If a car skids to a stop in 3.8s while undergoing a uniform acceleration of -9.55 m/s2, what is the car’s velocity?

Answer: type of force is friction

Explanation:

Answer:

When you rub your hands together, the action of scraping the

surface of your skin back and forth against each other causes

the molecules in your skin to move a little faster. The faster

that molecules move, the higher the temperature. So the

friction of rubbing your hands together makes them feel

warmer.

The force is friction. It's a force that opposes motion. It is present whenever two surfaces rub over each other, such as when you rub your hands together, or when you apply the brakes on a bike or in a car.

Explanation: I hope this helped you!

Answer:

ojuppuhp

Explanation:

A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.

A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.

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Answer:

a. as the distances increases , the gravitational force decreases

Answer:

Explanation:

Answer:

Explanation:

Ignoring air resistance the spring compression energy will equal the increase in potential energy from the maximum spring compression point to the top of the flight arc.

mgh = ½kx²

    h = kx²/2mg

    h = 180(0.03²) / (2(0.004)(9.8))

    h = 2.06632...

    h = 2.1 m

Answer:

hi there is that OK for the weekend of the following week as well

Explanation:

6th of March is fine for me

The minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

To determine the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop, we need to consider the maximum acceleration the pilot can withstand without losing consciousness.

Given:

Maximum acceleration without losing consciousness = 5.00g

Acceleration with g-suits to avoid blackout = 9.00g

First, we need to convert the speed of the F-15 from km/h to m/s:

Speed = 729 km/h = (729 * 1000) m/3600 s ≈ 202.5 m/s

Next, we'll calculate the acceleration experienced by the pilot in the circular loop. In a horizontal circular motion, the centripetal acceleration is given by:

Acceleration = ([tex]\rm Velocity^2[/tex]) / Radius

We can rearrange the equation to solve for the radius:

Radius = ([tex]\rm Velocity^2[/tex]) / Acceleration

Using the maximum acceleration of 5.00g, we convert it to [tex]\rm m/s^2[/tex]:

Maximum acceleration = 5.00g ≈ (5.00 * 9.8) [tex]\rm m/s^2[/tex] = 49 m/s^2

Now, we can calculate the minimum safe radius of curvature:

Radius = ([tex]\rm 202.5^2[/tex]) / 49 ≈ 838.1 meters

Therefore, the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

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what's your question?

Answer:

yes

Explanation:

because is pure ohmic risistance

The average speed of Lupert for the entire journey is 4.58 m/s.

The given parameters;

The average speed of Lupert is calculated as the ratio of the total distance to total time of motion;

[tex]average \ speed = \frac{(5.8 \times 8.9) \ + \ (7.9 \times 12.5) \ + \ (3.2 \times 4.7)}{8.9 \ + \ 3.7 \ + \ 12.5 \ + \ 6.3\ +\ 4.7} \\\\average \ speed = \frac{165.41}{36.1} \\\\average \ speed =4.58 \ m/s[/tex]

Thus, the average speed of Lupert for the entire journey is 4.58 m/s.

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This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

[tex]PV = nRT[/tex]

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

[tex]P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}[/tex]

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

[tex]P =\frac{F}{A}\\\\F=PA[/tex]

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

[tex]F=(7407.78\ KPa)(0.01\ m^2)\\[/tex]

F = 74.08 KN

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Answer:

As we are converting 220V AC into a 5V DC, first we need a step-down transformer to reduce such high voltage. Here we have used 9-0-9 1A step-down transformer, which convert 220V AC to 9V AC. In transformer there are primary and secondary coils which step up or step down the voltage according to the no of turn in the coils.

Selection of proper transformer is very important. Current rating depends upon the Current requirement of Load circuit (circuit which will use the generate DC). The voltage rating should be more than the required voltage. Means if we need 5V DC, transformer should at least have a rating of 7V, because voltage regulator IC 7805 at least need 2V more i.e. 7V to provide a 5V voltage.

