Answer:
B.
[tex]{ \tt{f(x) = \sqrt[3]{x + 11} }}[/tex]
let the inverse of f(x) be m:
[tex]{ \tt{m = \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3} = x + 11}} \\ { \tt{ {m}^{3} - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) = {m}^{3} - 11 }}[/tex]
substitute for x in place of m:
[tex]{ \bf{f {}^{ - 1}(x) = {x}^{3} - 11 }}[/tex]
PLEASE CORRECT BEFORE ANSWERING I AM HAVING TROUBLE GETTING THINNGS RIGHT SO PLEASE HELP
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Answer:
3
Step-by-step explanation:
AB is 1 unit long.
A'B' is 3 units long.
The scale factor is the ratio of these lengths:
scale factor = A'B'/AB = 3/1 = 3
ABC is dilated by a factor of 3 to get A'B'C'.
Two cars that are 150 miles apart start driving toward each other on parallel roads. The average speed of the first car is 60 miles per hour. The average speed of the second car is 55 miles per hour. Which equation can be used to determine t, the time it takes for the two cars to pass each other? A table showing Rate in mile per hour, Time in hours, and Distance in miles. The first row shows First Car and has 60, t, and 60 t. The second row shows Second Car and has, 55, t, and 55 t.
Answer:
60t + 55t = 150
Step-by-step explanation:
I took the test. I know it's correct!!!
The value of a car will “depreciate” over time. For example, a car that was worth $24 000 when it was new, is being sold for $13 500 three years later. Determine the annual depreciation rate on this car. Express your final answer as a percent, rounded to one decimal place.
Answer:
The car will depreciate at a rate of 21.14% per year.
Step-by-step explanation:
Given that the value of a car will “depreciate” over time, and, for example, a car that was worth $ 24,000 when it was new, is being sold for $ 13,500 three years later, to determine the annual depreciation rate on this car the following calculation must be performed:
13,500 x (1 + X) ^ 1x3 = 24,000
13,500 x (1 + 0.2114) ^ 3 = 24,000
X = 21.14%
Therefore, the car will depreciate at a rate of 21.14% per year.
Responde las preguntas 10 y 11 con base al siguiente gráfico. A 10. ¿Cuáles son los nombres de los ángulos de color azul y rojo respectivamente? A. Obtuso y llano. B. Llano y obtuso. C. Obtuso y agudo. D. Agudo y llano. 11. ¿Cuáles son los colores de un ángulo agudo y uno recto respectivamente? A. Naranja y verde. B. Morado y rojo. C. Morado y naranja. D. Verde y naranja. firmaciones ac
Answer:
10) Los ángulos en azul y rojo son llano y obtuso, respectivamente. (Respuesta: B)
11) Los ángulos agudo y recto están diferenciados por los colores morado y naranja, respectivamente. (Respuesta: C)
Step-by-step explanation:
Basándonos estrictamente en lo descrito en la figura, tenemos la siguiente clasificación por colores:
Agudo - Morado.
Plano o Recto - Naranja.
Obtuso - Rojo.
Llano - Azul.
Completo - Negro.
A continuación, se consigna las respuestas en forma de oración:
10) Los ángulos en azul y rojo son llano y obtuso, respectivamente. (Respuesta: B)
11) Los ángulos agudo y recto están diferenciados por los colores morado y naranja, respectivamente. (Respuesta: C)
The cost function in a computer manufacturing plant is C(x) = 0.28x^2-0.7x+1, where C(x) is the cost per hour in millions of dollars and x is the number of items produced per hour in thousands. Determine the minimum production cost.
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Answer:
$562,500 per hour
Step-by-step explanation:
The cost will be a minimum where C'(x) = 0.
C'(x) = 0.56x -0.7 = 0
x = 0.7/0.56 = 1.25
The cost at that production point is ...
C(1.25) = (0.28×1.25 -0.7)1.25 +1 = -0.35×1.25 +1 = 0.5625
The minimum production cost is $562,500 per hour for production of 1250 items per hour.
_____
Additional comment
This is different than the minimum cost per item. This level of production gives a per-item cost of $450. The minimum cost per item is $358.30 at a production level of 1890 per hour.
x -3,4,11,18 y -3,1,5,9
Is the relationship linear, exponential, or neither?
