Answer:
The pH of the resulting solution is 12.9.
Explanation:
Molarity of the HCl solution = 0.20 M
Volume of the HCl solution = 36.0 mL
[tex]1 mL = 0.001 L\\36.0 mL=36.0\times 0.001 L=0.0360 L[/tex]
Moles of HCl = n
[tex]0.20 M=\frac{n}{0.0360 L}\\n=0.20 M\times 0.0360 L=0.0072 mol[/tex]
Molarity of NaOH solution = 0.40 M
Volume of the NaOH solution = 30.0 mL
[tex]1 mL = 0.001 L\\30.0 mL=30.0\times 0.001 L=0.0300 L[/tex]
Moles of NaOH = n'
[tex]0.40 M=\frac{n'}{0.0300 L}\\n'=0.40 M\times 0.0300 L=0.012 mol[/tex]
[tex]HCl(aq)+NaOH(aq)\rightarrow NaCl(aq)+H_2O(l)[/tex]
According to the reaction, 1 mole of HCl reacts with 1 mole of NaOH then 0.0072 moles of HCl will react with :
[tex]=\frac{1}{1}\times 0.0072 mol=0.0072\text{ mol of NaOH}[/tex]
Mole of NaOH remained unreacted = 0.012 mol - 0.0072 mol = 0.048 mol
[tex]NaOH (aq)\rightarrow Na^+(aq)+OH^-(aq)[/tex]
Moles of Hydroxide ions remained unreacted = 0.0048 mol
These unreacted moles of hydroxide ion will be responsible for the pH of the final solution
Moles of hydroxide ions remained unreacted = 0.048 mol
Volume of the final solution = 36.0 mL + 30.0 mL = 66.0 mL
[tex]1 mL = 0.001 L\\66.0 mL=66.0\times 0.001 L=0.0660 L[/tex]
Molarity of the remained hydroxide ions in final solution:
[tex][OH^-]=\frac{0.0048 mol}{0.0660 L}=0.073 M[/tex]
The pOH of the final solution :
[tex]pOH=-\log[OH^-]\\pOH=-\log[0.073 M]=1.1\\14 = pH + pOH\\pH = 14 - pOH = 14 - 1.1 = 12.9[/tex]
The pH of the resulting solution is 12.9.
Answer:
pH = 1.14
Explanation:
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
From the above balanced reaction we observe that molar ratio for NaOH and HCl is equal.
Therefore at an equivalent point where the complete neutralization will occur, their respective concentrations are:
HCl being a strong acid:
[tex][H^+]=[HCl][/tex]
NaOH being a strong base:
[tex][OH^-]=[NaOH][/tex]
gram equivalent of HCl = 0.2 × 36 /1000 = 7.2/1000
gram equivalent of NaOH = 0.4 × 30 /1000 = 12/1000
gram equivalent of HCl remains after mixing = 4.8 /1000
Volume of mixture = 36 + 30 = 66 mL = 66/1000 litre
Normality of HCl in mixture = 4.8/1000 ÷ 66/1000 = 0.073
ion concentration = 0.073
pH = - log 0.073
pH = 1.14
Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is ________ M.
A) 0.0735
B) 0.0762
C) 0.0980
D) 0.0709
E) 0.00253
Answer: The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.
Explanation:
Given: Concentration of hydrogen fluoride = 0.126 M
Concentration of fluoride ions = 0.1 M
Volume of HCl = 9.0 mL
Concentration of HCl = 0.01 M
Volume of HCl = 25.0 mL
Moles of [tex]F^{-}[/tex] ions are calculated as follows.
[tex]Moles of F^{-} = molarity \times volume\\= 0.1 M \times 0.025 L\\= 0.0025 mol[/tex]
Moles of HF are as follows.
[tex]Moles of HF = Molarity \times Volume\\= 0.126 M \times 0.025 L\\= 0.00315 mol[/tex]
Moles of HCl are as follows.
[tex]Moles of HCl = Molarity \times volume\\= 0.01 M \times 0.009 L\\= 0.00009 mol[/tex]
Now, reaction equation with initial and final moles will be as follows.
[tex]H^{+} + F^{-} \rightarrow HF[/tex]
Initial: 0.00009 0.0025 0.00315
Equilibrium: (0.0025 - 0.00009) (0.00315 + 0.00009)
= 0.00241 = 0.00324
Total volume = (9.00 mL + 25.0 mL) = 34.0 mL = 0.034 L
Hence, concentration of fluoride ions is calculated as follows.