For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

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The projectile launch equations allow to find the results for the questions about the movement of the ball are:

Given parameters

To find

Projectile launching is an application of kinematics, where on the x-axis there is no acceleration and on the y-axis is the gravity acceleration.

The range is the distance traveled for the same departure height, see attached.

.

          R =[tex]\frac{v_o^2 \ sin 2\theta}{g}[/tex]  

         [tex]v_o^2 = \frac{ g R}{sin 2 \theta }[/tex]  

Let's calculate.

          v₀² = [tex]\frac{9.8 \ 31.5}{sin \ (2 \ 40)}[/tex]9.8 31.5 / sin (2 40.0)

          [tex]v_o = \sqrt{313.46}[/tex]o = ra 313.46

          v₀ = 17.7 m / s

At the point of maximum height the vertical speed is zero.

          v² = v₀² - 2 g y

          0 = v₀² - 2g y

          y = [tex]\frac{v_o^2}{2g}[/tex]  

Let's calculate.

         y = [tex]\frac{17.7^2}{2 \ 9.8}[/tex]  

         y = 16 m

In conclusion, using the projectile launch equations we can find the results for the questions about the movement of the ball are:

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Answer:Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Explanation:

Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

I think the answer is d.right?

Answer:

ω = 3.1 rad/s

θ = 36° from vertical

Explanation:

I will ASSUME that the bob and string is acting as a pendulum.

Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.

At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.

F = mg + mω²R

F/m = g + ω²R

F/m - g = ω²R

ω = √((F/m - g)/R)

ω = √((3/0.220 - 9.8)/0.40)

ω = 3.09691...

ω = 3.1 rad/s

Potential energy will convert to kinetic energy

       mgh = ½mv²

             h = v²/2g

R - Rcosθ = v²/2g

R(1 - cosθ) = v²/2g

   1 - cosθ = v²/2gR

        cosθ = 1 - v²/2gR

        cosθ = 1 - (Rω)²/2gR

        cosθ = 1 - Rω²/2g

        cosθ = 1 - 0.40(3.1²)/(2(9.8))

        cosθ = 0.804267

              θ = 36.46045...

              θ = 36°

Answer:

116.66N

Explanation:

work done = force x distance

1400 = force x 12

1400 / 12 = force

116.66N = force

F = W / d

 =1400 / 12

 = 116.6 N

Work = Force × Distance. The SI unit for work is the joule (J), or Newton • metre (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

"Distance is defined to be the magnitude or size of displacement between two positions. Note that the distance between two positions is not the same as the distance travelled between them. Distance travelled is the total length of the path travelled between two positions. Distance travelled is not a vector."

"The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction."

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    I think I would most likely remember car, level, dog, and book. I think I would remember these words because car and level came first, I love dogs, and I like reading books. I can associate something with dogs and books so it helps me remember those words.

           [Visual encoding is when people remember things by pictures in their head, but I have aphantasia so I am honestly not the best person to answer this question

The definition of electric field, Coulomb's law and Newton's second law allow to find the results for the questions about the electric field and the oscillation of the test charge are:

  a) In the attachment you have the scheme of the system

  b) The point where the electric field is zero is: x = 0 m

  c) The angular velocity of the test charge is w = 0.5 rad / s

Given parameters

To find

    a) system scheme

    b) point where the field is zero

    c) The angular velocity of q₃

The electric field is the field produced by a distribution of electric charges at a point in space, it is a vector quantity, for the special case that the charges are in one dimension the sum of the field produced by a series of charges is reduced to the sum algebraic. The field produced by point charges is:

     E = [tex]k \sum \frac{q_i}{r_i^2}[/tex]  

Where E is the electric field, k is the Coulomb constant, q the value of the charge and r the distances from the charge to the point of interest.

a) In the attachment we can see a diagram of the system, the reference system, the location of the charges and the electric field vectors are shown.

b) From the diagram we see that each field is in the opposite direction, therefore the total field is:

          [tex]E_{total} = E_1 - E_2 \\E_{total}= k \frac{q_1}{(-0.5- x)^2} - k \frac{q2}{(0.5-x)^2 }\\\\E_{total = 0[/tex]

           [tex]\frac{q}{(0.5+x)^2 } = \frac{q}{(0.5-x)^2}[/tex]

The value of the two charges is the same, therefore the value of position x is:

            x = 0 m

The point where the total electric field becomes zero is at the origin of the coordinate system.

c) We look for the value of the force on the test charge introduced q₃, for this using the Coulomb equation that establishes that the force is proportional to the product of the electric charges and is inversely proportional to the square of the distance

            [tex]F_{13} = k \frac{q_1 q_3x}{(x+0.5)^2}\\F_{23} = k \frac{q_2 q_3}{(x-0.5)^2 }[/tex]

Newton's second law gives the relationship between the net force and the product of mass and acceleration.

           [tex]\sum F = m \a \\k q q_3 [ \frac{1}{(x+0.5)^2} - \frac{1}{(x-0.5)2 } }] = m \frac{d^2x}{dt^2}[/tex]

if we use the binomial development

          (0.5 + x)⁻² = 0.5 +2 x

          (0.5 -x)⁻² = 0.5 -2x

we substitute

         k q q₃ [-4x] = [tex]m \frac{d^2x}{dt^2}[/tex]  

         [tex]-(\frac{4k \ q \ q_3}{m}) \ x = m \frac{d^2x}{dt^2}[/tex]    

In oscillatory motion the general equation of motion is

          [tex]- w^2 \ x = \frac{d^2x}{dt^2}[/tex]

Equating the two expressions the angular velocity is

         [tex]w^2 = \frac{4k \ q \q_3}{m}[/tex]  

Let's calculate.

         w²= [tex]\frac{4 \ 9 \ 10^9 \ 7 \ 10^{-9} \ 1 \ 10^{-9}}{1 \ 10^{-6}}[/tex] a 4 9 10⁹ 7 10-9 1 10-9 / 1 10-6

         w =[tex]\sqrt{0.252}[/tex]

         w = 0.5 rad / s

In conclusion, using the definition of electric field, Coulomb's law and Newton's second law we can find the results for the questions about the electric field and the oscillation of the test charge are:

  a) In the attachment you have the scheme of the system.

  b) The point where the electric field is zero is: x = 0 m

  c) The angular velocity of the test charge is w = 0.5 rad / s

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Answer:

I actually don't understand what you are asking for....but if you denote second then...

Explanation:

Just divide 120/6=20

Hence, it's traveling 20m per second.

Answer:

20 m/s

Explanation:

Speed = Distance/Time

Speed = 120m/6s

Speed = 20 m/s

Answer:

I believe the answer is C. 1 and 3

Explanation:

I'm 100% sure that 1 is correct, from what I remember learning.

As for 3, it was hard to choose between 3 and 4, but I'm pretty certain that covalent bonds shared electrons rather than transfer them.

Answer:

Explanation:

acceleration a = F/m = 44000/33000 = 1.3m/s²

F = ma = 70(1.3) = 93 N

Answer:

1) 50 facing towards the right

2) 150 facing right

3) 200 facing right

4) 0- no direction

5) 50- facing left

6) 50 facing right

Explanation:

forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted

Answer:

Explanation:

Answer:

Steel

Explanation:

the most commonly used metal in the world

Answer:

bonjour

Explanation:

bye

Density of liquid try thank you so much

Answer:

  a) measure the change in volume when the object is immersed; compute from range data

  b) find the ratio of mass to volume for a measured mass and volume

Explanation:

a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.

For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.

__

b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.

Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.

Answer:

Albino possibilities

Explanation:

Answer

Explanation:

Energy flows in one direction,and matter cycle the environment

Energy flows in one direction and matter cycles through the environment in an ecosystem.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.There are many ecosystems present in the environment.

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