Choose 1 answer:
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Answer:
linear
Step-by-step explanation:
The points all lie on a straight line. The relationship is linear.
p and q are two numbers.whrite down an expression of. a.) the sum of p and q. b) the product of p and q
6. A boy pushes his little brother in a box with a force of 500 N for 324 m How much work is this if the force of
friction acting on the sliding box is (a) 100 N (6) 250. N?
Answer:
(a) 129600 J
(b) 81000 J
Step-by-step explanation:
The work done is given by the product of force and the displacement in the direction of force.
Force, F = 500 N
distance, d = 324 m
(a) friction force, f = 100 N
The work done is
W = (F - f) x d
W = (500 - 100) x 324
W = 129600 J
(b) Friction, f = 250 N
The work done is
W = (F - f) d
W = (500 - 250) x 324
W = 81000 J
To the nearest 100th feet, find the volume of a hollow cylinder having inner radius =150 in, outer radius= 170 in and the height = 220 in
Answer:
R1 = 150 in = 12.5 ft
R2 = 170 in = 14.167 ft
H = 220 in = 18.333 ft
Volume of solid cylinder = Pi * R^2 * H
So the volume of a hollow cylinder must be V = Pi * H * (R2^2 - R1^2)
V = 3.142 * 18.33 * (14.17^2 - 12.5^2) = 2565 ft^3
.
One number is 2 less than a second number.
Twice the second number is 16 more than 4 times
the first. Find the two numbers.
Answer:
x = one number
y = second number
Where,
x = y - 3
2y = 4x - 16
Multiply the first equation by 2 and substitute the second equation into it.
2(x=y-3) : 2x = 2y - 6
2x = (4x - 16) - 6
Combine like terms
2x = 4x - 22
2x - 2x + 22 = 4x - 2x -22 + 22
22 = 2x
22/2 = 2x/2
11 = x
Step-by-step explanation:
in a group of boys the number of arrangments of boys 4 boys is 12 times the number of arrangment of 2 boys the number of boys in the group is
Answer:
4*12*2
Step-by-step explanation:
it will be the right answer
Answer:
There are 6 boys in group.
Step-by-step explanation:
Since we have given that
Number of arrangement of 4 boys = 12 times the number of arrangement of 2 boys.
So, Let the number of boys in the group be 'x'.
So, Number of boys in the group will be
\begin{gathered}x=\frac{12\times 2}{4}\\\\x=\frac{24}{4}\\\\x=6\end{gathered}
x=
4
12×2
x=
4
24
x=6
Hence, there are 6 boys in the group.
hope it helps you a follow would be appreciated
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Ау
What is the pre-image of vertex A' if the image shown
on the graph was created by a reflection across the y-
axis?
(-8. -6)
4-6. 8)
(8.6)
06. -
4
BY
-
Answer:
(- 6, 8 )
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
A' (6, 8 ) → A (- 6, 8 )
Then the pre-image of A' is A (- 6, 8 )
The pre-image of vertex A' would be (-8, 6) on the graph was created by a reflection across the y- axis
The pre-image of vertex A' after a reflection across the y-axis can be found by taking the corresponding point on the other side of the y-axis.
If the image is shown on the graph, and vertex A' is located at (8, 6), then the pre-image of vertex A' would be the point on the opposite side of the y-axis, which has the same x-coordinate but the opposite sign for the y-coordinate.
So, the pre-image of vertex A' would be (-8, 6).
