Chemistry College

I need help please!!

Answers

Answer 1

A. The units remaining after the conversion is mi

B. The units remaining after the conversion is atoms

A. How do I determine the units remaining?

From the question given above, the following expression was obtained:

in × ft/in × mi/ ft

To know the unit that will remain, we shall simplify the expression. Details below:

in × (ft/in) × (mi/ ft)

Cancel out in

ft × (mi/ ft)

Cancel out ft

Thus, the unit remaining is mi

B. How do I determine the units remaining?

From the question given above, the following expression was obtained:

g × mol/g × atoms/ mol

To know the unit that will remain, we shall simplify the expression. Details below:

g × (mol/g) × (atoms/ mol)

Cancel out g

mol × (atoms/ mol)

Cancel out mol

atoms

Thus, the unit remaining is atoms

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Related Questions

Identify the options below that are results of decreasing the temperature of a system that includes an exothermic reaction in the forward direction. A. The concentration of the reactants increases. B. The concentration of the products increases. C. The equilibrium constant decreases. D. The equilibrium shifts toward the products.

Answers

If the reaction is exothermic as described, a rise in temperature will thus trigger the opposite reaction, which will result in a decrease in the amount of the products and an increase in the number of reactants. The reverse outcome will occur if the temperature is lowered.

B. The concentration of the products increases.

A reaction is defined as exothermic if the overall standard enthalpy change (H) is negative. Exothermic processes typically produce heat. Exergonic reaction, which the IUPAC defines as "... a reaction for which the overall standard Gibbs energy change G is negative," is frequently mistaken with the phrase.

Because "H" contributes significantly to "G," a strongly exothermic process is typically also exergonic. Exothermic and exergonic chemical reactions make up the majority of the impressive demonstrations in schools.

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Find the volume, in mL, of an object whose density is 400 g/mL and has a mass of 600
mg.

Answers

The volume of the object is 1.5ml.

What is the volume of an object?

This refers to the space occupied within the boundaries of an object in three-dimensional space. It is also called the capacity of the object.

In the question:

ρ = 400 g/mL

m = 600 mg

v = ?

Formular for calculating density ρ:

ρ = m/v

Where,

ρ= Density of the object

m= Mass of the object

v = volume of the object

Were are given the values of density and mass in the question. We are to calculate the volume.

Makinig v subject of the formular we have:

v = m/ρ

v = 600 mg

400 g/mL

v = 1.5ml

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