HELP ANYONE KNOW THE ANSWER???

Answer:

1=(w=6,C=20.80

2=(W=2,C=27.05)

3=(w=11,C=14.25)

4=(w=15,C=11.05)

Step-by-step explanation:

Just do the work

0.55x15=8.25+2.80=11.05

1.10x6=6.6+14.20=20.8

11x0.65=7.15+7.10=14.25

Out of process of elimination, 2=(W=2,C=27.05)

Answer:

Below.

Step-by-step explanation:

The second option on the bottom matches the first of the top  list.

This is how we check:

w = 6 and C = 20 .80

Plug these into the top equation:

C = 14.2 + 1.10w

20.80 = 14.2 + 6(1.10) = 14.20 + 6.60 = 20.80.

So that proves that we have the right answer.

The last one on the bottom matches the second on the top list.

The third option ion the bottom matches the third equation on the top

.

The first one on bottom matches the last one the top.

The last 3 are answered in exactly the same way as the first.

Answer:

1 Original amount: 20

End amount: 15

2 Original amount: 30

End amount: 45

3 Original amount: 625

End amount: 550

4 Original amount: 320

End amount: 112

5 Original amount: 165

End amount: 222.75

6 Original amount: 326

End amount: 423.80

7 Original amount: 27

End amount: 38.61

8 Original amount: 60

End amount: 70.02

Answer:

Option B : ( - 1 , 1 )   ==>    x = -1 , y = 1

Step-by-step explanation:

2x - y = - 3              -------- ( 1 )

x + y = 0 => x = - y   -------( 2 )

Substitute ( 2 ) in ( 1 ) : 2x  - y = - 3

                                 2( - y ) - y = - 3

                                  - 2y - y = -  3

                                   - 3y = - 3

                                       y = 1

Substitute y in ( 2) : x + y = 0

                              x + 1 = 0

                                x =  - 1

Step-by-step explanation:

-5(4)+2

-20+2

-18

just put 4 on the place of x

Answer:

[tex]=-18[/tex]

Step-by-step explanation:

[tex]g(x)=-5x+2[/tex]

Let's substitute 4 for x and solve.

[tex]g(4)=-5(4)+2[/tex]

[tex]g(4)=-20+2[/tex]

[tex]g(4)=-18[/tex]

This means that when the function of [tex]g[/tex] is 4, then the [tex]x[/tex] value is [tex]-18[/tex]

Hope this helps.

Answer:  B is the correct answer.

Answer: [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

total sides = 6

p (rolling a 1) = [tex]\frac{1}{6}[/tex]

p (rolling a 2) = [tex]\frac{1}{6\\}[/tex]

Note:

or - add

and - multiply

∴ [tex]\frac{1}{6} +\frac{1}{6} = \frac{2}{6}[/tex]

∴ [tex]\frac{2}{6} = \frac{1}{3}[/tex]

hence, p (rolling a 1 or 2) = [tex]\frac{1}{3}[/tex]

9514 1404 393

Answer:

  h₁(t) = -16t² +110

Step-by-step explanation:

Put the given initial height into the given formula. That will give the requested function. If the function name is supposed to be h₁(t), then rename it.

  f(t) = -16t² +110 . . . . . . h = 110, the initial height

  h₁(t) = -16t² +110

Answer:

Sqaure root 5 - sqaure root 5 p

Step-by-step explanation:

See image below:)

FYI you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps and it is free.

Answer: D.  3.50+4.00x≤20

Step-by-step explanation:

According to the question,

Total amount spent = (price of a pint of blueberries)+ (Price per pint of raspderries)(number of pints of raspberries)

Total amount he can spend must be less than or equal to $20

x=number of pints of raspberries

As per given,

[tex]3.50+4.00x\leq20[/tex], required equation

Hence, D is the correct option

Answer:

[tex]-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}[/tex]

Step-by-step explanation:

Given

[tex]-\frac{3}{x} , \frac{7y}{x}[/tex]

Required

Add

The statement can be interpreted as:

[tex]-\frac{3}{x} + \frac{7y}{x}[/tex]

Take LCM

[tex]-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}[/tex]

