How many different simple random samples of size 4 from a population size 46

Answer:

100

Step-by-step explanation:

I assume you mean [tex]\frac{5}{12}[/tex] of the students in Year 9.

Basically, first you need to work out 1/12 of the students, which is just 240 divided by 12, equals 20.

So, we know 1/12 of 240 is 20, therefore, in order to work out 5/12, we must do 20 x 5, which is 100.

Answer:

The length is of 59 cm.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle with width w and length l is given by:

[tex]P = 2(w + l)[/tex]

Width of 49 centimeters and a perimeter of 216 centimeters:

This means that [tex]w = 49, P = 216[/tex]

The length is cm.

We have to solve the equation for l. So

[tex]P = 2(w + l)[/tex]

[tex]216 = 2(49 + l)[/tex]

[tex]216 = 98 + 2l[/tex]

[tex]2l = 118[/tex]

[tex]l = \frac{118}{2}[/tex]

[tex]l = 59[/tex]

The length is of 59 cm.

Hey there!

We are given two functions - one is Exponential while the another one is Linear.

[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]

1. Operation of Function

[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]

2. Substitution

[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]

3. Evaluate/Simplify

[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]

4. Final Answer

Answer:

65 students.

Step-by-step explanation:

Given that :

Every student planted as many plant as their number ;

Then let the number of student = x

Then the number of plant planted by each student will also = x

The total number of plants planted by all the students = 4225

The Number of students can be obtained thus ;

Total number of plants = Number of plants * number of plants per student

4225 = x * x

4225 = x²

√4225 = x

65 = x

Hence, there are 65 students

Answer:

(4, 2 )

Step-by-step explanation:

Given the 2 equations

3x + y = 14 → (1)

7x - 4y = 20 → (2)

Rearrange (1) making y the subject by subtracting 3x from both sides

y = 14 - 3x → (3)

Substitute y = 14 - 3x into (2)

7x - 4(14 - 3x) = 20 ← distribute parenthesis and simplify left side

7x - 56 + 12x = 20

19x - 56 = 20 ( add 56 to both sides )

19x = 76 ( divide both sides by 19 )

x = 4

Substitute x = 4 into (3) for corresponding value of y

y = 14 - 3(4) = 14 - 12 = 2

solution is (4, 2 )

Answer:

[tex]3x + y = 14 \\ y = 14 - 3x \\ substitute \: y \: into \: equation \: 2\\ 7x - 4(14 - 3x) = 20 \\ 7x - 56 + 12x = 20 \\ 19x = 76 \\ x = \frac{76}{19} =4 \\ y = 14 - 3( 4 ) = 2 \\ [/tex]

Answer:

[tex]\frac{29}{35}[/tex] ft (29/35 ft)

Step-by-step explanation:

Perimeter: [tex]2w+2l[/tex]

[tex]2(\frac{1}{5})+2(\frac{3}{14})=\frac{2}{5} +\frac{6}{14}[/tex]

Since [tex]\frac{6}{14} = \frac{3}{7}[/tex], the LCD would be 35

New equation: [tex]\frac{14}{35} +\frac{15}{35} =\frac{29}{35}[/tex]

[tex]\frac{29}{35}[/tex]

Hope this helped! Please mark brainliest :)

Answer:

Factors of number 52

Factors of 52: 1, 2, 4, 13, 26 and 52.

Negative Factors of 52: -1, -2, -4, -13, -26 and -52.

Prime Factors of 52: 2, 13.

Prime Factorization of 52: 2 × 2 × 13 = 22 × 13.

Sum of Factors of 52: 98.

Answer:

8/81

Step-by-step explanation:

It's most efficient to simplify the quotient algebraically before inserting the values of the variables x and y.  

The given expression reduces to x³ / y^4.

