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Answer: Given : Joe’s Earnings and hour worked

The relationship between money earned and hours worked is linear.

Joe computes the slope between (4, 30) and (12, 90), then computes the slope between (4, 30) and (10, 75).

To Find : How do the two slopes compare?

Solution:

Hours worked     Money earned

4                          $30

10                        $75

12                        $90

22                       $165

slope between (4, 30) and (12, 90),

= (90 - 30)/(12 - 4)

= 60/8

= 15/2

slope between (4, 30) and (10, 75)

= (75 - 30)/(10-4)

= 45/6

= 15/2

The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.

Both Slopes are same.

i hope this helped and have a nice day/night

The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same. The correct answer is the third option.

The slope between two points (x₁,y₁)  and  (x₂, y₂) on a straight line is given by (y₂ - y₁)/(x₂ -x₁ ).

Let's calculate the slopes:

The slope between (4, 30) and (12, 90):

Slope = (90 - 30) / (12 - 4)

= 60 / 8

= 7.5

The slope between (4, 30) and (10, 75):

Slope = (75 - 30) / (10 - 4)

= 45 / 6

= 7.5

As we can see, the slopes between the two sets of ordered pairs are the same.

Thus,  the slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.

Hence, the correct answer is the third option.

Learn more about the slope of the line here:

brainly.com/question/14511992

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Step-by-step explanation:

We write that x belongs to the interval if a ≤ x ≤ b. Graphically, a closed interval is represented by a segment whose two ends are filled. To write this interval in interval notation, you must use square brackets: [a,b].

Answer:

11. B.

12. C.

13. A.

14. D.

Step-by-step explanation:

for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them

for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.

for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.

for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.

Hello,

the line passing through (5,2) and (1,0) has for equation:

y-0=(x-1)*(-2)/(-4) or y=x/2-0.5

if y= 5 then 5=x/2-0.5 ==> 5.5=x/2 ==> x=11

Answer C

Answer:

C

Step-by-step explanation:

Since the points lie on the same line then the slope between consecutive points will be the same.

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (5, 2) and (x₂, y₂ ) = (1, 0)

m = [tex]\frac{0-2}{1-5}[/tex] = [tex]\frac{-2}{-4}[/tex] = [tex]\frac{1}{2}[/tex]

Calculate the slope again and equate to [tex]\frac{1}{2}[/tex]

with (x₁, y₁ ) = (1, 0) and (x₂, y₂ ) = (a, 5)

m = [tex]\frac{5-0}{a-1}[/tex] = [tex]\frac{1}{2}[/tex] , so

[tex]\frac{5}{a-1}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

a - 1 = 10 ( add 1 to both sides )

a = 11

Answer:

1344.

Step-by-step explanation :

.

The speed of the jet will be 166.4. If the jet fly for 12 hours, then the distance cover will be 1996.8.

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A jet travels 832 km in 5 hours.

Then the speed of the jet will be

Speed = 832 / 5

Speed = 166.4 km per hours

If the jet fly for 12 hours, then the distance cover will be

Distance = Speed x Time

Distance = 166.4 x 12

Distance = 1996.8 km

More about the speed link is given below.

https://brainly.com/question/7359669

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[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

[tex]\bold{ \red{\star{\blue{GIVEN }}}}[/tex]

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

[tex]\bold{\blue{\star{\red{TO \: \: FIND}}}}[/tex]

Average cost of 7 articles

[tex] \bold{ \green{ \star{ \orange{FORMULA \: USED}}}}[/tex]

[tex] \red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}[/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

[tex]Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k[/tex]

Given:

D be the event that a randomly chosen person has seen a dermatologist.

S be the event that a randomly chosen person has had surgery for skin cancer.

To find:

The correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist.

Solution:

Conditional probability: Probability of A given B is:

[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]

Let D be the event that a randomly chosen person has seen a dermatologist.

Let S be the event that a randomly chosen person has had surgery for skin cancer.

Using the conditional probability, the correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist is P(S|D).

Therefore, the correct option is D.

To check:put value of m and n in both equations

Answer: n=2 and m=1

Step-by-step explanation:

m+3n=7 , 5m-n=3

m=7-3n => 5(7-3n)-n=3

=> 35-15n-n=3

=> -16n=-32

=> n=2

n=2 => 5m-2=3

=> m=1

Answer:

the first option

Step-by-step explanation:

I have attached the explanation. hope this help

Answer:

1/3 more pounds of string beans.

Step-by-step explanation:

Amount of string beans: 5/12 of a lbs(pound)

Amount of lima beans: 1/12 of a lbs

Amount of string beans - Amount of lima beans = 5/12-1/12 =4/12 which simplifies down to 1/3.

Answer:

3.8106327168

Step-by-step explanation:

x=2.5/sin(41) = 3.81063271676

Step-by-step explanation:

Step 1: The factors of -60 that add up to -11 are -15 and 4.

Step 2:

[tex]( 6{x}^{2} - 15x)( 4x - 10)[/tex]

Step 3:

[tex]3x(2x - 5) + 2(2x - 5)[/tex]

[tex](3x + 2)(2x - 5) [/tex]

[tex]a = 28.[/tex]

Step-by-step explanation:

[tex] {a}n = a + (n - 1)d[/tex]

[tex]4 = a + (7 - 1)( - 4)[/tex]

[tex]4 = a + 6( - 4)[/tex]

[tex]4 = a + ( - 24)[/tex]

[tex]4 = a - 24[/tex]

[tex]4 + 24 = a[/tex]

[tex]28 = a[/tex]

(OR)

[tex]a = 28.[/tex]

Answer:

the square of hypotenuse rs eqaul to the sum of the square of the legs

Answer:

I've attached a picture of a unit circle with the quadrant labeled.