Answer: 3(2+x) or 3x+6

Step-by-step explanation:

Take this a step at a time

First is a sum of two and a number

set "a number" as x

sum of two and a number would be 2+x

triple it

3(2+x) or 3x+6

Answer:

3(x+2)

Step-by-step explanation:

Explanation:

The " sum of a number and 2

" means ADD them:

→ x+2

Triple that means multiply by

3

→ 3(x+2)

Answer:

[tex] \large{ \tt{❃ \: SOLUTION}} : [/tex]

[tex] \large{ \tt{✻ \: USING \: PYTHAGOREAN\: THEOREM : }}[/tex]

[tex] \large{ \tt{❁ {h}^{2} = {p}^{2} + {b}^{2} }}[/tex]

[tex] \large{ ↦( \sqrt{61} })^{2} = {5}^{2} + {b}^{2} [/tex]

[tex] \large{↦ \: 61 = 25 + {b}^{2} }[/tex]

[tex] \large{↦25 + {b}^{2} = 61 }[/tex]

[tex] \large{↦ {b}^{2} = 61 - 25}[/tex]

[tex] \large{↦ {b}^{2} = 36}[/tex]

[tex] \large{↦ {b} = \sqrt{36} }[/tex]

[tex] \large{↦ b = \sqrt{ \underline{3 \times 3} \times \underline{ 2 \times 2} }}[/tex]

[tex] \large{↦b = 3 \times 2}[/tex]

[tex] \large{ \boxed{ \boxed{ \bold{↦b = 6 \: units }}}}[/tex]

✺ Never give up on something that you actually want !

۵Hope I helped! ツ

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[tex]\quad\quad\quad\quad\boxed{\tt{ {c}^{2} = \sqrt{ {a}^{2} + {b}^{2} }}} [/tex]

[tex]\quad\quad\quad\quad\tt{ a = 5 } [/tex]

[tex]\quad\quad\quad\quad\tt{ b = ? } [/tex]

[tex]\quad\quad\quad\quad\tt{ {c = \sqrt{61} }} [/tex]

[tex]\quad\quad\quad\quad\tt{ {( \sqrt{61}) }^{2} = \sqrt{ {(5)}^{2} + {b}^{2} }} [/tex]

[tex]\quad\quad\quad\quad\tt{ {61}= \sqrt{ {25} + {b}^{2} }} [/tex]

[tex]\quad\quad\quad\quad\tt{ 61 = \sqrt{ 25 + {b}}} [/tex]

[tex]\quad\quad\quad\quad\tt{ {b } = \sqrt{25 - 61 }} [/tex]

[tex]\quad\quad\quad\quad\tt{ {b } = \sqrt{36 }}[/tex]

[tex]\quad\quad\quad\quad\tt{ {b } = 6 }[/tex]

[tex]\quad\quad\quad\quad \boxed {\boxed{\tt{ \color{magenta} {b } = 6\:units }}}[/tex]

___________________________________

#CarryOnLearning

✍︎ C.Rose❀

A sampling distribution is the probability distribution of a random - sample - based statistic. It describes a range of possible outcomes that of a statistic.

Answer: i hope you pass that quiz

Step-by-step explanation:

Answer:

you should pick green colour

Answer:

the answer is w = 148-12h/12+2h

The equivalent equation is -

[tex]$w=\frac{74-6h}{h+6}[/tex]

We have the equation written by Carly → 148 = 2 (6w + 6h + hw) that represent the width and height of the box in the shape of a rectangular prism.

We have to solve for w.

Any expression written in a form different from the original form, but gives same result for any input are called equivalent expressions.

