How do you find the diameter of a quarter circle?

Answer:

d) 16, 19, 14 + x

e) x + 20, 30, 33, 15, y - 20, x+x+20=60 and James would be 20.

f) 13

g) 120

Step-by-step explanation:

D.

(1) 14 + 2 = 16

(2) 14 + 5 = 19

(3) 14 + x

E.

(1) x + 20

(2) 10 + 20 = 30

(3) 13 + 20 = 33

(4) 35 - 20 = 15

(5) y - 20

(6) x + (x + 20) = 60 | 2x + 20 = 60 | 2x = 40 | x = 20

F.

200 - 148 = 52

52 / 4 = 13 each

G.

500 + 100 = 600

600 / 5 = 120 without the discount

Hope this helps!

Let a be first term

[tex]\\ \rm\longmapsto a_8=a+7d[/tex]

[tex]\\ \rm\longmapsto 26=a+7(3)[/tex]

[tex]\\ \rm\longmapsto a=26-21[/tex]

[tex]\\ \rm\longmapsto a=5[/tex]

Now

[tex]\\ \rm\longmapsto a_4=a+3d[/tex]

[tex]\\ \rm\longmapsto a_4=5+3(3)[/tex]

[tex]\\ \rm\longmapsto a_4=5+9[/tex]

[tex]\\ \rm\longmapsto a_4=14[/tex]

Answer:

y = ± 15

Step-by-step explanation:

Given

y² = 225 ( take the square root of both sides )

[tex]\sqrt{y^2}[/tex] = ± [tex]\sqrt{225}[/tex]

y = ± 15

That is y = 15, y = - 15

Since 15 × 15 = 225 and - 15 × - 15 = 225

y² = 225

y = √225

y = 15

y²= 225

y = √225

y = -15

y = ±15

Therefore values of y are 15 and -15

Must click thanks and mark brainliest

Step-by-step explanation:

First draw a lign segment like DF

Next keep the point on D make an arc by increasing the length of compass

As same keep the point on F make an arc lile same as before

Next there is apoint name it as any meeting on drew arc

connect it to the point with P

Answer:

Please find attached the drawing of ABCD, A'B'C'D', and A''B''C''D'', created with MS Excel

Step-by-step explanation:

The given composition of transformation is [tex]r_{y-axis} \ \circ \ r_{x = - 4}[/tex]

The transformation on the right, [tex]r_{x = - 4}[/tex], is carried out first as follows;

The point A with coordinate (-7, 7) reflected across the line x = -4, gives;

A(-7, 7) [tex]r_{x = - 4}[/tex] → A'(-1, 7)

Similarly, we have;

B(-5, 7) [tex]r_{x = - 4}[/tex] → B'(-3, 7)

C(-5, 1) [tex]r_{x = - 4}[/tex] → C'(-3, 1)

D(-7, 1) [tex]r_{x = - 4}[/tex] → D'(-1, 1)

Therefore, the image of the given rectangle after reflection across the lie, x = -4, is A'(-1, 7), B'(-3, 7), C'(-3, 1), and D'(-1, 1)

The second transformation, [tex]r_{y-axis}[/tex], is found as follows;

(x, y) [tex]r_{y-axis}[/tex] → (x, -y)

Therefore, we have;

A'(-1, 7) [tex]r_{y-axis}[/tex] → A''(-1, -7)

B'(-3, 7) [tex]r_{y-axis}[/tex] → B''(-3, -7)

C'(-3, 1) [tex]r_{y-axis}[/tex] → C''(-3, -1)

D'(-1, 1) [tex]r_{y-axis}[/tex] → D''(-1, -1)

The points ABCD, A'B'C'D', and A''B''C''D'' are plotted on MS Excel and the points joined with straight lines to form the drawing of the triangles as shown in the attached figure.

Answer:

Step-by-step explanation:

(a - b)(a + b) =a² - b²

(3x + 5)(3x -5) =(3x)² - 5² = 9x² - 25

(x +2)(x+2) = (x+ 2)² = x²+ 2*2*x+2² = x² + 4x + 4

(x+2)(3x -5 ) = x*3x - 5*x +2*3x +2*(-5)

                    = 3x² -5x +6x -10

                    = 3x² + x - 10

[tex]\frac{2*(3x+5)}{x+2}-\frac{5(x+2)}{3x-5}=3\\\\\frac{2*(3x+5)*(3x-5)}{(x+2)(3x-5)}-\frac{5*(x+2)(x+2)}{(3x-5)(x+2)}=3\\\\\frac{2*(9x^{2}-25)-5(x^{2}+4x+4)}{(3x-5)(x+2)}=3[/tex]

[tex]\frac{18x^{2}-25-5x^{2}-20x-20}{3x^{2}+x-10}=3\\\\\frac{18x^{2}-5x^{2}-20x - 25-20}{3x^{2}+x-10}=3\\\\[/tex]

13x² - 20x - 45 = 3*(3x² + x - 10)

13x² - 20x - 45 =9x² + 3x - 30

13x² - 9x² -20x - 3x - 45 + 30 = 0

4x² - 23x - 15 = 0

Answer:

Here is the detailed answer below

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

The degree is equal to the largest exponent on a variable. In this instance, it is 4.