Substituting 2 for x and 3 for y, we get:

 (2)³           8

--------- = ---------- (Agrees with first given possible answer)

 (3)^4         81

Answer:

(a) Residents

(b) [tex]Median = 0.13[/tex]

(c)  [tex]\bar x = 0.14[/tex]

(d) Right skewed

Step-by-step explanation:

Given

The data of residents without health insurance

Solving (a): The variable

The variable is the residents

Solving (b): The median

First, we sort the data

[tex]Sorted: 0.09, 0.10, 0.11, 0.13, 0.13, 0.14, 0.16, 0.19, 0.25[/tex]

So, the median position is:

[tex]Median = \frac{n + 1}{2}[/tex]

[tex]Median = \frac{9 + 1}{2}[/tex]

[tex]Median = \frac{10}{2}[/tex]

[tex]Median = 5th[/tex]

The 5th element of the dataset is: 0.13

So:

[tex]Median = 0.13[/tex]

Solving (c): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

[tex]\bar x = \frac{0.09+ 0.10+ 0.11+ 0.13+ 0.13+ 0.14+ 0.16+ 0.19+ 0.25}{9}[/tex]

[tex]\bar x = \frac{1.3}{9}[/tex]

[tex]\bar x = 0.14[/tex]

Solving (d): The shape of the distribution

In (b) and (c), we have:

[tex]Median = 0.13[/tex]

[tex]\bar x = 0.14[/tex]

By comparison, the mean is greater than the median.

Hence, the shape is: right skewed.

Answer:

$2550

Step-by-step explanation:

Calculation to determine the amount of retained earnings at the beginning of Year 2

Using this formula

Beginning Retained Earnings + Revenue − Expenses − Dividends = Ending Retained Earnings

Let plug in the formula

Beginning Retained Earnings + $3,200 − $1,700 − $1,100 = $2950

Beginning Retained Earnings= $2,950-$400

Beginning Retained Earnings = $2,550

Therefore the amount of retained earnings at the beginning of Year 2 is $2550

Answer:

-2x³ - 14x² + 7x - 4

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

(3x³ - 2x² + 4x - 8) - (5x³ + 12x² - 3x - 4)

Step 2: Simplify

Answer:

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

Step-by-step explanation:

0, 4, 6, 14, 17

inner quartile range of 0 - 17 is 1/2 of 17 subtracted from the higher number = 17 - 1/2 of 8.5 =  8.5 - 4.25 = 4.25 - 4.25 x 3

= 4.25 to 12.75 for inner quartile

inner quartile range is 12.75-4.25 = 8.5

We then 1.5 x 8.5 to show the outlier

= 12.75 meaning there is no outlier if is below.

Lower quartile fences  = 4.25 - 1.5 = 2.75

or -1.5 x 8.5 (the range) =   -12.75

Upper quartile fence = 12.75 + 1.5 = 14.25 x 8.5 =   121.125  this would be an outlier if it is 12.75 higher than 121.125 or 12.75 lower than 5.50.

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

An observation is considered an outlier if it exceeds a distance of 1.5 times the interquartile range (IQR) below the lower quartile or above the upper quartile. The values of the lower quartile - 1.5 x IQR and upper quartile + 1.5 x IQR are known as the inner fences.

An observation is an outlier if it falls more than above the upper quartile or more than below the lower quartile. The minimum value is so there are no outliers in the low end of the distribution. The maximum value is so there are no outliers in the high end of the distribution.

Answer:

y = [ 4 ]

Step-by-step explanation:

5y - 10 = 10

     +10  +10

5y = 20

/5     /5

y = 4

hope this helps ! ^^

Answer:

[tex]5y-10=10[/tex]

[tex]Add ~10[/tex]

[tex]5y=10+10[/tex]

[tex]5y=20[/tex]

[tex]divide ~by ~5[/tex]

[tex]y=4[/tex]

[tex]ANSWER: y=4[/tex]

-----------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

Answer:

The volume is increasing at a rate of 27093 cubic inches per second.

Step-by-step explanation:

Volume of a cone:

THe volume of a cone, with radius r and height h, is given by:

[tex]V = \frac{1}{3} \pi r^2h[/tex]

In this question:

We have to differentiate implictly is function of t, so the three variables, V, r and h, are differenciated. So

[tex]\frac{dV}{dt} = \frac{\pi r^2}{3}\frac{dh}{dt} + \frac{2\pi rh}{3}\frac{dr}{dt}[/tex]

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.4 in/s.