Calculate the degree of 5п 8 radians:

[tex]\frac{5\pi }{8} =\frac{5*180}{8} =\frac{900}{8} =112.5[/tex]

Locate the general location of 112.5° on the unit circle:

It's between 120°([tex]\frac{2\pi }{3}[/tex]) and 90°([tex]\frac{\pi }{2}[/tex]).

Find the quadrant it lies in:

Quadrant II

Answer:

Step-by-step explanation:

Set the equation and solve for x:

Correct choice is B

Answer:

I believe its the 1st answer.

A.88.2m

Answer:

Solution given:

initial velocity[u]=29.4m/s

g=9.8m/s²

maximum range=?

now

we have

[tex]\theta=90°[/tex]

maximum range =[tex]\frac{29.4²*sin90}{9.8}=88.2m[/tex]

The initial velocity is,

→ u = 29.4 m/s

General assumption,

→ g = 9.8m/s²

→ θ = 90°

Then the maximum range is,

→ (29.4² × sin90)/9.8

→ 88.2 m

Hence, option (A) is answer.

Answer:

x = sqrt(3)

Step-by-step explanation:

Use Thales theorem

Answer:

OMG I LOVE LOUIS SO MUCH HE IS SO PERFECT

Step-by-step explanation:

Answer:

29%

Step-by-step explanation:

First, let's fill in the table.

Male:

Freshmen: 4

Sophomore: 6

Juniors: 2

Seniors: 2

Total: 4 + 6 + 2 + 2

Total: 14

Female:

Freshmen: 3

Sophomore: 4

Juniors: 6

Seniors: 3

Total: 3 + 4 + 6 + 3

Total: 16

Now, to find the probability that a male would be a freshmen, we would do:

4/14

Convert it to a decimal:

.285

Convert to percentage:

29%

So, there is a 29% chance that a male is a freshmen.

Answer:

To solve this problem, we need to use the following two facts:

1) If a quadratic equation has integer coefficients only, and if one of the roots is a + √b (where a and b are integers), then a - √b is also a root of the equation.

2) If r and s are roots of a quadratic equation, then the equation is of the form x^2 – (r +s)x + rs = 0.

Since we know that 1 - √2 is a root of the quadratic equation, we can let:

r = 1 + √2

and

s = 1 - √2

Thus, r + s = (1 + √2) + (1 - √2) = 2 and rs = (1 + √2)(1 - √2) = 1 – 2 = -1.

Therefore, the quadratic equation must be x^2 – 2x – 1 = 0.

Answer: D

Step-by-step explanation:

Answer:

10-5=5 answer is 8^5

Step-by-step explanation:

Answer:

[tex]8^{5}[/tex]

Step-by-step explanation:

[tex]\frac{8^{10} }{8^{5} }[/tex]

Where are there more 8's ?

top

How many more?

5

Then they stay on top of fraction.

Another way :

[tex]x^{a}[/tex] ÷ [tex]x^{b}[/tex] = [tex]x^{a-b}[/tex]

[tex]8^{10}[/tex]  ÷ [tex]8^{5}[/tex] = [tex]8^{10-5}[/tex] = [tex]8^{5}[/tex]

Answer: There are 400 tadpoles in the year 1994.

This is because any point is of the form (x,y) where in this case

x = year number

y = tadpole population number

So (x,y) = (1994, 400) means x = 1994 and y = 400 pair up together.

In short, the year x = 1994 corresponds to the population of y = 400 tadpoles.

From the years 1990 to 1992, the population is increasing since the curve goes upward when moving from left to right. Then from 1992 to 1993, the population decreases hitting its lowest point in that specific region. From 1993 to 1997, the population increases before it decreases again from 1997 to 1999.

Hello,

In all reply x²'s coefficient is 1.

The polynom will be (x+i)(x-5)= x²+ix -5x-5i

Answer  C

Answer:

100 degrees

Step-by-step explanation:

You can tell by just looking at the picture :)

Answer:

D

Step-by-step explanation:

if cosec is 13/5 then sin is 5/13

Answer:

[tex]x=-3[/tex]

Step-by-step explanation:

Given:

[tex]4\frac{3}{10}-(2\frac{2}{5}x+5\frac{1}{2})=\frac{1}{2}(-3\frac{3}{5}x+1\frac{1}{5})[/tex]

Distribute to remove parentheses:

[tex]4\frac{3}{10}-2\frac{2}{5}x-5\frac{1}{2}=-\frac{18}{10}x+\frac{6}{10}[/tex]

For simplification and clarity, reduce all mixed numbers to simplified common fractions:

[tex]\frac{43}{10}-\frac{12}{5}x-\frac{11}{2}=-\frac{9}{5}x+\frac{3}{5}[/tex]

Combine like terms:

[tex]-\frac{12}{5}x-\frac{6}{5}=-\frac{9}{5}x+\frac{3}{5}[/tex]

Add 6/5 to both sides, then add 9/5x to both sides:

[tex]-\frac{3}{5}x=\frac{9}{5}[/tex]

Divide both sides by -3/5 to isolate x (recall dividing by a number is equal to multiplying by its reciprocal):

[tex]x=\frac{9}{5}\cdot -\frac{5}{3}, \\x=\frac{-9}{3},\\x=\boxed{-3}[/tex]