Answer: 2/1 (Choice D)
Explanation:
He flipped the coin 39 times, of which 26 heads came up. That must mean 39-26 = 13 tails came up.
The ratio of heads to tails is 26/13 = 2/1
We can write that as 2:1 to mean similar notation. The key is that we list heads first since the phrasing is "ratio of heads to tails", where heads is listed first. If you had tails first, then it would flip to 1/2 aka 1:2
convert six yard to feet
Answer:
18 feet
Step-by-step explanation:
To convert : multiply the length value by 3
=> 6 x 3
=> 18 feet
Can u help solve this
Answer:
Sure:)! the answer is-487.5
Step-by-step explanation:
1.3x3xr^31.3x3=3.93.9r^3r=55x5x5=1253.9x125=487.5As said in the problem pie=3 as determined in the problem. Hence, the answer is 487.5
Hope this helps :)!
Step-by-step explanation:
[tex]volume = \frac{4}{3} \pi \: {r}^{3} \\ = here\pi = 3 \\ then \: v = \frac{4}{3} \times 3 \times {5}^{3} \\ = 4 \times 125 \\ = 500 {in}^{3} \\ thank \: you[/tex]
Simplify: squrt 18x⁷
Answer:
3x^3 ⋅ √2x
Step-by-step explanation:
provisions for 630 men to last for 25 days. How many men must be transferred to another camp so that the food lasts for 30 days?
Answer:
105
Step-by-step explanation:
25 days = Food for 630 men
30 days = x (Inverse variation)
30 * x = 630 * 25
x = 630 * 25/30
= 21 * 25
= 525 men.
630 - 525 = 105 men.
Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.
Simplify -52 + 8|-1| + (-3).
integers
[tex]18 \div ( - 9) = [/tex]
[tex] - 10 \div 2 = [/tex]
[tex] - 2 + ( - 6) = [/tex]
[tex] - 8 - 4 = [/tex]
[tex]( - 2 \times - 12) \div (18 \div - 9 = [/tex]
[tex](120 - 30) \div ( - 42 - 3) = [/tex]
[tex]1000 \div (125 \times - 2) = [/tex]
[tex](5 - 30) \div ( 8 - 3) = [/tex]
[tex]12 \div (4 - 8) = [/tex]
please mark this answer as brainlist
Find the value of x for which (4/5)-4 X(4/5)-7 = (4/5)2x-1
Answer:
0.8 -4*0.8-7=0.8*2x-1
0.8-3.2-7=1.6x-1
0.8-10.2+1=1.6x
1.8-10.2=x1.6
-8.4=x 1.6
x= -8.4 / 1.6
x= - 5.25
Does the point (2, 6) lie on the circle shown? Explain.
O Yes, the distance from (3, 0) to (0, ) is 3 units.
O Yes, the distance from (0, 0) to (2, V6) is 3 units.
O No, the distance from (3, 0) to (2, 6) is not 3 units.
O No, the distance from (0, 0) to (2, 6) is not 3 units.
Answer:
A.
Step-by-step explanation:
the square root of 6 is roughly 1.57
so that means the ordered pair would read (2,1.57).
if you were to plot that point it would be on the circle.
Also the distance from the origin (0,0) to (3,0) is 3 units
We will see that the correct option is:
"No, the distance from (0, 0) to (2, 6) is not 3 units."
Does (2, 6) lie on the circle shown?
We know that the circle has a radius of 3 units, then we need to see if the distance between (0, 0) and (2, 6) is 3 units.
Here we have:
[tex]D = \sqrt{(6 - 0)^2 + (2 - 0)^2} = \sqrt{36 + 4} = \sqrt{40} \neq 3[/tex]
So the distance between (0, 0) and (2, 6) is different than 3 units, meaning that the point is not in the circle.
If you want to learn more about circles:
https://brainly.com/question/1559324
#SPJ5
find the median of the data down belove (please hurry)
Answer:
6.2
Step-by-step explanation:
You can find the median by adding up all of the numbers and dividing the result by how many numbers there are.
add them all together: 5 + 6 +5+6+9 = 31
there are five people, so divided 31 by 5
31 divided by 5 = 6.2
6.2
The numbers 8,x,9 and 36 are in proportion.Find x
If you can give the proportion then it would be better.
