I need help very badly. thanks​

Explanation:

For regular tessellations, the types of polygons that we can use are

We can only pick one of those shapes.

Shapes like regular octagons or pentagons will not work on their own because there is gap or overlap if we tried to glue them together. Think of tiles on the floor. There cannot be any gap or overlap when forming a tessellation.

If you wanted to use octagons to tessellate the plane, then you'd need squares to fill in the gaps. At this point, it's not considered a regular tessellation.

Answer:

1.75 × 10⁶

Step-by-step explanation:

7,000,000 ÷ 4 = 1750000

Which is 1.75 × 10⁶ in standard form

Answer:

I suck at math but take a picture and put it in the app called "Math-way" or "Photo-math" I'm a senior and still use these

Answer:

a. [tex]\frac{4\pi }{3}[/tex]

b. 240

Step-by-step explanation:

all you have to do to find a coterminal angle is to add or subtract 360 or [tex]2\pi[/tex] from the angle, so:

a. [tex]\frac{10\pi }{3} -2\pi =\frac{4\pi }{3}[/tex]

b. -120 + 360 = 240

Answer:

8/7 min  = [tex]1 \frac{1}{7} minutes[/tex]

Step-by-step explanation:

A rate 2 2/3 = 8/3 min per tank

B rate 2 min per tank

thus:

A rate = 3/8 tank per min

B rate = 1/2 tank per min

A+ B =  3/8 + 4/8 = 7/8 tank per min

7/8 x = 1

x = 8/7 min

Answer:

Step-by-step explanation:

Firstly we draw the circle marking its center point.

Then we choose an arbitrary point anywhere on the circumference of the circle.

Then we draw a line connecting the point and the center of the circle.

Now, we mark the next vertex of polygon on the circumference of the circle by measuring an angle with respect to the first line drawn from the center of the circle.

The measurement of the angle is based upon no. of vertices (=no. of side) of the polygon. We divide the full round angle 360° with the no. of vertices and obtain the angle between the each consecutive vertices from the center of the circle since the polygons are regular.

Polygons with the no. of vertices is as follows:

square -- 4

pentagon -- 5

hexagon -- 6

octagon -- 8

decagon -- 10

For decagon the central angle between each consecutive vertex:

[tex]\angle_{10}=\frac{360}{10}[/tex]

[tex]\angle_{10}=36^o[/tex]

For octagon the central angle between each consecutive vertex:

[tex]\angle_{8}=\frac{360}{8}[/tex]

[tex]\angle_{8}=45^o[/tex]

For hexagon the central angle between each consecutive vertex:

[tex]\angle_{6}=\frac{360}{6}[/tex]

[tex]\angle_{6}=60^o[/tex]

For pentagon the central angle between each consecutive vertex:

[tex]\angle_{5}=\frac{360}{5}[/tex]

[tex]\angle_{5}=72^o[/tex]

For square the central angle between each consecutive vertex:

[tex]\angle_{4}=\frac{360}{4}[/tex]

[tex]\angle_{4}=90^o[/tex]

The internal angle of a regular polygon is calculated as:

[tex]\angle=180-\frac{360}{n}[/tex]              where, n = number of sides (=vertices)

for example, in case of hexagon interior angle is:

[tex]\angle=180-\frac{360}{6}[/tex]

[tex]\angle=180-60[/tex]

[tex]\angle=60^o[/tex]

As the no. of sides increase the interior angles widen up and their values increase, which the central angle between the consecutive vertices decrease.

Answer:

The other person is definitely getting Brainlest thank you so much for your answer. YOU ARE A LIFE SAVER. :D XD.

Please give him/her Branliest ;D

Answer:

Step-by-step explanation:

The easiest way to solve this is with calculus, believe it or not. The position function is

[tex]s(t)=-16t^2+64t[/tex]. The first derivative of this is the velocity function:

v(t) = -32t + 64. From physics, we know that at the max height of an object's path, the velocity is equal to 0, so setting this velocity equation equal to 0 and solving for time, will tell us the time it took to get to the max height (which we don't know yet, but we will in a bit):

0 = -32t + 64 and

-64 = -32t so

t = 2 seconds. It takes 2 seconds to reach a max height. Plugging that 2 in for t in the position function will tell you the max height that corresponds to this time:

[tex]s(2)=-16(2)^2+64(2)[/tex] and

s(2) = 64 feet.

So the max height is 64 feet and it is reached at 2 seconds after launching.

Also from physics we know that at halfway through a parabolic path, which is also the max height, we are halfway through time-wise as well. That means that if it takes 2 seconds to reach the max height from the ground, it will take another 2 seconds to fall to the ground.

So the total time the rocket is in the air is 4 seconds: 2 seconds to reach the max height and another 2 to fall back down.