This means that [tex]\frac{dr}{dt} = 1.4, \frac{dh}{dt} = -2.4[/tex]

Radius is 140 in. and the height is 186 in.

This means that [tex]r = 140, h = 186[/tex]

At what rate is the volume of the cone changing?

[tex]\frac{dV}{dt} = \frac{\pi r^2}{3}\frac{dh}{dt} + \frac{2\pi rh}{3}\frac{dr}{dt}[/tex]

[tex]\frac{dV}{dt} = \frac{\pi (140)^2}{3}(-2.4) + \frac{2\pi 140*186}{3}1.4[/tex]

[tex]\frac{dV}{dt} = -0.8\pi(140)^2 + 62*2\pi*1.4*140[/tex]

[tex]\frac{dV}{dt} = 27093[/tex]

Positive, so increasing.

The volume is increasing at a rate of 27093 cubic inches per second.

Answer:

[tex]x^{3}cos(x^{2})=\sum _{n=0} ^{\infty} \frac{(-1)^{n}x^{4n+3}}{(2n)!}[/tex]

[tex]x^{3}sin(x^{2})=\sum _{n=0} ^{\infty} \frac{(-1)^{n}x^{4n+5}}{(2n+1)!}[/tex]

Step-by-step explanation:

A

Let's start with the first function:

[tex]x^{3}cos(x^{2})=x^{3}-\frac{x^{7}}{2!}+\frac{x^{11}}{4!}-\frac{x^{15}}{6!}+...[/tex]

In order to find the expression for the general term, we will need to analyze each part of the sum. First, notice that the sign of the terms of the sum will change with every new term, this tells us that the expression must contain a

[tex](-1)^{n}[/tex].

This will guarantee us that the terms will always change their signs so that will be the first part of our expression.

next, the power of the x. Notice the given sequence: 3, 7, 11, 15...

we can see this is an arithmetic sequence since the distance between each term is the same. There is a distance of 4 between each consecutive power, so this sequence can be found by adding a 4n to the original number, the 3. So the power is given by 4n+3.

so let's put the two things together:

[tex](-1)^{n}x^{4n+3}[/tex]

Finally the denominator, there is also a sequence there: 0!, 2!, 4!, 6!

This is also an arithmetic sequence, where we are multiplying each consecutive value of n by a 2, so in this case the sequence can be written as: (2n)!

So let's put it all together so we get:

[tex]\frac{(-1)^{n}x^{4n+3}}{(2n)!}[/tex]

So now we can build the whole series:

[tex]x^{3}cos(x^{2})=\sum _{n=0} ^{\infty} \frac{(-1)^{n}x^{4n+3}}{(2n)!}[/tex]

B

Now, let's continue with the next function:

[tex]x^{3}sin(x^{2})=x^{5}-\frac{x^{9}}{3!}+\frac{x^{13}}{5!}-\frac{x^{17}}{7!}+...[/tex]

In order to find the expression for the general term, we will need to analyze each part of the sum. First, notice that the sign of the terms of the sum will change with every new term, this tells us that the expression must contain a

[tex](-1)^{n}[/tex].

This will guarantee us that the terms will always change their signs so that will be the first part of our expression.

next, the power of the x. Notice the given sequence: 5, 9, 13, 17...

we can see this is an arithmetic sequence since the distance between each term is the same. There is a distance of 4 between each consecutive power, so this sequence can be found by adding a 4n to the original number, the 5. So the power is given by 4n+5.

so let's put the two things together:

[tex](-1)^{n}x^{4n+5}[/tex]

Finally the denominator, there is also a sequence there: 1!, 3!, 5!, 7!

This is also an arithmetic sequence, where we are multiplying each consecutive value of n by a 2 starting from a 1, so in this case the sequence can be written as: (2n+1)!

So let's put it all together so we get:

[tex]\frac{(-1)^{n}x^{4n+5}}{(2n+1)!}[/tex]

So now we can build the whole series:

[tex]x^{3}sin(x^{2})=\sum _{n=0} ^{\infty} \frac{(-1)^{n}x^{4n+5}}{(2n+1)!}[/tex]

Answer:

Below

Step-by-step explanation:

It is 5 1/4 PERCENT not just 5 1/4.