I am asuming
8:x::9:36
Then 8:x::1:4
So x = 32
Answered by Gauthmath must click thanks and mark brainliest
Answer:
x = 32
Step-by-step explanation:
[tex]\frac{8}{x}[/tex] = [tex]\frac{9}{36}[/tex] = [tex]\frac{1}{4}[/tex] ( cross- multiply )
x = 8 × 4 = 32
please answer algebra question I put it into a calculator and it didn’t work 4x-5=4(x-2)+3
Answer:
solving for X it would be (-infinity ♾️, +infinity ♾️) or all real numbers
1. write it on a piece of paper
[tex]\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}[/tex]
[tex]\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}[/tex]
[tex]\\ \sf\longmapsto \dfrac{6+11}{4}[/tex]
[tex]\\ \sf\longmapsto \dfrac{17}{4}[/tex]
2:-
[tex]\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}[/tex]
[tex]\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}[/tex]
[tex]\\ \sf\longmapsto \dfrac{155+225}{35}[/tex]
[tex]\\ \sf\longmapsto \dfrac{380}{35}[/tex]
[tex]\\ \sf\longmapsto 12[/tex]
3:-
[tex]\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}[/tex]
[tex]\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}[/tex]
[tex]\\ \sf\longmapsto \dfrac{132+160}{30}[/tex]
[tex]\\ \sf\longmapsto \dfrac{292}{30}[/tex]
4:-
[tex]\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}[/tex]
[tex]\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}[/tex]
[tex]\\ \sf\longmapsto 4+\dfrac{10}{3}[/tex]
[tex]\\ \sf\longmapsto \dfrac{12+10}{3}[/tex]
[tex]\\ \sf\longmapsto \dfrac{22}{3}[/tex]
[tex] \bf \large \longrightarrow \: \: 1 \frac{1}{2} \: + \: 2 \frac{3}{4} \: = \: \\ [/tex]
[tex] \bf \large \longrightarrow \: \: \frac{3}{2} \: + \: \frac{11}{4} \\ [/tex]
[tex] \bf \large \longrightarrow \: \: \frac{6 \: + \:11 }{4} \\ [/tex]
[tex] \bf \large \longrightarrow \: \: \frac{17}{4} \\ [/tex]
2.[tex]\bf \large \longrightarrow \: \: 4 \frac{3}{7} \: + \: 6 \frac{1}{5} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{31}{7} \: + \: \frac{31}{5} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{155 \: + \: 217}{35} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{372}{35} \\ [/tex]
3.[tex]\bf \large \longrightarrow \: \: 4 \frac{2}{5} \: + \: 5 \frac{2}{6} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{22}{5} \: + \: \frac{32}{6} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{132 \: + \: 160}{30} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{292}{30} \\ [/tex]
4.[tex]\bf \large \longrightarrow \: \: 3 \frac{7}{7} \: + \: 3 \frac{1}{3} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{28}{7} \: + \: \frac{10}{3} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \cancel\frac{28 ^{4} }{7 \: ^{1} } \: + \: \frac{10}{3} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{4}{1} \: + \: \frac{10}{3} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{12 \: + \: 10}{3} \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \frac{22}{3} \\ [/tex]
Find the surface area of the composite figure
Answer: SA = 644 cm²
Step-by-step explanation:
STEP ONE: Find the surface area of the smaller rectangle (green)
There are in total 5 sides because one of the sides is not shown on the surface level.
Upper base = 3 × 3 = 9 cm²
4 sides = 3 × 8 × 4 = 96 cm²
Total = 9 + 96 = 105 cm²
STEP TWO: Find the surface area of the larger rectangle (orange)
There are in total 5 whole sides with one side covered by the base of the smaller rectangle (green) which should later be subtracted.
Front and back = 7 × 10 × 2 = 140 cm²
Left and right = 7 × 12 × 2 = 168 cm²
Lower base = 10 × 12 = 120 cm²
Upper base = 10 × 12 - 3 × 3 = 111 cm²
Total = 140 + 168 + 120 + 111 = 539 cm²
STEP THREE: Find the total surface area
SA = Green + Orange = 105 + 539 = 644 cm²
Hope this helps!! :)
Please let me know if you have any questions
HELP QUICK ILL GIVE BRAINLIEST
Answer:
here's the answer to your question
Answer: √18
√(4-1)^2 + (5-2)^2
√9 + 9
√18
Answered by Gauthmath must click thanks and mark brainliest
Evaluate the functions in the given points.
