HELP TIMED QUESTION. Determine whether the equation is an identity or not an identity.

Answer:

2/13,3/13,4/13....

hope it helps

Answer:

Step-by-step explanation:

4/13=40/130

1/13=10/130

numbers between 10/130 and 40/130 are 11/130,12/130,13,130 ,...,39/130.

we can select  any three out of these.

179 is the answer

hope it helps

Answer:

179 = CLXXIX = 100 + 50 + 10 + 10 + 10 − 1

Step-by-step explanation:

Numbers close to CLXXIX

Below are the numbers CLXXVI through CLXXXII, which are close to CLXXIX. The right column shows how each roman numeral adds up to the total.

176 = CLXXVI = 100 + 50 + 10 + 10 + 5 + 1

177 = CLXXVII = 100 + 50 + 10 + 10 + 5 + 1 + 1

178 = CLXXVIII = 100 + 50 + 10 + 10 + 5 + 1 + 1 + 1

179 = CLXXIX = 100 + 50 + 10 + 10 + 10 − 1

180 = CLXXX = 100 + 50 + 10 + 10 + 10

181 = CLXXXI = 100 + 50 + 10 + 10 + 10 + 1

182 = CLXXXII = 100 + 50 + 10 + 10 + 10 + 1 + 1

Symbol Value

I 1

V 5

X 10

L 50

C 100

D 500

M 1000

I hope this helps.

Answer:

B

Step-by-step explanation:

Answer:

= -2

Step-by-step explanation:

-2 -(-7)

= 5

Answer:

a=2

b=-3

c=2

d=0

Step-by-step explanation:

3a+b=3......1

3c-d=6.......2

a-b=5....... 3

a+b+d=2d-1

a+b=2d-d-1

a+b=d-1......4

taking equation 1 and 3 we get,

3a+b =3....... 1

a-b=5

a=5+b

substitute the value of a in equation 1 we get,

3*(5+b)+b=3

15+3b+b=3

4b=3-15

4b=-12

b=-12/4

b=-3

now putting the value of b in equation 3 we get,

a-b=5

a+3=5

a=5-3

a=2

substitute the value of a and b in equation 4 we get,

a+b=d-1

2-3=d-1

-1=d-1

d=-1+1

d=0

substitute the value of d in equation 2 we get,

3c-d=6

3c-0=6

3c=6

c=6/3

c=2

[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]

Now constructing equations

[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]

[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]

[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]

[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]

Adding eq(1) and (2)

[tex]\\ \sf\longmapsto 4a=8[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]

[tex]\\ \bf\longmapsto a=2[/tex]

Put the value in eq(2)

[tex]\\ \sf\longmapsto a-b=5[/tex]

[tex]\\ \sf\longmapsto b=a-5[/tex]

[tex]\\ \sf\longmapsto b=2-5[/tex]

[tex]\\ \bf\longmapsto b=-3[/tex]

put the values in eq(4)

[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]

[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]

[tex]\\ \sf\longmapsto d-1=2d-1[/tex]

[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]

[tex]\\ \sf\longmapsto -d=0[/tex]

[tex]\\ \bf\longmapsto d=0[/tex]

Put the value in eq(3)

[tex]\\ \sf\longmapsto 3c-d=6[/tex]

[tex]\\ \sf\longmapsto 3c-0=6[/tex]

[tex]\\ \sf\longmapsto 3c=6+0[/tex]

[tex]\\ \sf\longmapsto 3c=6[/tex]

[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]

[tex]\\ \sf\longmapsto c=2[/tex]

Answer:

The answer is 98

Step-by-step explanation:

Can I get branly plz and hope this help

Answer:

(x + 1)(x + 5)

Step-by-step explanation:

Given

(x + 1)² + 4(x + 1) ← factor out (x + 1) from each term

= (x + 1)(x + 1 + 4)

= (x + 1)x + 5)

Parameterize C by

r(t) = 〈x(t), y(t)〉 = 〈cos(t), sin(t)〉

with 0 ≤ t ≤ π. Then the line integral is

[tex]\displaystyle \int_C (2+x^2y)\,\mathrm ds = \int_0^\pi (2+\cos^2(t)\sin(t))\left\|\mathbf r'(t)\right\|\,\mathrm dt \\\\ = \int_0^\pi (2+\cos^2(t)\sin(t)) \,\mathrm dt = \boxed{\frac23+2\pi}[/tex]

Answer:

x = 6

Step-by-step explanation:

The tangent- tangent angle WVU is half the difference of the measure of the intercepted arcs. , that is

5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - (23x - 5) )

5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - 23x + 5)

5x + 17 = [tex]\frac{1}{2}[/tex] (14x + 10) ← multiply both sides by 2 to clear the fraction )

10x + 34 = 14x + 10 ( subtract 14x from both sides )

- 4x + 34 = 10 ( subtract 34 from both sides )

- 4x = - 24 ( divide both sides by - 4 )

x = 6

Answer:

God bless you

i don't have nice handwriting

Answer:

(D) 2 x 10²

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Answer:

2 × 10 ^2

Step-by-step explanation:

(d) option is correct

Answer:

keep the pic clearly

Step-by-step explanation:

keep the pic clearly

6,3:y=4,2:2,4

y=3,6

Chọn a

Answer:

b

Step-by-step explanation:

Answer: 96

Step-by-step explanation:

This equation helps

X / 100 = is / of

32/100 = X / 300 (cross multiplication)

32 times 300, divided by 100

= 96

Answer:

96

Step-by-step explanation:

every percent is out of hundred so (32 * 300)/100 = 96

Answer:

- sin(x) is the ratio of the opposite leg to the hypotenuse in a right triangle, while cos(x) is the ratio of the adjacent leg to the hypotenuse in a right triangle.