5 1/4 % = 5.25%

= 5.25/100

= 0.0525.

Answer:

1) a)  accepting the new drug is better based on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects

b) Accepting and using the current drug in use when it is not as effective as the new drug

c) Type 1 error

2) a) rejecting the vitamin supplement based on not knowing the harmful side effects

b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.

c) Type II error

3) Increase the significance level  ( A )

Step-by-step explanation:

1)

a) To make a type 1 error in this situation is accepting the new drug is better and prescribing it to the millions of people based only on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects

b) A type II error in context is :Accepting and using the current drug in use when it is not as effective as the new drug

c)  Type I error

2)

a) Type 1 error is rejecting the vitamin supplement based on not knowing the harmful side effects

b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.

c) Type II error

3) If committing a type 1 error is much worse

Increase the significance level

Answer: A

Step-by-step explanation:

The main parent functions are x, and x raised to the power of something (examples: [tex]x^2, x^3, x^4[/tex], etc)

Answer:

A. 18

Step-by-step explanation:

Recall: the Mid-segment Theorem states that the length of the mid-segment theorem of a triangle is half the length of its third side.

DE = ½(AC) (Triangle Mid-segment Theorem)

AC = 36 (given)

Plug in the value

DE = ½(36)

DE = 18

Answer:

The slope of diagonal AB is 0 and its equation is [tex]y=-2[/tex].

Step-by-step explanation:

Horizontal lines have zero slope. Since diagonal AB represents a horizontal line (same y-value regardless of x-value), the slope of diagonal AB is 0.

Horizontal lines can be expressed as [tex]y=n[/tex] where [tex]n[/tex] is some real number. In this case, diagonal AB sits on a line with only y-values of -2, and therefore the equation of the line the diagonal is on is [tex]\boxed{y=-2}[/tex].

Answer:

2n+2

_____

9 2n

Answer:

this would look like

0.5x+x=165

1.5x=165

x=110

Hope This Helps!!!

Answer:

Y = 2/3X + 4/3

Step-by-step explanation:

(1,2) (4,4)

M = 2/3

Y = 2/3X + b

4 = 8/3 + b

12 = 8 + 3b

4 = 3b

B = 4/3

Y = 2/3X + 4/3

Answer:

en la calasa ni esta en la estacion

Answer:

1 ans A second phi okay yed

Answer:

[tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra I

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]:                                                              [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                            [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Product Rule]:                                                                                [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = (x^3 + 7x - 1)(5x + 2)[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

= ∑ 6*n*x^n-1

Radius of convergence = 1

Step-by-step explanation:

f(x) = 6(1-x)^-2

Maclaurin series can be expressed using the formula

f(x) =  f(0) + f '(0)x + f ''(0)/ 2!  (x)^2 + f '''(0)/3! (x)^3 + f (4)(0) 4! x4 + .

attached below is the detailed solution

Radius of convergence = 1

The Maclaurin series for f(x) = 6 / (1 - x )^2  = ∑ 6*n*x^n-1  ( boundary ; ∞ and n = 1 )

Answer:

Given Two equations :-

[tex]3x {}^{2} - 2 {y}^{2} = 57 .\: .\: .\: . \:(i) \\ - 2 {x}^{2} + 3 {y}^{2} = -23.\: .\: .\: . \:(ii)[/tex]

[tex](3x {}^{2} - 2 {y}^{2} = 57 ) \times 2 .\: .\: .\: . \:(i) \\ ( - 2 {x}^{2} + 3{y}^{2} = - 23) \times 3.\: .\: .\: . \:(ii)[/tex]

[tex]6x {}^{2} - 4 {y}^{2} =114 .\: .\: .\: . \:(i) \\ - 6 {x}^{2} + 9 {y}^{2} = - 69.\: .\: .\: . \:(ii)[/tex]

[tex]0 + 5 {y}^{2} = 45 \\ 5y {}^{2} = 45 [/tex]

[tex] {y}^{2} = 9[/tex]

[tex]y = + - 3[/tex]

3x²- 2×9 = 57

3x² - 18 = 57

3x² = 57 + 18

3x²= 75

x² = 25

x = ± 5