what scenerio in which a population is evolving. Explain how the variants within a population was generated.
Please help!! Need the Correct Answer ASAP!!
Which statement is true?
A.Peat is a fossil fuel because rewetting it takes only 3–5 years.
B.Peat is a fossil fuel because the total time for restoration is lengthy.
C.Peat is not a fossil fuel because it has biologic origins, making it a biofuel.
D.Peat is not a fossil fuel because humans can promote the replenishment of peat.
Answer:
c) peat is not a fossil fuel because it has biologic origins, making it biofuel
Explanation:
Peat is soil/ turf
All claims in science should be supported by biology
Answer:
yes
Explanation:
Because science &biology have a connection
18. Why are enzymes important to cells?
о
They provide structural support.
о
They form the two layers of membranes.
They store large quantities of energy.
о
They help bring about chemical reactions
Answer:
An enzyme is a type of protein found within a cell. Enzymes create chemical reactions in the body. They actually speed up the rate of a chemical reaction to help support life.
predators are... a. primary producers b. primary consumers c. secondary consumers
Answer:
Primary consumers
They eat the majority of prey
In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,250 pine trees in 1990 and 1,500 pines in 1995.
What was the average change of the size of the population from 1985 to 1995?
What was the density of pine trees each year that they were counted?
What was the average change of density from 1985 to 1995?
Answer:
Suppose that we have a given function f(x)
The average rate of change of the function between two values x₁ and x₂ is given by:
[tex]r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}[/tex]
a) We want to find the average (rate) of change on the size of population from 1985 to 1995.
We have that:
f(1985) = 750
f(1995) = 1500
Then we have:
[tex]r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75[/tex]
This means that the population of trees increases, in average, at a rate of 75 trees per year.
b) What is the density of trees each year that they were counted?
This will be equal to the quotient between the number of trees and the area.
1985: number of trees = 750 pines
area = 250 ha
Then the density is:
D(1985) = (750 pines)/(250 ha) = 3 pines/ha
So 1985, there were 3 pines per hectare.
1990: number of trees = 1250 pines
area = 250 ha
Then the density is:
D(1990) = (1250 pines)/(250 ha) = 5 pines/ha
1995: number of trees = 1500 pines
area = 250 ha
The density is:
D(1995) = (1500 pines)/(250 ha) = 6 pines/ha
3) now we want to get the average change between 1985 and 1995 in the density, this will be:
[tex]r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha[/tex]
So, on average, each year the number of pines per hectare increases by 0.3
¿Qué nombres reciben los tejidos que dan
origen a los tejidos adultos de las plantas?
a. Tejidos diferenciados
b. Tejidos indiferenciados (meristemos)
c. Tejidos vegetales
Answer:
D
Explanation:
If 622 water molecules were removed during the synthesis of a specific polysaccharide, how many monomers were joined together to make this molecule? need help please and thank you
Answer:
623 monomers
Explanation:
In a dehydration synthesis reaction, one water molecule is removed for every bond that is created between 2 monomers.
Linking 3 monomers together would remove 2 water molecules.
Following this pattern, the number of water molecules removed will always be one less than the number of monomers that were joined together.
So, if 622 water molecules were removed, then 623 monomers were joined together.
The answer is 623 monomers.
Por qué algunas enfermedades se padecen solo una vez?
Answer:
por que a mi saber, cuando te infectas con una enfermedad viral al contagiarte y después sanar tu cuerpo crea anticuerpos que estos asu vez hacen que seas inmune a ese virus y otras veces las enfermedades son erradicadas con la vacunación.
Try this for yourself. Suppose you want to estimate the number of field mice in a small field. One day you capture 500 mice, mark all of them and release them. The next week you capture 200 mice of which 40 were marked by you yesterday. What is your estimate of the population size?
Answer:
The approximate size of the field mice population is 2500 individuals.
Explanation:
There are different methods to study population density. There are direct methods and indirect methods. Among these last ones, we might find the "Mark-Recapture technique".
The Mark-Recapture technique assumes that the population is closed, during the sampling season there is no mortality nor natality, marks in the individual last the whole sampling season, and these do not affect the marked individual or their behavior. These marked individuals are randomly distributed in the population, and all the individuals have the same probability of being sampled.
The method consists of capturing a sample of individuals belonging to the population under study, in this case, the field mice population. After capturing the individuals, the researcher marks them and release them again. The third step is to sample again, capture a new amount of individuals, and count how many of them are marked. These marked individuals belong to the first sample. We can calculate the population size by using the Lincoln Index or any other index.