-The graph of y = sin(x) at x = 0 starts at the origin, and then increases, while the graph of y = cos(x) starts at a max, and then decreases.

Here's a 3rd: sin(x) is the cofunction of cos(x), which means that sin(x) = cos(90-x). This also shows that they are different.

Their LCM is

70

hope it helps you.

Answer:

Their L.C.M IS

70....

IT IS YOUR ANSWER

Answer:

it should be 90 I could be wrong

Answer:

t=r/(sq)

Step-by-step explanation:

r=sqt

=> r/(sq)=t

Answer:

T= r/(sq)

Step-by-step explanation:

r= sqt

=r/(sq) =t

Answer:

[tex]5x^3\sqrt{6}[/tex]

Step-by-step explanation:

We need to simplify

[tex]\sqrt{3x^4}\times\sqrt{5x^2}\times\sqrt{10}[/tex]

Right away we can take out the perfect squares. Remember a perfect square is the result of multiplying any value by itself.

[tex]= x^2\sqrt{3}\times x\sqrt{5}\times\sqrt{10} \\= x^3\sqrt{3\times 5 \times 10}\\= x^3\sqrt{3 \times 5 \times 5 \times 2 }\\= 5x^3\sqrt{6}[/tex]

The square root of 3x⁴ times square root of 5x² times square root of 10, the product of all the term is,  5x³ [tex]\sqrt{6}[/tex]

In mathematics, square roots is a concept in which, if we multiply square roots of any number by itself then it will give us an original number.

if 'a' is square root of 'b' then it will represent as, a = √b.

Given that,

three terms,

[tex]\sqrt3{x^{4} }[/tex]

[tex]\sqrt{5x^{2} }[/tex]

[tex]\sqrt{10}[/tex]

by multiplying all the three terms,

⇒ [tex]\sqrt3{x^{4} }[/tex] × [tex]\sqrt{5x^{2} }[/tex] × [tex]\sqrt10} }[/tex]

⇒  √(3x⁴×5x²10)

⇒   √ 150x⁶

⇒     5x³ [tex]\sqrt{6}[/tex]

Hence, the product is   5x³ [tex]\sqrt{6}[/tex]

To know more about square root check:

https://brainly.com/question/29286039

#SPJ2

Answer:

For it to be parallel the answer is B (3)

Answer:

B) 3

Explanation:

If two lines are parallel that means that their equations have the same value of slope.

Answer:

Step-by-step explanation:

I'm assuming that the length of the spring is s and the mass of the object is m. If that be the case, the direct variation equation, which a line btw, is

s = km where k is the constant of proportionality. We have to solve for k, the slope of the line, in order to determine the model for this situation.

9 = k(30) so

[tex]k=\frac{9}{30}=\frac{3}{10}[/tex] Now that we know, the slope of the line, we can rewrite the equation with the slope in place:

[tex]s=\frac{3}{10}m[/tex], choice A.

Answer:

7/15

Step-by-step explanation:

hope the picture helps

Answer:

[tex]144\pi[/tex]cm

multiple 24 pi with 6 on a scientific calculator.

Answer:

4pi

Step-by-step explanation:

that is the procedure above

Answer:  [tex](x-3)^2 + (y-2)^2 = 16[/tex]

Explanation:

The center of this circle is point A(3,2). These coordinates are the (h,k) values.

The radius is r = 4

Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.

The combined radical is: [tex]- 26\sqrt{3}[/tex]

The radical is given as:

[tex]- 12\sqrt{12} - 2\sqrt{3}[/tex]

We start by expressing 12 as 4 * 3

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4* 3} - 2\sqrt{3}[/tex]

Split the radical

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4}* \sqrt{3} - 2\sqrt{3}[/tex]

Take square root of 4

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12*2* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24\sqrt{3} - 2\sqrt{3}[/tex]

Combine like terms

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 26\sqrt{3}[/tex]

Hence, the combined radical is: [tex]- 26\sqrt{3}[/tex]

Read more about surd radicals at:

https://brainly.com/question/14923091

Answer:

Step-by-step explanation:

I'm pretty sure its b

number is described as rational if it can be written as a fraction (one integer divided by another integer). A number is irrational if it cannot be written as a fraction. The decimal form of an irrational number does not terminate or recur.

Answer:

true

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

An integer can be written as a fraction by giving it a denominator of one