Answer:

Step-by-step explanation:

Answer:

1.2055 × 10⁴

Step-by-step explanation:

10,000 + 2,000 + 50 + 5

= 12,055

Writing 12,055 in standard form

The first digit in standard form should be between 1 and 10

Therefore, the first digit in 12,055 is 1 then point other numbers

As in 1.2055

There are 4 digits after the decimal point.

So we have 10⁴

12,055 = 1.2055 × 10⁴

Check:

1.2055 × 10⁴

= 1.2055 × 10,000

= 12,055

Answer:

Step-by-step explanation:

[tex]\frac{5}{10}*\frac{-4}{12}-\frac{1}{3}-\frac{4}{12}*\frac{2}{10}\\\\=\frac{1}{2}*\frac{-1}{3}-\frac{1}{3}-\frac{1}{3}*\frac{1}{5}\\\\= \frac{-1}{3}[\frac{1}{2}+1+\frac{1}{5}]\\\\=\frac{-1}{3}[\frac{1*5}{2*5}]+\frac{1*10}{1*10}+\frac{1*2}{5*2}]\\\\=\frac{-1}{3}[\frac{5}{10}+\frac{10}{10}+\frac{2}{10}]\\\\=\frac{-1}{3}[\frac{5+10+2}{10}]\\\\=\frac{-1}{3}*\frac{17}{10}\\\\=\frac{-17}{30}[/tex]

Answer:

1 grapefruit cost $0.50 and 1 apple cost $0.53

Step-by-step explanation:

To find the unit cost of 1 fruit, divide the cost by the amount of fruit.

Grapefruit = 3.00 ÷ 6 = $0.50

Apple = 2.65 ÷ 5 = $0.53

Answer:

Lines  C and D

Step-by-step explanation:

For a pair of lines to be perpendicular ,

    the product of their slope must be - 1 .

Slope of A:

[tex]2x - 3y = 6\\\\-3y = -2x + 6\\\\y = \frac{-2x}{-3} + \frac{6}{-3}\\\\[/tex]

[tex]y = \frac{2}{3}x - 2\\\\slope_A = \frac{2}{3}[/tex]

Slope of B:

[tex]3x - 2y = - 9\\\\-2y = - 3x - 9\\\\y = \frac{-3x}{-2} - \frac{9}{-2}\\\\y =\frac{3x}{2} + \frac{9}{2}\\\\slope_B = \frac{3}{2}[/tex]

Slope of C:

[tex]y = - \frac{3}{2}x - 5 \\\\slope_C = -\frac{3}{2}[/tex]

Slope of D:

[tex]y = \frac{2}{3}x + 2\\\\slope_D = \frac{2}{3}[/tex]

Product of the slopes = - 1

[tex]slope_A \times slope_B = \frac{2}{3} \times \frac{3}{2} = 1 \neq - 1 \\\\Therefore, not\ perpendicular.\\\\Slope_B \times slope_C = \frac{3}{2} \times \frac{-3}{2} = \frac{-9}{4} \neq -1\\\\Therefore , not \ perpendiucalr.\\\\Slope_C \times slope_D = -\frac{3}{2} \times \frac{2}{3} = - 1\\\\Therefore , perpendicular\\\\\\Slope_A \times slope_D = \frac{2}{3} \times \frac{2}{3} = \frac{4}{9} \neq 1\\\\therefore , not \ perpendicular.[/tex]

Given:

The function is:

[tex]f(x)=-2x^2+7x+4[/tex]

To find:

Express the quadratic equation in the form of [tex]f(x)=a(x-h)^2+k[/tex], then state the minimum or maximum value,axis of symmetry and minimum or maximum point.

Solution:

The vertex form of a quadratic function is:

[tex]f(x)=a(x-h)^2+k[/tex]              ...(i)

Where, a is a constant, (h,k) is the vertex and x=h is the axis of symmetry.

We have,

[tex]f(x)=-2x^2+7x+4[/tex]

It can be written as:

[tex]f(x)=-2\left(x^2-3.5x\right)+4[/tex]

Adding and subtracting square of half of coefficient of x inside the parenthesis, we get

[tex]f(x)=-2\left(x^2-3.5x+(\dfrac{3.5}{2})^2-(\dfrac{3.5}{2})^2\right)+4[/tex]

[tex]f(x)=-2\left(x^2-3.5x+(1.75)^2\right)-2\left(-(1.75)^2\right)+4[/tex]

[tex]f(x)=-2\left(x-1.75\right)^2+2(3.0625)+4[/tex]

[tex]f(x)=-2\left(x-1.75\right)^2+6.125+4[/tex]

[tex]f(x)=-2\left(x-1.75\right)^2+10.125[/tex]                ...(ii)

On comparing (i) and (ii), we get

[tex]a=-2,h=1.75,k=10.125[/tex]

Here, a is negative, the given function represents a downward parabola and its vertex is the point of maxima.