The Lincolns Index states that to obtain the population size, the research must follow the following procedure:
1) Take an initial sample with n1 number of individuals
2) Mark all the sampled individuals and release them
3) Take a second sample with n2 number of individuals
4) Count the number of marked individuals m
To estimate the total number of individuals in this population, N, the following equation must be considered:
N = (n1 x n2)/m
In the exposed example, this is:
• n1= 500 individuals in the first sample
• n2= 200 individuals in the second sample
• m= 40 individuals in the second sample that were previously marked
as they were part of the first sample
N = (n1 x n2)/m = (500 x 200) / 40 = 2500 individuals
The approximate size of the field mice population is 2500 individuals.
P is an autosomal dominant allele that produces a pigment, p is a recessive allele that produces no pigment. A pigmented and a non-pigmented organism mate and produce a pigmented offspring. They then mate and produce a non-pigmented offspring. What is the probability the next offspring will be pigmented
Answer:3/4
Explanation:4 possibilities, 3 dominant
If a pigmented and non-pigmented organism mate and produce a pigmented organism, which mate again and produce non-pigmented organisms, the probability that the next offspring will be pigmented is ¾ as P is the dominant, pigment-producing allele.
What are dominant alleles?The association between two genetic variants is referred to as dominant. Each gene has two alleles that an individual inherits from each parent. One allele of a gene, known as the dominant gene, will be expressed if the alleles are different. The impact of the additional allele, known as the recessive one, is concealed.
If one is in charge, the other must be recessive. Then it is referred to as recessive. A dominant gene, or dominant form of a gene, is a specific variant of a gene that expresses itself more powerfully on its own than any other version of the gene that the individual is carrying—in this example, the recessive—for a variety of reasons.
Now, it mainly refers to patterns of inheritance typically used in combination with a Punnett square, where if a person has two copies of a gene and one is shown to frequently be passed down from one generation to another, it is referred to as dominant.
According to biochemistry, what is happening in this situation is that the genetic variant may, for a variety of reasons, cause a cell to perform a very advantageous or very disadvantageous function that the other version of the gene cannot cover up or counteract.
Therefore, the probability that the next offspring will be pigmented is ¾ as P is the dominant, pigment-producing allele.
Read more about dominant alleles, here
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What methods help control pollution source
Practicing conservation tillage traps contaminants from Runoff water. Practicing conservation tillage helps prevent BLANK
A. Air pollution
B. Water pollution
C. Soil erosion
Many of the phenotypes of DiGeorge syndrome have been traced back to one of the genes that is in the deleted region, TBX1. Some of the evidence for the important role of TBX1 in DiGeorge syndrome came from individuals who have some of the symptoms of DiGeorge syndrome without having the typical deletion. Closer examination showed that some of these individuals had SNV in the TBX1 gene. Which of the following SNVS would be most likely to create a similar phenotype to the deletion?
A. A variant in the promoter region of TBX1 that increases its expression
B. A variant in the intronic region of TBX1 that does not affect splicing. X
C. A nonsense variant near the 5' end of the TBX1 gene.
D. A silent variant near the 5' end of the TBX1 gene.
Answer:
D. A silent variant near the 5' end of the TBX1 gene.
Explanation:
TBX1 gene is wild type human being. It gives instructions for making protein called T-box 1. It plays an important role in tissue formation and organs during embryonic development.
explain what it means to view something from a frae of reference. provide an example that illustrate your explanation.
Answer:
ex. where you are standing now
a perspective that one uses to determine if an object is moving.
Explanation:
in physics, a frame of reference, or reference frame, is a perspective that one uses to determine if an object is moving. ... For example, when you see a ball roll down a street, you can tell the ball is moving because the frame of reference is the streets, whatever may be on the side of the roads, or the Earth.
wikipedia
You are carrying a case of 24 bottles of water up the stairs to your third-story apartment. What type of contraction are the muscles in your arms experiencing
Answer:
Concentric contraction.
Explanation:
Concentric contraction is a type of contraction that the muscles in arms experiencing when an individual lifting 24 bottles of water up the stairs. A concentric contraction is a type of muscle activation that creates tension on your muscle as it shortens. As your muscle shortens, it produces enough force to move an object in the upward direction. In weight training we can easily see concentric movement.
