{y} \times z = (0.064)^{1/3} \times (3) = 0.4 \times 3 = 1.2[/tex]

Thus,  the constant of proportionality k is 1.2. And the relation between z and y is:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}[/tex]

Putting value y = 0.0125, we get:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}\\\\z = \dfrac{1.2}{(0.125)^{1/3} } = \dfrac{1.2}{0.5} = 2.4[/tex]

Thus, for the given relation between y and z, we have:

Learn more about proportionality here:

https://brainly.com/question/13082482

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Work Shown:

7(-2-7k) + 4

7(-2) + 7(-7k) + 4

-14 - 49k + 4

-49k + (-14+4)

-49k - 10

In the second step, I distributed the outer 7 to each term inside. From there, I grouped and combined like terms, which were the -14 and 4.

Answer:

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

Step-by-step explanation:

Dejemos que el número de calendarios

Pedro vendió = x

Katrina vendió = y

Pedro y su compañera Karina vendieron 520 calendarios en diciembre.

x + y = 520 .... Ecuación 1

Pedro vendió 120 calendarios más que su socio.

x = y + 120

Sustituimos y + 120 por x

y + 120 + y = 520

2 años = 520 - 120

2 años = 400

y = 400/2

y = 200 calendarios

Resolviendo para x

x = y + 120

x = 200 + 120

x = 320 calendarios

Por lo tanto,

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

9514 1404 393

Answer:

  y = 9x^2 -8x +9

Step-by-step explanation:

The given equation has derivative ...

  y' = 2ax +b

The requirements on slope give rise to two equations:

  2a(1) +b = 10

  2a(-1) +b = -26

Adding these equations together gives ...

  2b = -16   ⇒   b = -8

Then we have ...

  2a -8 = 10

  a = (10 +8)/2 = 9

__

The given point lets us find the constant term c.

  y = 9x^2 -8x +c

  c = y -(9x -8)x = 29 -(9(2) -8)(2) = 29 -20 = 9

The equation of the parabola is ...

  y = 9x^2 -8x +9

Answer:

$127.75

Step-by-step explanation:

Multiply the cost by the area to find the total cost

Answer:

perpendicular slope = - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] + 5 ← is in slope- intercept form

with slope m = [tex]\frac{1}{2}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{2} }[/tex] = - 2

Answer:

I figured out that the probability that both marbles are red is 20/56 and the probability that both are green is 6/56. Then I added them together to get 26/56.

Hope this answer is right !

Answer:

The formula of the circumference of the circle

[tex]C =\pi D[/tex]

Step-by-step explanation:

To find the circumference of the circle follow the given steps.

1. Take a thread.

2. Fix one end of the thread at one point of the circle.

3. Move the thread along the length of the circle.

4. You reach the same fix end.

5. Measure the length of the thread.

6. It is the circumference of the circle.

The formula of the circumference of the circle

[tex]C =\pi D[/tex]

where D is the diameter of the circle.

Answer:

d. No because n·(1 - [tex]\hat p[/tex]) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·[tex]\hat p[/tex] > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - [tex]\hat p[/tex]) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, [tex]\hat p_1[/tex] = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, [tex]\hat p_2[/tex] = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·[tex]\hat p[/tex] ≥ 10, and n·(1 - [tex]\hat p[/tex]) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·[tex]\hat p[/tex]₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - [tex]\hat p[/tex]₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·[tex]\hat p[/tex]₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - [tex]\hat p[/tex]₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - [tex]\hat p[/tex]₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - [tex]\hat p[/tex]₂) = 8.96 is less than 10

Answer:

Step-by-step explanation:

17.63+145.86+52.91=206.40

i have no clue what you really need the question is unclear

Answer: 30

Step-by-step explanation:

there are 5 fifths in 1 hinting the name fifths

So that means there are 30 fifths in 6

Answer:

1

Step-by-step explanation:

4^0

Any number raised to the 0 power is 1.

Answer:

1

Step-by-step explanation:

Anything raised to  0  is  1.

Answer:

A. y^3 + 27

Step-by-step explanation:

Ed22

Answer: A. y3+27

Step-by-step explanation:

Answer:

242/48

Step-by-step explanation:

Answer:

[tex]\bar x = 260.1615[/tex]

[tex]\sigma = 70.69[/tex]

The confidence interval of standard deviation is: [tex]53.76[/tex] to [tex]103.25[/tex]

Step-by-step explanation:

Given

[tex]n =20[/tex]

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}[/tex]

[tex]\bar x = \frac{5203.23}{20}[/tex]

[tex]\bar x = 260.1615[/tex]

[tex]\bar x = 260.16[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

[tex]\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}[/tex][tex]\sigma = \sqrt{\frac{94938.80}{19}}[/tex]

[tex]\sigma = \sqrt{4996.78}[/tex]

[tex]\sigma = 70.69[/tex] --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

[tex]c =0.95[/tex]

So:

[tex]\alpha = 1 -c[/tex]

[tex]\alpha = 1 -0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the degree of freedom (df)

[tex]df = n -1[/tex]

[tex]df = 20 -1[/tex]

[tex]df = 19[/tex]

Determine the critical value at row [tex]df = 19[/tex] and columns [tex]\frac{\alpha}{2}[/tex] and [tex]1 -\frac{\alpha}{2}[/tex]

So, we have:

[tex]X^2_{0.025} = 32.852[/tex] ---- at [tex]\frac{\alpha}{2}[/tex]

[tex]X^2_{0.975} = 8.907[/tex] --- at [tex]1 -\frac{\alpha}{2}[/tex]

So, the confidence interval of the standard deviation is:

[tex]\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }[/tex] to [tex]\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }[/tex]

[tex]70.69 * \sqrt{\frac{20 - 1}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{20 - 1}{8.907}[/tex]

[tex]70.69 * \sqrt{\frac{19}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{19}{8.907}[/tex]

[tex]53.76[/tex] to [tex]103.25[/tex]