[tex]Concentration = \frac{moles}{volume}\\= \frac{0.00241 mol}{0.034 L}\\= 0.0709 M[/tex]
Thus, we can conclude that concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.
time is direct propotinally to rate of chemical reaction .explain if time is negretted and temperature remain costant?
Answer:
the constant temperature will be 12 .F bec in places it is cold
The compound chromium(II) chloride is a strong electrolyte. Write the transformation that occurs when solid chromium(II) chloride dissolves in water. Be sure to specify states such as (aq) or (s).
Answer:
CrCl₂(s) ⇒ Cr²⁺(aq) + 2 Cl⁻(aq)
Explanation:
Chromium (II) chloride is a strong electrolyte, that is, when dissolved in water, it completely dissociates into the ions. The cation is chromium (II) and the anion is chloride. The balanced equation for the solution of chromium (II) chloride is:
CrCl₂(s) ⇒ Cr²⁺(aq) + 2 Cl⁻(aq)
Is sucrose classified as aldose or ketose?
Answer:
Because sucrose is a complex disaccharide, it is not classified as either an aldose or a ketone. Instead, it is a compound that contains both. glucose is aldose sugar and fructose is a ketose sugar.
what is Lewis acid and Lewis base? give examples
Explanation:
example is copper iron...........
300g de acido comercial se disuelve en agua destilada contenidos en un cono, cuyo radio es de 0.005Km y 300cm de altura, si la densidades de 1.2g/m3 ¿Cuál es la concentración expresada en %m/m?
Answer:
97.0%m/m es la concentración de la solución
Explanation:
El porcentaje masa/masa (%m/m) se define como 100 veces el radio entre la masa de soluto (300g de HCl) y la masa de la solución. Para hallar la masa de la solución debemos hallar la masa del agua (Solvente) haciendo uso de la ecuación del volumen de un cono. Con el volumen del cono podemos hallar la masa del agua haciendo uso de la densidad, así:
Volumen:
Volumen Cono = π*r²*h / 3
Donde r es el radio = 0.300m
h la altura = 5m
Volumen = π*(5m)²*0.300m / 3
7.85m³
Masa Agua:
7.85m³ * (1.2g / m³) = 9.42g Agua
Masa solución:
300g HCl + 9.42g Agua = 309.42g Solución
%m/m:
300g HCl / 309.42g * 100 =
97.0%m/m es la concentración de la solucióncho một thực phẩm có độ ẩm tương đối là 81 hỏi hoạt độ nước trong thực phẩm đó là bao nhiêu
Explanation:
For a food with a relative humidity of 81, what is the water activity in the food?
Water activity in a food = relative humidity / 100
Substitute the given values in this formula to get water activity:
Water activity in a food = 81 / 100
Hence, water activity =0.81
which of these is not a gas? A. hydrogen B. gravity C. Oxygen D. heluim
Answer:
B. Gravity
Explanation:
Gravity is a force, not a gas :)
Answer:
B: Gravity
Explanation:
gravity pulls on the gad
What is the difference between acids and strong acids?
a. Strong acids produce all of their H30+ ions
b. Strong acids release all of their H30+ ions
c. Strong acids produce all of their OH- ions
d.Strong acids release all of their OH ions
Answer:
A and b are the both the answers
The mass of a crucible and lid is 23.422 g. After adding a sample of hydrate compound the crucible, cover, and contents weigh 24.746 g. After heating with a Bunsen burner to remove the water of hydration, the mass of the crucible, cover, and sample was 24.213 g. How many moles of water did the hydrate compound contain
Answer:
0.030 mole
Explanation:
Mass of crucible + lid = 23.422 g
Mass of crucible + lid + compound = 24.746 g
Mass of crucible + lid + compound - water = 24.213
Mass of water = Mass of crucible + lid + compound + heat
= 24.746 - 24.213
= 0.533 g
Mole of water in the hydrated compound = mass of water in the compound/molar mass of water
= 0.533/18
= 0.0296 mole = 0.030 mole
Combustion of 5.024 mg of coniine yields 13.90 mg CO2 and 6.048 mg of H2O. What is the empirical formula for coniine, listing the elements in the order C, H, N?