Sickle cell anemia in the United States disproportionately affects African Americans; 1 in 700 African Americans are affected by sickle cell anemia, while only 1 in 160,000 Americans of European descent are affected. The absolute risk of a newborn African American child having sickle cell anemia is ____________%, and the relative risk compared to a newborn European American child is ____________-fold
Answer:
0.0014; 0.0044
Explanation:
The absolute risk (AR) of a disease refers to the risk of developing the disease over a given time period. In this case, the absolute risk of the newborn African American child having sickle cell anemia is equal to 1 individual with the disease over 700 individuals >> AR = 1 / 700 = 0.0014. Moreover, the Relative Risk (RR) is calculated by comparing the likelihood of the absolute risk occurring between two distinct groups. In this case, the relative risk for the newborn African American having sickle cell anemia compared to a newborn European American child can be calculated by dividing the absolute risk of the newborn European American child with the measured absolute risk of the newborn African American child >> RR = 0.0000625 / 0.0014 = 0.0044.
A degraded ecosystem is replaced with a different but productive ecosystem type, one that might even include some nonnative species. For example, a degraded forest might be replaced with a productive pasture.a. passive restoration b. remediation c. partial restoration d. rehabilitation e. complete restoration
Answer:
d. rehabilitation
Explanation:
Technology-associated rehabilitation is an ecological practice that allows a degraded area to be restored, rehabilitating all its degraded habitats. However, this restoration is not done naturally, but is caused by human intervention, which can cultivate the entire plant population in the area, even adding non-native species, which are selected to leave the productive area, but ecologically harmonious.
A muscle that is stimulated so frequently that the relaxation phase is eliminated is said to exhibit _______. Question 13 options: tetanus recruitment treppe wave summation
Answer:
tetanus
Explanation:
Tetanus causes a strong tonic contraction in skeletal muscles. This triggers a series of intermittent, progressive, and extremely painful muscle spasms. Tetanus is presented by patients who have stimulated a muscle too often, without allowing a moment of rest.
A particular cross gives a modified dihybrid ratio of 9:7. What phenotypic ratio would you expect in a testcross of the fully heterozygous F1 crossed with the fully recessive type
Answer:
3:1
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
Which of these is a benefit of fish farming?
A. It can deplete native fish populations
B. It can restock lakes depleted by recreational fishing
C. It can pollute natural bodies of water
D. It can pass diseases to native fish populations
Answer:
The answer to this would be B
Explanation:
B:It can restock lakes depleted by recreational fishing
Different types of cells have different numbers and types of
O nuclei
O DNA
O cell membranes
O organelles
Which of the following is a unifying characteristic of life?
Answer:
where is option I can't see
D - Telophase
C - Anaphase
A - Prophase
B - Metaphase
th
Choose the correct description for each phase of mitosis.
Answer:
A-B-C-D
Explanation:
PROPHASE; 1. chromosomes become thicker
2. nuclear membrane disintegrates
3. centrosome divide to form centrioles
4. centrioles move to the opposite polls of the cell
METAPHASE; 1. chromosomes get arranged at the equator
2. centrioles produce spindle fibre that attach to the middle of the chromosomes
ANAPHASE; 1. shortest stage of mitosis
2. spindles will pull apart each chromosomes to form chromatids
TELLOPHASE; 1. each chromatid moves to opposite polls of the cell
2. nuclear membrane appears around both of them
3. the centrioles sill stop producing spindles
4. centrosomes will then form again
cytokinesis then divides by the cleavage furrow to form the two daughter cells
Which of the cardiac cell characteristics describes the
ability to initiate an electrical impulse?
Answer:
The correct answer is: automaticity.
Explanation:
Cardiac muscle has several properties. These properties are: automaticity (given by the pacemaker cells), conductivity (meaning that each cardiac cell can transmit the electrical impulse to the next cardiac cells), contractility (like other types of muscles, cardiac muscle cells can contract), and irritability (each cell can contract on its own without the external stimuli).
Cardiac pacemaker cells are the ones with the capacity to initiate the electrical impulse by creating rhythmic impulses called action potentials, and thus directly regulating heart rate.