Answer:

x = 5; y = 5

Step-by-step explanation:

One angle is a right angle, so its measure is 90 degrees.

One angle measures 45 degrees, so the unknown angle must also measure 45 degrees.

x and y are opposite two 45-degree angles, so x = y.

In a 45-45-90 triangle, the ratio of the lengths of the sides is

1 : 1 : sqrt(2)

We have

x : y : 5sqrt(2)

x/1 = 5sqrt(2)/sqrt(2)

x = 5

y = 5

Answer:

300 yd³

Step-by-step explanation:

Volume = lwh

l = 6

w = 5

h = 10

so, 6×5×10 = 300 yd³

Answer:

24

Step-by-step explanation:

Since the triangles are similar the side lengths must be proportional

2/12 = 4/PQ cross multiply expressions

2PQ = 48 divide both sides by 2

PQ = 24

Answer:

[tex]U = x[/tex]

[tex]V=10[/tex]

Step-by-step explanation:

Given

[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]

Required

Find U and V

We have:

[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]

Expand

[tex]x^2 + 6x + 9 + 14x + 42 + 49 = (U + V)^2[/tex]

Collect like terms

[tex]x^2 + 6x + 14x + 9 + 42 + 49 = (U + V)^2[/tex]

[tex]x^2 + 20x + 100 = (U + V)^2[/tex]

Expand

[tex]x^2 + 10x + 10x + 100 = (U + V)^2[/tex]

Group

[tex][x^2 + 10x] + [10x + 100] = (U + V)^2[/tex]

Factorize each group

[tex]x[x + 10] + 10[x + 10] = (U + V)^2[/tex]

Factor out x + 10

[tex][x + 10][x + 10] = (U + V)^2[/tex]

So, we have:

[tex][x + 10]^2 = (U + V)^2[/tex]

By comparison

[tex]U = x[/tex]

[tex]V=10[/tex]

Answer:

16

Step-by-step explanation:

[tex] \tan(x) = \frac{13}{46} [/tex]

[tex] \tan {}^{ - 1} ( \frac{13}{46} ) = 16[/tex]

Answer:

12

Step-by-step explanation:

[tex]\sqrt{64}[/tex] + [tex]\sqrt[3]{64}[/tex]

= 8 + 4

= 12

Square root of 64 = [tex] \sf \sqrt{64} = \sqrt{8 \times 8} = \boxed{\bf 8}[/tex]

Cube root of 64 = [tex] \sf \sqrt[3]{64} = \sqrt[3]{4 \times 4 \times 4} = \boxed{ \bf4}[/tex]

So,

Square root of 64 + Cube root of 64

[tex] = \sf \sqrt{64} + \sqrt[3]{64} \\ \sf = 8 + 4 \\ = \boxed{ \bf12}[/tex]

12 is the answer of the question asked.

____________

Hope it helps.

RainbowSalt2222

Answer:

should be 15.

Step-by-step explanation:

Answer:

The formula for iqr is q3 - q1

24

Step-by-step explanation:

The box plot is a visual way of presenting a dataset where the rectangle is used to represent the quartiles.

The given parameters are:

Male:                                                               Female

[tex]Minimum = 0[/tex]                                                 [tex]Minimum = 0[/tex]

[tex]Q_1 = 1[/tex]                                                              [tex]Q_1 = 5[/tex]

[tex]Median = 20[/tex]                                                    [tex]Median = 6[/tex]

[tex]Q_3 = 25[/tex]                                                            [tex]Q_3 = 10[/tex]

[tex]Maximum = 50[/tex]                                               [tex]Maximum = 18[/tex]

A. IQR  for male dataset

The IQR is calculated as follows:

[tex]IQR = Q_3 - Q_1[/tex]

For the male's data:

[tex]IQR = 25-1[/tex]

[tex]IQR = 24[/tex]

Hence, the IQR of the male dataset is 24.

B. Difference in median values

We have:

[tex]Median = 20[/tex]  ----- Male dataset                                                    

[tex]Median = 6[/tex] ----- Female dataset

So, the difference (d) is:

[tex]d = 20 - 6[/tex]

[tex]d = 14[/tex]

Hence, the difference in median of both dataset is 14.