Maximum value = 10.125

Axis of symmetry : [tex]x=1.75[/tex]

Maximum point = (1.75,10.125)

Therefore, the vertex form of the given function is [tex]f(x)=-2\left(x-1.75\right)^2+10.125[/tex], the maximum value is 10.125, the axis of symmetry is [tex]x=1.75[/tex] and the maximum point is (1.75,10.125).

[tex]\displaystyle\ \boxed{a^m\cdot a^n=a^{m+n}}\\\\4^{3c} \cdot 4^{5c}=\frac{4}{16} \\\\4^{3c+5c}=4^{-1}\\\\8c=-1\\\\c=-\frac{1}8}[/tex]

Answer:

X=(d - 2)/4 is the answer of your question

Answer:i don’t know

Step-by-step explanation:i don’t know

Given:

Modeling: Slope intercept equation of a line

To find:

The slope intercept equation of a line.

Solution:

The slope intercept equation of a line is defined as:

[tex]y=mx+b[/tex]

Where, m is the slope and b is the y-intercept.

It means the line intersects the y-axis at (0,b).

For example: The slope of a line is 2 and its y-intercept is 1, then the slope intercept of the line is:

[tex]y=2x+1[/tex]

Therefore, the slope intercept form of a line is [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept.

3 and 4

Step-by-step explanation:

y=5x

y=5(0)

y=0

y=5x

y=5(10)

y=50

y=5x

y=5(51)

y=255

y=5x

y=5(400)

y=2000

Answer:

-4

Step-by-step explanation:

bc it is

.......................

Answer:

it must be 85 (approx.)

Step-by-step explanation:

Answer:

Hey Mate! Here's your answer.

Step-by-step explanation:

One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25

One packet of biscuits requires 1 \times \frac{2}{3}1×32

One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35

Total ingradiants for one packet of biscuits =

Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625

Then, total quantity of both ingredients used in 10 such packets of biscuits =

Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32

Hope it helped you!

Answer:

Step-by-step explanation:

First we'll simplify this using the Sum Identity for sin(x + y) where [tex]x=\frac{3\pi}{2}[/tex] and y = x. Notice we have 2 of those so we simplify first into

[tex]2sin(\frac{3\pi}{2}+x)=-2[/tex] and divide away the 2 on the left to get

[tex]sin(\frac{3\pi}{2}+x)=-1[/tex] and now we'll expand:

[tex]sin\frac{3\pi}{2}cosx+cos\frac{3\pi}{2}sinx=-1[/tex] and go to your unit circle to find the sin and cos of [tex]\frac{3\pi}{2}[/tex] and fill in where they go:

(-1cosx + 0sinx) = -1 which simplifies to

-1cosx = -1 so

cosx = 1 and

x = 0 or 2π, depending upon what your interval is.

Answer:

(3x + 7y)^2 =  9 x^2 + 42xy + 49y^2

Step-by-step explanation:

Step-by-step explanation:

let wrong answers be y

let right answer be x

3x-1y=79

find another equation

OPTION A is the correct answer.

Answer:

A

Step-by-step explanation:

Thanks to the given angle, we can say that the triangle formed by tracing another height has two congruent legs

So

x = 9 + 7 = 16

y = √2 * 9^2 = 9√2

Answer:

A

Step-by-step explanation:

Completing the rectangle formed by legs 9 and 7 , gives us a right triangle on the left.

Using the sine ratio and the exact value sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{9}{y}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

y = 9[tex]\sqrt{2}[/tex]

Using the tan ratio in the right triangle and the value tan45° = 1 , then

tan45° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{9}{adj}[/tex] = 1

adj = 9

Then

x = 9 + 7 = 16

Answer:

Null set

Step-by-step explanation:

Odd(0)

Even (E)

Prime (P)

Answer:

Its A since the other person didnt say it

Step-by-step explanation:

Answer:

Sila put a wrong number in her calculator when multiplying the numerators.

Step-by-step explanation:

StartFraction 12 kilometers Over 1 EndFraction times StartFraction 0.62 miles Over 1 kilometer EndFraction times StartFraction 5280 feet Over 1 mile EndFraction = 392,832 feet

Correct calculation:

12 km/ 1 * 0.6miles / 1km * 5280 feet / 1 mile

= (12km * 0.62 miles * 5280 feet) / (1 * 1 km * 1 mile)

= 39,283.2 feet

Sila's calculation:

12 km/ 1 * 0.6miles / 1km * 5280 feet / 1 mile

= 392,832 feet

Answer:

[tex]2x - 35273 = 5361925 \\ 2x = 5361925 + 35273 \\ 2x = 5397198 \\ x = \frac{5397198}{2} \\ x = 2698599[/tex]

[tex]\displaystyle\ 2x-35273=5361925\\\\2x=53\underline{61925}+\underline{35273} \\\\2x=5397198\\\\\\x=\frac{5397198}{2} =2698599\\\\\underline{x=2698599\qquad }\\\\2\cdot 2698599-35273=5361925\\\\5397198-35273=5361925\\\\5361925=5361925[/tex]