Hw help ASAP PLZZZZZZ

Answer: About 72%

Step-by-step explanation:

It's a conditional probability.

(Number of graduates on financial aid)/(Number of graduates)

[tex]\frac{1879}{2610} =0.7199[/tex]

0.7199 = 71.99% ≈ 72%

Answer:

2nd choice

Step-by-step explanation:

Answer:

The point of intersection is [tex]( \frac{-1\pm\sqrt{5}}{2}, 0)[/tex]

Step-by-step explanation:

f(x) = 2x^2 + 3x - 3 and g(x) = - x^2

By equating them

2x^2 + 3x - 3 = -x^2

3x^2 + 3 x - 3 =  0

x^2 + x - 1 = 0

[tex]x^2 +x - 1 = 0 \\\\x = \frac{-1\pm\sqrt{5}}{2}[/tex]

Answer:

Values of x

Step-by-step explanation:

The domain of a function is the set of all possible inputs for the function while the co-domain is the set of all possible outputs of the function.

In other words, domain is the set of x-values that you can put into any given equation while co-domain is the sex of f(x)-values that you get from substituting the values of x.

Hope it's clear

Answer:

The volume of the cube is 0.171 cubic inches.

Step-by-step explanation:

The volume of a cube given by :

[tex]V=s^3[/tex]

Where

s is the length of one of the sides.

We need to find the volume of the sugar cube if its side is 5/9 inches per side.

So,

[tex]V=(\dfrac{5}{9})^3\\\\V=0.171\ inches^3[/tex]

So, the volume of the cube is 0.171 cubic inches.

Answer:

a) A

b) C and E

c) C, D and F

d) two

e) Equal

Answer:

Bottom left

Step-by-step explanation:

Mark brainliest please

Yes, Lara is correct.

The steps are as follow:

So Lara is correct

Learn more about Congruent triangle here:

https://brainly.com/question/1675117

#SPJ2

Answer:

It will take Noshwa 3 hours and 36 minutes to travel 72 miles.

Step-by-step explanation:

Since Noshwa is completing the bike portion of a triathlon, assuming that she travels 40 miles in 2.5 hours, to determine how long will it take her to travel 72 miles, the following calculation must be performed:

40 = 2.5

72 = X

72 x 2.5 / 50 = X

180/50 = X

3.6 = X

1 = 60

0.6 = X

0.6 x 60 = X

36 = X

Therefore, it will take Noshwa 3 hours and 36 minutes to travel 72 miles.

Answer:

2/3

Step-by-step explanation:

[tex]2 \frac{1}{4} : \frac{1}{2}[/tex] = [tex]\frac{9}{4} : \frac{1}{2}[/tex]

[tex]\frac{\frac{9}{4} }{\frac{1}{2} }[/tex] = [tex]\frac{3}{x}[/tex]

3 * 1/2 = 9/4x

3/2 = 9/4 x

x = 3/2 ÷ 9/4 = 3/2 * 4/9 = 12/18 = 6/9 = 2/3

Step-by-step explanation:

this is a relatively easy function. Just plug in the value for x

Answer: 2/5x to the second.

may I have the brainiest? pls

Answer:

68% is a special

value for these problems

empirical rule suggests ± 1 standard deviation

z = (x - μ)/σ

1 = (x - 38000)/1000

Between $37,000 and $39,000

Step-by-step explanation:

Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.

Step-by-step explanation:

Order the dataset from least to greatest:

-38 → -13 → -9 → -2 → 14 → 28

Then find the values that lies in the middle:

-38 → -13 → -9 → -2 → 14 → 28

Since there are 2 values, find the average of those 2 values:

[tex]\frac{-9+(-2)}{2} =\frac{-11}{2} =-5.5[/tex]

The median value = -5.5.

The median value of data set B is -5.5, which is less than the median value of  3.1 in dataset A.

Answer:

1.

a. 2

b. 0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.

c. 0.1428 = 14.28% probability that delays will occur.

2.

a. 0.4512 = 45.12% probability that the service time is one minute or less.

b. 0.6988 = 69.88% probability that the service time is two minutes or less.

c. 0.3012 = 30.12% probability that the service time is more than two minutes.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

Question 1:

a. What is the mean or expected number of customers that will arrive in a five-minute period?