C. Best measure of center

The female box plot (see attachment) has an outlier. This means that the measure of center to use for the female dataset is the median.

The male box plot has no outlier; this means that the mean can be used as a measure of center for the male box plot

D. Reason for outlier

There are several reasons that could cause an outlier in a dataset. One of the reasons is human error during data entry

Read more about box plots at:

https://brainly.com/question/1523909

Answer:

x = 20

y = 70

Step-by-step explanation:

Since B and D are parallel :

6x - 10 + 3x + 10 = 180 add/subtract like terms

9x = 180 divide both sides by 9

x = 20

angle represented by y and 6x - 10 are supplementary and their sum is 180

y + 6x - 10 = 180 replace x with 20

y + 6*20 - 10 = 180

y + 120 - 10 = 180

y + 110 = 180 subtract 110 from both sides

y = 70

Answer:

false

Step-by-step explanation:

these angles are horizonal

Answer:

4x+2

Step-by-step explanation:

(5x+4)-(x+2)=(5-1)*x+(4-2)=4x+2

An example of an exponential function is given as follows:

A. Investing $1,000 at an annual interest rate of 3%, compounded monthly.

An increasing exponential function is modeled by:

[tex]A(t) = A(0)(1 + r)^t[/tex]

In which:

As we saw above, the rate of change is a percent, and in this problem, only option A has a rate of change as a percent, hence it is an exponential function.

More can be learned about exponential functions at https://brainly.com/question/25537936

#SPJ1

Answer:

29.5 square inches

Step-by-step explanation:

Let's divide the shape into 3 parts to make it easy for us to find the area.

- a wide triangle

- a triangle

- a shorter rectangle

For the wider rectangle, the area is;

A1 = 8 × 2 = 16 in²

For the triangle, the area is;

A2 = ½(7 - 2) × 3

A2 = 7.5 in²

For the shorter rectangle, the area is;

A3 = 3 × 2

A3 = 6 in²

Total area = A1 + A2 + A3 = 16 + 7.5 + 6 = 29.5 square inches

Answer:

7

Step-by-step explanation:

Answer:

3/4 cup of milk.

Step-by-step explanation:

1 1/2= 6/4. 6÷2=3.

Answer:

3/4

Step-by-step explanation:

Half the recipe means multiply by 1/2

1 1/2 * 1/2

Change the mixed number to an improper fraction

(2*1+1)/2 * 1/2

3/2 * 1/2

3/4

Answer:

1.2 = 12/10 = 6/5

2.25 = 225/100 = 9/4

3.5 = 35/10 = 7/2

4.06 = 406/100 = 203/50

Step-by-step explanation:

Hi there!

Given;

(x-9)² = 81........(i)

Take whole square right side;

(x-9) = ±√(81)

(x-9) = ±9

Therefore, the answer is option A.

Hope it helps!

Answer:

[tex]x = 12[/tex]

Step-by-step explanation:

[tex]4 + 2x = 4x - 20[/tex]

[tex]4 + 20 = 4x - 2x[/tex]

[tex]24 = 2x[/tex]

[tex]x = 12[/tex]

Answer:

3.33%

Step-by-step explanation:

Intrest = P. A. *Intrest Rate * Time

(1/3)*P. A. = P. A. *Intrest Rate * 10

Intrest Rate = 1/30)=3.33%

Answer:

S = 1256

Step-by-step explanation:

S = 4[tex]\pi[/tex][tex]r^2[/tex]

S = 4[tex]\pi[/tex][tex](10)^2[/tex]

S = 4[tex]\pi[/tex][tex](100)[/tex]

S = [tex]4(314)[/tex]

S = 1256

Answer:

400pi, or 1256.637...

Step-by-step explanation:

S = 4pir^2

S = 4pi(10^2)

S = 4pi(100)

S = 400pi

x ³ = 1

x ³ - 1 = 0

x ³ - 1³ = 0

Factorize the right side as a difference of cubes:

(x - 1) (x ² + x + 1) = 0

Then

x - 1 = 0   or   x ² + x + 1 = 0

The first equation yields x = 1 as a root.

For the other equation, rearrange and complete the square to get the other two roots,

x ² + x + 1/4 = -3/4

(x + 1/2)² = -3/4

x + 1/2 = ±√(-3/4) = ± i √3/2

x = -1/2 ± i √3/2

x = (-1 ± i √3)/2

Since complex roots occurs in conjugate pairs, taking the sum of these two roots eliminates the imaginary part:

(-1 + i √3)/2 + (-1 - i √3)/2 = (-1 - 1)/2 = -2/2 = -1

and adding to 1 indeed shows that the sum of roots is zero.