a. f(x) = x
2 − 6 for f(0), f(−6), f(√6), f(
1
2
)
b. f(x) = x
3 + 2x for f(0), f(−2), f(−1), f(
1
2
)
c. f(x) =
1−2x
3
for f(0), f(−2), f(2), f (
1
2
) , f(m), f(m − 1), f(−m)
d.f(x) = |x| −
1
x
for f(−1), f(2), f(h), f (
1
2
) , f(−h + 2) where h ≠ 0
Answer:
Hey I'm sorry I didn't get to answer your question it's just that I need the points because I don't have enough to get help with my question. I hope you get the answer that you need for you question. Good Luck :)..............
Step-by-step explanation:
solve for x on the diagram below
Answer:
20 is the answer
Step-by-step explanation:
x+3x+10=90(right angle triangle)
4x=90-10
x=80/4
x=20°
Answer:
x = 20
Step-by-step explanation:
Based on the square indication at the corner of the angle, we can assume it's a right angle, so 90°. This means that x + 3x + 10 = 90. Solve it like any algebraic equation, isolating x. add x to 3x + 10, this would net you 4x + 10 = 90. Subtract 10 on both sides of the equation to further isolate x, meaning 4x = 80. Simplify this, dividing 4 on both sides, meaning x = 20.
Urgently need help step by step explanation needed
Answer:
p=8
Step-by-step explanation:
-5log(p+1)+2=-8
-5log(p+1)=-10
log(p+1)=2
p+1=9, p=8
i need help anybody ?
Answer and Step-by-step explanation:
Simply use the Pythagorean Theorem to solve.
The Pythagorean Theorem is used to solve for a side in right triangles.
[tex]A^{2} +B^{2}= C^{2}[/tex]
Plug the sides values into the equation.
[tex]A^{2} + 13^2 = 20^2\\\\A^2 + 169 = 400\\\\A^2 = 231\\\\A = 15.1987[/tex]<- This is the answer.
#teamtrees #PAW (Plant And Water)
If 12 out of 30 fruits are oranges, how many oranges fruits will there be per 100 fruits total?
Answer:
40 oranges are there in 100 fruites.
Simplify the following expression: 5(3x) - 3(7x - 2)
�� 6x + 6 �� 36x + 6
�� 6 - 6x �� 6 - 36x
Answer:
The answer is in the screenshot -6x-6
Step-by-step explanation:
The internal dimension of a lidless wooden box is 48cm × 38cm × 32cm. If the thickness of the tank is 1 cm, find the volume of the wooden box
Step-by-step explanation:
this is confusing.
first the description says "the internal dimensions".
and then it tells us the thickness of the tank walls (1cm).
so, I am not sure what the given numbers describe.
in any case, the volume is length × width × height.
so, either
48×38×32
or
46×36×31 (as for length and width we need to consider 2 walls, one on each end, for the height only one wall, as the tank is open and lidless.
whatever you choose, make sure to mark the result as cm³.
Find the area of the shaded region. Round your answer to the nearest hundredth.
Answer:
Step-by-step explanation:
The formula for finding the area of a pentagon(regular) given 1 side is
A = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}s^{2}\)[/tex]
s (the side) = 12
Area = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}12^{2}\)[/tex]
Area = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}144\)[/tex]
Area = sqrt(5(5 + 2*2.2361) * 36
Area = sqrt(5( 5 + 4.4721)) * 36
Area = sqrt(5*9.4721) * 36
Area = sqrt(47.3606) * 36
Area = 6.882 * 36
Area = 247.7485
The area of the circle = pi r*2 but we don't have r.
If you know any trig, the formula for the radius of the circle is
R = s/(2*sin(180)/n) n = 5 because you are using a 5 sided figure.
R = 12/(2*sin(180/5)
R = 12/2* sin(36)
R = 6 / sin(36)
R = 10.207
So the area of the circle is pi * R^2
Area = 3.14 * 10.2078^2
Area = 327.1854
The area of the shaded part is the difference between the 2 areas we found
Answer: 327.1854 - 247.7485
Answer: 79.44
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Answer: will be A
Step-by-step explanation:
if you have 500 dollars and spend 20 every week then what would be the slope explain
Answer:
y=-20m+500
Step-by-step explanation:
I will be marking brainliest please help me with these questions.