0.4 customers per minute, so for 5 minutes:

[tex]\mu = 0.4*5 = 2[/tex]

So 2 is the answer.

Question b:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]

[tex]P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707[/tex]

[tex]P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707[/tex]

[tex]P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1805[/tex]

0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.

Question c:

This is:

[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]

In which:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

The values we have in item b, so:

[tex]P(X \leq 3) = 0.1353 + 0.2707 + 0.2707 + 0.1805 = 0.8572[/tex]

[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8572 = 0.1428[/tex]

0.1428 = 14.28% probability that delays will occur.

Question 2:

[tex]\mu = 0.6[/tex]

a. What is the probability that the service time is one minute or less?

[tex]P(X \leq 1) = 1 - e^{-0.6} = 0.4512[/tex]

0.4512 = 45.12% probability that the service time is one minute or less.

b. What is the probability that the service time is two minutes or less?

[tex]P(X \leq 2) = 1 - e^{-0.6(2)} = 1 - e^{-1.2} = 0.6988[/tex]

0.6988 = 69.88% probability that the service time is two minutes or less.

c. What is the probability that the service time is more than two minutes?

[tex]P(X > 2) = e^{-1.2} = 0.3012[/tex]

0.3012 = 30.12% probability that the service time is more than two minutes.

Answer:

x≥-4

Step-by-step explanation:

Step-by-step explanation:

ii hope this will help you

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Answer:

x = 1

x = -2

Step-by-step explanation:

Hello!

We can solve the quadratic by factoring the equation.

Standard Form of a Quadratic: [tex]ax^2 + bx + c = 0[/tex]

Given our equation: [tex]x^2 + x - 2 = 0[/tex]

Find two numbers that multiply up to "ac" but add up to "b". The two numbers are 2 and -1. Expand x into 2x and -1x.

Set each factor to 0 and solve for x:

The solutions for x are 1 and -2.

Answer:

0.9802 = 98.02% probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

A bottle maker believes that 23% of his bottles are defective.

This means that [tex]p = 0.23[/tex]

Sample of 602 bottles

This means that [tex]n = 602[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.23[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.23*0.77}{602}} = 0.0172[/tex]

What is the probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%?

p-value of Z when X = 0.23 + 0.04 = 0.27 subtracted by the p-value of Z when X = 0.23 - 0.04 = 0.19.

X = 0.27

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.27 - 0.23}{0.0172}[/tex]

[tex]Z = 2.33[/tex]

[tex]Z = 2.33[/tex] has a p-value of 0.9901

X = 0.19

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.19 - 0.23}{0.0172}[/tex]

[tex]Z = -2.33[/tex]

[tex]Z = -2.33[/tex] has a p-value of 0.0099

0.9901 - 0.0099 = 0.9802

0.9802 = 98.02% probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%

Step-by-step explanation:

I am sorry question samajh Nahin a Raha question dijiye

Answer:

y = 3

Step-by-step explanation:

Given that the shapes are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{AB}{EF}[/tex] = [tex]\frac{CD}{GH}[/tex] , substitute values

[tex]\frac{3}{2}[/tex] = [tex]\frac{4.5}{y}[/tex] ( cross- multiply )

3y = 9 ( divide both sides by 3 )

y = 3

Answer:

0.52 = 52% probability that an email is detected as spam.

Step-by-step explanation:

Probability that an email is detected as spam:

99% of 50%(are spam).

5% of 100 - 50 = 50%(false positives, that is, e-mails that are not spam but are detected as spams).

What is the probability that an email is detected as spam?

[tex]p = 0.99*0.5 + 0.05*0.5 = 0.52[/tex]

0.52 = 52% probability that an email is detected as spam.

Answer:

YES, they are equal

Step-by-step explanation:

Given the expressions

h(x) = 2x – 3;j(x) = - 4x + 6; k(x) = – 2x + 3

h(x) + j(x) = 2x – 3 + (-4x + 6)

h(x) + j(x) =  2x - 3 -4x + 6

h(x) + j(x) = 2x - 4x -3 + 6

h(x) + j(x) = -2x + 3 = k(x)

This shows that h(x) + j(x) =  k(x)

9514 1404 393

Answer:

  3/4

Step-by-step explanation:

It might be easier to start by expressing the ratios with AD as the denominator.