We have -  

[tex]$log(\frac{x}{\omega}) = 2\pi[/tex]

log(x) - log(ω) = 2π

log(x) = 2π + log(ω)

x = [tex]e^{(2\pi + log(\omega))} = e^{2\pi } \times e^{log(\omega)}[/tex]

According to the question, we have -

148 = 2 (6w + 6h + hw)

(6w + 6h + hw) = 74

hw + 6w = 74  - 6h

w(h + 6) = 74 - 6h

[tex]$w=\frac{74-6h}{h+6}[/tex]

Hence, the equivalent equation is -

[tex]$w=\frac{74-6h}{h+6}[/tex]

To solve more questions on Rearranging expression, visit the link below-

https://brainly.com/question/1824488

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Answer:

$0.35

Step-by-step explanation:

8.40/24 = $0.35

Answer:

x ≥ 40

Step-by-step explanation:

3x - 55 ≥ 65

combine like terms

3x  ≥ 65 + 55

3x  ≥120

divide both sides of the equation by 3

x  ≥ 40

Answer:

12313685 is the answer............happy to help u

Answer:

x=42°

Step-by-step explanation:

take x degree as reference angle

using tan rule

tan x=opposite/adjacent

tan x=9/10

tan x=0.9

x=[tex]tan^{-1}[/tex]0.9

x=41.98

x=42 degree

Answer:

41.987° which rounds to 42 degrees

Step-by-step explanation:

Answer(s):

[tex]\displaystyle y = 300sin\:(\frac{\pi}{8}x + \frac{\pi}{2}) + 400 \\ y = 300cos\:\frac{\pi}{8}x + 400[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 400 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-4} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{\pi}{8}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{16} \hookrightarrow \frac{2}{\frac{\pi}{8}}\pi \\ Amplitude \hookrightarrow 300[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 400 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{16} \hookrightarrow \frac{2}{\frac{\pi}{8}}\pi \\ Amplitude \hookrightarrow 300[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 300sin\:\frac{\pi}{8}x + 400,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle 4\:units[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle 4\:units,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-4} = \frac{-\frac{\pi}{2}}{\frac{\pi}{8}}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 300sin\:(\frac{\pi}{8}x + \frac{\pi}{2}) + 400.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [36, 400],[/tex]from there to [tex]\displaystyle [20, 400],[/tex]they are obviously [tex]\displaystyle 16\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 16.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 400,[/tex]in which each crest is extended three hundred units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

P1.H.x²+y²=34

centre[h,k]=(0,0)

point=[3,5]

now

radius=[tex]\sqrt{(0-3)²+(0-5)²}=\sqrt{34}[/tex]

now

equation of a circle is;

(x-h)²+(y-k)²=[tex]\sqrt{34}²[/tex]

x²+y²=34

P:2I.(x-6)²+(y+7)²=121

centre[h,k]=(6,-7)

diameter=22

radius[r]=22/2=11

now

equation of a circle is;

(x-h)²+(y-k)²=r²

(x-6)²+(y+7)²=11²

(x-6)²+(y+7)²=121

Answer: Hello the options related to this question is missing below are the missing options

A. Themes

B. Excerpts

C. Descriptors

D. Codes

answer:

Descriptors

Step-by-step explanation:

Descriptors is a piece of data used to describe how other data are to be stored or stored. they are very necessary in Dedoose for producing mixed methods research

while a mixed method research is a type of research that uses past research data. using all possible ways

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

Answer:

Data B

Step-by-step explanation:

Given the data :

A: 20347, 20327, 22117, 21762, 20864, 20102, 21684, 20063, 21728, 21580, 21720, 20920, 21442, 20766

B: 3.38, 4.64, 4.09, 3.93, 4.25, 4.63, 4.78, 4.25

The spread of a data gives the variation in the data values of a given sample.

To obtain which data has the larger spread, we obtain the coefficient of variation. Which is the ratio of the standard deviation and the mean of the dataset.

(Standard deviation / mean) * 100%

Using calculator :

Data A :

Mean, x = 21101.5714

Standard deviation, s = 700.28925

Coefficient of Variation :

(700.28925 / 21101.5714) * 100% = 3.32%

Data B :

Mean, x = 4.24375

Standard deviation, s = 0.457006955

Coefficient of Variation :

(0.457006955 / 4.24375) * 100% = 10.77%

10.77% > 3.32%

Hence. Data B has a larger spread

Answer:

- 9 + 9i

Step-by-step explanation:

(- 7 + 3i) - (2 - 6i)

- 7 + 3i - 2 + 6i

- 7 - 2 + 9i

- 9 + 9i