Pacemaker cells are located in the sinoatrial (SA) node, in the upper portion of the right atrial wall. In these cells, depolarization of the cardiac muscle begins, and the electrical impulse generated by it is transmitted to the atrioventricular (AV) node, the His bundle and then the Purkinje fibers - this order of events is necessary for the correct contraction of the heart to occur. All of these structures are part of the Conduction System of the heart.
do both plant cells and prokaryotic cells have 70S ribosomes
Which of the following events contributes to the termination of a signal generated by the binding of a ligand to a receptor tyrosine kinase? Only one answer is correct
1. Phosphatases hydrolyze key phosphorylated residues.
2. Kinases hydrolyze key phosphorylated residues.
3. Kinases phosphorylate key residues.
4. The receptor tyrosine kinase dimerizes.
5. GTPase removes a phosphoryl group from GTP.
6. Phosphatases phosphorylate key residues.
Answer:
1. Phosphatases hydrolyze key phosphorylated residues.
Explanation:
Receptor Tyrosine Kinases (RTKs) are high-affinity transmembrane protein receptors that bind to a wide variety of ligands (e.g., growth factors, cytokines, hormones). These receptors (RTKs) have a transmembrane domain and therefore these proteins act as membrane receptors, as well as exhibit catalytic activity. The intracellular C terminal region of RTKs contains catalytic domains responsible for both autophosphorylation and tyrosine phosphorylation of their protein substrates. Moreover, Protein Tyrosine Phosphatase (PTPs) are critical enzymes that remove phosphate groups from tyrosine residues in different substrates (including RTKs), thereby regulating key signaling pathways such as cell proliferation, cell differentiation, and cell-cell adhesion.
Two species of closely related frogs are found in the same pond high in the Andes of South America. Both species only have teeth on the top jaw. One has small teeth for holding small live prey prior to swallowing. The other species has very large sharp teeth for injuring and killing large prey prior to biting off pieces of flesh for consumption. The above is an example of:
Complete question:
Two species of closely related frogs are found in the same pond high in the Andes of South America. Both species only have teeth on the top jaw. One has small teeth for holding small live prey prior to swallowing. The other species has very large sharp teeth for injuring and killing large prey prior to biting off pieces of flesh for consumption. The above is an example of:
Directional selectionAnalogous structuresCharacter displacementHybridization Vestigial structuresAnswer:
Character displacementExplanation:
Competition is an ecological and evolutive process very common in nature. Competition might be intra- or interspecific. Competition between different species in a community or ecosystem might be due to the same resource use, or the same territory, shelter, etcetera. When a resource is useful for two or more species, and limited, they compete to gain it.
The principle of competitive exclusion states that different species with the same requirements sharing the niche can not coexist indefinitely based on the same limited resource. When two competing species coexist, this is because of niche partitioning or niche differentiation.
Differentiation of effective niche is closely related to character displacement.
Character displacement is the result of interspecific competition, in which two or more species that live in the same habitat manage to avoid competition by developing different traits. Morphological divergence, or any adaptative trait development, fixated genetically, is the product of niche segregation. Species tend to differentiate morphologically in the presence of strong competitors. Traits divergence favors coexistence in the same place.
In the exposed example, both species live in the same pond. But to avoid competition and competitive exclusion, species developed different teeth sizes to feed on different prey items.
2 True or False. A projectleie an object that once set in motion continues in motion by its own martia O True False
Answer:
The answer is true.Explanation:PARTICLES MOVING ALONG THE PATH POSSES A TWO DIMENSIONAL MOTIONMARK ME AS BRAINIST PLZ
I need help asap
I need help asap
Answer:
c
Explanation:
i dont care
In these imprinted cells, the SNRPN transcript overlaps with another gene, called UBE3A, which is transcribed in the opposite direction. This means that the region that the RNA polymerase transcribes in these two genes actually overlaps; in some cases, overlapping transcription in opposite directions leads to transcriptional interference, meaning that collisions between the polymerases traveling in opposite directions can interfere with transcription. It is believed that this takes place in this case, meaning that the more SNRPN transcription occurs, the more this disrupts transcription of UBE3A. Based on this information as well as information about the effects of imprinting on SNRPN transcription, which of the following statements about UBE3A transcription would be true?
a. The maternal copy of UBE3A is expressed and the paternal copy is silenced.
b. The paternal copy of UBE3A is expressed and the maternal copy is silenced.
c. Both copies of UBE3A are highly expressed.
d. Both copies of UBE3A are silenced.
Answer:
a. The maternal copy of UBE3A is expressed and the paternal copy is silenced.
Explanation:
When UBE3A chromosome is in neurons, paternal allele is silent and maternal allele is expressed in process of genomic imprinting. In some cases UBE3A is expressed from both paternal and maternal chromosomes. The paternal chromosome is blue whereas maternal chromosome is magenta.