  AD/AC = 2/1   ⇒   AC/AD = 1/2

  AD/AB = 3/1   ⇒   AB/AD = 1/3

From the latter, we have ...

  (AD -AB)/AD = 1 -1/3 = 2/3 = BD/AD

Then the desired ratio is ...

  AC/BD = (AC/AD)/(BD/AD) = (1/2)/(2/3) = (3/6)/(4/6)

  AC/BD = 3/4

Answer:

No.

Step-by-step explanation:

y/x has to be the same number no matter what except at point (0 0) which it must also include for it to be a direct variation.

*y=2x+3 is not a direct variation because you can not write it as y/x=k where k is some constant number. If we were y=2x, then yes since y/x=2.

*You could also take two points and see if they are proportional. That is, you can see if y2/x2 gives the same value as y1/x1 where (x1,y1) and (x2,y2) are points on the line y=2x+3. This must work for every pair of points on the linear relation except at x=0 (where you would or should have y=0 if it is directly proportional).

Let's try it out. If x=1, then y=2(1)+3=5.

5/1=5

If x=2, then y=2(2)+3=7

7/2=3.5

As you can see 5 doesn't equal 3.5.

*For it to be a direct variation, it also must contain the point (0,0) and be a diagonal line when graphed. It can also be written in form y=kx where k is a constant number. This fails two of the the things I mentioned. It doesn't contain point (0,0) because y=2(0)+3=3 not 0. It cannot be written in form y=kx because of the plus 3.

If it were y=2x, then the answer would be yes.

Answer:

  a. $16.90

  b. 23.5%

Step-by-step explanation:

a. After the two discounts, the original price is multiplied by ...

  (1 -10%)(1 -15%) = 0.90×0.85 = 0.765

Then the original price is found from ...

  $12.93 = 0.765 × original price

  original price = $12.93 / 0.765 ≈ $16.90

__

b. The effective discount from the original price is ...

  1 -0.765 = 0.235 = 23.5%

Answer:

Step-by-step explanation:

Let AC = x

AB - AC = 4 cm

AB = 4 +x  ----------------(I)

Pythagorean theorem

AB² + AC² =BC²

(4 + x)² + x² = 9²

Use the identity (a + b)² = a² + 2ab + b² where a = 4 & b = x

4² +2*4*x  +x² + x²= 81

16 + 8x + 2x² = 81

2x² + 8x + 16 - 81 = 0

2x² + 8x - 65= 0

a = 2 ; b = 8 ; c = -65

D = b² - 4ac

   = 8² - 4*2*(-65)

  = 64 +  520

D = 584

√D = √584 = 24.16

[tex]x=\frac{-b+\sqrt{D}}{2a} \ or \ x =\frac{-b-\sqrt{D}}{2a}\\\\x= \frac{-8+24.16}{2*2} \ or \ x = \frac{-8-24.6}{2*2}[/tex]   {Ignore this as it is negative.}

x = 16.16/4

x = 4.04

AC = 4.04 Cm

AB = 4 + 4.04 = 8.04 cm

Area of triangle ABC = [tex]\frac{1}{2}* base * height[/tex]

                                   [tex]=\frac{1}{2}*4.04 *8.04\\\\= 2.02 * 8.04[/tex]

                                   = 16.24 sq.cm

Answer:

22=4

Step-by-step explanation:

0977-=ytb

Answer:

64

Step-by-step explanation:

[tex]\sqrt[3]{512} = 8\\8x8 = 64[/tex]

Answer:

H0 : μN ≤ μD

H1 : μN > μD

Right tailed

Test statistic = 1.33

Pvalue = 0.097

Fail to reject the Null

Step-by-step explanation:

H0 : μN ≤ μD

H1 : μN > μD

The test is right tailed ; culled from the direction of the greater than sign ">"

Night students :

n1 =30 x1= 3.34 s1 = 0.02

Day students:

n2 = 30 x2 = 3.32 s2 = 0.08

The test statistic :

(x1 - x2) / √(s1²/n1) + (s2²/n2)

T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)

T = 0.02 / 0.0150554

Test statistic = 1.328

Using the conservative approach ;

df = Smaller of n1 - 1 or n2 - 1

df = 30 - 1 = 29

Pvalue(1.328, 29) = 0.097

At α = 0.10

Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student