To know more about vertex , here
https://brainly.com/question/21191648
#SPJ2
Simplify the expression3x 3√648x4y8
Answer:
= 1296x √ xy
Step-by-step explanation:
Apply exponent rule: a^b . a^c = a^b + c 3 . 3 = 3^ 1 + 1
= x . 3^1+1 √648x . 4y . 8
Add the numbers: 1 + 1 = 2
= x . 3^2 √648x . 4y . 8
= 3^2 . 144x √ xy
Refine
= 1296x √ xy
Evaluate the following expressions
Step-by-step explanation:
a.2+9-5=6
b.-9+1=-8
c.7(-36+50/120)2
=7(24/120)2
(2/3)x-1=27/8,find x
Answer:
x = 105/16
Step-by-step explanation:
2/3x - 1 = 27/8
Add 1 to each side
2/3x - 1+1 = 27/8+1
2/3x = 27/8 + 8/8
2/3x = 35/8
Multiply each side by 3/2
3/2 * 2/3x = 35/8 *3/2
x = 105/16
Find the height of a cone with a diameter of 12 m whose volume is 226m Use 3.14 for pi and round your answer to the nearest meter
Answer:
6m
Step-by-step explanation:
h=3(/V πr^2)=3(226/ π·6^2)≈5.99484
round to 6
The side lengths of a triangle are 5,10, and 13. Is this a right Triangle?
No because 5^2 +10^2 is not equavalent to 13^2
by using the pythagoras' theorem
The fourth term of an=(1/2)^n is
Answer:
[tex]1/16[/tex]
Step-by-step explanation:
The formula for the sequence [tex]a_n=\frac{1}{2}^n[/tex] is used to find the [tex]n[/tex]th term of the sequence.
To find the fourth term, substitute [tex]n=4[/tex]:
[tex]a_4=\left(\frac{1}{2})\right ^4,\\a_4=\frac{1^4}{2^4}=\boxed{\frac{1}{16}}[/tex]
Answer:
1/16
Step-by-step explanation:
the nth term is
[tex]a_{n} = (\frac{1}{2} )^{n}[/tex]
the 4th term is found by substituting n=4
[tex]a_{4} =(\frac{1}{2} )^{4} = \frac{1^{4} }{2^{4} } = \frac{1}{16}[/tex]
Robin will choose a movie from the Red Box when all movies are in stock. If she
randomly chooses a Romance, Comedy, or Action, what is the probability she will
choose a Romance?
PLEASE HELP ME ASAP (72 POINTS)
Answer:
d=10.45t
Step-by-step explanation:
The last one is the answer.
Hope this helps!
--Applepi101
Answer:
D) d=10.45t
Step-by-step explanation:
His distance(d) was 100. And his time(t) was 9.58 seconds.
So 100=9.58x
x≈10.44
The answer is D, because 10.45 is greater than 10.44.
I hope this helps!
If land the domain of the following peicewise function f(x)={x^2 +2 if -6
Answer:
? what is this question asking
Step-by-step explanation:
ALEKS questions driving me insane
Answer:
3000
growth
3.4
Step-by-step explanation:
Answer:
k bestie here we go again...
Initial price: $3200
Function represents growth
Price increases by 4.1% every year
yo so ill give you a trick
the very first number in the equation is ALWAYS the initial price for exponential functions
if the decimal in the parantheses has a 1 in front of it (e.g. 1.041) it's ALWAYS going to be growth
To find how much it increases move the decimal forward by 2 places
What is the derivative of x^2?
Answer:
[tex]\displaystyle \frac{d}{dx}[x^2] = 2x[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = x^2[/tex]
Step 2: Differentiate
Basic Power Rule: [tex]\displaystyle \frac{dy}{dx} = 2x^{2 - 1}[/tex]Simplify: [tex]\displaystyle \frac{dy}{dx} = 2x[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
someone find x for me lol
Hi there!
[tex]\large\boxed{x = 60^o}[/tex]
We know:
∠AGB ≅ ∠DGC because they are vertical angles. They both are 90°.
∠AGE ≅ FGC because they are vertical angles, equal 30°.
∠BGF ≅ ∠DGE are vertical angles, both equal x.
All angles sum up to 360°, so:
360° = 90° + 90° + 30° + 30° + x + x
Simplify:
360° = 240° + 2x
Subtract:
120° = 2x
x = 60°
In a large sample of customer accounts, a utility company determined that the average number of days between when a bill was sent out and when the payment was made is with a standard deviation of days. Assume the data to be approximately bell-shaped.
Required:
a. Between what two values will approximately 68% of the numbers of days be?
b. Estimate the percentage of customer accounts for which the number of days is between 18 and 46.
c. Estimate the percentage of customer accounts for which the number of days is between 11 and 53.