Answer:
C8H17N
Explanation:
Number of moles of c
13.90 × 10^-3/44 g/mol × 1 = 0.000316 moles
Mass of C= 0.000316 moles × 12 = 0.00379 g
Number of moles of H
6.048 × 10^-3/18 × 2 = 0.000672 moles
Mass of H
0.000672 moles × 1 = 0.000672 g
Mass of N
0.005024 - [0.00379 g + 0.000672 g]
= 0.000562 g
Number of moles of N
0.000562 g/14 = 0.00004 moles
Divide through by the lowest ratio;
C= 0.000316/0.00004, H= 0.000672 /0.00004, N= 0.00004/0.00004
C= 8, H = 17, N = 1
Hence the empirical formula is;
C8H17N
If you reacted 88.9 g of ammonia with excess oxygen, what mass of water would you expect to make? You will need to balance the equation first.
NH3(g) + O2(g) -> NO(g) + H2O(g)
Explanation:
here's the answer to your question
What is it?? plzzzz help
write down any two test for the CH2=CH2[ethene]
Answer:
a) Linear polymerization
b) cyclic polymerization
When do epa’s refrigerant management regulations exempt refrigerant from the venting prohibition
The Environmental Protection Agency (EPA) refrigerant management regulations would exempt any refrigerant from venting problem when it determines that the refrigerant in an appliance do not pose a threat to the environment (surrounding) if released.
A refrigerant can be defined as any chemical substance that undergoes a phase change (liquid and gas) so as to enable the cooling and freezing of materials. They are typically used in air conditioners, refrigerators, water dispensers, etc.
In the United States of America, the Environmental Protection Agency (EPA) is a governmental agency which was established by U.S Congress and it is saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, degradation, pesticide use, contamination, and hazardous waste spills. Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act.
Simply stated, the Environmental Protection Agency (EPA) is the governmental agency set up to ensure that various industries, factories and people comply with laws and regulations concerning the environment.
In conclusion, appliances such as a refrigerator, air conditioner (AC), etc., whose refrigerants do not pose a threat (potentially cause damage) to the environment if released are typically exempted by the EPA's refrigerant management regulations.
Find more information: https://brainly.com/question/23968117
A gaseous mixture containing 7.00 moles of nitrogen, 2.50 moles of oxygen, and 0.500 mole of helium exerts a total pressure of 0.900 atm. What is the partial pressure of the nitrogen?
Answer:
Partial Pressure = 0.630atm
Explanation:
The total pressure of a mixture of gases is equal to the partial pressure of those gases. The partial pressure of a gas is defined as:
Partial pressure = Mole Fraction * Total pressure
The mole fraction of a gas is the ratio between the moles of the gas and the total moles.
To solve this question we need to find the mole fraction of nitrogen to find its partial pressure:
Mole Fraction nitrogen:
7.00 moles Nitrogen / (7.00moles N2 + 2.50moles O2 + 0.500moles He) = 0.700 = Mole fraction.
Partial Pressure = 0.700* 0.900atm
Partial Pressure = 0.630atmThis is the chemical formula for zinc bromate: . Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.
Answer:
30%
Explanation:
This is the chemical formula for zinc bromate: Zn(BrO₃)₂. Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.
Step 1: Determine the mass of 1 mole of Zn(BrO₃)₂
M(Zn(BrO₃)₂) = 1 × M(Zn) + 2 × M(Br) + 6 × M(O)
M(Zn(BrO₃)₂) = 1 × 65.38 g/mol + 2 × 79.90 g/mol + 6 × 16.00 g/mol
M(Zn(BrO₃)₂) = 321.18 g/mol
Step 2: Determine the mass of oxygen in 1 mole of Zn(BrO₃)₂
There are 6 moles of atoms of oxygen in 1 mole of Zn(BrO₃)₂.
6 × m(O) = 6 × 16.00 g = 96.00 g
Step 3: Calculate the mass percent of oxygen in Zn(BrO₃)₂
%O = mO/mZn(BrO₃)₂ × 100%
%O = 96.00 g/321.18 g × 100% ≈ 30%
When you burn a birthday candle, you may wonder whether the fire you see is matter. The
flame consists of hot, glowing gases, such as oxygen, carbon dioxide, water vapor, and
parts of the candle that have been vaporized. The heat and light given off are forms of
energy. The smoke contains ash and unburned particles.
a. From the above description of a candle flame, list at least three things that are matter and
three things that are not mattel. (6 points)
Matter
Not Matter
Answer:
matter
1. Candle. not matter
1. light
2. Unburned Particles
2. heat
3. Ash
3. energy
Explanation:
1.The candle is experiencing a solid phase into a gas phase because the heat given off causes smoke.
