Help me out plzzzzzz

Answer:

[tex]x = \frac{5}{13} [/tex]

Step-by-step explanation:

[tex] \frac{3}{4} x + \frac{5}{4} = 4x[/tex]

[tex]3x + 5 = 16x[/tex]

[tex]3x - 16x = - 5[/tex]

[tex] - 13x = - 5[/tex]

[tex]x = \frac{5}{13} [/tex]

Answer:

6.72

Step-by-step explanation:

I multiplied both numbers by 10 to make it easier in my opinion. That made the equation 994.66 x 148

Then, I divided it until i got to the thousandths place. Lastly, i just rounded making it 6.72

Answer:

(G)77

Step-by-step explanation:

44+11=55.

55+22=77.

77+33=110.

110+44=154.

154+55=209.

Answer:

-16

Step-by-step explanation:

x = -3 is less than -2, so you should use the first equation 5x-1

thus, 5(-3)-1 = -16

Answer:

7, 8, 9

Step-by-step explanation:

1/5 = 6/30

1/3 = 10/30

Answer:

2

Step-by-step explanation:

first multiply everything by 6 to get rid of the fractions

then we get 5m-4 -6 = 24m -9m -30

simplify the equation 5m-10=15m-30

subtract 5m from both sides and add 30 to both sides 10m=20

divide by 10, m=2

Answer:

0.0300300030000...

Step-by-step explanation:

An irrational number has endless non-repeating digits to the right of the decimal point. They can be written as decimals, but not as fractions.

1632 can be written as 3264/2

0.25 can be written as 1/4

0 could be written as 0/0

but 0.0300300030000 cannot be written as a fraction, and it satisfies the condition of an irrational number having endless non-repeating digits to the right of the decimal point.

Answer:

[tex] \frac{5}{8} k = 25 \\ \frac{5k}{8} = 25 \\ 5k = 25 \times 8 \\ 5k = 200 \\ k = \frac{200}{5} \\ k = 40[/tex]

I hope it helped U

stay safe stay happy

Answer:

k=1/40

Step-by-step explanation:

multiple both sides by 8k

5= 25×8k

simplify 25×8k to 200k

5=200k

divide both sides by 200

5/200=k

simplify 5/200 to 1/40

1/40= k

switch sides

k=1/40

Answer:

It is 7x + 12

Step-by-step explanation:

[tex]5(3x + 2) - 2(4x - 1)[/tex]

open brackets:

[tex] = 15x + 10 - 8x + 2[/tex]

group like terms together:

[tex] = (15x - 8x) + (10 + 2)[/tex]

factorise out x :

[tex] = x(15 - 8) + 12 \\ = 7x + 12[/tex]

Answer:

answer) the change is $7.90

Answer:

...

Step-by-step explanation:

Answer:

Parallel lines

Step-by-step explanation:

To graph an exponential,

d. T-chart using random values for x and y.

The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.

These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.

Now,

We know an exponential function is a function in which the independent variable is the exponent.

One such function is y = eˣ

Now, To graph an exponential function you come up with values to use in the graph should be a T-chart using random values for x and y.

As it would result in graphing the complete nature of the function.

Learn more about graphs here :

brainly.com/question/2288321

#SPJ7

Step-by-step explanation:

ABCD is a quadrilateral triangle,where AD=BC and <DAB =<CBA.

In ∆ABD and ∆BAC

•AD=BC. (given)

•<DAB=<CBA (given)

•AB=BA. (common side)

Therefore, ∆ABD ≌ ΔBAC. {SAS congruence rule}

Answer:

no soultion

Step-by-step explanation:

did on paper

Answer:

exactly one solution

Step-by-step explanation:

got it right on khan lol

Answer: 8 hours

Step-by-step explanation:

Given information

Admission fee = $7.00

Hour rent fee = $1.50

Number of hours = h

Total fee = $19

Set equation according to the given information

Total fee = admission fee + (hours) × (hour rend fee)

Substitute values into the equation

19 = 7 + 1.5h

Subtract 7 on both sides

19 - 7 = 7 + 1.5h - 7

12 = 1.5h

Divide 1.5 on both sides

12 / 1.5 = 1.5h / 1.5

[tex]\boxed{h=8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:  Choice B

Work Shown:

[tex]-2 \le 2x-4 < 4\\\\-2+4 \le 2x-4+4 < 4+4\ \text{ ... add 4 to all sides}\\\\2 \le 2x < 8\\\\2/2 \le 2x/2 < 8/2\ \text{ ... divide all sides by 2}\\\\1 \le x < 4\\\\[/tex]

This says that x is between 1 and 4; it can equal 1, but it can't equal 4.

To visually represent this, we'll have a closed circle at 1, an open circle at 4, with shading in between these circles. This is represented by graph B.

Answer:

11

Step-by-step explanation:

2^10 + 2^10 = 2^x

1024 + 1024 = 2^x

2,048 = 2^x

x = 11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 11[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2^{10}+2^{10} = 2^x\\--------------\\\rightarrow 2^{10} = 1024\\\\\rightarrow 1024 + 1024 = 2^x\\\\\rightarrow 2048 = 2 ^x\\\\\rightarrow log(2^x)=log(2048)\\\\\rightarrow xlog(2)=log(2048)\\\\\rightarrow \frac{log(2)}{log(2)} =\frac{log(2048)}{log(2)}\\\\\rightarrow x = \frac{log(2048)}{log(2)}\\\\\rightarrow \boxed{x = 11}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]2(3m + 6n) + 3(5m - 2n) + 5( - 6m + n) \\ [/tex]

open the brackets:

[tex] = (6m + 12n) + (15m - 6n) + ( - 30m + 5n) \\ [/tex]

group the coefficients of m and n in their brackets:

[tex] = (6 + 15 - 30)m + (12 - 6 + 5)n \\ [/tex]

then operate the brackets:

[tex] = - 9m + 11n[/tex]

Answer:

[tex]4y + 6y = 90 \\ 10y = 90 \\ y = 9 \\ thank \: you[/tex]

Answer:

Yes

Step-by-step explanation:

6 × 18.75 = 112.50

8 × 18.75 = 150.00

11 × 18.75 = 206.25

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Answer:

12. (2, -3)

13. AH: +15   B: +721   CB: 0   N: +462   WB: -1200

Step-by-step explanation:

12.

When a point is reflected over the x-axis, the y coordinate becomes opposite because you are changing its y value, not its x-value. So (-2, 3) reflecting over the x-axis becomes (-2, -3).

The same concept goes for reflecting over the y-axis. The x coordinate becomes opposite because you are changing its x value. (It's like folding the graph in half and seeing where the point matches up with. So (-2, -3) reflecting over the y-axis becomes (2, -3).

13.

All you have to do is list each artifact and where they were found in relation the sea level (0). If it is above sea level then it is a positive number, below sea level is a negative number.

Arrow head: +15 (since it is 15 feet above sea level)

Woven basket: -1200 (since it is 1200 feet below sea level)

Answer:

31000 or 31 × 10^3

6.2 (5× 10^3)

Answer:

y- intercept, x=0

8(0)-4y=12

y=-3

Answer:

5n+3

Step-by-step explanation:

:)

Answer:

[tex]\alpha n=5n+3[/tex]

Step-by-step explanation:

Answer:

She didn't change the direction of the sign

Step-by-step explanation:

When dividing both sides by a negative number in an inequality, you must change the sign.

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]