When a < 0 in the quadratic function y = ax2 + bx + C, the graph of the quadratic function opens _____?
Answer:
downwards
Step-by-step explanation:
Given the quadratic function in standard form
y = ax² + bx + c ( a ≠ 0 )
• If a > 0 then the graph opens upwards
• If a < 0 then the graph opens downwards
here bro hope you answer,if you can't just blank it:)
Answer:
DIRECTION: On your activity notebook, answer each of the following:
A. MODIFIED TRUE OR FALSE. Determine whether each statement is true or false. If the statement is false, explain why.
1. The total area under the normal distribution is infinite.False [its 1]
2. The standard normal distribution is a continuous distribution .True.
3. All variables that are approximately normally distributed can be transformed to standard normal variables.True
4. The z value corresponding to a number below the mean is always negative true..
5. The area under the standard normal distribution to the left of z-0 is negative.
True
*REVERSE PROPORTION*
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Answer:
33.3%
Step-by-step explanation:
The selling price of £42 is (1 +40%) times the total purchase price.
1.40 × purchase price = £42
purchase price = £42/1.40 = £30
The total profit is 40% of this, so is ...
£30 × 40% = £12
The purchase price of the skirt is ...
total cost - glove cost = skirt cost = £30 -3 = £27
The profit on the skirt is ...
total profit - glove profit = skirt profit = £12 -100% × £3 = £9
Then the percentage profit on the skirt is ...
skirt profit % = skirt profit / skirt cost × 100% = £9/£27 × 100% = 33.3%
The percentage profit on the cost of the skirt was 33.3%.
A set of solar batteries is used in a research satellite. The satellite can run on only one battery, but it runs best if more than one battery is used. The variance σ2 of lifetimes of these batteries affects the useful lifetime of the satellite before it goes dead. If the variance is too small, all the batteries will tend to die at once. Why? If the variance is too large, the batteries are simply not dependable. Why? Engineers have determined that a variance of σ2 = 23 months (squared) is most desirable for these batteries. A random sample of 30 batteries gave a sample variance of 16.3 months (squared). Using a 0.05 level of significance, test the claim that σ2 = 23 against the claim that σ2 is different from 23.
Answer:
Hence, we reject H_0 as There is sufficient evidence to show that population variance is not 23
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=30[/tex]
Variance [tex]\sigma= 16.8[/tex]
Significance Level [tex]\alpha=0.05[/tex]
[tex]\sigma = 23[/tex]
Genet=rally the Hypothesis are as follows
Null [tex]H_0=\sigma^2=23[/tex]
Alternative [tex]H_a=\sigma^2 \neq 23[/tex]
Generally the equation for Chi distribution t is mathematically given by
t test statistics
[tex]X^2=\frac{(n-1)\sigma}{\sigma^2}[/tex]
[tex]X^2=\frac{(30-1)16.8^2}{23}[/tex]
[tex]X^2=355.86[/tex]
Therefore
Critical Value
[tex]P_{\alpha,df}[/tex]
Where
[tex]df=29[/tex]
[tex]P_{\alpha,df}=16.0471 and 45.7223[/tex]
[tex]X^2=45.7223[/tex]
Hence, we reject H_0 as There is sufficient evidence to show that population variance is not 23
simplify. can someone help i am lost
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Answer:
[tex](S)\cdot(H)\cdot(E)\cdot(e)\cdot(\theta)\cdot(\epsilon+1+1)\cdot(\xi)\cdot(s)\cdot(h)[/tex]
Step-by-step explanation:
The inverse function of fun(x) is indicated using a -1 exponent. That is ...
[tex]\text{fun}(\text{fun}^{-1}(x)) = x\\\text{fun}^{-1}(\text{fun}(x)) = x[/tex]
The usual trig identities apply:
sin²(x) +cos²(x) = 1
sec²(x) -tan²(x) = 1
sin(x) = 1/csc(x)
__
So, the expression simplifies to ...
[tex](S)\cdot(H)\cdot(E)\cdot(e)\cdot(\theta)\cdot(\epsilon+1+1)\cdot(\xi)\cdot(s)\cdot(h)[/tex]