2. Chemical Potential Energy to Heat EnergyThe candle has Chemical Potential Energy then when it gets lit by the flame heat energy is released.
Determine the type of alcohol corresponding to each given description or name. 1-pentanol 3-ethyl-3-pentanol 2-hexanol An alcohol with two other carbons attached to the carbon with the hydroxyl group_____.An alcohol with one other carbon attached to the carbon with the hydroxyl group____.An alcohol with three other carbons attached to the carbon with the hydroxyl group____.
Answer:
1). 1-pentanol - Primary
2). 3-ethyl-3-pentanol - Tertiary
3). 2-hexanol - Secondary
4). Alcohol with two other carbons attached to the carbon with the hydroxyl group - Secondary
5). Alcohol with one other carbon attached to the carbon with the hydroxyl group - Primary
6). Alcohol with three other carbons attached to the carbon with the hydroxyl group - Tertiary
Explanation:
The distinct types of alcohol have been matched with the categories above as per their descriptions provided. In chemistry, alcohols have been categorized into three different categories namely primary, secondary, and tertiary.
In the primary type, those alcohols are involved in which there is an association of hydroxyl group to a primary atom of carbon along with a minimum of two atoms of hydrogen. Example; ethanol.
In the secondary type, the alcohols have an association of carbon atoms to hydroxyl with a single atom of hydrogen and has a formula of '-CHROH.' Example: 2 - propanol.
In the tertiary alcohols, here the association is between the hydroxyl group with the carbon atom that is saturated and possessing 3 atoms of carbon associated with it. It has a formula of '-CR2OH.' Example: 3-ethyl-3-pentanol, -tert -butyl alcohol, etc.
Question 2 10
10 Points
Which of the following chemical equations depicts a balanced chemical equation?
O A. AgNO, Kcro > KNO, Agro,
OB. AgNO3 + Kycro, » 2K NO; + Agro,
C.3AgNO3 + 2K,Cro--> 3KNO3 + 249900,
D. 2AgNO, K Cro-> 2KNO; 1Cro,
Resol Selection
Answer:
2AgNO, K Cro-> 2KNO; 1Cro,
Help naming this plzzzzzzzzzzzzz
Answer:
A. 3-chloro-1-methylcyclobutane.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to infer that the name of this compound is A. 3-chloro-1-methylcyclobutane because of the fact that the parent chain is a cyclobutane which starts by the methyl radical as it has the priority over the chlorine radical which is actually named first at the third carbon (clockwise).
Therefore the name is given in A, accordingly to the IUPAC rules of nomenclature.
Regards!
Part A
If the theoretical yield of a reaction is 23.5 g and the actual yield is 14.8 g, what is the percent yield?
Answer:
[tex]\boxed {\boxed {\sf 63.0 \%}}[/tex]
Explanation:
The percent yield is the ratio of the actual yield to the theoretical yield.
[tex]percent \ yield = \frac{actual \ yield}{theoretical \ yield} * 100[/tex]
The actual yield is the amount obtained from performing a chemical reaction. For this problem, it is 14.8 grams. The theoretical yield is the potential amount from performing a chemical reaction at maximum performance. For this problem, it is 23.5 grams.We can substitute the known values into the formula.
[tex]percent \ yield= \frac{ 14.8 \ g}{23.5 \ g}*100[/tex]
Divide.
[tex]percent \ yield = 0.629787234043*100[/tex]
Multiply.
[tex]percent \ yield = 62.9787234043[/tex]
The original measurements for the theoretical and actual yields have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place.
The 7 to the right, in the hundredths place, tells us to round the 9 up to a 0. Since we rounded up to 0, we have to move to the next place to the left and round the 2 up to a 3.
[tex]percent \ yield \approx 63.0[/tex]
The percent yield is approximately 63.0 percent.
The smallest atoms can themselves exhibit quantum-mechanical behavior. Calculate the de Broglie wavelength (in picometers) of a hydrogen atom traveling at 490 m/s. Express your answer using three significant figures.
Answer:
810 pm
Explanation:
Step 1: Given and required data
Velocity of the atom (v): 490 m/sMass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kgPlanck's constant (h): 6.63 × 10⁻³⁴ J.sStep 2: Calculate the de Broglie wavelength of the hydrogen atom
We will use de Broglie's equation.
λ = h / m × v
λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m
Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers
We will use the conversion factor 1 m = 10¹² pm.