Answer/Step-by-step explanation:
1. To find the area of the shaded region, you'd find the area of the white rectangular shape, next, find the area of the whole triangular shape, then find the difference of their areas to get the area of the shaded region. Thus, the formula to use would be:
Area of shaded region = area of triangle - area of rectangle
Area of shaded region = ½*base*height - length*width
1. a. Volume of triangular prism = area of triangular base * height of prism
Volume of triangular prism = ½bh * H
Where,
b = 6 m
h = 4 m
H = 8 m
Substitute
Volume of prism = ½*6*4*8
Volume of prism = 96 m³
b. Volume of sphere = ⁴/3πr³
Where,
r = 9 cm
Substitute
Volume = ⁴/3*π*9³
Volume = ⁴/3*π*729
Volume ≈ 3,053.6 cm³ (nearest tenth)
2. Use Pythagorean theorem to find the height of the cone
radius of the cone (r) = ½(16) = 8 cm
Slant height (l) = 11 cm
height (h) = ?
Using Pythagorean theorem, we have:
h = √(l² - r²)
Substitute
h = √(11² - 8²)
h = √(57)
h ≈ 7.5 cm (nearest tenth)
b. Volume of the cone = ⅓πr²h
where,
r = 8 cm
h = 7.5 cm
Volume = ⅓*π*8²*7.5
Volume = 502.7 cm³ (nearest tenth)
m. Proportions
1) Write a proportion for the situation, then solve the
proportion to answer the question.
nation:
a. A 6 foot high fence casts a 7 foot shadow.
Standing beside the fence is a tree that casts a
31.5 foot shadow. How tall is the tree?
Answer:
height of tree is 27 ft
Step-by-step explanation:
The corresponding parts of the problem are in proportion
let h be the height of the tree , then
[tex]\frac{6}{h}[/tex] = [tex]\frac{7}{31.5}[/tex] ( cross- multiply )
7h = 189 ( divide both sides by 7 )
h = 27
Height of tree is 27 feet
A regular square pyramid has a slant height of 5 in and a base area of 49 in2. Find the surface area of the pyramid. ------------------------------------------------------------------------------------------- 171.5 square inches 70 square inches 119 square inches 245 square inches
Answer:
C: 119 square inches
Step-by-step explanation:
We are given;
Slant height; L = 5 in
Base area; B = 49 in²
Since it's a square pyramid, the base portion has a square shape.
Thus, area of base = x²
Where x is a side of the square.
Thus;
x² = 49
x = √49
x = 7
Perimeter of base = 7 × 4 = 28 in
Area of pyramid = ½PL + B
Plugging in the relevant values;
Area of pyramid = (½ × 28 × 5) + 49
Area of pyramid = 119 in²
When leaving a town, a car accelerates from 30 kmh-1 to 60 kmh-1 in 5 s. Assuming the
acceleration is constant, find the distance travelled in this time.
A. 6 m
B. 62.5 m
C. 41.7 m
D. 20.8 m
Answer:
B .62.5 m
Step-by-step explanation:
convert Kmh-1 in to ms-1
30 Kmh-1 = (30×1000) ÷3600 = 8.3ms-1
60 Kmh-1 = (60×1000) ÷3600 = 16.6 ms-1
acceleration = (16.6 - 8.3) ÷ 5 = 1.66 ms-2
V^2 = U^2 +2aS
(16.6)^2 = (8.3)^2 + 2×1.66 ×S
S = 62.5 m
HELP DUE IN 10 MINUTES
Answer:
Step-by-step explanation:
For Part A, use the pythagorean theorem to find the height, which ca be found by finding one length of the leg. Using the imaginary bisector, you can determine one of the legs is 5 cm, and the hypotenuse is 13 cm
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse. Plug in the values to solve for one leg, you get 25+b^2=169
Solve algebraically, b^2= 144, so b=12, which is the height.
Part B
Determine the surface area of each cardboard piece, and add together.
20 × 13 × 2 = 520
1/2 × 10 × 12 × 2 = 120
20 × 10 = 200
So approximately 840 cm of cardboard was used
Please help: 6m - m = 5/6(6m - 10)
Will mark brainliest!!
Answer:
No solution.
Step-by-step explanation:
[tex]6m-m=\frac{5}{6}(6m-10)\\5m=5m-\frac{25}{3}\\0\neq -\frac{25}{3}[/tex]
Therefore, there is no solution.