8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm
The number of moles of H in 5 moles of glucose (C6H1206) is
Answer:
60 mols hydrogen
Explanation:
1 mol of glucose contains 12 mols of Hydrogen
5 mols of glucose contains 12 * 5 = 60 moles of hydrogen.
Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant figures in calculations. Please show work!
3) Convert 0.250 moles of aluminum sulfate to grams.
4) Convert 2.70 grams of ammonia to moles.
Answer:
0.000731 grams aluminium sulfate
46.0 mols ammonia
Explanation:
ALS = shorthand for aluminium sulfate which has a molar mass of 342.15 g/mol
[tex]ALS: \frac{0.250mols}{1} *\frac{1g}{342.15mols} = \frac{0.250g}{342.15}=0.0007307 g[/tex]
NH3 has a molar mass of 17.031 g/mol
[tex]NH3: \frac{2.70g}{1} *\frac{17.031mols}{1g} = \frac{0.250g}{342.15}=45.9837 mols[/tex]
Aluminium sulphate (AlS) whose molar mass is= [tex]\sf{ 342.15\dfrac{g}{mol} }[/tex]
we have to find the 0.250 moles of aluminum sulphate.
[tex]\implies AlS=\dfrac{1g}{342.15~mole}×0.250~mole \\\\\implies AlS=\dfrac{0.250}{342.15}\\\\\implies \dfrac{\frac{250}{1000}}{\frac{34215}{100}}\\\\\implies \dfrac{250}{1000}×\dfrac{100}{34215}\\\\=0.00073067\approx{0.0007307~g}[/tex]
[tex]\\\\\\[/tex]
Ammonia(NH3) whose molar mass is =[tex]\sf{17.031\dfrac{mol}{g} }[/tex]
We have to find 2.70 grams of ammonia
[tex]\implies NH_{3}=\dfrac{17.031~mol}{1g}×2.70g\\\\ 17.031×2.70\\\\\dfrac{17031}{1000}×\dfrac{270}{100}\\\\ \dfrac{4598370}{100000}\\\\=45.9837\approx{46~mole}[/tex]
An example of a molecular compound that obeys the octet rule in which all atoms have a zero formal charge is:
Answer:
[tex]NCl_3[/tex]
Explanation:
An octet rule is a thumb rule in the chemical sciences in which there is a natural tendency for an atom to prefer eight electrons in the valence shell of the atom. When there are less than eight electrons in the atom, they react with other atoms and form more stable compounds.
In the context, nitrogen trichloride, [tex]NCl_3[/tex], is an example of molecular compound which obeys the octet rule having a zero formal charges on each atom of the compound.
Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.
Answer:
Please find the complete solution in the attached file.
Explanation:
Hi,Valency of chlorine is 1. Why?Thank you
Answer:
The chlorine element belongs to group 17 because it has 7 valence electron . Its valency is 1 . It can gain one electron from any other atom to become stable. This means that it can never form a double or triple bond.
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Answer:
please translate in english
Calcium carbonate reacts with stomach acid (HCI) according to the following equation:
Caco, (s) + 2 HCl(aq) - CaCl, (aq) + CO2(g) + H20 (1)
Tums, an antacid, contains CaCo3. If Tums is added to 25.7 mL of a 0.738 M HCl solution, how many grams of Co, are produced?
Answer:
0.418 g of CO₂ will be produced
Explanation:
Equation of the reaction is given below:
CaCO₃ (s) + 2HCl (aq) ----> CaCl₂(aq) + CO₂ (g) + H₂O (l)
From the equation of reaction , 1 mole of CaCO₃ reacts with 2 molemolesmof HCl to produce 1 mole of CO₂
Number of moles of HCl in 25.7 ml of a 0.738 M solution of HCl is obtained using the formula below:
Number of moles = molarity × volume (Litres)
Number of moles of HCl = 0.738 M × 25.7 mL × 1 L/1000 mL = 0.0190 moles
Since the antacid, Tums will be excess, the limiting reactant is HCl
2 moles of HCl produces 1 mole of CO₂
0.0190 moles of HCl will produce 0.0190 moles ÷ 2 = 0.0095 molesof CO₂
Mass of 0.0095 moles of CO₂ = Numbe of moles × molar mass of CO₂
Molar mass of CO₂ = 44.0 g/mol
Mass of CO₂ produced = 0.00950 moles × 44.0 g/mol = 0.418 g of CO₂
Therefore, 0.418 g of CO₂ will be produced if Tums is added to 25.7 mL of a 0.738 M HCl solution
